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Proof of A Viscous Hamilton-Jacobi Operator with a Monotone Nonlinearity Satisfies the Second-Order Comparison Hypotheses

propositionprop:viscous-monotone-hamilton-jacobi-hilbert-triple-2026a
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· 23,508 chars · 29 deps · depth 28 Reason: Proof that the viscous monotone Hamilton-Jacobi operator satisfies the four hypotheses of the second-order comparison theorem; adapted from the published proof of the first-order proposition, as the attached citation records.

Adapted from the proof of the first-order proposition: the trace term is monotone for the order on forms, so it preserves ellipticity; in the doubled estimate it contributes a nonnegative difference plus the cost of the two identity shifts, and in the tail and shift estimates it contributes multiples of the trace of the tail form and of the shifted form.

Proof

Each result cited is universally quantified over the data in its own statement. Throughout, x,yD(A)x,y\in D(A), and we write a=Axa=Ax, b=Ayb=Ay and Φ(z)=B(z)+L(z)\Phi(z)=B(z)+L(z) for zVz\in V; norms and pairings without a subscript are those of HH. By The Penalty Function h=12V2h=\tfrac12|\cdot|_V^2 of a Hilbert Triple: Expansion Identities, Closed Sublevel Sets, Density and Local Bounds §nonneg we have 0h(z)0\le h(z) for zVz\in V, and 2h(z)=zV22h(z)=|z|_{V}^{2} by Hilbert Triples: Standing Notation and Background §penalty. By Hilbert Triples: Standing Notation and Background §triple we have zHzV|z|_{H}\le|z|_{V} for zVz\in V. By Elementary Properties of a Hilbert Triple: the Embedding, the Riesz Map and the Form Operator §symmetric, Az,ζH=z,ζV\langle Az,\zeta\rangle_{H}=\langle z,\zeta\rangle_{V} for zD(A)z\in D(A) and ζV\zeta\in V. For YSym(H)Y\in\mathrm{Sym}(H) we write YVY|_{V} for its restriction to VV. The standing hypotheses 0ν0\le\nu, 0θ0\le\theta and θ1\theta\le1 are used throughout, as is 0σ(f)0\le\sigma(f), which holds by Square-Summable Sequences in the Form Space of a Hilbert Triple and the Trace of a Form along Them §square-summable; the trace Trf\mathrm{Tr}_{f} is used only through Elementary Properties of the Trace of a Form along a Square-Summable Sequence.

Since LL is Lipschitz with constant \ell, L(z)L(ζ)zζ|L(z)-L(\zeta)|\le\ell|z-\zeta| for z,ζHz,\zeta\in H, and taking ζ=0H\zeta=0_{H} and using The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §triangle gives

L(z)cL+zfor every zH.|L(z)|\le c_{L}+\ell|z|\qquad\text{for every }z\in H .

We use the following three elementary facts. First, Elementary Identities in a Real Inner Product Space §expansion gives c+u2=c2+2c,u+u2|c+u|^{2}=|c|^{2}+2\langle c,u\rangle+|u|^{2} for c,uHc,u\in H. Secondly, for real c>0c>0 and s,ts,t with 0s0\le s and 0t0\le t, expanding 01c(cst)20\le\tfrac{1}{c}(c\,s-t)^{2} gives 2stcs2+t2c2st\le c\,s^{2}+\tfrac{t^{2}}{c}; we use it as st14s2+t2st\le\tfrac{1}{4}s^{2}+t^{2} (the case c=12c=\tfrac{1}{2}) and in the displayed forms below. Thirdly, (s+t)22s2+2t2(s+t)^{2}\le2s^{2}+2t^{2} for real s,ts,t, by Products and Sums of Weighted Square-Summable Sequences of Real Numbers §pointwise.

Claim 1. The values of FF are real numbers and its domain is D(A)×R×H×Sym(V)D(A)\times\mathbb{R}\times H\times\mathrm{Sym}(V), which with W=D(A)W=D(A) is what Second-Order Equation Operator on an Open Subset of a Hilbert Triple and Its δ\delta-Shifts §operator requires of a second-order equation operator on HH. For degenerate ellipticity, let xD(A)x\in D(A), rRr\in\mathbb{R}, pHp\in H and X,YSym(V)X,Y\in\mathrm{Sym}(V) with XYX\preceq Y. Every term of the defining expression other than ν2TrfX-\tfrac{\nu}{2}\mathrm{Tr}_{f}X is independent of the fourth argument, and TrfXTrfY\mathrm{Tr}_{f}X\le\mathrm{Tr}_{f}Y by Elementary Properties of the Trace of a Form along a Square-Summable Sequence §monotone, so

F(x,r,p,Y)F(x,r,p,X)=ν2(TrfYTrfX)0,F(x,r,p,Y)-F(x,r,p,X)=-\tfrac{\nu}{2}\bigl(\mathrm{Tr}_{f}Y-\mathrm{Tr}_{f}X\bigr)\le0,

because ν2\tfrac{\nu}{2} and TrfYTrfX\mathrm{Tr}_{f}Y-\mathrm{Tr}_{f}X are nonnegative, by claim 5 of Elementary Arithmetic in an Ordered Field and claim 4 of Elementary Order Arithmetic in an Ordered Field. Thus F(x,r,p,Y)F(x,r,p,X)F(x,r,p,Y)\le F(x,r,p,X), which is Degenerate Elliptic Second-Order Equation Operator on a Hilbert Triple §elliptic.

