TheoremBase

Extend bounded dH−Lipschitzd_H-Lipschitz functions from H−1H^{-1} = D(A) to H by density and the uniformly continuous extension lemma, keeping bound and Lipschitz constant; this turns g into a cost gbar on V. Existence: the constants +-C_g/gamma are sub/super bounds for the shifted operator, so the Hilbert-triple existence theorem gives a bounded uniformly continuous solution w, Lipschitz by the viscous Hamilton-Jacobi theorem; the bridge lemma makes u0u_0 + w| a renormalised solution. Comparison: extend uiu_i - u0u_0, apply the bridge back and the shifted comparison. Uniqueness and the free solution follow.

Proof

Each result cited is universally quantified over the data in its own statement.

Conventions. By The Wick-Square Problem on the Sobolev Triple of Order Two: Standing Notation §triple, (H,V,A)(H,V,A) is a Hilbert triple in the setting of Hilbert Triples: Standing Notation and Background, with H=H−3H=H^{-3}, V=H−2V=H^{-2}, D(A)=H−1⊆V⊆HD(A)=H^{-1}\subseteq V\subseteq H, and ∣x∣H≤∣x∣V|x|_{H}\le|x|_{V} for x∈Vx\in V (Hilbert Triples: Standing Notation and Background §triple). Elementary arithmetic in R\mathbb{R} (the triangle inequality, maxima of two numbers, the limit laws and the order of limits) is used under The Real Numbers: Standing Notation and Background §background. Continuity of real functions on subsets of (H,dH)(H,d_{H}) is equivalent to sequential continuity (Real Hilbert Spaces: Standing Notation and Background §topology). Every function that is Lipschitz with a constant Λ≥0\Lambda\ge0 (Lipschitz Map Between Metric Spaces) on a subset SS of a metric space is uniformly continuous on SS: given ε>0\varepsilon>0, the number ε/(Λ+1)\varepsilon/(\Lambda+1) serves as δ\delta. Every function uniformly continuous on SS is continuous at every point of SS relative to SS (Continuous Map Between Metric Spaces): the δ\delta of uniform continuity serves at each point.

Step 0 (Extension from the state space). We show: (E) if M,Λ≥0M,\Lambda\ge0 and f:H−1→Rf:H^{-1}\to\mathbb{R} satisfies ∣f(x)∣≤M|f(x)|\le M and ∣f(x)−f(y)∣≤Λ∣x−y∣H|f(x)-f(y)|\le\Lambda|x-y|_{H} for x,y∈H−1x,y\in H^{-1}, then there is f^:H→R\hat{f}:H\to\mathbb{R}, continuous on HH, with f^=f\hat{f}=f on H−1H^{-1}, ∣f^(x)∣≤M|\hat{f}(x)|\le M and ∣f^(x)−f^(y)∣≤Λ∣x−y∣H|\hat{f}(x)-\hat{f}(y)|\le\Lambda|x-y|_{H} for all x,y∈Hx,y\in H. Indeed, H−1=D(A)H^{-1}=D(A) is nonempty (it contains 0H0_{H}) and dense in HH by The Resolvent of the Form Operator of a Hilbert Triple: Minimisation, Contraction, and Density of the Domain §dense-in-h, that is dense in the topological space of the metric space (H,dH)(H,d_{H}) (Real Hilbert Space §topology); ff is Lipschitz, hence uniformly continuous, on H−1H^{-1}. By Extension of a Uniformly Continuous Real Function from a Dense Subset §existence with (X,d)=(H,dH)(X,d)=(H,d_{H}) and S=H−1S=H^{-1} there is f^:H→R\hat{f}:H\to\mathbb{R}, continuous on HH, with f^=f\hat{f}=f on H−1H^{-1}, and by Extension of a Uniformly Continuous Real Function from a Dense Subset §bounds, ∣f^(x)∣≤M|\hat{f}(x)|\le M for x∈Hx\in H. Let x,y∈Hx,y\in H. By The Penalty Function h=12∣⋅∣V2h=\tfrac12|\cdot|_V^2 of a Hilbert Triple: Expansion Identities, Closed Sublevel Sets, Density and Local Bounds §dense (with U=HU=H, open in HH by Hilbert Triples: Standing Notation and Background §open-sets), choose for each j∈Nj\in\mathbb{N} points xj,yj∈H−1x_{j},y_{j}\in H^{-1} with ∣xj−x∣H<1/j|x_{j}-x|_{H}<1/j and ∣yj−y∣H<1/j|y_{j}-y|_{H}<1/j. Then ∣f^(xj)−f^(yj)∣=∣f(xj)−f(yj)∣≤Λ∣xj−yj∣H≤Λ(∣x−y∣H+2/j)|\hat{f}(x_{j})-\hat{f}(y_{j})|=|f(x_{j})-f(y_{j})|\le\Lambda|x_{j}-y_{j}|_{H}\le\Lambda(|x-y|_{H}+2/j); as xj→xx_{j}\to x and yj→yy_{j}\to y in HH and f^\hat{f} is continuous, letting j→∞j\to\infty gives ∣f^(x)−f^(y)∣≤Λ∣x−y∣H|\hat{f}(x)-\hat{f}(y)|\le\Lambda|x-y|_{H}.

