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Proof of Elementary Properties of the Trace of a Form along a Square-Summable Sequence

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· 8,189 chars · 20 deps · depth 26 Reason: Proof of the elementary properties of the trace along a square-summable sequence, including the tail limit by a head-and-remainder split of the defining series.

Linearity, monotonicity and the norm bound come from the corresponding properties of series of real numbers; the tail estimate splits the series at a cut-off chosen from the convergence of the defining series and uses the convergence of orthonormal expansions on the finitely many leading terms.

Proof

Each result cited is universally quantified over the data in its own statement. Throughout, kk and mm range over N\mathbb{N}, and for XSym(V)X\in\mathrm{Sym}(V) we write ak(X)=X(fk,fk)a_{k}(X)=X(f_{k},f_{k}), so that TrfX=k=1ak(X)\mathrm{Tr}_{f}X=\sum_{k=1}^{\infty}a_{k}(X), a convergent series by Square-Summable Sequences in the Form Space of a Hilbert Triple and the Trace of a Form along Them §trace. We use repeatedly that the norm of a member bb of Sym(E)\mathrm{Sym}(E), for a real inner product space EE, is nonnegative: by Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §norm it is the greatest lower bound of a set of nonnegative reals, of which 00 is a lower bound, so 0b0\le\lVert b\rVert by Existence of the Infimum of a Nonempty Subset of R\mathbb{R} Bounded Below.

Claim 1. By Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §identity, ak(X+X)=ak(X)+ak(X)a_{k}(X+X')=a_{k}(X)+a_{k}(X') and ak(λX)=λak(X)a_{k}(\lambda X)=\lambda\,a_{k}(X) for every kk. The three series k=1ak(X)\sum_{k=1}^{\infty}a_{k}(X), k=1ak(X)\sum_{k=1}^{\infty}a_{k}(X') and k=1ak(X+X)\sum_{k=1}^{\infty}a_{k}(X+X') converge, so claim 1 of Elementary Properties of Series of Real Numbers gives the first two identities. For the third, 0SymSym(V)0_{\mathrm{Sym}}\in\mathrm{Sym}(V) by claim 1 of Elementary Properties of Bounded Symmetric Bilinear Forms: Norm, Quadratic Form, Order and Continuity, and 00Sym=0Sym0\,0_{\mathrm{Sym}}=0_{\mathrm{Sym}}, both forms taking the value 00 at every pair; so the homogeneity just proved, applied with λ=0\lambda=0, gives Trf0Sym=0Trf0Sym=0\mathrm{Tr}_{f}0_{\mathrm{Sym}}=0\cdot\mathrm{Tr}_{f}0_{\mathrm{Sym}}=0.

Claim 2. Suppose XXX\preceq X'. Since fkVf_{k}\in V, Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §order gives ak(X)ak(X)a_{k}(X)\le a_{k}(X') for every kk. Both series converge, so claim 4 of Elementary Properties of Series of Real Numbers gives TrfXTrfX\mathrm{Tr}_{f}X\le\mathrm{Tr}_{f}X'.

Claim 3. Put μk=XSym(V)fkV2\mu_{k}=\lVert X\rVert_{\mathrm{Sym}(V)}\,|f_{k}|_{V}^{2}. As recorded in Square-Summable Sequences in the Form Space of a Hilbert Triple and the Trace of a Form along Them §trace, μkak(X)μk-\mu_{k}\le a_{k}(X)\le\mu_{k} for every kk, and k=1μk\sum_{k=1}^{\infty}\mu_{k} converges with sum XSym(V)σ(f)\lVert X\rVert_{\mathrm{Sym}(V)}\,\sigma(f); by claim 1 of Elementary Properties of Series of Real Numbers the series k=1(μk)\sum_{k=1}^{\infty}(-\mu_{k}) converges with sum XSym(V)σ(f)-\lVert X\rVert_{\mathrm{Sym}(V)}\,\sigma(f). Claim 4 of that lemma, applied twice, gives

XSym(V)σ(f)  TrfX  XSym(V)σ(f),-\lVert X\rVert_{\mathrm{Sym}(V)}\,\sigma(f)\ \le\ \mathrm{Tr}_{f}X\ \le\ \lVert X\rVert_{\mathrm{Sym}(V)}\,\sigma(f),

and claim 6 of Properties of the Absolute Value in an Ordered Field turns this into the stated bound.

