Β· 4,285 chars Β· 6 deps Β· depth 13 Reason: Proof: absolute convergence gives convergence by comparing the nonnegative series with terms a_k+|a_k| against twice the series of absolute values; the two bounds follow by comparison of sums and the two-sided characterisation of the absolute value.
Absolute convergence gives convergence by comparing the nonnegative series with terms akβ+β£akββ£ against twice the series of absolute values; the two bounds then follow by comparison of sums and the two-sided characterisation of the absolute value.
Proof
Each result cited below is universally quantified over the data in its own statement, and is applied to the data named in the step where it is cited. Throughout, β£β β£ is the absolute value on R, and we write 2 for 1+1, so that 2β£akββ£=β£akββ£+β£akββ£.
Claim 1. Suppose that βk=1ββakβ converges absolutely, that is, by Series of Real Numbers Β§absolute, that βk=1βββ£akββ£ converges.
Step 1 (termwise bounds). Fix kβN. By claim 3 of Properties of the Absolute Value in an Ordered Field we have ββ£akββ£β€akββ€β£akββ£. Applying claim 3 of Elementary Arithmetic in an Ordered Field to the inequality ββ£akββ£β€akβ gives 0β€akββ(ββ£akββ£)=akβ+β£akββ£. Applying the same claim to the inequality akββ€β£akββ£ gives 0β€β£akββ£βakβ, and
so a second use of claim 3 of Elementary Arithmetic in an Ordered Field, in the direction from 0β€yβx to xβ€y with x=akβ+β£akββ£ and y=2β£akββ£, gives akβ+β£akββ£β€2β£akββ£. Thus
Step 2 (comparison). The linearity clause Elementary Properties of Series of Real Numbers Β§linearity takes two sequences whose series converge and a scalar; we apply it with (β£akββ£)kβNβ in both sequence slots, which is legitimate since βk=1βββ£akββ£ converges by assumption, and with the scalar Ξ»=2. It gives that the series βk=1ββ2β£akββ£ converges. By the comparison test Series of Nonnegative Real Numbers, Comparison, and the Geometric Series Β§comparison, applied to the sequences (akβ+β£akββ£)kβNβ and (2β£akββ£)kβNβ, whose hypotheses are exactly the bounds of Step 1, the series βk=1ββ(akβ+β£akββ£) converges.
Step 3 (conclusion). By Elementary Properties of Series of Real Numbers Β§linearity, applied again with (β£akββ£)kβNβ in both sequence slots and with Ξ»=β1, the series βk=1ββ(ββ£akββ£) converges, with sum ββk=1βββ£akββ£. Since
Claim 2. Suppose again that βk=1βββ£akββ£ converges, and write L=βk=1βββ£akββ£. By Claim 1 the series βk=1ββakβ converges, and by Elementary Properties of Series of Real Numbers Β§linearity, applied with (β£akββ£)kβNβ in both sequence slots and with Ξ»=β1, the series βk=1ββ(ββ£akββ£) converges with sum βL. By claim 3 of Properties of the Absolute Value in an Ordered Field we have ββ£akββ£β€akβ and akββ€β£akββ£ for every kβN. Applying the comparison of sums Elementary Properties of Series of Real Numbers Β§order first to the pair of convergent series βk=1ββ(ββ£akββ£) and βk=1ββakβ, and then to the pair βk=1ββakβ and βk=1βββ£akββ£, gives
Convergence of βk=1βββ£akββ£ is precisely absolute convergence of βk=1ββakβ, by Series of Real Numbers Β§absolute, and the remaining inequality ββk=1ββakβββ€βk=1βββ£akββ£ is Claim 2.