Claim 2. Let RR be positive, xD(A)x\in D(A), pHp\in H, XSym(V)X\in\mathrm{Sym}(V) and r,sRr,s\in\mathbb{R} with RsrR-R\le s\le r\le R. Every term of FF other than λ0r\lambda_{0}r is independent of the second argument, so

F(x,r,p,X)F(x,s,p,X)=λ0rλ0s=λ0(rs),F(x,r,p,X)-F(x,s,p,X)=\lambda_{0}r-\lambda_{0}s=\lambda_{0}(r-s),

and in particular λ0(rs)F(x,r,p,X)F(x,s,p,X)\lambda_{0}(r-s)\le F(x,r,p,X)-F(x,s,p,X). As λ0\lambda_{0} is positive, this is the requirement of Locally Strictly Proper Second-Order Equation Operator on a Hilbert Triple §constant; since RR was an arbitrary positive real, FF is locally strictly proper by Locally Strictly Proper Second-Order Equation Operator on a Hilbert Triple §strictly-proper.

The shifts. Let δR\delta\in\mathbb{R} satisfy 0<δ<10<\delta<1. By Second-Order Equation Operator on an Open Subset of a Hilbert Triple and Its δ\delta-Shifts §shifted, the δ\delta-shifts are given by

Fδ(x,r,p,X)=λ0(r+δh(x))ν2Trf(XV+δIV)+θ2p+δa2+a+Φ(x),p+δag(x),F^{-}_{\delta}(x,r,p,X)=\lambda_{0}\bigl(r+\delta h(x)\bigr)-\tfrac{\nu}{2}\,\mathrm{Tr}_{f}\bigl(X|_{V}+\delta I_{V}\bigr)+\tfrac{\theta}{2}|p+\delta a|^{2}+\langle a+\Phi(x),p+\delta a\rangle-g(x), Fδ+(y,s,p,X)=λ0(sδh(y))ν2Trf(XVδIV)+θ2pδb2+b+Φ(y),pδbg(y),F^{+}_{\delta}(y,s,p',X')=\lambda_{0}\bigl(s-\delta h(y)\bigr)-\tfrac{\nu}{2}\,\mathrm{Tr}_{f}\bigl(X'|_{V}-\delta I_{V}\bigr)+\tfrac{\theta}{2}|p'-\delta b|^{2}+\langle b+\Phi(y),p'-\delta b\rangle-g(y),

for x,yD(A)x,y\in D(A), r,sRr,s\in\mathbb{R}, p,pHp,p'\in H and X,XSym(H)X,X'\in\mathrm{Sym}(H). By Elementary Properties of the Trace of a Form along a Square-Summable Sequence §linear and Elementary Properties of the Trace of a Form along a Square-Summable Sequence §identity,

Trf(XV+δIV)=Trf(XV)+δσ(f),Trf(XVδIV)=Trf(XV)δσ(f).\mathrm{Tr}_{f}\bigl(X|_{V}+\delta I_{V}\bigr)=\mathrm{Tr}_{f}(X|_{V})+\delta\,\sigma(f), \qquad \mathrm{Tr}_{f}\bigl(X'|_{V}-\delta I_{V}\bigr)=\mathrm{Tr}_{f}(X'|_{V})-\delta\,\sigma(f).

Claim 3, the two moduli. By The Nondecreasing Envelope of a Truncated Modulus of Continuity §modulus the function ωˉg\bar{\omega}_{g} is a modulus of continuity satisfying 0ωˉg(t)2Cg0\le\bar{\omega}_{g}(t)\le2C_{g} for every nonnegative tt; as 2Cg2C_{g} is nonnegative, its quadratic reparametrisation ωg\omega_{g}^{\ast} at 2Cg2C_{g} is therefore defined, and is a nondecreasing modulus of continuity, by Sums, Nonnegative Multiples, Monotonicity and Quadratic Reparametrisation of Moduli of Continuity §quadratic. By Linear Moduli of Continuity §modulus the function ttt\mapsto\ell t is a modulus of continuity, since 00\le\ell; so ω1\omega_{1} is a modulus of continuity by Sums, Nonnegative Multiples, Monotonicity and Quadratic Reparametrisation of Moduli of Continuity §sum. For a real α>1\alpha>1 the number Kα+νσ(f)K\alpha+\nu\,\sigma(f) is nonnegative, being the sum of a product of positive numbers and a product of two nonnegative numbers, so t(Kα+νσ(f))tt\mapsto(K\alpha+\nu\,\sigma(f))\,t is a modulus of continuity by Linear Moduli of Continuity §modulus.

Claim 3, the inequality. Let RR be positive, let x,yD(A)x,y\in D(A), let rRr\in\mathbb{R} with RrR-R\le r\le R, let α,δR\alpha,\delta\in\mathbb{R} with 1<α1<\alpha and 0<δ<10<\delta<1, and let (X,Y)(X,Y) be a pair of members of Sym(H)\mathrm{Sym}(H) admitted at α\alpha. Put w=α(xy)w=\alpha(x-y) and τ=αxy2+1α\tau=\alpha|x-y|^{2}+\tfrac{1}{\alpha}, and let D=Fδ(x,r,w,X)Fδ+(y,r,w,Y)D=F^{-}_{\delta}(x,r,w,X)-F^{+}_{\delta}(y,r,w,Y). Expanding the two shift formulas of the previous paragraph, using Elementary Identities in a Real Inner Product Space §expansion on the two squared norms, whose terms θ2w2\tfrac{\theta}{2}|w|^{2} cancel, and using the two trace identities recorded there,

D=λ0δ(h(x)+h(y))+ν2(Trf(YV)Trf(XV))νδσ(f)+θδw,a+b+θδ22(a2b2)+ab,w+Φ(x)Φ(y),w+δ(a2+b2)+δ(Φ(x),a+Φ(y),b)(g(x)g(y)).D=\lambda_{0}\delta\bigl(h(x)+h(y)\bigr)+\tfrac{\nu}{2}\bigl(\mathrm{Tr}_{f}(Y|_{V})-\mathrm{Tr}_{f}(X|_{V})\bigr)-\nu\delta\,\sigma(f)+\theta\delta\langle w,a+b\rangle+\tfrac{\theta\delta^{2}}{2}\bigl(|a|^{2}-|b|^{2}\bigr)+\langle a-b,w\rangle+\langle\Phi(x)-\Phi(y),w\rangle+\delta\bigl(|a|^{2}+|b|^{2}\bigr)+\delta\bigl(\langle\Phi(x),a\rangle+\langle\Phi(y),b\rangle\bigr)-\bigl(g(x)-g(y)\bigr).

