Every solution on an initial subinterval is symmetric (the difference with its transpose solves a homogeneous linear equation), positive semidefinite (it solves a Lyapunov equation with a modified coefficient), and below the Lyapunov solution (the difference solves a Lyapunov equation with positive semidefinite source); this gives an a priori norm bound, and the a priori bound theorem gives existence and uniqueness.
Real arithmetic is that of The Real Numbers as a Type (iv) and The Real Numbers as a Type (vi). Let be the right-hand side of the initial value problem of The Riccati Differential Equations of Filtering and Control (i) for , , ,
that is, is the function of The Riccati Differential Equations of Filtering and Control (i). For , a solution on below is a solution on , in the sense of Solution of an Initial Value Problem on (ii), of the initial value problem of The Initial Value Problem for a First-Order System of Ordinary Differential Equations (ii) with right-hand side and initial value ; for this is exactly a solution of The Riccati Differential Equations of Filtering and Control (i) with data , , and , since is its function . Functions formed pointwise from functions on a set, such as , , and below, are those of Maps Formed Pointwise from Vector and Matrix Operations (i). Matrix computations below use Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes (i), Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes (ii), Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes (iii) and Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes (vii), together with Products of Real Matrices with Zero Matrices, Negatives and Differences (i), Products of Real Matrices with Zero Matrices, Negatives and Differences (ii), Products of Real Matrices with Zero Matrices, Negatives and Differences (iii), Additive Laws for Vectors in and for Real Matrices: Group Laws and Rules for Differences (i) and Additive Laws for Vectors in and for Real Matrices: Group Laws and Rules for Differences (ii); in particular , the case of , since entrywise by Real Matrices: the Set of Real m x n Matrices with Their Entrywise Operations (iv).
Step 1: bounds on the coefficients. The functions and are continuous on by Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (iii) and Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (v), hence bounded on by the extreme value theorem of The Real Line: Standing Notation and Background for Calculus on Intervals (x). Fix with and for every ; then by Rules for the Operator Norm: Bound, Least Constant, Definiteness, Homogeneity, Triangle Inequality and Products (i).
Step 2: continuity of . Let be the product metric of and on , a metric by The Product Metric is a Metric (i), and let . By Continuity of Projections, Negatives and Differences, and Derivatives on Subintervals (i), the function , , the restriction to of the second projection, is continuous on , and, , and being continuous on , so are the functions , and on . Since , Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (iv) and Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (v) (products, a transpose and sums of continuous functions) and Continuity of Projections, Negatives and Differences, and Derivatives on Subintervals (ii) (the difference), applied to the metric space and its subset , show that is continuous on .
Step 3: the local Lipschitz bound. Let with , let and let with and . Since ,
By Rules for the Operator Norm: Bound, Least Constant, Definiteness, Homogeneity, Triangle Inequality and Products (vi), Rules for the Operator Norm: Bound, Least Constant, Definiteness, Homogeneity, Triangle Inequality and Products (v) (so ), Rules for the Operator Norm: Bound, Least Constant, Definiteness, Homogeneity, Triangle Inequality and Products (vii) and The Operator Norm of Entries, Transposes, Multiples of the Identity, Orthogonal Factors and Diagonal Matrices (v),
Step 4: solutions on initial subintervals. Let be as in (ii); every lies in by The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (iii). Fix with and a solution on . The restrictions of , and to are continuous on by Restricting a Continuous Map to a Smaller Subset Preserves Continuity (ii); the restriction of to is differentiable relative to , with the restriction of as its derivative, by Continuity of Projections, Negatives and Differences, and Derivatives on Subintervals (iii) (with and for and ); and is continuous on by Rules for Derivatives of Vector- and Matrix-Valued Maps (i). Below, , , and denote these restrictions, ranges over , and the argument is often omitted. The Lyapunov Differential Equation (i), The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (i), The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (iv), Linear Systems with Continuous Coefficients: Continuity, Global Lipschitz Bound and Well-Posedness of the Initial Value Problem (i) and Linear Systems with Continuous Coefficients: Continuity, Global Lipschitz Bound and Well-Posedness of the Initial Value Problem (v) are applied below with in place of , which is allowed since .
