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Proof of Second-Order Taylor Expansion with Peano Remainder

theoremthm:second-order-taylor-peano-2026a
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· 6,784 chars · 14 deps · depth 10 Reason: First published version. Restricts to an affine path, forms the auxiliary function whose value at 1 is the Taylor remainder, applies the mean value theorem twice, and estimates using continuity of the second partial derivatives and symmetry of the Hessian.

Proof

Claim numbers refer to Elementary Order Arithmetic in an Ordered Field and to Properties of the Absolute Value in an Ordered Field as indicated. Recall from Step 0 of the proof of Equality of Mixed Second Partial Derivatives and Symmetry of the Hessian the fact, used again here, that squares are strictly monotone on nonnegative reals; we re-derive it: if 0≤α0\le\alpha, 0≤β0\le\beta and α<β\alpha<\beta, then 0<β0<\beta by claim 2, so βα<ββ\beta\alpha<\beta\beta by claim 10, while αα≤βα\alpha\alpha\le\beta\alpha, whence α2<β2\alpha^{2}<\beta^{2} by claim 2; and conversely α2<β2\alpha^{2}<\beta^{2} forces α<β\alpha<\beta, since β≤α\beta\le\alpha would give β2≤α2\beta^{2}\le\alpha^{2}.

Throughout, ∥z∥\lVert z\rVert denotes the Euclidean distance from z∈Rnz\in\mathbb{R}^{n} to the origin, so ∥z∥\lVert z\rVert is the nonnegative real with ∥z∥2=∑i=1nzi2\lVert z\rVert^{2}=\sum_{i=1}^{n}z_{i}^{2}; in particular zi2≤∥z∥2z_{i}^{2}\le\lVert z\rVert^{2} for each ii, hence ∣zi∣≤∥z∥|z_{i}|\le\lVert z\rVert by the monotonicity just recorded and claim 4 of Properties of the Absolute Value in an Ordered Field.

Step 1 (a path interval). Since x∈Ux\in U and UU is open, there is rr with 0<r0<r such that every point at Euclidean distance less than rr from xx lies in UU. Suppose h∈Rnh\in\mathbb{R}^{n} satisfies ∥h∥<r⋅2−1\lVert h\rVert<r\cdot2^{-1}. For τ∈R\tau\in\mathbb{R} with ∣τ∣<2|\tau|<2, the point x+τhx+\tau h is at distance ∣τ∣ ∥h∥|\tau|\,\lVert h\rVert from xx, since the squared distance is ∑i(τhi)2=τ2∥h∥2=(∣τ∣∥h∥)2\sum_i(\tau h_i)^2=\tau^{2}\lVert h\rVert^{2}=(|\tau|\lVert h\rVert)^{2} and both quantities are nonnegative. By claim 10 this is less than 2⋅(r⋅2−1)=r2\cdot(r\cdot2^{-1})=r when ∥h∥≠0\lVert h\rVert\ne0, and equals 0<r0<r otherwise. Hence x+τh∈Ux+\tau h\in U for every τ\tau in the open interval (−2,2)(-2,2), which contains 00 and 11.

Step 2 (the path functions). Write ∂if\partial_{i}f for ∂f/∂xi\partial f/\partial x_{i} and ∂ij2f\partial^{2}_{ij}f for ∂2f/∂xi ∂xj\partial^{2}f/\partial x_{i}\,\partial x_{j}, in the notation of C^2 Real-Valued Map on an Open Subset of Euclidean Space. Since ff is of class C2C^{2} it is of class C1C^{1}, and each ∂if\partial_{i}f is of class C1C^{1} on UU. So by A Real-Valued C^1 Function is Differentiable at Every Point both ff and each ∂if\partial_{i}f are differentiable at every point of UU.

