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Proof of Change of Variables for the Lebesgue Integral under a Continuously Differentiable Bijection of Euclidean Space with Symmetric Positive Definite Jacobian Matrix, and the Density of a Push-Forward

theoremthm:change-of-variables-diffeomorphism-euclidean-2026a
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· 25,042 chars · 57 deps · depth 27 Reason: Proof of thm:change-of-variables-diffeomorphism-euclidean-2026a, from scratch (no inverse function or pullback theorem).

Near each point F is, after composing with the inverse Jacobian matrix, a map close to the identity, so the image of a small cube has measure at most the integral of det DF over it; summing over grids gives the inequality for continuous compactly supported integrands, and applying it to the inverse map gives equality. A Gaussian weight turns both sides into finite measures that agree on test functions, hence everywhere, which yields the formula for all Borel functions and the density of the push-forward.

Proof

Each result cited below is universally quantified over the data in its own statement.

The natural number dd is read in R\mathbb{R} as in The Real Numbers: Standing Notation and Background §numbers wherever a real number is required. Write λ=λd\lambda=\lambda_{d} and J(x)=detDF(x)J(x)=\det DF(x); since DF(x)DF(x) is symmetric, it lies in S(d)\mathcal{S}(d), and 0<J(x)0<J(x) for every xx by Determinants of Positive Definite Matrices: Positivity, the Bound logdetAtrAd\log\det A\le\mathrm{tr}\,A-d, Bounds under Pinching, and the Expansion of det(I+tB)\det(I+tB) §positive. Metric notions on Rd\mathbb{R}^{d} (open sets, closures, boundedness, compactness) refer to the Euclidean distance dEd_{E} as in Euclidean Space and Lebesgue Measure: Standing Notation §space, with dE(x,y)=xyd_{E}(x,y)=\lVert x-y\rVert; a real-valued function on a subset AA of Rd\mathbb{R}^{d} is called continuous when it is continuous on AA for dEd_{E} and the absolute-value metric of R\mathbb{R}. A function continuous on Rd\mathbb{R}^{d} is continuous on every subset AA, directly from Continuous Map Between Metric Spaces. By Probability Measures on Euclidean Space and Random Vectors: Standing Notation §borel-maps, a map RdRd\mathbb{R}^{d}\to\mathbb{R}^{d} is Borel exactly when its components are, a continuous map RdR\mathbb{R}^{d}\to\mathbb{R} is Borel, and compositions of Borel maps are Borel; indicators of Borel sets, sums and products of real-valued Borel maps are Borel by claims 1 to 3 of Arithmetic, Absolute Values, and Pointwise Limits of Measurable Real-Valued Functions. For aRda\in\mathbb{R}^{d} and a positive real number ss put

P(a,s)={xRd:aixi<ai+s for every i[d]},P(a,s)=\{x\in\mathbb{R}^{d}:a_{i}\le x_{i}<a_{i}+s\ \text{for every }i\in[d]\},

the half-open cube with corner aa and side ss, and let Q(c,r)Q(c,r) be the closed cube of A Continuously Differentiable Map Whose Jacobian Matrix is Close to the Identity Maps a Cube into a Slightly Larger Cube. Let e=(1,,1)Rde=(1,\dots,1)\in\mathbb{R}^{d}. Claims 1 to 5 use only the hypotheses of the theorem on FF, so they hold for every map satisfying those hypotheses.

Claim 1 (Continuity and measurability; claim 1). (a) The components of FF and of F1F^{-1} and the functions jFi\partial_{j}F_{i} and j(F1)i\partial_{j}(F^{-1})_{i} are continuous on Rd\mathbb{R}^{d}, and FF and F1F^{-1} are continuous at every point in the Euclidean sense. (b) If u:RdRu:\mathbb{R}^{d}\to\mathbb{R} is continuous, then so are uFu\circ F and uF1u\circ F^{-1}. (c) JJ is continuous. (d) FF, F1F^{-1} and JJ are Borel, and F(B)B(Rd)F(B)\in\mathcal{B}(\mathbb{R}^{d}) for every BB(Rd)B\in\mathcal{B}(\mathbb{R}^{d}).

