Each result cited is universally quantified over the data appearing in its own statement, and is applied here to the data named in the statement above. We use countable choice, to select representatives and indices indexed by N.
Throughout, Lp is a real vector space with the pointwise operations, by Minkowski's Inequality (ii), and for f∈Lp the class [f] is as in The Lebesgue Space Lᵖ(μ) (i).
Claim 1. The two operations on Lp are well defined by The Lebesgue Space Lᵖ(μ) (ii). Each of the conditions 1 to 8 of Vector Space over a Field is an identity between classes whose two sides are, by the definition of the operations, the classes of the two sides of the corresponding identity in Lp; since those identities hold in Lp, the conditions hold in Lp. For instance ([f]+[g])+[h]=[(f+g)+h]=[f+(g+h)]=[f]+([g]+[h]), and [f]+[0X]=[f+0X]=[f], where 0X is the map taking the value 0 everywhere, so [0X] is a zero vector and is the zero vector by claim 1 of Elementary Identities in a Vector Space; and [f]+[−f]=[f+(−f)]=[0X] gives condition 4. So Lp is a vector space over R.
The number ∥[f]∥p is well defined and nonnegative by The Lebesgue Space Lᵖ(μ) (iii). If ∥[f]∥p=0 then f=0 almost everywhere by Elementary Properties of the p-Seminorm (v), that is f∼0X, so [f]=[0X] is the zero vector; this is condition (a) of Norms and Real Normed Spaces (i). Condition (b) holds because ∥c[f]∥p=∥[cf]∥p=∥cf∥p=∣c∣∥f∥p by Elementary Properties of the p-Seminorm (ii), and condition (c) because ∥[f]+[g]∥p=∥f+g∥p≤∥f∥p+∥g∥p by Minkowski's Inequality (i). Hence Lp is a real normed space. Its distance is dp([f],[g])=∥[f]−[g]∥p by Norms and Real Normed Spaces (iii), and [f]−[g]=[f]+[−g]=[f−g], which gives the stated formula.
A construction. Let (Fm)m∈N be a Cauchy sequence in (Lp,dp) and for each m let fm∈Lp be a representative of Fm. We construct natural numbers m1<m2<…, a function h∈Lp, a null set N and a function g∈Lp such that for every x∈X∖N the sequence (fmj(x))j converges to g(x) with ∣fmj(x)∣≤h(x) for every j, and such that ∥fmj−g∥p converges to 0.
Step 1. For each j∈N the Cauchy condition, applied with the positive number (1/2)j, provides Mj∈N with dp(Fk,Fl)<(1/2)j whenever k,l≥Mj; choose such an Mj for each j. Define m1=M1 and, recursively, mj+1 to be the larger of mj+1 and Mj+1. Then mj<mj+1 for every j, and mj≥Mj, so both mj and mj+1 are at least Mj and
∥fmj+1−fmj∥p=dp(Fmj+1,Fmj)<(21)j,
the first equality by claim 1. Write uj=fmj.
Step 2. For J∈N put TJ=∑j=1J∣uj+1−uj∣, a finite sum in Lp, and GJ=∣u1∣+TJ; also put T0=0X and G0=∣u1∣. Each ∣uj+1−uj∣ lies in Lp with the same seminorm as uj+1−uj, by Elementary Properties of the p-Seminorm (iii) applied in both directions, and likewise for ∣u1∣. By Minkowski's Inequality (iii),
∥GJ∥p≤∥u1∥p+j=1∑J∥uj+1−uj∥p≤∥u1∥p+j=1∑J(21)j≤∥u1∥p+1=:C,
the last inequality because the partial sums of the series of the (1/2)j are at most its sum, which is 1, by claims 2 and 4 of Series of Nonnegative Real Numbers, Comparison, and the Geometric Series. By Elementary Properties of the p-Seminorm (i) and Properties of Real Powers (v) this gives ∫XGJpdμ=(∥GJ∥p)p≤Cp for every J.
The sequence (GJ)J is pointwise nondecreasing, since each added term is nonnegative, so (GJp)J is pointwise nondecreasing by Properties of Real Powers (v). Let H:X→[0,∞] be its pointwise least upper bound. By Monotone Convergence Theorem the map H is measurable and ∫XHdμ is the least upper bound of the numbers ∫XGJpdμ, hence at most Cp and in particular finite. By The Lebesgue Integral and Null Sets (v) the set N={x∈X:H(x)=∞} belongs to F and has measure 0; it is therefore null.
Step 3. Let H~:X→R be the map equal to H off N and to 0 on N; it takes real values because H is finite off N, and it is nonnegative. It is measurable: for a real c<0 the set {x∈X:H~(x)>c} is X, while for 0≤c it equals {x∈X:H(x)>c}∩(X∖N), a member of F because H is measurable and N∈F; the criterion in Measurable Functions and the Lebesgue Integral: Standing Notation (iii) applies. Put h=∣H~∣1/p, which is measurable by Elementary Properties of the p-Seminorm (vi) applied with the exponents 1/p and p, and satisfies hp=H~≤H pointwise by Properties of Real Powers (iv). Hence ∫Xhpdμ≤∫XHdμ<∞ by claim 1 of Linearity and Monotonicity of the Lebesgue Integral, and the Integrability Criterion, so h∈Lp.
