TheoremBase

The ray is a defined set symbol given by a predicative formula, so the rays of the given kind are the members of a subset of the power set of the real line cut out by a predicative condition.

Proof

Take for the form I(a,b)I(a,b) of Intervals of the Real Line as Defined Set Symbols, Typed Terms and Values of Maps the ray form of RR: if R(a)R(a) is (a,∞)(a,\infty) or [a,∞)[a,\infty), then I(a,b)I(a,b) is (a,∞)(a,\infty), respectively [a,∞)[a,\infty); if R(a)R(a) is (βˆ’βˆž,a)(-\infty,a) or (βˆ’βˆž,a](-\infty,a], then I(a,b)I(a,b) is (βˆ’βˆž,b)(-\infty,b), respectively (βˆ’βˆž,b](-\infty,b]. In each case R(a)=I(a,a)R(a)=I(a,a) for every a∈Ra\in\mathbb{R}.

The identity idR\mathrm{id}_{\mathbb{R}} is a map Rβ†’R\mathbb{R}\to\mathbb{R} with idR(a)=a\mathrm{id}_{\mathbb{R}}(a)=a for every a∈Ra\in\mathbb{R}, by Basic Properties of Functions: Equality, Composition, Identity, Inverse and Restriction (iii). By Intervals of the Real Line as Defined Set Symbols, Typed Terms and Values of Maps (iii), with D=RD=\mathbb{R} and s=t=idRs=t=\mathrm{id}_{\mathbb{R}}, there is a map F:Rβ†’P(R)F:\mathbb{R}\to\mathcal{P}(\mathbb{R}) with F(a)=I(a,a)=R(a)F(a)=I(a,a)=R(a) for every a∈Ra\in\mathbb{R}. Let R=F[R]\mathcal{R}=F[\mathbb{R}] be the image of R\mathbb{R} under FF; it is a set by Images of Sets under Functions Are Sets, and a Function with a Set Domain Is a Set (i). By The Image and the Preimage of a Class under a Class (i), a set zz lies in R\mathcal{R} if and only if (a,z)∈F(a,z)\in F for some a∈Ra\in\mathbb{R}, that is, z=F(a)=R(a)z=F(a)=R(a) for some a∈Ra\in\mathbb{R}. So R\mathcal{R} has the stated property, and since every F(a)F(a) lies in P(R)\mathcal{P}(\mathbb{R}), RβŠ†P(R)\mathcal{R}\subseteq\mathcal{P}(\mathbb{R}). Any set with the stated property has the same elements as R\mathcal{R} and so equals R\mathcal{R}. Taking for RR each of the four forms in turn gives the last sentence of (i).

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