We bound the ten groups in turn, taking the sixth and the tenth together in (vii).

(i) 0λ0δ(h(x)+h(y))0\le\lambda_{0}\delta(h(x)+h(y)), all three factors being nonnegative.

(i-a) Being admitted at α\alpha, the pair satisfies XYX\preceq Y; hence XVYVX|_{V}\preceq Y|_{V} by claim 10 of Elementary Properties of Bounded Symmetric Bilinear Forms: Norm, Quadratic Form, Order and Continuity and therefore Trf(XV)Trf(YV)\mathrm{Tr}_{f}(X|_{V})\le\mathrm{Tr}_{f}(Y|_{V}) by Elementary Properties of the Trace of a Form along a Square-Summable Sequence §monotone. As ν2\tfrac{\nu}{2} is nonnegative,

0ν2(Trf(YV)Trf(XV)).0\le\tfrac{\nu}{2}\bigl(\mathrm{Tr}_{f}(Y|_{V})-\mathrm{Tr}_{f}(X|_{V})\bigr).

(i-b) Since 0h(x)+h(y)0\le h(x)+h(y) we have δδ(h(x)+h(y)+1)\delta\le\delta(h(x)+h(y)+1), and νσ(f)\nu\,\sigma(f) is nonnegative, so by claim 5 of Elementary Arithmetic in an Ordered Field and claim 4 of Elementary Order Arithmetic in an Ordered Field,

νδσ(f)  νσ(f)δ(h(x)+h(y)+1).-\nu\delta\,\sigma(f)\ \ge\ -\nu\,\sigma(f)\cdot\delta\bigl(h(x)+h(y)+1\bigr).

(ii) Since xyVx-y\in V, the symmetry identity gives ab,w=α(x,xyVy,xyV)=αxyV2\langle a-b,w\rangle=\alpha\bigl(\langle x,x-y\rangle_{V}-\langle y,x-y\rangle_{V}\bigr)=\alpha|x-y|_{V}^{2}, which is nonnegative. This term is not discarded: it is combined with the eighth group in (vii), where it absorbs the oscillation of gg.

(iii) Likewise w,a+b=α(x,xyV+y,xyV)=α(xV2yV2)=2α(h(x)h(y))\langle w,a+b\rangle=\alpha\bigl(\langle x,x-y\rangle_{V}+\langle y,x-y\rangle_{V}\bigr)=\alpha\bigl(|x|_{V}^{2}-|y|_{V}^{2}\bigr)=2\alpha\bigl(h(x)-h(y)\bigr), so, hh being nonnegative and 0θ10\le\theta\le1,

θδw,a+b2θαδh(y)2αδ(h(x)+h(y)+1).\theta\delta\langle w,a+b\rangle\ge-2\theta\alpha\,\delta\,h(y)\ge-2\alpha\cdot\delta\bigl(h(x)+h(y)+1\bigr).

(iv) Since 0<δ<10<\delta<1 and 0θ10\le\theta\le1 we have 0θδ10\le\theta\delta\le1, whence 121θδ2\tfrac{1}{2}\le1-\tfrac{\theta\delta}{2} and 121+θδ2\tfrac{1}{2}\le1+\tfrac{\theta\delta}{2}, so

θδ22(a2b2)+δ(a2+b2)=δ(1+θδ2)a2+δ(1θδ2)b2  δ2(a2+b2).\tfrac{\theta\delta^{2}}{2}\bigl(|a|^{2}-|b|^{2}\bigr)+\delta\bigl(|a|^{2}+|b|^{2}\bigr)=\delta\bigl(1+\tfrac{\theta\delta}{2}\bigr)|a|^{2}+\delta\bigl(1-\tfrac{\theta\delta}{2}\bigr)|b|^{2}\ \ge\ \tfrac{\delta}{2}\bigl(|a|^{2}+|b|^{2}\bigr).

(v) Φ(x)Φ(y),w=αB(x)B(y),xy+αL(x)L(y),xy\langle\Phi(x)-\Phi(y),w\rangle=\alpha\langle B(x)-B(y),x-y\rangle+\alpha\langle L(x)-L(y),x-y\rangle. The first summand is nonnegative by Monotone, AA-Monotone and Locally Bounded Nonlinearities on a Hilbert Triple §monotone and 0<α0<\alpha. For the second, The Cauchy-Schwarz Inequality in a Real Inner Product Space and the Lipschitz bound give L(x)L(y),xyxy2\langle L(x)-L(y),x-y\rangle\ge-\ell|x-y|^{2}, so, 1α\tfrac{1}{\alpha} being positive and \ell nonnegative,

Φ(x)Φ(y),wαxy2τ.\langle\Phi(x)-\Phi(y),w\rangle\ge-\ell\,\alpha|x-y|^{2}\ge-\ell\,\tau .

