TheoremBase

Proof

By Extreme Value Theorem on a Compact Interval, ff attains a maximum and minimum on [a,b][a,b]. If both extrema occur at endpoints and f(a)=f(b)f(a)=f(b), then ff is constant and any c∈(a,b)c\in(a,b) satisfies f′(c)=0f'(c)=0. Otherwise, at least one extremum occurs at some c∈(a,b)c\in(a,b), and then Fermat Stationary Point Criterion gives f′(c)=0f'(c)=0.

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