Take the Brenier optimal map T from the diagonal Gaussian to mu for the Euclidean cost and apply McCann's tangent inequality at the Gaussian, whose score is minus the scaling map. Writing relative entropy as entropy plus half the weighted second moment and expanding the weighted square of T turns this inequality into the weighted Talagrand bound.
Each result cited is universally quantified over the data in its own statement.
Throughout, , , and are as in the statement. Let be the diagonal Gaussian density with variances , its normalizing constant, the scaling map and the weighted square of ; let be the identity map of , and let be Lebesgue measure on . The entropy , the set , the score , the tangent spaces and the spaces with inner product are those named in Relative Entropy and Relative Score with Respect to a Diagonal Gaussian Measure: Comparison with the Entropy, the Score and the Relative Free Energy of a Quadratic Potential. The proof runs McCann's tangent inequality at the source along the Brenier map from to for the ordinary Euclidean cost; the weighted cost appears only through the weighted squares in the comparison of relative entropy and entropy, so no rescaling of the variances is needed.
Step 1 ( relative to itself). The constant function on with value is Borel and nonnegative, and for every one has by The Integral of an Indicator Function is the Measure of the Set; so the constant is a density of with respect to in the sense of The Radon-Nikodym Theorem for a Finite Measure and a Sigma-Finite Measure, and Uniqueness of Densities. For the function of The Function : Continuity, Young's Inequality and Lower Bounds, with the Elementary Bounds for the Exponential and the Logarithm one has , because by The Function : Continuity, Young's Inequality and Lower Bounds, with the Elementary Bounds for the Exponential and the Logarithm §log. Hence is the zero function, which is integrable with respect to with integral by claim 6(a) of Borel Measurability and Bounded Integration on a Metric Space ( being a Borel measure on by Probability Measures on Euclidean Space and Random Vectors: Standing Notation §measures). By Relative Entropy of Probability Measures §relative-entropy, has finite relative entropy with respect to and .
Step 2 (Second moments, entropies and absolute continuity). By The Entropy Inequality for Nonnegative Functions, and Quadratic Moments Bounded by the Relative Entropy with Respect to a Diagonal Gaussian Measure §second-moment, applied to and, by Step 1, to , both and belong to . By Relative Entropy and Relative Score with Respect to a Diagonal Gaussian Measure: Comparison with the Entropy, the Score and the Relative Free Energy of a Quadratic Potential §integrable, applied to each of them, the function is integrable (in particular Borel) with respect to and with respect to . By Relative Entropy and Relative Score with Respect to a Diagonal Gaussian Measure: Comparison with the Entropy, the Score and the Relative Free Energy of a Quadratic Potential §entropy, applied to and to , both have finite entropy, so both belong to , and, using Step 1 for the second identity,
Since has finite entropy, it is absolutely continuous by Basic Properties of the Entropy on the Wasserstein Space: Comparison with the Gaussian Relative Entropy, Lower Bound, Translation Invariance, Absolute Continuity, Closed Sublevel Sets and Lower Semicontinuity §absolutely-continuous.
Step 3 (The score of ). We apply The Score of a Measure with a Positive Continuously Differentiable Density with . By The Diagonal Gaussian Density on Euclidean Space: Regularity, Gradient, Normalization, Second Moments and Exponential Moments of Diagonal Quadratic Forms §regularity, is smooth and positive on , in particular of class there (Smooth Map on a Euclidean Open Set, with ); is the measure with density with respect to by Diagonal Gaussian Measures on Euclidean Space §measure, and it belongs to by Step 2. By The Diagonal Gaussian Density on Euclidean Space: Regularity, Gradient, Normalization, Second Moments and Exponential Moments of Diagonal Quadratic Forms §gradient, , so the map of The Score of a Measure with a Positive Continuously Differentiable Density is . Its squared norm has -integral at most , where is the least variance and the second moment of , by the bound displayed in the preamble of Finite Fisher Information Relative to a Diagonal Gaussian Measure: the Ornstein-Uhlenbeck Functional, the Relative Score and the Relative Fisher Information, which holds for every member of . Moreover by Relative Entropy and Relative Score with Respect to a Diagonal Gaussian Measure: Comparison with the Entropy, the Score and the Relative Free Energy of a Quadratic Potential §tangent, and is a linear subspace of by Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §closed, so . Hence has finite Fisher information by The Score of a Measure with a Positive Continuously Differentiable Density §projection, and its score is
by The Score of a Measure with a Positive Continuously Differentiable Density §equality.
Step 4 (An optimal map). By Existence of an Optimal Coupling of Two Probability Measures with Finite Second Moment, read with , there is an optimal coupling of and , both being in by Step 2. Since is absolutely continuous (Step 2), Brenier's Theorem: Optimal Couplings out of an Absolutely Continuous Measure are Induced by a Unique Map §map, with in place of and in place of , gives a Borel map with and . Thus is an optimal map from to in the sense of Optimal Transport Maps and Uniquely Mapped Pairs of Probability Measures §map. Its coordinate functions are written , as in the statement.
Step 5 (The tangent inequality). By Steps 2 and 3, and has finite Fisher information, and by Step 4, is an optimal map from to . So McCann's Tangent Inequality: the Entropy Lies Above its Tangent Along Optimal Maps §tangent, with in place of and in place of , gives . By the preamble of McCann's Tangent Inequality: the Entropy Lies Above its Tangent Along Optimal Maps, the Borel maps and are square-integrable random vectors on the probability space , so their pointwise difference is one too, by The Space of Square-Integrable Random Vectors §space read on that probability space as in Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §fields; that is, is Borel and . By Step 3, is Borel (preamble of Finite Fisher Information Relative to a Diagonal Gaussian Measure: the Ornstein-Uhlenbeck Functional, the Relative Score and the Relative Fisher Information) and . Hence the function on given by is Borel, and for every , both by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions. So, by monotonicity, additivity and positive homogeneity of the integral of nonnegative measurable functions (Linearity and Monotonicity of the Lebesgue Integral §nonnegative),
and is integrable with respect to by Integrable Function and the Lebesgue Integral. By Step 3, is the class of , and for every ; so the formula for the inner product of in Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §fields, followed by Linearity and Monotonicity of the Lebesgue Integral §integrable (with in place of both and , and ), gives . Therefore
Step 6 (The weighted square of the map). The function is Borel and integrable with respect to (Step 2; by Step 4). By the change-of-variables formula of Probability Measures on Euclidean Space and Random Vectors: Standing Notation §pushforward, the function is integrable with respect to and
Step 7 (Conclusion). For every put . Expanding , dividing by and summing over gives
Hence the nonnegative function equals , a linear combination of three functions that are integrable with respect to by Steps 6, 2 and 5; so it is Borel and integrable with respect to , and by Linearity and Monotonicity of the Lebesgue Integral §integrable
By (3), the first term on the right is ; by the second identity in (1), the second term is . So the right-hand side equals
by (2) and then the first identity in (1). Multiplying by gives the inequality of the statement, for the Borel map of Step 4, which satisfies .
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