Sums of vectors obey Properties of Finite Sums of Vectors and sums of real numbers obey Properties of Finite Sums; we use the recursion and restriction rules (claim 1 of each), and write S for the successor map of Natural Numbers. Inner product identities are those of Real Inner Product Space Β§inner-product and Elementary Identities in a Real Inner Product Space Β§bilinear.
Claim 1. Let A be the set of nβN such that for every n-tuple vβEn and every wβE one has β¨βk=1nβvkβ,wβ©=βk=1nββ¨vkβ,wβ©. For n=1 both sides equal β¨v1β,wβ© by the recursion rules, so 1βA. Let nβA and let vβES(n), wβE. Let vβ² be the restriction of v to [n]. By the recursion rule and the restriction rule, βk=1S(n)βvkβ=βk=1nβvkβ²β+vS(n)β, and likewise βk=1S(n)ββ¨vkβ,wβ©=βk=1nββ¨vkβ²β,wβ©+β¨vS(n)β,wβ©. Hence, by additivity in the first argument and nβA applied to vβ²,
β¨k=1βS(n)βvkβ,wβ©=β¨k=1βnβvkβ²β,wβ©+β¨vS(n)β,wβ©=k=1βnββ¨vkβ²β,wβ©+β¨vS(n)β,wβ©=k=1βS(n)ββ¨vkβ,wβ©.
So S(n)βA, and A=N by Principle of Induction for the Natural Numbers. The identity in the second argument follows by symmetry (a) applied to both sides.
Claim 2. Apply claim 1 to the n-tuple with components ckβvkβ and use homogeneity (c): β¨ckβvkβ,wβ©=ckββ¨vkβ,wβ©. The second identity follows by symmetry.
Claim 3. By claim 2, β¨βk=1nβckβvkβ,vjββ©=βk=1nβckββ¨vkβ,vjββ©. By orthonormality, β¨vkβ,vjββ©=0 for kξ =j and β¨vjβ,vjββ©=β£vjββ£2=1, so the n-tuple with components ckββ¨vkβ,vjββ© has all components 0 except possibly the j-th, which is cjβ; its sum is cjβ by claim 7 of Properties of Finite Sums.
Claim 4. Put u=βk=1nβckβvkβ. By Real Inner Product Space Β§norm, claim 2 (first identity, with w=u) and claim 3 together with symmetry, β£uβ£2=β¨u,uβ©=βk=1nβckββ¨vkβ,uβ©=βk=1nβckββ¨u,vkββ©=βk=1nβckβckβ.
Claim 5. Let c:[n]βR satisfy βk=1nβckβvkβ=0Eβ, the zero vector. For every jβ[n], claim 3 and Elementary Identities in a Real Inner Product Space Β§zero give cjβ=β¨0Eβ,vjββ©=0. This is linear independence.