Claim 4. By Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §identity, IV(fk,fk)=fk,fkVI_{V}(f_{k},f_{k})=\langle f_{k},f_{k}\rangle_{V}, which equals fkV2|f_{k}|_{V}^{2} by Real Inner Product Space §norm. The series defining TrfIV\mathrm{Tr}_{f}I_{V} and σ(f)\sigma(f) therefore have the same terms, and hence the same sum.

Claim 5. Let kNk\in\mathbb{N}. Since fkVf_{k}\in V, Hilbert Triples: Standing Notation and Background §triple gives fkHfkV|f_{k}|_{H}\le|f_{k}|_{V}, and both are nonnegative; so fkH2fkV2|f_{k}|_{H}^{2}\le|f_{k}|_{V}^{2} by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field, and 0fkH20\le|f_{k}|_{H}^{2} by claim 5 of Elementary Arithmetic in an Ordered Field. By claim 3 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series the series k=1fkH2\sum_{k=1}^{\infty}|f_{k}|_{H}^{2} converges and its sum σH(f)\sigma_{H}(f) satisfies σH(f)σ(f)\sigma_{H}(f)\le\sigma(f); and 0σH(f)0\le\sigma_{H}(f) by claim 2 of that lemma.

Let YSym(H)Y\in\mathrm{Sym}(H). Then YVSym(V)Y|_{V}\in\mathrm{Sym}(V) by Hilbert Triples: Standing Notation and Background §restriction, so Trf(YV)\mathrm{Tr}_{f}(Y|_{V}) is defined, and YV(fk,fk)=Y(fk,fk)Y|_{V}(f_{k},f_{k})=Y(f_{k},f_{k}) by Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §restriction. By claim 2 of Elementary Properties of Bounded Symmetric Bilinear Forms: Norm, Quadratic Form, Order and Continuity, Y(fk,fk)YfkH2|Y(f_{k},f_{k})|\le\lVert Y\rVert\,|f_{k}|_{H}^{2}; the series k=1YfkH2\sum_{k=1}^{\infty}\lVert Y\rVert\,|f_{k}|_{H}^{2} converges with sum YσH(f)\lVert Y\rVert\,\sigma_{H}(f) by claim 1 of Elementary Properties of Series of Real Numbers, so the argument of claim 3, with YfkH2\lVert Y\rVert\,|f_{k}|_{H}^{2} in place of μk\mu_{k}, gives Trf(YV)YσH(f)|\mathrm{Tr}_{f}(Y|_{V})|\le\lVert Y\rVert\,\sigma_{H}(f). Finally YσH(f)Yσ(f)\lVert Y\rVert\,\sigma_{H}(f)\le\lVert Y\rVert\,\sigma(f) by claim 5 of Elementary Arithmetic in an Ordered Field, the multiplier Y\lVert Y\rVert being nonnegative.

Claim 6, the tail forms. Let mNm\in\mathbb{N}. By The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §tail-forms, NmN_{m} is the tail form, in the sense of Coordinate Maps of a Finite Orthonormal Tuple: Forms, the Tail Form, and Quadratic Test Functions §tail, of the orthonormal mm-tuple with components e1,,eme_{1},\dots,e_{m}. Write Pmz=i=1mz,eiHeiP_{m}z=\sum_{i=1}^{m}\langle z,e_{i}\rangle_{H}e_{i} for the map of Coordinate Maps of a Finite Orthonormal Tuple: Forms, the Tail Form, and Quadratic Test Functions formed with that tuple. That clause gives

Nm(z,z)=zPmzH2(zH),0SymNmIH.N_{m}(z,z)=|z-P_{m}z|_{H}^{2}\quad(z\in H), \qquad 0_{\mathrm{Sym}}\preceq N_{m}\preceq I_{H}.

Put βk(m)=NmV(fk,fk)\beta_{k}(m)=N_{m}|_{V}(f_{k},f_{k}), which equals Nm(fk,fk)=fkPmfkH2N_{m}(f_{k},f_{k})=|f_{k}-P_{m}f_{k}|_{H}^{2} by Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §restriction. Applying Bounded Symmetric Bilinear Forms on a Real Inner Product Space: Norm, Order, Identity Form and Restriction §order to 0SymNmIH0_{\mathrm{Sym}}\preceq N_{m}\preceq I_{H} at the vector fkf_{k}, and then claim 5,

0βk(m)fkH2fkV2for all k,mN.0\le\beta_{k}(m)\le|f_{k}|_{H}^{2}\le|f_{k}|_{V}^{2}\qquad\text{for all }k,m\in\mathbb{N}.

In particular Trf(NmV)=k=1βk(m)\mathrm{Tr}_{f}(N_{m}|_{V})=\sum_{k=1}^{\infty}\beta_{k}(m) is nonnegative, by claim 2 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series.