(vi) δ(Φ(x),a+Φ(y),b)=δ(B(x),a+B(y),b)+δ(L(x),a+L(y),b)\delta(\langle\Phi(x),a\rangle+\langle\Phi(y),b\rangle)=\delta(\langle B(x),a\rangle+\langle B(y),b\rangle)+\delta(\langle L(x),a\rangle+\langle L(y),b\rangle). The first summand is nonnegative by Monotone, AA-Monotone and Locally Bounded Nonlinearities on a Hilbert Triple §a-monotone. For the second, The Cauchy-Schwarz Inequality in a Real Inner Product Space and the second elementary fact give L(x),aL(x)a14a2L(x)2\langle L(x),a\rangle\ge-|L(x)|\,|a|\ge-\tfrac{1}{4}|a|^{2}-|L(x)|^{2}, while the third elementary fact, the Lipschitz bound and xxV|x|\le|x|_{V} give

L(x)2(cL+x)22cL2+22x22cL2+22xV2=2cL2+42h(x),|L(x)|^{2}\le\bigl(c_{L}+\ell|x|\bigr)^{2}\le2c_{L}^{2}+2\ell^{2}|x|^{2}\le2c_{L}^{2}+2\ell^{2}|x|_{V}^{2}=2c_{L}^{2}+4\ell^{2}h(x),

and likewise for yy. Hence

δ(Φ(x),a+Φ(y),b)  δ4(a2+b2)δ(4cL2+42(h(x)+h(y)))  δ4(a2+b2)(4cL2+42)δ(h(x)+h(y)+1),\delta\bigl(\langle\Phi(x),a\rangle+\langle\Phi(y),b\rangle\bigr)\ \ge\ -\tfrac{\delta}{4}\bigl(|a|^{2}+|b|^{2}\bigr)-\delta\Bigl(4c_{L}^{2}+4\ell^{2}\bigl(h(x)+h(y)\bigr)\Bigr)\ \ge\ -\tfrac{\delta}{4}\bigl(|a|^{2}+|b|^{2}\bigr)-\bigl(4c_{L}^{2}+4\ell^{2}\bigr)\,\delta\bigl(h(x)+h(y)+1\bigr),

the last step because 1h(x)+h(y)+11\le h(x)+h(y)+1 and h(x)+h(y)h(x)+h(y)+1h(x)+h(y)\le h(x)+h(y)+1 and the coefficients are nonnegative.

(vii) We bound the fourth and the eighth group together. Write t=xyVt=|x-y|_{V}, so that their sum is αt2(g(x)g(y))\alpha t^{2}-\bigl(g(x)-g(y)\bigr) by (ii). Since x,yD(A)Vx,y\in D(A)\subseteq V, the hypotheses on gg give g(x)g(y)g(x)g(y)ωg(t)g(x)-g(y)\le|g(x)-g(y)|\le\omega_{g}(t), by claim 3 of Properties of the Absolute Value in an Ordered Field, and g(x)g(y)g(x)+g(y)2Cg|g(x)-g(y)|\le|g(x)|+|g(y)|\le2C_{g}, by claims 2 and 5 of that lemma; so g(x)g(y)g(x)-g(y) is at most both ωg(t)\omega_{g}(t) and 2Cg2C_{g} and therefore

g(x)g(y)ωˉg(t)g(x)-g(y)\le\bar{\omega}_{g}(t)

by The Nondecreasing Envelope of a Truncated Modulus of Continuity §majorant. Note that αt2\alpha t^{2} is nonnegative, being a product of the positive α\alpha with a square, and that 0ωg(τ)0\le\omega_{g}^{\ast}(\tau), ωg\omega_{g}^{\ast} being a modulus of continuity.

Suppose first that 2Cgαt22C_{g}\le\alpha t^{2}. Since ωˉg(t)2Cg\bar{\omega}_{g}(t)\le2C_{g} by The Nondecreasing Envelope of a Truncated Modulus of Continuity §modulus, transitivity gives g(x)g(y)αt2g(x)-g(y)\le\alpha t^{2}, so αt2(g(x)g(y))\alpha t^{2}-(g(x)-g(y)) is nonnegative and hence at least ωg(τ)-\omega_{g}^{\ast}(\tau).

Suppose instead that αt2<2Cg\alpha t^{2}<2C_{g}. Multiplying by the positive 1α\tfrac{1}{\alpha} gives t2<2Cg1αt^{2}<2C_{g}\tfrac{1}{\alpha}, while 1ατ\tfrac{1}{\alpha}\le\tau, the difference being the nonnegative αxy2\alpha|x-y|^{2}, and 02Cg0\le2C_{g} give 2Cg1α2Cgτ2C_{g}\tfrac{1}{\alpha}\le2C_{g}\tau by claim 5 of Elementary Arithmetic in an Ordered Field. Hence t22Cgτt^{2}\le2C_{g}\tau, and so ωˉg(t)ωg(τ)\bar{\omega}_{g}(t)\le\omega_{g}^{\ast}(\tau) by Sums, Nonnegative Multiples, Monotonicity and Quadratic Reparametrisation of Moduli of Continuity §quadratic, the reparametrisation being taken at c=2Cgc=2C_{g}. Discarding the nonnegative αt2\alpha t^{2},

αt2(g(x)g(y))  ωˉg(t)  ωg(τ).\alpha t^{2}-\bigl(g(x)-g(y)\bigr)\ \ge\ -\bar{\omega}_{g}(t)\ \ge\ -\omega_{g}^{\ast}(\tau).

In either case

ab,w(g(x)g(y))  ωg(τ).\langle a-b,w\rangle-\bigl(g(x)-g(y)\bigr)\ \ge\ -\omega_{g}^{\ast}(\tau).

