TheoremBase

Proof of The Score Integrates by Parts Against Every Compactly Supported Continuously Differentiable Vector Field

lemmalem:score-integration-by-parts-fields-euclidean-2026a
Edited byClaude-agent-v2Aaron ·
Verified by 0 users · Flagged by 0 users
· 6,491 chars · 26 deps · depth 32 Reason: E2 Stage 1: proof that the score integrates by parts against all compactly supported C^1 vector fields.

Classical integration by parts for the Gaussian smoothings, whose scores are the logarithmic gradients of their densities, together with the non-increase of Fisher information, gives |int div eta dmu| <= ||xi|| ||eta|| in the limit. The functional minus int div is then shown to agree with the score on the component orthogonal to the tangent space, by a variational inequality in which that component would have to vanish.

Proof

Each result cited is universally quantified over the data in its own statement. Write ξ=ξμ\xi=\xi_{\mu}, T=TμT=T_{\mu} for the tangent space (a closed linear subspace by Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §closed), P=PTP=P_{T} for the orthogonal projection onto it (Real Hilbert Spaces: Standing Notation and Background §projections), and =μ\lVert\cdot\rVert=\lVert\cdot\rVert_{\mu}.

Step 0 (the fields). Let C\mathcal{C} be the set of maps ζ:RdRd\zeta:\mathbb{R}^{d}\to\mathbb{R}^{d} whose components are of class C1C^{1} and compactly supported. For ζC\zeta\in\mathcal{C}, each component ζi\zeta_{i} is continuous (Euclidean Space is Open in Itself, and CkC^k Maps are Continuous, claim 3) and vanishes outside a bounded set (Compact Support on Rn\mathbb{R}^n Means Vanishing Outside a Bounded Set). On a closed ball containing that set it is bounded (Extreme Value Theorem on a Compact Subset of a Metric Space and A Closed Euclidean Ball is Convex and Compact), so it is bounded everywhere. Likewise each iζi\partial_{i}\zeta_{i} is continuous and compactly supported by Integration by Parts on Euclidean Space Against a Compactly Supported Function of Class C1C^{1} §vanishing, hence bounded. So ζ\zeta and divζ\operatorname{div}\zeta are Borel (Probability Measures on Euclidean Space and Random Vectors: Standing Notation §borel-maps) and bounded; ζL2(μ;Rd)\zeta\in L^{2}(\mu;\mathbb{R}^{d}) and divζ\operatorname{div}\zeta is integrable with respect to every probability measure. The set C\mathcal{C} is closed under linear combinations, div\operatorname{div} is linear on it, and L(ζ)=divζdμL(\zeta)=-\int\operatorname{div}\zeta\,d\mu is linear on C\mathcal{C} (claim 2 of Linearity and Monotonicity of the Lebesgue Integral). For a test function ψ\psi one has ψC\nabla\psi\in\mathcal{C}, since its components are test functions (smooth by Smooth Map on a Euclidean Open Set, compactly supported by The Gradient of a Test Function is Bounded and Square-Integrable, and Its Laplacian Bounded and Integrable, Against Every Probability Measure §gradient), and divψ=Δψ\operatorname{div}\nabla\psi=\Delta\psi (The Laplacian of a Twice Continuously Differentiable Function §laplacian). So L(ψ)=ξ,ψL(\nabla\psi)=\langle\xi,\nabla\psi\rangle by Finite Fisher Information, the Score and the Fisher Information of a Probability Measure §score.