Apply (E) to gg with M=CgM=C_{g}, Λ=ℓg\Lambda=\ell_{g}, and let gˉ:V→R\bar{g}:V\to\mathbb{R} be the restriction of the resulting extension to VV. Then ∣gˉ(x)∣≤Cg|\bar{g}(x)|\le C_{g} and ∣gˉ(x)−gˉ(y)∣≤ℓg∣x−y∣H|\bar{g}(x)-\bar{g}(y)|\le\ell_{g}|x-y|_{H} for x,y∈Vx,y\in V, and gˉ∣H−1=g\bar{g}|_{H^{-1}}=g. Hence The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space and Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two apply to CgC_{g}, ℓg\ell_{g} and gˉ\bar{g}; we let F♯F^{\sharp} be the shifted operator for gˉ\bar{g}, and the renormalised notions there, taken for the running cost gˉ∣H−1=g\bar{g}|_{H^{-1}}=g, are those of the theorem.

Step 1 (Existence). Put C=Cg/γC=C_{g}/\gamma, nonnegative since γ>0\gamma>0 (The Wick-Square Problem on the Torus: Standing Notation §parameters). Let x∈D(A)x\in D(A), and let 0Sym0_{\mathrm{Sym}} be the zero form of Sym(V)\mathrm{Sym}(V). By The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §noise, Trf0Sym\mathrm{Tr}_{f}0_{\mathrm{Sym}} is the lattice sum of the zero family, all of whose cube sums are 00, so it is 00 (Cube Sums of Families on the Integer Lattice §lattice-sum); G(0H,0H)=G(0⋅0H,0H)=0G(0_{H},0_{H})=G(0\cdot0_{H},0_{H})=0 by bilinearity of G∈Sym(H)G\in\mathrm{Sym}(H) (The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §gradient-form); and ⟨Ax+Bqx,0H⟩H=0\langle Ax+B_{q}x,0_{H}\rangle_{H}=0 by Elementary Identities in a Real Inner Product Space §zero. Hence by The Shifted Hamilton-Jacobi-Bellman Equation of the Wick-Square Problem on the Sobolev Triple of Order Two §operator

F♯(x,−C,0H,0Sym)=−Cg−gˉ(x)≤0,F♯(x,C,0H,0Sym)=Cg−gˉ(x)≥0.F^{\sharp}(x,-C,0_{H},0_{\mathrm{Sym}})=-C_{g}-\bar{g}(x)\le0,\qquad F^{\sharp}(x,C,0_{H},0_{\mathrm{Sym}})=C_{g}-\bar{g}(x)\ge0 .

F♯F^{\sharp} is a second-order equation operator on HH relative to (H,V,A)(H,V,A) (The Shifted Hamilton-Jacobi-Bellman Equation of the Wick-Square Problem on the Sobolev Triple of Order Two §operator) satisfying all the structural hypotheses of Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple by The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space §hypotheses. That theorem gives w:H→Rw:H\to\mathbb{R} that is a viscosity solution of F♯F^{\sharp} on HH (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §solution), satisfies ∣w(x)∣≤C|w(x)|\le C for x∈Hx\in H (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §bounded), and is uniformly continuous on HH (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §uniformly-continuous), hence continuous on HH (Conventions).

Next apply Lipschitz Regularity of Bounded Continuous Viscosity Solutions of a Viscous Hamilton-Jacobi Equation with a Monotone Nonlinearity on a Hilbert Triple, whose standing hypothesis that HH is not finite-dimensional holds by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §infinite, with λ0=γ\lambda_{0}=\gamma, the constants Cg,ℓgC_{g},\ell_{g}, the cost gˉ\bar{g}, B=BqB=B_{q} (a monotone nonlinearity by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §drift), the given ν>0\nu>0, the sequence ff (square-summable in VV by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §noise), Γ=G\Gamma=G (with 0Sym⪯G⪯IH0_{\mathrm{Sym}}\preceq G\preceq I_{H} by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §gradient-form), C′=CC'=C and u=wu=w. The operator of that theorem is then, term by term, F♯F^{\sharp}, of which ww is a bounded continuous viscosity solution. By Lipschitz Regularity of Bounded Continuous Viscosity Solutions of a Viscous Hamilton-Jacobi Equation with a Monotone Nonlinearity on a Hilbert Triple §lipschitz, with Λ0=ℓg/γ+2Cg/γ+1\Lambda_{0}=\ell_{g}/\gamma+2C_{g}/\gamma+1,

∣w(x)−w(y)∣≤Λ0 ∣x−y∣Hfor all x,y∈H.|w(x)-w(y)|\le\Lambda_{0}\,|x-y|_{H}\qquad\text{for all }x,y\in H .