(a) By clause 1 of C^k Maps on a Euclidean Open Set, read through Differential Calculus and Convexity on Euclidean Open Sets: Standing Notation §derivatives, the components FiF_{i}, (F1)i(F^{-1})_{i} and the functions jFi\partial_{j}F_{i}, j(F1)i\partial_{j}(F^{-1})_{i} are continuous at every point of Rd\mathbb{R}^{d} in the Euclidean sense, hence continuous by claim 1 of Euclidean Continuity Agrees with Metric Continuity for Real-Valued Functions; and FF and F1F^{-1} are continuous at every point in the Euclidean sense by Coordinatewise Criterion for Continuity of a Map Between Euclidean Spaces. (b) Let xRdx\in\mathbb{R}^{d}. By claim 1 of Euclidean Continuity Agrees with Metric Continuity for Real-Valued Functions, uu is continuous at F(x)F(x) in the Euclidean sense; by (a) and Composition of Continuous Euclidean Maps, uFu\circ F is continuous at xx in the Euclidean sense, hence continuous at xx by the same claim 1. The same argument applies to uF1u\circ F^{-1}. (c) By Determinant of a Real Square Matrix, J(x)=σSdsgn(σ)i=1dσ(i)Fi(x)J(x)=\sum_{\sigma\in S_{d}}\operatorname{sgn}(\sigma)\prod_{i=1}^{d}\partial_{\sigma(i)}F_{i}(x) is a finite sum of constant multiples of finite products of the continuous functions of (a), hence continuous by claims 2, 3 and 4 of Continuity of Sums and Products of Real-Valued Functions on a Metric Space, applied by induction on the number of factors and of summands. (d) FF, F1F^{-1} and JJ are Borel by (a), (c) and the preamble. Since FF is a bijection with inverse F1F^{-1}, yF(B)y\in F(B) holds exactly when F1(y)BF^{-1}(y)\in B, so F(B)=(F1)1(B)F(B)=(F^{-1})^{-1}(B) is Borel.

Claim 2 (Closed hulls of half-open cubes). For aRda\in\mathbb{R}^{d} and positive ss, the closure P(a,s)\overline{P}(a,s) of P(a,s)P(a,s) is compact, and aP(a,s)P(a,s)a\in P(a,s)\subseteq\overline{P}(a,s).

For yP(a,s)y\in P(a,s), aiyis|a_{i}-y_{i}|\le s for every ii, so dE(a,y)=aydsd_{E}(a,y)=\lVert a-y\rVert\le d\,s by Coordinate Bounds Control the Euclidean Norm. Hence P(a,s)P(a,s) is bounded, and its closure is compact by The Closure of a Bounded Subset of Rn\mathbb{R}^n is Compact. A point of P(a,s)P(a,s) lies in every open set containing it, so P(a,s)P(a,s)P(a,s)\subseteq\overline{P}(a,s) by Closure of a Subset of a Topological Space; and aP(a,s)a\in P(a,s) as 0<s0<s.

Claim 3 (Images of half-open cubes). Let aRda\in\mathbb{R}^{d}, let ss be positive and P=P(a,s)P=P(a,s). Then F(P)B(Rd)F(P)\in\mathcal{B}(\mathbb{R}^{d}), the number I=Rd1PJdλI=\int_{\mathbb{R}^{d}}\mathbf{1}_{P}\,J\,d\lambda is finite, and λ(F(P))I\lambda(F(P))\le I.

