Extend bounded functions from = D(A) to H by density and the uniformly continuous extension lemma, keeping bound and Lipschitz constant; this turns g into a cost gbar on V. Existence: the constants +-C_g/gamma are sub/super bounds for the shifted operator, so the Hilbert-triple existence theorem gives a bounded uniformly continuous solution w, Lipschitz by the viscous Hamilton-Jacobi theorem; the bridge lemma makes + w| a renormalised solution. Comparison: extend - , apply the bridge back and the shifted comparison. Uniqueness and the free solution follow.
Each result cited is universally quantified over the data in its own statement.
Conventions. By The Wick-Square Problem on the Sobolev Triple of Order Two: Standing Notation §triple, is a Hilbert triple in the setting of Hilbert Triples: Standing Notation and Background, with , , , and for (Hilbert Triples: Standing Notation and Background §triple). Elementary arithmetic in (the triangle inequality, maxima of two numbers, the limit laws and the order of limits) is used under The Real Numbers: Standing Notation and Background §background. Continuity of real functions on subsets of is equivalent to sequential continuity (Real Hilbert Spaces: Standing Notation and Background §topology). Every function that is Lipschitz with a constant (Lipschitz Map Between Metric Spaces) on a subset of a metric space is uniformly continuous on : given , the number serves as . Every function uniformly continuous on is continuous at every point of relative to (Continuous Map Between Metric Spaces): the of uniform continuity serves at each point.
Step 0 (Extension from the state space). We show: (E) if and satisfies and for , then there is , continuous on , with on , and for all . Indeed, is nonempty (it contains ) and dense in by The Resolvent of the Form Operator of a Hilbert Triple: Minimisation, Contraction, and Density of the Domain §dense-in-h, that is dense in the topological space of the metric space (Real Hilbert Space §topology); is Lipschitz, hence uniformly continuous, on . By Extension of a Uniformly Continuous Real Function from a Dense Subset §existence with and there is , continuous on , with on , and by Extension of a Uniformly Continuous Real Function from a Dense Subset §bounds, for . Let . By The Penalty Function of a Hilbert Triple: Expansion Identities, Closed Sublevel Sets, Density and Local Bounds §dense (with , open in by Hilbert Triples: Standing Notation and Background §open-sets), choose for each points with and . Then ; as and in and is continuous, letting gives .
Apply (E) to with , , and let be the restriction of the resulting extension to . Then and for , and . Hence The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space and Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two apply to , and ; we let be the shifted operator for , and the renormalised notions there, taken for the running cost , are those of the theorem.
Step 1 (Existence). Put , nonnegative since (The Wick-Square Problem on the Torus: Standing Notation §parameters). Let , and let be the zero form of . By The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §noise, is the lattice sum of the zero family, all of whose cube sums are , so it is (Cube Sums of Families on the Integer Lattice §lattice-sum); by bilinearity of (The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §gradient-form); and by Elementary Identities in a Real Inner Product Space §zero. Hence by The Shifted Hamilton-Jacobi-Bellman Equation of the Wick-Square Problem on the Sobolev Triple of Order Two §operator
is a second-order equation operator on relative to (The Shifted Hamilton-Jacobi-Bellman Equation of the Wick-Square Problem on the Sobolev Triple of Order Two §operator) satisfying all the structural hypotheses of Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple by The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space §hypotheses. That theorem gives that is a viscosity solution of on (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §solution), satisfies for (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §bounded), and is uniformly continuous on (Existence of a Bounded, Uniformly Continuous Viscosity Solution on a Hilbert Triple §uniformly-continuous), hence continuous on (Conventions).
Next apply Lipschitz Regularity of Bounded Continuous Viscosity Solutions of a Viscous Hamilton-Jacobi Equation with a Monotone Nonlinearity on a Hilbert Triple, whose standing hypothesis that is not finite-dimensional holds by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §infinite, with , the constants , the cost , (a monotone nonlinearity by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §drift), the given , the sequence (square-summable in by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §noise), (with by The Sobolev Triple of Order Two for the Wick-Square Problem: the Domain Is the Sobolev Space of Order -1, Unit Families Are Square-Summable, the Gradient Form and the Riccati Drift §gradient-form), and . The operator of that theorem is then, term by term, , of which is a bounded continuous viscosity solution. By Lipschitz Regularity of Bounded Continuous Viscosity Solutions of a Viscous Hamilton-Jacobi Equation with a Monotone Nonlinearity on a Hilbert Triple §lipschitz, with ,
By Viscosity Subsolution, Supersolution and Solution of a Second-Order Equation on a Hilbert Triple §solution, is both a viscosity subsolution and a viscosity supersolution of on ; as is bounded and continuous on , Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two §from-shifted shows that is a renormalised viscosity subsolution and supersolution, i.e. a renormalised viscosity solution (Renormalised Viscosity Subsolutions, Supersolutions and Solutions of the Wick-Square Problem, Tested by the Gaussian Penalty plus a Regular Function §solution). Since , one has and for ; in particular is bounded and Lipschitz from to , so . This proves clause 1.
Step 2 (Comparison). Let , a renormalised viscosity subsolution and a renormalised viscosity supersolution. For , choose with and for , and let be the extension of given by (E): continuous on , on , Lipschitz with constant from to , and . By Renormalised Viscosity Solutions versus Viscosity Solutions of the Shifted Equation on the Sobolev Triple of Order Two §to-shifted, is a viscosity subsolution and a viscosity supersolution of on . With one has and on , so The Riccati Shift: the Renormalised Operator at the Free Solution plus a Regular Function is the Shifted Operator, Which Satisfies the Hilbert-Triple Comparison Hypotheses, and Its Touching Points Lie in the State Space §comparison gives for every . For , therefore, . This proves clause 2.
Step 3 (Uniqueness). By Step 1 there is a renormalised viscosity solution in . If are renormalised viscosity solutions, each is both a subsolution and a supersolution (Renormalised Viscosity Subsolutions, Supersolutions and Solutions of the Wick-Square Problem, Tested by the Gaussian Penalty plus a Regular Function §solution), so Step 2 applied to and to gives and on ; hence . This proves clause 3.
Step 4 (The free solution). Let be the zero function. Then the hypotheses of the theorem hold with the constants and in place of and , and the set and the renormalised notions do not involve these constants. Steps 0 and 1, carried out with these constants, give a renormalised viscosity solution with for every , so . Thus is a renormalised viscosity solution in , and by Step 3 it is the only one. This proves clause 4.
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