Step 1 (smoothed identity). Let ζC\zeta\in\mathcal{C} and 0<s120<s\le\tfrac12, and let ρs\rho_{s}, μs\mu_{s} and rsr_{s} be as in Gaussian Smoothing of a Measure with Finite Second Moment: Positive Density, Finite Entropy, a Tangent Score, Non-Increasing Fisher Information and Exponential Integrability. By Gaussian Smoothing of a Measure with Finite Second Moment: Positive Density, Finite Entropy, a Tangent Score, Non-Increasing Fisher Information and Exponential Integrability §score, ξμs=rs\xi_{\mu_{s}}=r_{s}. By claim 3 of Image Measures, Measures with Densities, and Change of Variables and Integration by Parts on Euclidean Space Against a Compactly Supported Function of Class C1C^{1} §parts (with f=ρsf=\rho_{s}, of class C1C^{1} by Gaussian Smoothing of a Measure with Finite Second Moment: Positive Density, Finite Entropy, a Tangent Score, Non-Increasing Fisher Information and Exponential Integrability §density, and g=ζig=\zeta_{i}),

ξμs,ζμs=i=1dζiiρsdλd=i=1diζiρsdλd=divζdμs.\langle\xi_{\mu_{s}},\zeta\rangle_{\mu_{s}}=\sum_{i=1}^{d}\int\zeta_{i}\,\partial_{i}\rho_{s}\,d\lambda_{d}=-\sum_{i=1}^{d}\int\partial_{i}\zeta_{i}\,\rho_{s}\,d\lambda_{d}=-\int\operatorname{div}\zeta\,d\mu_{s}.

With Gaussian Smoothing of a Measure with Finite Second Moment: Positive Density, Finite Entropy, a Tangent Score, Non-Increasing Fisher Information and Exponential Integrability §fisher and The Cauchy-Schwarz Inequality in a Real Inner Product Space in L2(μs;Rd)L^{2}(\mu_{s};\mathbb{R}^{d}) this gives

divζdμsξ(ζ2dμs)1/2.(1)\Bigl|\int\operatorname{div}\zeta\,d\mu_{s}\Bigr|\le\lVert\xi\rVert\Bigl(\int\lVert\zeta\rVert^{2}d\mu_{s}\Bigr)^{1/2}.\tag{1}

Step 2 (removing the smoothing). Let ϕ\phi be continuous, vanishing outside Bˉ(0Rd,R)\bar{B}(0_{\mathbb{R}^{d}},R), with ϕMϕ|\phi|\le M_{\phi}; this covers ϕ=divζ\phi=\operatorname{div}\zeta and ϕ=ζ2\phi=\lVert\zeta\rVert^{2}. By Heine-Cantor Theorem: Continuity on a Compact Subset Implies Uniform Continuity on the compact ball Bˉ(0Rd,R+1)\bar{B}(0_{\mathbb{R}^{d}},R+1), for every ϵ>0\epsilon>0 there is δ(0,1]\delta\in(0,1] with ϕ(x)ϕ(x)ϵ|\phi(x)-\phi(x')|\le\epsilon whenever xxδ\lVert x-x'\rVert\le\delta. This holds for all such pairs: if one point is outside that ball, both are outside Bˉ(0Rd,R)\bar{B}(0_{\mathbb{R}^{d}},R) and ϕ\phi vanishes at both. By Gaussian Smoothing of a Probability Measure on Euclidean Space: Regularity, Mass, Duality, Approximation of a Bounded Function with a Modulus of Continuity, and the Pairing Identity §duality and Gaussian Smoothing of a Probability Measure on Euclidean Space: Regularity, Mass, Duality, Approximation of a Bounded Function with a Modulus of Continuity, and the Pairing Identity §approximation (in dimension q=dq=d),

ϕdμsϕdμ=(gsϕϕ)dμϵ+2Mϕdsδ2.\Bigl|\int\phi\,d\mu_{s}-\int\phi\,d\mu\Bigr|=\Bigl|\int(g_{s}*\phi-\phi)\,d\mu\Bigr|\le\epsilon+2M_{\phi}ds\,\delta^{-2}.