Compactness data. F(P)F(P) is Borel by Claim 1(d), PP being Borel by claim 1 of Uniform Grids on a Half-Open Box and Grid Hulls of a Compact Set in Rn\mathbb{R}^n (with n=dn=d, corner aa, m=1m=1), which also gives λ(P)=sd\lambda(P)=s^{d}. Put P+=P(ase,3s)P^{+}=P(a-s\,e,3s) and let K=P(ase,3s)K=\overline{P}(a-s\,e,3s), a nonempty compact set containing P+P^{+} by Claim 2; note that {x:aixiai+s for every i}P+\{x:a_{i}\le x_{i}\le a_{i}+s\text{ for every }i\}\subseteq P^{+}. For i,j[d]i,j\in[d] let eij(x)=j(F1)i(F(x))e'_{ij}(x)=\partial_{j}(F^{-1})_{i}(F(x)), the entry in row ii and column jj of DF1(F(x))DF^{-1}(F(x)). By Claim 1, the functions jFi\partial_{j}F_{i}, eije'_{ij} and JJ are continuous on Rd\mathbb{R}^{d}, hence on KK; by Heine-Cantor Theorem: Continuity on a Compact Subset Implies Uniform Continuity they are uniformly continuous on KK, and by Extreme Value Theorem on a Compact Subset of a Metric Space each of the finitely many functions eije'_{ij} and JJ attains a least and a greatest value on KK. If vL\ell\le v\le L' then v+L|v|\le|\ell|+|L'| by claims 3 and 6 of Properties of the Absolute Value in an Ordered Field; so with β=1+i,j(ij+Lij)\beta=1+\sum_{i,j}(|\ell_{ij}|+|L'_{ij}|), where ij\ell_{ij} and LijL'_{ij} are the least and greatest values of eije'_{ij} on KK, we have 1β1\le\beta and eij(x)β|e'_{ij}(x)|\le\beta for all xKx\in K and i,ji,j; and with MJM_{J} the greatest value of JJ on KK, 1PJMJ1P\mathbf{1}_{P}J\le M_{J}\mathbf{1}_{P}, so IMJλ(P)=MJsd<I\le M_{J}\lambda(P)=M_{J}s^{d}<\infty by claim 1 of Linearity and Monotonicity of the Lebesgue Integral and The Integral of an Indicator Function is the Measure of the Set.

Order of choices. Let γ\gamma be a positive real number. Put θ=γ/(2sd)\theta=\gamma/(2s^{d}), and choose a real η\eta with 0<η10<\eta\le1 and 2dη(I+γ/2)γ/22^{d}\eta\,(I+\gamma/2)\le\gamma/2. By the uniform continuity above, choose a positive real ω\omega (the least of finitely many radii) such that all x,xKx,x'\in K with dE(x,x)<ωd_{E}(x,x')<\omega satisfy jFi(x)jFi(x)<η/(d2β)|\partial_{j}F_{i}(x)-\partial_{j}F_{i}(x')|<\eta/(d^{2}\beta) for all i,ji,j and J(x)J(x)<θ|J(x)-J(x')|<\theta. By claim 2 of The Archimedean Property of the Real Numbers, choose NNN\in\mathbb{N} with ds<Nωd\,s<N\omega, and put r=s/(2N)r=s/(2N), so that dr<ωd\,r<\omega.

One cell. Let QκQ_{\kappa}, for κ[N]d\kappa\in[N]^{d}, be the cells QN,κQ_{N,\kappa} of claim 1 of Uniform Grids on a Half-Open Box and Grid Hulls of a Compact Set in Rn\mathbb{R}^n (with n=dn=d, corner aa, side ss, m=Nm=N): pairwise disjoint Borel sets with union PP and λ(Qκ)=(s/N)d\lambda(Q_{\kappa})=(s/N)^{d}. Fix κ\kappa and let cRdc\in\mathbb{R}^{d} have coordinates ci=ai+(κi12)s/Nc_{i}=a_{i}+(\kappa_{i}-\tfrac12)s/N. Then QκQ(c,r)P+KQ_{\kappa}\subseteq Q(c,r)\subseteq P^{+}\subseteq K, and every xQ(c,r)x\in Q(c,r) satisfies dE(x,c)dr<ωd_{E}(x,c)\le d\,r<\omega by Coordinate Bounds Control the Euclidean Norm. Let A=DF(c)A=DF(c), symmetric and positive definite, and A=DF1(F(c))A'=DF^{-1}(F(c)), its inverse matrix, so AA=AA=IdA'A=AA'=I_{d} and Ail=eil(c)β|A'_{il}|=|e'_{il}(c)|\le\beta. For i[d]i\in[d] let Li(y)=l=1dAilylL_{i}(y)=\sum_{l=1}^{d}A'_{il}y_{l}; by claim 1 of Quadratic and Affine Functions of Class C2C^2, Translation, and Quadratic Perturbation of Semiconvexity (with M=0dM=0_{d}, q=(Ai1,,Aid)q=(A'_{i1},\dots,A'_{id}), constant 00), LiL_{i} is of class C2C^{2} on Rd\mathbb{R}^{d} with gradient qq, i.e. lLi=Ail\partial_{l}L_{i}=A'_{il} (Gradient of a Real-Valued Function on a Euclidean Open Set), hence of class C1C^{1} by claim 2 of Euclidean Space is Open in Itself, and CkC^k Maps are Continuous. Let G=(L1F,,LdF)G=(L_{1}\circ F,\dots,L_{d}\circ F), i.e. G(x)=AF(x)G(x)=A'F(x). By claims 2 (with k=1k=1) and 1 of A Composition of CkC^k Maps Between Euclidean Open Sets is of Class CkC^k, the components of GG are of class C1C^{1} and jGi(x)=lAiljFl(x)\partial_{j}G_{i}(x)=\sum_{l}A'_{il}\,\partial_{j}F_{l}(x). As δij=(AA)ij=lAiljFl(c)\delta_{ij}=(A'A)_{ij}=\sum_{l}A'_{il}\,\partial_{j}F_{l}(c), claims 4 and 5 of Properties of the Absolute Value in an Ordered Field (the latter by induction over the finite sum) give, for xQ(c,r)x\in Q(c,r) and all i,ji,j,