Define on (−2,2)(-2,2) the functions F(τ)=f(x+τh)F(\tau)=f(x+\tau h) and Φi(τ)=∂if(x+τh)\Phi_{i}(\tau)=\partial_{i}f(x+\tau h). By Chain Rule Along an Affine Path, applied to ff and to each ∂if\partial_{i}f, these are differentiable at every τ∈(−2,2)\tau\in(-2,2), with

F′(τ)=∑i=1n∂if(x+τh) hi=∑i=1nΦi(τ)hi,Φi′(τ)=∑j=1n∂ji2f(x+τh) hj.F'(\tau)=\sum_{i=1}^{n}\partial_{i}f(x+\tau h)\,h_{i}=\sum_{i=1}^{n}\Phi_{i}(\tau)h_{i},\qquad \Phi_{i}'(\tau)=\sum_{j=1}^{n}\partial^{2}_{ji}f(x+\tau h)\,h_{j}.

Step 3 (an auxiliary function). Put Q=∑i=1n∑j=1n∂ij2f(x) hihjQ=\sum_{i=1}^{n}\sum_{j=1}^{n}\partial^{2}_{ij}f(x)\,h_{i}h_{j} and define G:(−2,2)→RG:(-2,2)\to\mathbb{R} by

G(τ)=F(τ)−F(0)−τ F′(0)−τ2 Q⋅2−1.G(\tau)=F(\tau)-F(0)-\tau\,F'(0)-\tau^{2}\,Q\cdot2^{-1}.

The map τ↦F(0)+τF′(0)+τ2Q⋅2−1\tau\mapsto F(0)+\tau F'(0)+\tau^{2}Q\cdot2^{-1} is differentiable at each τ0\tau_{0} with derivative F′(0)+τ0QF'(0)+\tau_{0}Q: its difference quotient at τ0\tau_{0} for an increment k≠0k\ne0 equals F′(0)+(2τ0+k)Q⋅2−1F'(0)+(2\tau_{0}+k)Q\cdot2^{-1}, which differs from F′(0)+τ0QF'(0)+\tau_{0}Q by kQ⋅2−1kQ\cdot2^{-1}, and given ε\varepsilon with 0<ε0<\varepsilon one may take δ\delta to be ε\varepsilon if Q=0Q=0 and otherwise the value ε(∣Q∣⋅2−1)−1\varepsilon\bigl(|Q|\cdot2^{-1}\bigr)^{-1}, positive by claims 5 and 7, so that ∣kQ⋅2−1∣=∣k∣ ∣Q∣⋅2−1<ε|kQ\cdot2^{-1}|=|k|\,|Q|\cdot2^{-1}<\varepsilon by claims 4 of Properties of the Absolute Value in an Ordered Field and 10. By Derivative of a Sum and of a Difference, GG is therefore differentiable at every τ0∈(−2,2)\tau_{0}\in(-2,2) with

G′(τ0)=F′(τ0)−F′(0)−τ0 Q.G'(\tau_{0})=F'(\tau_{0})-F'(0)-\tau_{0}\,Q .

Also G(0)=0G(0)=0, and G(1)G(1) is exactly the quantity whose absolute value is to be estimated, since F(1)=f(x+h)F(1)=f(x+h), F(0)=f(x)F(0)=f(x) and F′(0)=∑i∂if(x)hiF'(0)=\sum_{i}\partial_{i}f(x)h_{i}.

Step 4 (two applications of the mean value theorem). By Mean Value Theorem on an Open Interval applied to GG on (−2,2)(-2,2) with the points 0<10<1, there is θ∈(0,1)\theta\in(0,1) with G(1)−G(0)=G′(θ)G(1)-G(0)=G'(\theta), so G(1)=G′(θ)G(1)=G'(\theta).

For each ii, apply Mean Value Theorem on an Open Interval to Φi\Phi_{i} on (−2,2)(-2,2) with the points 0<θ0<\theta: there is θi∈(0,θ)\theta_{i}\in(0,\theta) with Φi(θ)−Φi(0)=Φi′(θi) θ\Phi_{i}(\theta)-\Phi_{i}(0)=\Phi_{i}'(\theta_{i})\,\theta. Hence, using Step 2 and F′(θ)−F′(0)=∑i(Φi(θ)−Φi(0))hiF'(\theta)-F'(0)=\sum_{i}\bigl(\Phi_{i}(\theta)-\Phi_{i}(0)\bigr)h_{i},

G′(θ)=∑i=1nΦi′(θi) θ hi−θ Q=θ∑i=1n∑j=1n(∂ji2f(x+θih)−∂ij2f(x))hjhi.G'(\theta)=\sum_{i=1}^{n}\Phi_{i}'(\theta_{i})\,\theta\,h_{i}-\theta\,Q=\theta\sum_{i=1}^{n}\sum_{j=1}^{n}\Bigl(\partial^{2}_{ji}f(x+\theta_{i}h)-\partial^{2}_{ij}f(x)\Bigr)h_{j}h_{i}.