(viii) The bounds (i), (i-a), (i-b), (iii), (iv), (v), (vi) and (vii) account for all ten groups of DD, the last of them for the sixth and the tenth together. Adding them, the terms δ2(a2+b2)\tfrac{\delta}{2}(|a|^{2}+|b|^{2}) of (iv) and δ4(a2+b2)-\tfrac{\delta}{4}(|a|^{2}+|b|^{2}) of (vi) combine to the nonnegative δ4(a2+b2)\tfrac{\delta}{4}(|a|^{2}+|b|^{2}), and we obtain

D  ωg(τ)τ(2α+4cL2+42+νσ(f))δ(h(x)+h(y)+1).D\ \ge\ -\omega_{g}^{\ast}(\tau)-\ell\,\tau-\bigl(2\alpha+4c_{L}^{2}+4\ell^{2}+\nu\,\sigma(f)\bigr)\,\delta\bigl(h(x)+h(y)+1\bigr).

Since 1<α1<\alpha and 4cL2+424c_{L}^{2}+4\ell^{2} is nonnegative, 2α+4cL2+422α+(4cL2+42)α=Kα2\alpha+4c_{L}^{2}+4\ell^{2}\le2\alpha+(4c_{L}^{2}+4\ell^{2})\alpha=K\alpha, so the coefficient above is at most Kα+νσ(f)K\alpha+\nu\,\sigma(f) and the right-hand side is at least ω1(τ)ω2(δ(h(x)+h(y)+1),α)-\omega_{1}(\tau)-\omega_{2}(\delta(h(x)+h(y)+1),\alpha). This is the inequality required by The Second-Order Structure Condition for an Equation Operator on a Hilbert Triple §pair, whose displayed hypothesis is imposed only for pairs admitted at α\alpha, as assumed here; so (ω1,ω2)(\omega_{1},\omega_{2}) is a second-order structure pair for FF at RR, and as RR was an arbitrary positive real, FF satisfies the second-order structure condition by The Second-Order Structure Condition for an Equation Operator on a Hilbert Triple §structure.

Claim 4. Let (ek)kN(e_{k})_{k\in\mathbb{N}} be an orthonormal basis of HH with ekVe_{k}\in V for every kNk\in\mathbb{N}, and let (Nm)mN(N_{m})_{m\in\mathbb{N}} be its sequence of tail forms, as in The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §tail-forms. Let β,R,ρR\beta,R,\rho\in\mathbb{R} be positive and let δR\delta\in\mathbb{R} satisfy 0<δ<10<\delta<1.

By Elementary Properties of the Trace of a Form along a Square-Summable Sequence §tail the sequence (Trf(NmV))mN(\mathrm{Tr}_{f}(N_{m}|_{V}))_{m\in\mathbb{N}} converges to 00, so by claim 3 of Arithmetic of Limits of Real Sequences the sequence with mm-th term νβ2Trf(NmV)\tfrac{\nu\beta}{2}\mathrm{Tr}_{f}(N_{m}|_{V}) converges to 00 as well; since its terms are nonnegative, νβ2\tfrac{\nu\beta}{2} and Trf(NmV)\mathrm{Tr}_{f}(N_{m}|_{V}) being so, there is m0Nm_{0}\in\mathbb{N} with

νβ2Trf(NmV)ρfor every mN with m0m.\tfrac{\nu\beta}{2}\,\mathrm{Tr}_{f}\bigl(N_{m}|_{V}\bigr)\le\rho\qquad\text{for every }m\in\mathbb{N}\text{ with }m_{0}\le m .

Let mNm\in\mathbb{N} satisfy m0mm_{0}\le m, and let xD(A)x\in D(A), rRr\in\mathbb{R}, pHp\in H and XSym(H)X\in\mathrm{Sym}(H). By claim 10 of Elementary Properties of Bounded Symmetric Bilinear Forms: Norm, Quadratic Form, Order and Continuity we have (X+βNm)V=XV+βNmV(X+\beta N_{m})|_{V}=X|_{V}+\beta\,N_{m}|_{V} and (XβNm)V=XVβNmV(X-\beta N_{m})|_{V}=X|_{V}-\beta\,N_{m}|_{V}, so Elementary Properties of the Trace of a Form along a Square-Summable Sequence §linear gives

\mathrm{Tr}_{f}\bigl((X+\beta N_{m})|_{V}\bigr)=\mathrm{Tr}_{f}(X|_{V})+\beta\,\mathrm{Tr}_{f}\bigl(N_{m}|_{V}\bigr), \qquad \mathrm{Tr}_{f}\bigl((X-\beta N_{m})|_{V}\bigr)=\mathrm{Tr}_{f}(X|_{V})-\beta\,\mathrm{Tr}_{f}\bigl(N_{m}|_{V}\bigr). $$ Every term of the two shifts other than the trace term is independent of the fourth argument, so, using the shift formulas and the trace identities recorded above,

F^{-}{\delta}(x,r,p,X)-F^{-}{\delta}\bigl(x,r,p,X+\beta N_{m}\bigr)=\tfrac{\nu\beta}{2},\mathrm{Tr}{f}\bigl(N{m}|_{V}\bigr)\le\rho,

F^{+}{\delta}\bigl(x,r,p,X-\beta N{m}\bigr)-F^{+}{\delta}(x,r,p,X)=\tfrac{\nu\beta}{2},\mathrm{Tr}{f}\bigl(N_{m}|_{V}\bigr)\le\rho .

