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Proof of An Absolutely Convergent Series of Real Numbers Converges

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Β· 4,285 chars Β· 6 deps Β· depth 13 Reason: Proof: absolute convergence gives convergence by comparing the nonnegative series with terms a_k+|a_k| against twice the series of absolute values; the two bounds follow by comparison of sums and the two-sided characterisation of the absolute value.

Absolute convergence gives convergence by comparing the nonnegative series with terms ak+∣ak∣a_k+|a_k| against twice the series of absolute values; the two bounds then follow by comparison of sums and the two-sided characterisation of the absolute value.

Proof

Each result cited below is universally quantified over the data in its own statement, and is applied to the data named in the step where it is cited. Throughout, βˆ£β‹…βˆ£|\cdot| is the absolute value on R\mathbb{R}, and we write 22 for 1+11+1, so that 2∣ak∣=∣ak∣+∣ak∣2|a_{k}|=|a_{k}|+|a_{k}|.

Claim 1. Suppose that βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k} converges absolutely, that is, by Series of Real Numbers Β§absolute, that βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}| converges.

Step 1 (termwise bounds). Fix k∈Nk\in\mathbb{N}. By claim 3 of Properties of the Absolute Value in an Ordered Field we have βˆ’βˆ£akβˆ£β‰€akβ‰€βˆ£ak∣-|a_{k}|\le a_{k}\le|a_{k}|. Applying claim 3 of Elementary Arithmetic in an Ordered Field to the inequality βˆ’βˆ£akβˆ£β‰€ak-|a_{k}|\le a_{k} gives 0≀akβˆ’(βˆ’βˆ£ak∣)=ak+∣ak∣0\le a_{k}-(-|a_{k}|)=a_{k}+|a_{k}|. Applying the same claim to the inequality akβ‰€βˆ£ak∣a_{k}\le|a_{k}| gives 0β‰€βˆ£akβˆ£βˆ’ak0\le|a_{k}|-a_{k}, and

∣akβˆ£βˆ’ak=2∣akβˆ£βˆ’(ak+∣ak∣),|a_{k}|-a_{k}=2|a_{k}|-\bigl(a_{k}+|a_{k}|\bigr) ,

so a second use of claim 3 of Elementary Arithmetic in an Ordered Field, in the direction from 0≀yβˆ’x0\le y-x to x≀yx\le y with x=ak+∣ak∣x=a_{k}+|a_{k}| and y=2∣ak∣y=2|a_{k}|, gives ak+∣akβˆ£β‰€2∣ak∣a_{k}+|a_{k}|\le2|a_{k}|. Thus

0≀ak+∣akβˆ£β‰€2∣ak∣forΒ everyΒ k∈N.0\le a_{k}+|a_{k}|\le2|a_{k}|\qquad\text{for every }k\in\mathbb{N}.

Step 2 (comparison). The linearity clause Elementary Properties of Series of Real Numbers Β§linearity takes two sequences whose series converge and a scalar; we apply it with (∣ak∣)k∈N(|a_{k}|)_{k\in\mathbb{N}} in both sequence slots, which is legitimate since βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}| converges by assumption, and with the scalar Ξ»=2\lambda=2. It gives that the series βˆ‘k=1∞2∣ak∣\sum_{k=1}^{\infty}2|a_{k}| converges. By the comparison test Series of Nonnegative Real Numbers, Comparison, and the Geometric Series Β§comparison, applied to the sequences (ak+∣ak∣)k∈N(a_{k}+|a_{k}|)_{k\in\mathbb{N}} and (2∣ak∣)k∈N(2|a_{k}|)_{k\in\mathbb{N}}, whose hypotheses are exactly the bounds of Step 1, the series βˆ‘k=1∞(ak+∣ak∣)\sum_{k=1}^{\infty}\bigl(a_{k}+|a_{k}|\bigr) converges.