By Equality of Mixed Second Partial Derivatives and Symmetry of the Hessian we may replace ∂ij2f(x)\partial^{2}_{ij}f(x) by ∂ji2f(x)\partial^{2}_{ji}f(x), so with Rji(τ)=∂ji2f(x+τh)−∂ji2f(x)R_{ji}(\tau)=\partial^{2}_{ji}f(x+\tau h)-\partial^{2}_{ji}f(x),

G(1)=θ∑i=1n∑j=1nRji(θi) hjhi.G(1)=\theta\sum_{i=1}^{n}\sum_{j=1}^{n}R_{ji}(\theta_{i})\,h_{j}h_{i}.

Step 5 (the estimate). Let ε∈R\varepsilon\in\mathbb{R} with 0<ε0<\varepsilon. Since n≥1n\ge1, the element n⋅nn\cdot n is positive (a sum of copies of 11, positive by claim 6 and claim 3), so ε′=ε (n⋅n)−1\varepsilon'=\varepsilon\,(n\cdot n)^{-1} is positive by claims 7 and 5. Each ∂ji2f\partial^{2}_{ji}f is continuous at xx, by condition 2 of C^2 Real-Valued Map on an Open Subset of Euclidean Space; taking the least of the finitely many radii by repeated use of claim 9, there is θ0\theta_{0} with 0<θ00<\theta_{0} such that every z∈Uz\in U at distance less than θ0\theta_{0} from xx satisfies ∣∂ji2f(z)−∂ji2f(x)∣<ε′|\partial^{2}_{ji}f(z)-\partial^{2}_{ji}f(x)|<\varepsilon' for all i,ji,j.

Let δ\delta be the least, by claim 9, of r⋅2−1r\cdot2^{-1} and θ0\theta_{0}, so 0<δ0<\delta. Suppose ∥h∥<δ\lVert h\rVert<\delta. Then x+h∈Ux+h\in U by Step 1 with τ=1\tau=1, and Steps 1 to 4 apply. For each ii we have 0<θi<θ<10<\theta_{i}<\theta<1, so the distance from x+θihx+\theta_{i}h to xx is θi∥h∥≤∥h∥<θ0\theta_{i}\lVert h\rVert\le\lVert h\rVert<\theta_{0} by claim 10 and claim 2; hence ∣Rji(θi)∣<ε′|R_{ji}(\theta_{i})|<\varepsilon' for all i,ji,j.

Also ∣hi∣≤∥h∥|h_{i}|\le\lVert h\rVert and ∣hj∣≤∥h∥|h_{j}|\le\lVert h\rVert, so ∣Rji(θi)hjhi∣=∣Rji(θi)∣ ∣hj∣ ∣hi∣≤ε′∥h∥2|R_{ji}(\theta_{i})h_{j}h_{i}|=|R_{ji}(\theta_{i})|\,|h_{j}|\,|h_{i}|\le\varepsilon'\lVert h\rVert^{2} by claim 4 of Properties of the Absolute Value in an Ordered Field and repeated use of claim 10 together with claim 2. Since 0<θ<10<\theta<1 we have ∣θ∣≤1|\theta|\le1, so by the triangle inequality (claim 5 of Properties of the Absolute Value in an Ordered Field) applied to the n⋅nn\cdot n summands,

∣G(1)∣≤∑i=1n∑j=1n∣Rji(θi)hjhi∣≤(n⋅n) ε′∥h∥2=ε ∥h∥2.|G(1)|\le\sum_{i=1}^{n}\sum_{j=1}^{n}\bigl|R_{ji}(\theta_{i})h_{j}h_{i}\bigr|\le (n\cdot n)\,\varepsilon'\lVert h\rVert^{2}=\varepsilon\,\lVert h\rVert^{2}.

Since G(1)G(1) is the expression in the statement, this is the assertion.

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