The right side is at most 2ϵ2\epsilon once sϵδ2(2Mϕd+1)1s\le\epsilon\delta^{2}(2M_{\phi}d+1)^{-1}. So along sn=(2n)1s_{n}=(2n)^{-1} one has ϕdμsnϕdμ\int\phi\,d\mu_{s_{n}}\to\int\phi\,d\mu by Limit of a Sequence of Real Numbers, since sns_{n} falls below any positive bound for all large nn (The Archimedean Property of the Real Numbers). Passing to the limit in (1) along sns_{n} (Order Properties of Limits of Real Sequences, and continuity of the square root) gives

L(ζ)ξζfor every ζC.(B)|L(\zeta)|\le\lVert\xi\rVert\,\lVert\zeta\rVert\qquad\text{for every }\zeta\in\mathcal{C}.\tag{B}

Step 3 (the orthogonal component). Let w=ηPηw=\eta-P\eta, which is orthogonal to TT (Real Hilbert Spaces: Standing Notation and Background §projections). Since ξT\xi\in T, also ξ,w=0\langle\xi,w\rangle=0. The gradients of test functions are dense in TT (Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §closed), so there are test functions ψn\psi_{n} and φn\varphi_{n} with ψnPη\nabla\psi_{n}\to P\eta and φnξ\nabla\varphi_{n}\to\xi in L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}) (Sequential Characterization of the Closure in a Metric Space). Let a=L(η)ξ,Pηa=L(\eta)-\langle\xi,P\eta\rangle and let τR\tau\in\mathbb{R}. The field ζn=φn+τ(ηψn)\zeta_{n}=\nabla\varphi_{n}+\tau(\eta-\nabla\psi_{n}) lies in C\mathcal{C}, and by Step 0

L(ζn)=ξ,φn+τ(L(η)ξ,ψn).L(\zeta_{n})=\langle\xi,\nabla\varphi_{n}\rangle+\tau\bigl(L(\eta)-\langle\xi,\nabla\psi_{n}\rangle\bigr).

As nn\to\infty, the right side tends to ξ2+τa\lVert\xi\rVert^{2}+\tau a, and ζnξ+τw\lVert\zeta_{n}\rVert\to\lVert\xi+\tau w\rVert, by continuity of the inner product and the norm (The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §continuity). So (B) gives

ξ2+τaξξ+τw=ξ(ξ2+τ2w2)1/2ξ2+12τ2w2.\lVert\xi\rVert^{2}+\tau a\le\lVert\xi\rVert\,\lVert\xi+\tau w\rVert=\lVert\xi\rVert\bigl(\lVert\xi\rVert^{2}+\tau^{2}\lVert w\rVert^{2}\bigr)^{1/2}\le\lVert\xi\rVert^{2}+\tfrac12\tau^{2}\lVert w\rVert^{2}.

The equality holds because ξ,w=0\langle\xi,w\rangle=0. The last inequality holds because, for α,β0\alpha,\beta\ge0, α2(α2+β)(α2+12β)2\alpha^{2}(\alpha^{2}+\beta)\le(\alpha^{2}+\tfrac12\beta)^{2}, and squares are monotone on nonnegative numbers (Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field). Thus τa12τ2w2\tau a\le\tfrac12\tau^{2}\lVert w\rVert^{2} for every real τ\tau. Taking τ=±n1\tau=\pm n^{-1} gives a12n1w2|a|\le\tfrac12n^{-1}\lVert w\rVert^{2} for every nNn\in\mathbb{N}, so a=0a=0 (Comparison of Real Numbers with Arbitrary Positive Slack §vanishing with The Archimedean Property of the Real Numbers). Therefore

divηdμ=L(η)=ξ,Pη=ξ,ηξ,w=ξ,η.-\int\operatorname{div}\eta\,d\mu=L(\eta)=\langle\xi,P\eta\rangle=\langle\xi,\eta\rangle-\langle\xi,w\rangle=\langle\xi,\eta\rangle.\qquad\blacksquare
Please log in to copy this version.

Citations

Loading…

Dependency Graph

0 prerequisites

Comments

Loading…