jGi(x)δij=l=1dAil(jFl(x)jFl(c))dβηd2β=ηd.|\partial_{j}G_{i}(x)-\delta_{ij}|=\Bigl|\sum_{l=1}^{d}A'_{il}\bigl(\partial_{j}F_{l}(x)-\partial_{j}F_{l}(c)\bigr)\Bigr|\le d\,\beta\,\frac{\eta}{d^{2}\beta}=\frac{\eta}{d}.

By A Continuously Differentiable Map Whose Jacobian Matrix is Close to the Identity Maps a Cube into a Slightly Larger Cube §cube, G(x)C:=Q(G(c),(1+η)r)G(x)\in C:=Q(G(c),(1+\eta)r) for every xQ(c,r)x\in Q(c,r). Since AA=IdAA'=I_{d}, F(x)=AG(x)F(x)=A\,G(x), so F(Qκ)A(C)={Az:zC}F(Q_{\kappa})\subseteq A(C)=\{Az:z\in C\}. The set CC is the product of the closed intervals [Gi(c)(1+η)r,Gi(c)+(1+η)r][G_{i}(c)-(1+\eta)r,\,G_{i}(c)+(1+\eta)r], which belong to B(R)\mathcal{B}(\mathbb{R}) and have Lebesgue measure 2(1+η)r2(1+\eta)r by claim 4 of Existence of Lebesgue Measure on the Real Line; so CC is a Borel rectangle, it belongs to B(Rd)\mathcal{B}(\mathbb{R}^{d}) by claim 1 of Finite Products of Lebesgue Measure and Coordinate Integration on Rl\mathbb{R}^l and claim 5 of The Borel Sigma-Algebra of a Euclidean Space as a Product, and Measurability of Projections, Sequentially Continuous Maps, and Open and Closed Sets, and λ(C)=(1+η)d(s/N)d\lambda(C)=(1+\eta)^{d}(s/N)^{d} by Lebesgue Measure on Rn\mathbb{R}^n. By Lebesgue Measure under a Triangular or Symmetric Positive Definite Linear Map §spd, A(C)A(C) is Borel with λ(A(C))=detAλ(C)\lambda(A(C))=\det A\,\lambda(C). For xQκx\in Q_{\kappa}, detA=J(c)<J(x)+θ\det A=J(c)<J(x)+\theta. Hence, by claim 2 of Basic Properties of a Measure, The Integral of an Indicator Function is the Measure of the Set and claim 1 of Linearity and Monotonicity of the Lebesgue Integral,

λ(F(Qκ))(1+η)ddetAλ(Qκ)=(1+η)ddetA1Qκdλ(1+η)d1Qκ(J+θ)dλ.\lambda(F(Q_{\kappa}))\le(1+\eta)^{d}\det A\,\lambda(Q_{\kappa})=(1+\eta)^{d}\int\det A\,\mathbf{1}_{Q_{\kappa}}\,d\lambda\le(1+\eta)^{d}\int\mathbf{1}_{Q_{\kappa}}(J+\theta)\,d\lambda .