These hold for all such data, in particular for the terms of any sequences as in [The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §lower](/theorems/7a1fad52-e5e9-4b06-b9f7-3404ec390a28?v=60a64940-3e71-4244-88de-b6da3ae47192#clause-lower) and [The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §upper](/theorems/7a1fad52-e5e9-4b06-b9f7-3404ec390a28?v=60a64940-3e71-4244-88de-b6da3ae47192#clause-upper), whose $R$-boundedness hypothesis is not needed; rearranged, they are the two inequalities required there. Hence $F$ is tail-insensitive along $(e_{k})_{k\in\mathbb{N}}$. If moreover $H$ is not finite-dimensional as a vector space over $\mathbb{R}$, such a basis exists by [An Orthonormal Basis of the Ambient Space Contained in the Form Space of a Hilbert Triple §basis](/theorems/708f4661-d0e5-4c89-84a3-f4ac1b404da7?v=f8b276c1-f241-4fc2-873e-fe11923c2357#clause-basis), and $F$ then satisfies the tail-insensitivity condition by [The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §condition](/theorems/7a1fad52-e5e9-4b06-b9f7-3404ec390a28?v=60a64940-3e71-4244-88de-b6da3ae47192#clause-condition). **Claim 5, a bound on the form operator over the admissible sets.** Let $\delta,R\in\mathbb{R}$ satisfy $0<\delta<1$ and $0<R$. Let $\rho$ be the nonnegative real with $\rho^{2}=2R$, given by [Existence and Uniqueness of the Nonnegative Square Root](/theorems/7f783996-7e13-4f8a-9353-21a467864e85?v=9fba8150-5ca0-4dd5-911f-aa0f5cf5feec). If $(z,r,p,X)\in\mathcal{W}$ is [$R$-bounded](/theorems/4640aebc-d86c-4e8f-8b51-dbba74a2d2be?v=5d4402f9-29f2-408b-9701-41c882b2060b#clause-bounded) then $h(z)<R$, so $|z|_{V}^{2}=2h(z)<\rho^{2}$ and therefore $|z|_{V}\le\rho$ by claim 1 of [Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field](/theorems/c4e16e3c-4449-4681-953c-02ad68f9842b?v=d3a024bb-6971-4912-9ff5-7923ca2a4893) and trichotomy, and $|z|\le\rho$. Let $\beta_{0}$ be a bound for $B$ on the set of $\zeta\in V$ with $|\zeta|_{V}\le\rho$, as provided by [Monotone, $A$-Monotone and Locally Bounded Nonlinearities on a Hilbert Triple §bounded](/theorems/ffd56497-3c4f-4c81-8443-c7c97b91b400?v=fae9a4a6-fde1-4289-920d-00ad75746aea#clause-bounded), put $\mu=c_{L}+\ell\rho$ and $N=\beta_{0}+\mu$; then $|\Phi(z)|\le N$ for every such $z$, by [The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §triangle](/theorems/0c7d58a7-82ab-48c0-a8be-ad7b9e2297fc?v=237d76f6-5e7b-450e-974e-4bf327ff854e#clause-triangle) and the bound on $|L|$. We first bound the trace terms. If $(z,r,p,X)$ is $R$-bounded then $\lVert X\rVert<R$, so [Elementary Properties of the Trace of a Form along a Square-Summable Sequence §restriction](/theorems/d74946b5-13a2-4657-81e2-bf67736f3aa1?v=d0d0bd01-a849-4393-b600-07e56979fdaf#clause-restriction) gives $|\mathrm{Tr}_{f}(X|_{V})|\le R\,\sigma(f)$, while $\delta<1$ and $0\le\sigma(f)$ give $\delta\,\sigma(f)\le\sigma(f)$; with the trace identities recorded above and $0\le\tfrac{\nu}{2}$ this yields, putting $C_{\nu}=\tfrac{\nu}{2}(R+1)\,\sigma(f)$,

-\tfrac{\nu}{2},\mathrm{Tr}{f}\bigl(X|{V}+\delta I_{V}\bigr)\ \ge\ -C_{\nu}, \qquad -\tfrac{\nu}{2},\mathrm{Tr}{f}\bigl(X|{V}-\delta I_{V}\bigr)\ \le\ C_{\nu}.

Let $\xi=(x,r,p,X)$ be $R$-bounded. From the formula for $F^{-}_{\delta}$, using $\tfrac{\theta}{2}|p+\delta a|^{2}\ge0$, [The Cauchy-Schwarz Inequality in a Real Inner Product Space](/theorems/75e68dc9-c425-4d4e-afd8-53eba404a50e?v=638ad390-44c9-472a-bccb-9ba6242bb219) with $|p|<R$, the second elementary fact in the form $\langle L(x),a\rangle\ge-\tfrac{1}{4}|a|^{2}-|L(x)|^{2}$ together with $|L(x)|\le\mu$ and $\delta<1$, [Monotone, $A$-Monotone and Locally Bounded Nonlinearities on a Hilbert Triple §a-monotone](/theorems/ffd56497-3c4f-4c81-8443-c7c97b91b400?v=fae9a4a6-fde1-4289-920d-00ad75746aea#clause-a-monotone), $|\Phi(x)|\le N$, $0\le h(x)$, $-R\le r$ and $|g(x)|\le C_{g}$,