Let x∈X∖N, so that H(x)=H~(x) is a nonnegative real number. For every J we have (GJ(x))p≤H(x), hence GJ(x)≤h(x) by Properties of Real Powers (vi). Since ∣uj(x)∣≤Gj−1(x) for every j, by the triangle inequality of claim 5 of Properties of the Absolute Value in an Ordered Field applied along the telescoping identity uj=u1+∑i=1j−1(ui+1−ui), we obtain
∣uj(x)∣≤h(x)for every j∈N.
Moreover (TJ(x))J is nondecreasing and bounded above by h(x), so it converges by A Bounded Monotone Sequence of Real Numbers Converges (i) and is therefore a Cauchy sequence of real numbers. For l>j≥1 the same triangle inequality gives
∣ul(x)−uj(x)∣≤i=j∑l−1∣ui+1(x)−ui(x)∣=Tl−1(x)−Tj−1(x),
so (uj(x))j is a Cauchy sequence of real numbers and hence converges, by The Real Numbers: Standing Notation and Background (iii).
Step 4. Define g:X→R by letting g(x) be the limit of (uj(x))j for x∈/N and g(x)=0 for x∈N. Writing u~j=uj1X∖N for the map equal to uj off N and to 0 on N, which is measurable by claims 1 and 3 of Arithmetic of Measurable Real- and [0,∞]-Valued Maps since X∖N∈F, the sequence (u~j(x))j converges to g(x) at every x∈X, so g is measurable by claim 5 of Arithmetic of Measurable Real- and [0,∞]-Valued Maps. Passing to the limit in the bound ∣uj(x)∣≤h(x), valid off N, and using g=0=∣g∣≤h on N together with h≥0, we get ∣g∣≤h pointwise, so g∈Lp by Elementary Properties of the p-Seminorm (iii).
For x∈/N the sequence (∣uj(x)−g(x)∣)j converges to 0, hence so does ((∣uj(x)−g(x)∣)p)j by Properties of Real Powers (vii) and 0p=0. Also ∣uj−g∣≤∣uj∣+∣g∣≤2h pointwise off N, by claims 2 and 5 of Properties of the Absolute Value in an Ordered Field, so ∣uj−g∣p≤2php there, by Properties of Real Powers (v) and Properties of Real Powers (iii); the map 2php is integrable since h∈Lp. The maps ∣uj−g∣p are measurable by Power-Integrable Functions and the p-Seminorm (i). Applying The Lebesgue Integral and Null Sets (vii), with the constant limit function 0X, gives
j→∞lim∫X∣uj−g∣pdμ=0.
By Elementary Properties of the p-Seminorm (i) the integral equals (∥uj−g∥p)p, and applying Properties of Real Powers (vii) with the exponent 1/p to this sequence of nonnegative reals, together with ((∥uj−g∥p)p)1/p=∥uj−g∥p and 01/p=0, we conclude that ∥uj−g∥p converges to 0. This completes the construction.
Claim 2. Let (Fm) be a Cauchy sequence in (Lp,dp); choose a representative fm of each Fm and run the construction, obtaining mj, g and the convergence ∥fmj−g∥p→0, that is dp(Fmj,[g])→0.
Let ε be a positive real number. There is M∈N with dp(Fk,Fl)<ε/2 for all k,l≥M, and there is j with mj≥M and dp(Fmj,[g])<ε/2, because mj≥j for every j and dp(Fmj,[g])→0. For every k≥M the triangle inequality in the metric dp gives
dp(Fk,[g])≤dp(Fk,Fmj)+dp(Fmj,[g])<ε.
Hence (Fm) converges to [g]∈Lp. So every Cauchy sequence in (Lp,dp) converges, that is (Lp,dp) is complete, and Lp is a real Banach space by Norms and Real Normed Spaces (v).
Claim 3. Let (Fm) converge to F, with representatives fm and f as in the statement. The sequence (Fm) is Cauchy: given a positive ε, choose M with dp(Fm,F)<ε/2 for m≥M; then dp(Fk,Fl)≤dp(Fk,F)+dp(F,Fl)<ε for k,l≥M. Run the construction with these representatives, obtaining m1<m2<…, a function h∈Lp, a null set N1 and g∈Lp with (fmj(x))j converging to g(x) and ∣fmj(x)∣≤h(x) for every x∈/N1 and every j, and with dp(Fmj,[g])→0.
By A Subsequence of a Convergent Sequence Has the Same Limit the subsequence (Fmj)j converges to F, so for every positive ε we have, for large j,
∥g−f∥p=dp([g],F)≤dp([g],Fmj)+dp(Fmj,F)<ε.
Hence ∥g−f∥p=0, by Comparison of Real Numbers with Arbitrary Positive Slack, so g−f=0 almost everywhere by Elementary Properties of the p-Seminorm (v); let N2 be the null set of points where g and f differ. By The Lebesgue Integral and Null Sets (i) the set N=N1∪N2 is null, and for x∈X∖N the sequence (fmj(x))j converges to g(x)=f(x) and satisfies ∣fmj(x)∣≤h(x) for every j. This is the assertion.