TheoremBase

A probability measure gives X measure 1, which is below ∞; the measure of a probability space is a probability measure.

Proof

Proof of (i). If μ\mu is a probability measure, then by Measure, Measure Space, and Probability Measure (v)

μ(X)=1<∞\mu(X)=1<\infty

by Real Numbers Lie Strictly below ∞, and Each Element of a Subset of [−∞,∞] Lies below Its Supremum (i) (as 1∈R1\in\mathbb{R}), so μ\mu is finite by Measure, Measure Space, and Probability Measure (iii).

Proof of (ii). By Probability Spaces, Events and Random Elements (i), PP is a probability measure on the measurable space (Ω,F)(\Omega,\mathcal{F}), so PP is finite by (i). ■\blacksquare

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