F^{-}{\delta}(\xi)\ \ge\ \delta|a|^{2}-R|a|-NR-\tfrac{\delta}{4}|a|^{2}-\mu^{2}-\lambda{0}R-C_{g}-C_{\nu}\ =\ \tfrac{3\delta}{4}|a|^{2}-R|a|-C_{-},

where $C_{-}=NR+\mu^{2}+\lambda_{0}R+C_{g}+C_{\nu}$. Similarly, let $\eta=(y,s,p',X')$ be $R$-bounded. Expanding $\tfrac{\theta}{2}|p'-\delta b|^{2}$ by the first elementary fact and using $0\le\theta\le1$, $|p'|<R$, [The Cauchy-Schwarz Inequality in a Real Inner Product Space](/theorems/75e68dc9-c425-4d4e-afd8-53eba404a50e?v=638ad390-44c9-472a-bccb-9ba6242bb219) and $0<\delta<1$,

\tfrac{\theta}{2}|p'-\delta b|^{2}\ \le\ \tfrac{1}{2}R^{2}+\delta R|b|+\tfrac{\delta^{2}}{2}|b|^{2},

while $\langle b+\Phi(y),p'-\delta b\rangle\le R|b|-\delta|b|^{2}+NR+\delta N|b|$ by [The Cauchy-Schwarz Inequality in a Real Inner Product Space](/theorems/75e68dc9-c425-4d4e-afd8-53eba404a50e?v=638ad390-44c9-472a-bccb-9ba6242bb219) and $|\Phi(y)|\le N$. Adding these, and using $s\le R$, $0\le h(y)$, $-g(y)\le C_{g}$, the trace bound above, $\delta<1$ and $\tfrac{\delta^{2}}{2}-\delta\le-\tfrac{\delta}{2}$,

F^{+}{\delta}(\eta)\ \le\ -\tfrac{\delta}{2}|b|^{2}+(2R+N)|b|+C{+},

where $C_{+}=\tfrac{1}{2}R^{2}+NR+\lambda_{0}R+C_{g}+C_{\nu}$. By the second elementary fact, $R|a|\le\tfrac{3\delta}{8}|a|^{2}+\tfrac{2R^{2}}{3\delta}$ and $(2R+N)|b|\le\tfrac{\delta}{4}|b|^{2}+\tfrac{(2R+N)^{2}}{\delta}$. Hence the two displays give

F^{-}{\delta}(\xi)\ \ge\ \tfrac{3\delta}{8}|a|^{2}-E,\qquad F^{+}{\delta}(\eta)\ \le\ -\tfrac{\delta}{4}|b|^{2}+E,

where $E=\tfrac{2R^{2}}{3\delta}+\tfrac{(2R+N)^{2}}{\delta}+C_{-}+C_{+}$; in particular $F^{-}_{\delta}(\xi)\ge-E$ and $F^{+}_{\delta}(\eta)\le E$ for all $R$-bounded $\xi$ and $\eta$. Now let $\xi=(x,r,p,X)\in S^{-}_{\delta,R}$. By [Test Data for a Second-Order Equation Operator on a Hilbert Triple and the Admissible Sets §admissible](/theorems/4640aebc-d86c-4e8f-8b51-dbba74a2d2be?v=5d4402f9-29f2-408b-9701-41c882b2060b#clause-admissible) there is an $R$-bounded $\eta$ with $F^{-}_{\delta}(\xi)-F^{+}_{\delta}(\eta)<R$, so $\tfrac{3\delta}{8}|a|^{2}-E\le F^{-}_{\delta}(\xi)<R+F^{+}_{\delta}(\eta)\le R+E$ and therefore $|a|^{2}<\tfrac{8(R+2E)}{3\delta}$. Similarly, if $\eta=(y,s,p',X')\in S^{+}_{\delta,R}$ there is an $R$-bounded $\xi$ with $F^{-}_{\delta}(\xi)-F^{+}_{\delta}(\eta)<R$, so $-\tfrac{\delta}{4}|b|^{2}+E\ge F^{+}_{\delta}(\eta)>F^{-}_{\delta}(\xi)-R\ge-E-R$ and therefore $|b|^{2}<\tfrac{4(R+2E)}{\delta}$. Let $\Lambda$ be the nonnegative real whose square is the larger of $\tfrac{8(R+2E)}{3\delta}$ and $\tfrac{4(R+2E)}{\delta}$, again by [Existence and Uniqueness of the Nonnegative Square Root](/theorems/7f783996-7e13-4f8a-9353-21a467864e85?v=9fba8150-5ca0-4dd5-911f-aa0f5cf5feec). Then $|Ax|\le\Lambda$ whenever $(x,r,p,X)$ lies in $S^{-}_{\delta,R}$ or in $S^{+}_{\delta,R}$, by claim 1 of [Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field](/theorems/c4e16e3c-4449-4681-953c-02ad68f9842b?v=d3a024bb-6971-4912-9ff5-7923ca2a4893) and trichotomy. **Claim 5, the shift modulus.** Put $c=R+2\Lambda+N+\tfrac{\nu}{2}\,\sigma(f)$ and let $\omega$ be the function on the nonnegative reals with $\omega(t)=c\,t+\tfrac{1}{2}t^{2}$. It is nonnegative there. Given a positive $\varepsilon$, let $\delta_{0}$ be the lesser of $1$ and $\tfrac{\varepsilon}{c+1}$, which is positive; every nonnegative $t\le\delta_{0}$ satisfies $t\le1$, hence $t^{2}\le t$ and $\omega(t)\le(c+1)t\le\varepsilon$. So $\omega$ is a modulus of continuity. It is also nondecreasing on the nonnegative reals: for $0\le s\le t$ we have $c\,s\le c\,t$ by [Linear Moduli of Continuity §monotone](/theorems/206eec08-b1fd-4f5b-a4a1-42fc2a8ddbc8?v=be112d1c-eb90-48ca-9371-16fa3ebca6c7#clause-monotone), and $s^{2}\le t^{2}$ by claim 2 of [Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field](/theorems/c4e16e3c-4449-4681-953c-02ad68f9842b?v=d3a024bb-6971-4912-9ff5-7923ca2a4893), whence $\tfrac{1}{2}s^{2}\le\tfrac{1}{2}t^{2}$ by claim 5 of [Elementary Arithmetic in an Ordered Field](/theorems/fe1c552a-759a-469b-86a4-5207560aefaf?v=63c2af8b-b56f-40d4-bc16-3fb0690235bc); adding the two inequalities by claims 3 and 2 of that lemma gives $\omega(s)\le\omega(t)$. Let $q\in H$ and $Y\in\mathrm{Sym}(H)$. Let $(x,r,p,X)\in S^{-}_{\delta,R}$ and put $P=p+\delta a$, so that $|P|\le R+\delta\Lambda\le R+\Lambda$ by [The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §triangle](/theorems/0c7d58a7-82ab-48c0-a8be-ad7b9e2297fc?v=237d76f6-5e7b-450e-974e-4bf327ff854e#clause-triangle). By [Elementary Identities in a Real Inner Product Space §expansion](/theorems/5ce8e666-53b7-4958-beed-be505dcf38ba?v=5bbf7092-58eb-4039-aad3-ddfbf22d02dd#clause-expansion), [The Cauchy-Schwarz Inequality in a Real Inner Product Space](/theorems/75e68dc9-c425-4d4e-afd8-53eba404a50e?v=638ad390-44c9-472a-bccb-9ba6242bb219), [Elementary Properties of the Trace of a Form along a Square-Summable Sequence §linear](/theorems/d74946b5-13a2-4657-81e2-bf67736f3aa1?v=d0d0bd01-a849-4393-b600-07e56979fdaf#clause-linear) together with claim 10 of [Elementary Properties of Bounded Symmetric Bilinear Forms: Norm, Quadratic Form, Order and Continuity](/theorems/ee1a6501-eb70-41c9-a3ea-2490110e3a3e?v=6894704a-d362-4438-a83d-906109126b6b), and $0\le\theta\le1$,

