TheoremBase

All maps involved are continuous, hence integrable; by the product rule FG is an antiderivative of F'G + FG', so the second part of the fundamental theorem and additivity of the integral in the integrand give the formula.

Proof

Continuity and integrability. Let x∈[a,b]x\in[a,b]. As FF and GG are differentiable at xx, they are continuous at xx by The Increment Form of the Derivative, and Differentiability Implies Continuity (ii); as xx was arbitrary, FF and GG are continuous on [a,b][a,b] by The Real Line: Standing Notation and Background for Calculus on Intervals (vi). Let h=Fβ€²G+FGβ€²:[a,b]β†’Rh=F'G+FG':[a,b]\to\mathbb{R}, the pointwise sum. By Continuity of Sums and Products of Real-Valued Functions on a Metric Space (v), applied with (X,d)=(R,dR)(X,d)=(\mathbb{R},d_{\mathbb{R}}) and A=[a,b]A=[a,b], the maps FGβ€²FG', Fβ€²GF'G, hh and FGFG are continuous on [a,b][a,b]. Each of them is therefore bounded, by Extreme Value Theorem on a Closed Real Interval (i), and integrable on [a,b][a,b], by A Continuous Function on a Closed Interval is Riemann Integrable (i). For FGβ€²FG' and Fβ€²GF'G this is (i).

An antiderivative of hh. Let x∈[a,b]x\in[a,b]. By Derivatives of Constants, the Identity, Sums, Scalar Multiples, Products, Reciprocals, Quotients and Powers (vi), FGFG is differentiable at xx and

(FG)β€²(x)=Fβ€²(x) G(x)+F(x) Gβ€²(x)=h(x),(FG)'(x)=F'(x)\,G(x)+F(x)\,G'(x)=h(x),

the derivative being unique by Derivative of a Real Function on an Interval (ii). In particular FGFG is continuous on [a,b][a,b] and differentiable at every x∈(a,b)x\in(a,b) with (FG)β€²(x)=h(x)(FG)'(x)=h(x), and hh is bounded and integrable on [a,b][a,b]. By Fundamental Theorem of Calculus, Part II: Evaluating an Integral by an Antiderivative (i), applied to hh in place of ff and FGFG in place of FF,

∫abh=(FG)(b)βˆ’(FG)(a)=F(b) G(b)βˆ’F(a) G(a).\int_{a}^{b}h=(FG)(b)-(FG)(a)=F(b)\,G(b)-F(a)\,G(a).

Conclusion. By Rules for the Riemann Integral: Sums, Scalar Multiples, Monotonicity, Bounds and Constants (i), applied to the bounded integrable maps Fβ€²GF'G and FGβ€²FG',

∫abh=∫abFβ€²G+∫abFGβ€².\int_{a}^{b}h=\int_{a}^{b}F'G+\int_{a}^{b}FG' .

Comparing the two expressions for ∫abh\int_{a}^{b}h and subtracting ∫abFβ€²G\int_{a}^{b}F'G gives

∫abFGβ€²=F(b) G(b)βˆ’F(a) G(a)βˆ’βˆ«abFβ€²G,\int_{a}^{b}FG'=F(b)\,G(b)-F(a)\,G(a)-\int_{a}^{b}F'G,

which, as (FGβ€²)(t)=F(t) Gβ€²(t)(FG')(t)=F(t)\,G'(t) and (Fβ€²G)(t)=Fβ€²(t) G(t)(F'G)(t)=F'(t)\,G(t) for t∈[a,b]t\in[a,b] by Pointwise Operations on Real-Valued Maps (i), is (ii).

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