(a) . The function is differentiable with by Rules for Derivatives of Vector- and Matrix-Valued Maps (viii), so is differentiable with by Rules for Derivatives of Vector- and Matrix-Valued Maps (iv). As and ,
and . Hence, with the function , whose transpose is ,
The functions and , and the constant function , are continuous on by Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (iv), Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (v) and Continuity of Projections, Negatives and Differences, and Derivatives on Subintervals (ii). Thus is a solution of the initial value problem with right-hand side (the function of Linear Systems with Continuous Coefficients: Continuity, Global Lipschitz Bound and Well-Posedness of the Initial Value Problem (i) for , and ) and initial value ; so is , whose derivative is by Rules for Derivatives of Vector- and Matrix-Valued Maps (ix), while . By Linear Systems with Continuous Coefficients: Continuity, Global Lipschitz Bound and Well-Posedness of the Initial Value Problem (v), , so and for every .
(b) . The function is continuous on by Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (iv) and Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (v), and by (a) , which lies in and is positive semidefinite by Rules for Symmetric and Positive Semidefinite Matrices: Closure, Self-Adjointness, Polarization, Congruence and Cones (v). Hence the function is continuous on by the same two clauses, and every lies in by Rules for Symmetric and Positive Semidefinite Matrices: Closure, Self-Adjointness, Polarization, Congruence and Cones (i) and is positive semidefinite by Rules for Symmetric and Positive Semidefinite Matrices: Closure, Self-Adjointness, Polarization, Congruence and Cones (vii). Let be as in (a), continuous on . By (a) and , , so and , and
Thus is a solution of the initial value problem of The Lyapunov Differential Equation (i) with data , and ; it is the only one by The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (i), and since and every lie in and are positive semidefinite, every is positive semidefinite by The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (iv), that is, by The Positive Semidefinite Ordering is a Partial Order Compatible with the Linear Structure (vii).
(c) and . The function is differentiable, by Rules for Derivatives of Vector- and Matrix-Valued Maps (iv), with
with as in (b), continuous on with every in and positive semidefinite. Also is positive semidefinite: for every , by Products of Real Matrices with Zero Matrices, Negatives and Differences (i), so by the dot product formula, which is the condition of Positive Semidefinite and Positive Definite Real Matrices (i). So is a solution of the initial value problem of The Lyapunov Differential Equation (i) with data , and ; by The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (i) and The Lyapunov Differential Equation: Well-Posedness, Representation, Symmetry, Positive Semidefiniteness, Comparison and the Backward Equation (iv), every is positive semidefinite, so by The Positive Semidefinite Ordering is a Partial Order Compatible with the Linear Structure (vi). With (b), The Operator Norm of a Symmetric Matrix: Quadratic Forms, Eigenvalues and the Semidefinite Ordering (xi) gives .
Step 5: the a priori bound. is differentiable on , hence continuous by Rules for Derivatives of Vector- and Matrix-Valued Maps (i), so is continuous on by Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (iii) and Continuity of Vector- and Matrix-Valued Maps: the Componentwise Criterion, Norms and Algebraic Operations (v) and has a greatest value on by The Real Line: Standing Notation and Background for Calculus on Intervals (x). Then , and by Step 4(c) every solution on , for every with , satisfies for every .
Step 6: conclusion. By Steps 2, 3 and 5, the hypotheses of A Priori Bounded Initial Value Problems with Locally Lipschitz Right-Hand Side Have Exactly One Solution on the Whole Interval (iii) hold with , right-hand side , , for each radius , and ; so the initial value problem has exactly one solution on , which is (i). is a solution on with , so Step 4 applies to : for every , and by Step 4(a)-(c), which is (ii), and by Step 4(c), which is (iii).
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