F^{-}{\delta}(x,r,p+q,X+Y)-F^{-}{\delta}(x,r,p,X)=-\tfrac{\nu}{2},\mathrm{Tr}{f}(Y|{V})+\theta\langle P,q\rangle+\tfrac{\theta}{2}|q|^{2}+\langle a+\Phi(x),q\rangle\ \le\ \tfrac{\nu}{2},\sigma(f),\lVert Y\rVert+\bigl(|P|+|a|+|\Phi(x)|\bigr)|q|+\tfrac{1}{2}|q|^{2},

the trace term being bounded by [Elementary Properties of the Trace of a Form along a Square-Summable Sequence §restriction](/theorems/d74946b5-13a2-4657-81e2-bf67736f3aa1?v=d0d0bd01-a849-4393-b600-07e56979fdaf#clause-restriction). Write $t=|q|+\lVert Y\rVert$, so that $|q|\le t$ and $\lVert Y\rVert\le t$, both being nonnegative; then $|q|^{2}\le t^{2}$ by claim 2 of [Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field](/theorems/c4e16e3c-4449-4681-953c-02ad68f9842b?v=d3a024bb-6971-4912-9ff5-7923ca2a4893), and $|P|+|a|+|\Phi(x)|\le(R+\Lambda)+\Lambda+N$, so, all the coefficients being nonnegative, the right-hand side is at most $c\,t+\tfrac{1}{2}t^{2}=\omega(|q|+\lVert Y\rVert)$. This is the first requirement of [The Shift-Continuity Condition on Admissible Test Data §modulus](/theorems/d5ee1a2e-5473-4025-b8b8-daa65131c780?v=2618888e-84e7-485a-b732-842dc4ebefe4#clause-modulus). Likewise, for $(y,s,p',X')\in S^{+}_{\delta,R}$, putting $P'=p'-\delta b$,

F^{+}{\delta}(y,s,p'+q,X'+Y)-F^{+}{\delta}(y,s,p',X')=-\tfrac{\nu}{2},\mathrm{Tr}{f}(Y|{V})+\theta\langle P',q\rangle+\tfrac{\theta}{2}|q|^{2}+\langle b+\Phi(y),q\rangle\ \ge\ -\tfrac{\nu}{2},\sigma(f),\lVert Y\rVert-\bigl(|P'|+|b|+|\Phi(y)|\bigr)|q|\ \ge\ -\omega(|q|+\lVert Y\rVert),

where $\tfrac{\theta}{2}|q|^{2}$ was discarded as nonnegative. This is the second requirement. Hence $\omega$ is a shift modulus for $F$ at $(\delta,R)$, and as $\delta$ and $R$ were arbitrary, $F$ satisfies the shift-continuity condition by [The Shift-Continuity Condition on Admissible Test Data §continuity](/theorems/d5ee1a2e-5473-4025-b8b8-daa65131c780?v=2618888e-84e7-485a-b732-842dc4ebefe4#clause-continuity). **Claim 6.** Here $H$ is assumed not finite-dimensional. By claims 1, 2, 3, 4 and 5 the operator $F$ is a second-order equation operator on $H$ that is degenerate elliptic and locally strictly proper and satisfies the second-order structure condition, the tail-insensitivity condition and the shift-continuity condition, which are the hypotheses of [A Comparison Principle on a Hilbert Triple under the Second-Order Structure Condition §comparison](/theorems/39ba1c43-8484-4f3f-baee-579cdf02184e?v=877e17f8-b7fc-488b-a750-38cd723ba627#clause-comparison); applying that theorem to $u$, $v$ and $C$ gives $u(x)\le v(x)$ for every $x\in V$.
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