By Viscosity Subsolution, Supersolution and Solution of a Second-Order Equation on a Hilbert Triple §solution, ww is both a viscosity subsolution and a viscosity supersolution of F♯F^{\sharp} on HH; as ww is bounded and continuous on HH, Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two §from-shifted shows that u=u0+w∣H−1u=u_{0}+w|_{H^{-1}} is a renormalised viscosity subsolution and supersolution, i.e. a renormalised viscosity solution (Renormalised Viscosity Subsolutions, Supersolutions and Solutions of the Wick-Square Problem, Tested by the Gaussian Penalty plus a Regular Function §solution). Since u−u0=w∣H−1u-u_{0}=w|_{H^{-1}}, one has ∣u(x)−u0(x)∣≤Cg/γ|u(x)-u_{0}(x)|\le C_{g}/\gamma and ∣(u−u0)(x)−(u−u0)(y)∣≤Λ0∣x−y∣H|(u-u_{0})(x)-(u-u_{0})(y)|\le\Lambda_{0}|x-y|_{H} for x,y∈H−1x,y\in H^{-1}; in particular u−u0u-u_{0} is bounded and Lipschitz from (H−1,dH)(H^{-1},d_{H}) to R\mathbb{R}, so u∈Cu\in\mathcal{C}. This proves clause 1.

Step 2 (Comparison). Let u1,u2∈Cu_{1},u_{2}\in\mathcal{C}, u1u_{1} a renormalised viscosity subsolution and u2u_{2} a renormalised viscosity supersolution. For i∈{1,2}i\in\{1,2\}, choose Mi,Λi≥0M_{i},\Lambda_{i}\ge0 with ∣(ui−u0)(x)∣≤Mi|(u_{i}-u_{0})(x)|\le M_{i} and ∣(ui−u0)(x)−(ui−u0)(y)∣≤Λi∣x−y∣H|(u_{i}-u_{0})(x)-(u_{i}-u_{0})(y)|\le\Lambda_{i}|x-y|_{H} for x,y∈H−1x,y\in H^{-1}, and let wi:H→Rw_{i}:H\to\mathbb{R} be the extension of ui−u0u_{i}-u_{0} given by (E): continuous on HH, ∣wi∣≤Mi|w_{i}|\le M_{i} on HH, Lipschitz with constant Λi\Lambda_{i} from (H,dH)(H,d_{H}) to R\mathbb{R}, and ui=u0+wi∣H−1u_{i}=u_{0}+w_{i}|_{H^{-1}}. By Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two §to-shifted, w1w_{1} is a viscosity subsolution and w2w_{2} a viscosity supersolution of F♯F^{\sharp} on HH. With C12=max⁡{M1,M2}C_{12}=\max\{M_{1},M_{2}\} one has w1≤C12w_{1}\le C_{12} and −C12≤w2-C_{12}\le w_{2} on HH, so The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space §comparison gives w1(x)≤w2(x)w_{1}(x)\le w_{2}(x) for every x∈Vx\in V. For x∈H−1⊆Vx\in H^{-1}\subseteq V, therefore, u1(x)=u0(x)+w1(x)≤u0(x)+w2(x)=u2(x)u_{1}(x)=u_{0}(x)+w_{1}(x)\le u_{0}(x)+w_{2}(x)=u_{2}(x). This proves clause 2.

Step 3 (Uniqueness). By Step 1 there is a renormalised viscosity solution in C\mathcal{C}. If u,u′∈Cu,u'\in\mathcal{C} are renormalised viscosity solutions, each is both a subsolution and a supersolution (Renormalised Viscosity Subsolutions, Supersolutions and Solutions of the Wick-Square Problem, Tested by the Gaussian Penalty plus a Regular Function §solution), so Step 2 applied to (u,u′)(u,u') and to (u′,u)(u',u) gives u≤u′u\le u' and u′≤uu'\le u on H−1H^{-1}; hence u=u′u=u'. This proves clause 3.

Step 4 (The free solution). Let gg be the zero function. Then the hypotheses of the theorem hold with the constants 00 and 00 in place of CgC_{g} and ℓg\ell_{g}, and the set C\mathcal{C} and the renormalised notions do not involve these constants. Steps 0 and 1, carried out with these constants, give a renormalised viscosity solution u∈Cu\in\mathcal{C} with ∣u(x)−u0(x)∣≤0/γ=0|u(x)-u_{0}(x)|\le0/\gamma=0 for every x∈H−1x\in H^{-1}, so u=u0u=u_{0}. Thus u0u_{0} is a renormalised viscosity solution in C\mathcal{C}, and by Step 3 it is the only one. This proves clause 4.

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