Claim 6, the limit. Let εR\varepsilon\in\mathbb{R} be positive; the order of the choices below is: first the cut-off nn, then the index m0m_{0}.

The cut-off. The partial sums of k=1fkV2\sum_{k=1}^{\infty}|f_{k}|_{V}^{2} converge to σ(f)\sigma(f) by Series of Real Numbers §convergent, so there is nNn\in\mathbb{N} with

σ(f)k=1nfkV2<ε2.\sigma(f)-\sum_{k=1}^{n}|f_{k}|_{V}^{2}<\tfrac{\varepsilon}{2}.

The leading terms. Fix kNk\in\mathbb{N}. By Orthonormal Expansions in a Real Hilbert Space §expansion the series i=1fk,eiHei\sum_{i=1}^{\infty}\langle f_{k},e_{i}\rangle_{H}e_{i} converges in HH with sum fkf_{k}; its mm-th partial sum is PmfkP_{m}f_{k}, so the sequence (Pmfk)mN(P_{m}f_{k})_{m\in\mathbb{N}} converges to fkf_{k} in (H,dH)(H,d_{H}), that is, (fkPmfkH)mN(|f_{k}-P_{m}f_{k}|_{H})_{m\in\mathbb{N}} converges to 00, the distance being the norm of the difference by Real Inner Product Space §distance. By claim 2 of Arithmetic of Limits of Real Sequences the sequence (βk(m))mN(\beta_{k}(m))_{m\in\mathbb{N}}, whose terms are products of that sequence with itself, converges to 00. Hence, by Finite Sums of Real Numbers: Nonnegativity, Domination by the Sum, and Limits §limit applied with N=nN=n to these nn sequences, the sequence whose mm-th term is k=1nβk(m)\sum_{k=1}^{n}\beta_{k}(m) converges to k=1n0\sum_{k=1}^{n}0, which is 00 by claim 3 of Properties of Finite Sums applied with λ=0\lambda=0. So there is m0Nm_{0}\in\mathbb{N} such that

k=1nβk(m)<ε2for every mN with m0m,\sum_{k=1}^{n}\beta_{k}(m)<\tfrac{\varepsilon}{2}\qquad\text{for every }m\in\mathbb{N}\text{ with }m_{0}\le m,

the sum being nonnegative by claim 5 of Properties of Finite Sums.

The remaining terms. Let mNm\in\mathbb{N}, put μk=fkV2\mu_{k}=|f_{k}|_{V}^{2}, and let wkw_{k} be βk(m)1μk\beta_{k}(m)\tfrac{1}{\mu_{k}} if μk0\mu_{k}\ne0 and 00 if μk=0\mu_{k}=0. If μk=0\mu_{k}=0 then βk(m)=0\beta_{k}(m)=0, since 0βk(m)μk0\le\beta_{k}(m)\le\mu_{k}; so μkwk=βk(m)\mu_{k}w_{k}=\beta_{k}(m) in either case. Moreover 0wk10\le w_{k}\le1: this is clear when μk=0\mu_{k}=0, and otherwise μk\mu_{k} is positive, so 1μk\tfrac{1}{\mu_{k}} is positive by claim 7 of Elementary Order Arithmetic in an Ordered Field, and multiplying 0βk(m)μk0\le\beta_{k}(m)\le\mu_{k} by it, by claim 5 of Elementary Arithmetic in an Ordered Field, gives 0wk10\le w_{k}\le1. Claim 5 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series, applied with these μk\mu_{k} and wkw_{k} and with M=1M=1, now gives

0k=1βk(m)k=1nβk(m)σ(f)k=1nμk<ε2.0\le\sum_{k=1}^{\infty}\beta_{k}(m)-\sum_{k=1}^{n}\beta_{k}(m)\le\sigma(f)-\sum_{k=1}^{n}\mu_{k}<\tfrac{\varepsilon}{2}.

Conclusion. Let mNm\in\mathbb{N} with m0mm_{0}\le m. Adding the two displayed estimates gives 0Trf(NmV)<ε0\le\mathrm{Tr}_{f}(N_{m}|_{V})<\varepsilon, whence Trf(NmV)0<ε|\mathrm{Tr}_{f}(N_{m}|_{V})-0|<\varepsilon by claim 1 of Properties of the Absolute Value in an Ordered Field. As ε\varepsilon was an arbitrary positive real, the sequence (Trf(NmV))mN(\mathrm{Tr}_{f}(N_{m}|_{V}))_{m\in\mathbb{N}} converges to 00.

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