Step 3 (conclusion). By Elementary Properties of Series of Real Numbers Β§linearity, applied again with (∣ak∣)k∈N(|a_{k}|)_{k\in\mathbb{N}} in both sequence slots and with Ξ»=βˆ’1\lambda=-1, the series βˆ‘k=1∞(βˆ’βˆ£ak∣)\sum_{k=1}^{\infty}\bigl(-|a_{k}|\bigr) converges, with sum βˆ’βˆ‘k=1∞∣ak∣-\sum_{k=1}^{\infty}|a_{k}|. Since

ak=(ak+∣ak∣)+(βˆ’βˆ£ak∣)forΒ everyΒ k∈N,a_{k}=\bigl(a_{k}+|a_{k}|\bigr)+\bigl(-|a_{k}|\bigr)\qquad\text{for every }k\in\mathbb{N},

the same clause Elementary Properties of Series of Real Numbers Β§linearity, applied to the two convergent series produced in Steps 2 and 3 and to any scalar, shows that βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k} converges.

Claim 2. Suppose again that βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}| converges, and write L=βˆ‘k=1∞∣ak∣L=\sum_{k=1}^{\infty}|a_{k}|. By Claim 1 the series βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k} converges, and by Elementary Properties of Series of Real Numbers Β§linearity, applied with (∣ak∣)k∈N(|a_{k}|)_{k\in\mathbb{N}} in both sequence slots and with Ξ»=βˆ’1\lambda=-1, the series βˆ‘k=1∞(βˆ’βˆ£ak∣)\sum_{k=1}^{\infty}\bigl(-|a_{k}|\bigr) converges with sum βˆ’L-L. By claim 3 of Properties of the Absolute Value in an Ordered Field we have βˆ’βˆ£akβˆ£β‰€ak-|a_{k}|\le a_{k} and akβ‰€βˆ£ak∣a_{k}\le|a_{k}| for every k∈Nk\in\mathbb{N}. Applying the comparison of sums Elementary Properties of Series of Real Numbers Β§order first to the pair of convergent series βˆ‘k=1∞(βˆ’βˆ£ak∣)\sum_{k=1}^{\infty}\bigl(-|a_{k}|\bigr) and βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k}, and then to the pair βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k} and βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}|, gives

βˆ’Lβ‰€βˆ‘k=1∞ak≀L.-L\le\sum_{k=1}^{\infty}a_{k}\le L .

By claim 6 of Properties of the Absolute Value in an Ordered Field this two-sided bound is equivalent to βˆ£βˆ‘k=1∞akβˆ£β‰€L\bigl|\sum_{k=1}^{\infty}a_{k}\bigr|\le L, which is the assertion.

Claim 3. Assume that ∣akβˆ£β‰€bk|a_{k}|\le b_{k} for every k∈Nk\in\mathbb{N} and that βˆ‘k=1∞bk\sum_{k=1}^{\infty}b_{k} converges. By claim 1 of Properties of the Absolute Value in an Ordered Field we have 0β‰€βˆ£ak∣0\le|a_{k}|, so 0β‰€βˆ£akβˆ£β‰€bk0\le|a_{k}|\le b_{k} for every k∈Nk\in\mathbb{N}. The comparison test Series of Nonnegative Real Numbers, Comparison, and the Geometric Series Β§comparison, applied to the sequences (∣ak∣)k∈N(|a_{k}|)_{k\in\mathbb{N}} and (bk)k∈N(b_{k})_{k\in\mathbb{N}}, shows that βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}| converges and that

βˆ‘k=1∞∣akβˆ£β‰€βˆ‘k=1∞bk.\sum_{k=1}^{\infty}|a_{k}|\le\sum_{k=1}^{\infty}b_{k} .

Convergence of βˆ‘k=1∞∣ak∣\sum_{k=1}^{\infty}|a_{k}| is precisely absolute convergence of βˆ‘k=1∞ak\sum_{k=1}^{\infty}a_{k}, by Series of Real Numbers Β§absolute, and the remaining inequality βˆ£βˆ‘k=1∞akβˆ£β‰€βˆ‘k=1∞∣ak∣\bigl|\sum_{k=1}^{\infty}a_{k}\bigr|\le\sum_{k=1}^{\infty}|a_{k}| is Claim 2.

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