Summation. As FF is injective, the Borel sets F(Qκ)F(Q_{\kappa}) are pairwise disjoint with union F(P)F(P), and κ1Qκ=1P\sum_{\kappa}\mathbf{1}_{Q_{\kappa}}=\mathbf{1}_{P} pointwise. By claim 1 of Basic Properties of a Measure, claim 1 of Linearity and Monotonicity of the Lebesgue Integral (by induction over the finite set [N]d[N]^{d}) and The Integral of an Indicator Function is the Measure of the Set,

λ(F(P))=κλ(F(Qκ))(1+η)d1P(J+θ)dλ=(1+η)d(I+θsd).\lambda(F(P))=\sum_{\kappa}\lambda(F(Q_{\kappa}))\le(1+\eta)^{d}\int\mathbf{1}_{P}(J+\theta)\,d\lambda=(1+\eta)^{d}\bigl(I+\theta s^{d}\bigr).

Since 0<η10<\eta\le1, induction on dd with η2η\eta^{2}\le\eta gives (1+η)d1+(2d1)η1+2dη(1+\eta)^{d}\le1+(2^{d}-1)\eta\le1+2^{d}\eta, so by the choice of θ\theta and η\eta,

λ(F(P))I+γ2+2dη(I+γ2)I+γ.\lambda(F(P))\le I+\tfrac{\gamma}{2}+2^{d}\eta\bigl(I+\tfrac{\gamma}{2}\bigr)\le I+\gamma .

In particular λ(F(P))\lambda(F(P)) is finite, and as γ\gamma was arbitrary, λ(F(P))I\lambda(F(P))\le I (were λ(F(P))>I\lambda(F(P))>I, the choice γ=12(λ(F(P))I)\gamma=\tfrac12(\lambda(F(P))-I) would contradict the display).

Claim 4 (Preimages of compact sets). Let SRdS\subseteq\mathbb{R}^{d} be nonempty and compact. Then there are aRda\in\mathbb{R}^{d} and a positive ss with F1(S)P(a,s)F^{-1}(S)\subseteq P(a,s).

For each ii, the component (F1)i(F^{-1})_{i} is continuous (Claim 1(a)), so its restriction to SS has the continuity property required in Extreme Value Theorem on a Compact Subset of a Metric Space, which gives real numbers iui\ell_{i}\le u_{i} with i(F1)i(y)ui\ell_{i}\le(F^{-1})_{i}(y)\le u_{i} for every ySy\in S. With t=miniit=\min_{i}\ell_{i}, s=maxiuit+1s=\max_{i}u_{i}-t+1 (positive, indeed 1s1\le s, since t=i0ui0maxiuit=\ell_{i_{0}}\le u_{i_{0}}\le\max_{i}u_{i} for an index i0i_{0} attaining the minimum) and a=tea=t\,e we get ai(F1)i(y)<ai+sa_{i}\le(F^{-1})_{i}(y)<a_{i}+s for all ySy\in S and ii.

Claim 5 (Lower bound for continuous integrands). Let ψ:RdR\psi:\mathbb{R}^{d}\to\mathbb{R} be continuous with 0ψ0\le\psi, and let SRdS\subseteq\mathbb{R}^{d} be compact with ψ(y)=0\psi(y)=0 for every ySy\notin S. Then

RdψdλRd(ψF)Jdλin [0,].\int_{\mathbb{R}^{d}}\psi\,d\lambda\le\int_{\mathbb{R}^{d}}(\psi\circ F)\,J\,d\lambda\qquad\text{in }[0,\infty].

Both integrands are nonnegative and Borel by Claim 1. If S=S=\varnothing, then ψ=0\psi=0 and the left side is 00 (claim 1 of Linearity and Monotonicity of the Lebesgue Integral with c=0c=0). Otherwise take P0=P(a,s)F1(S)P_{0}=P(a,s)\supseteq F^{-1}(S) from Claim 4, so that SF(P0)S\subseteq F(P_{0}), and let K0=P(a,s)K_{0}=\overline{P}(a,s), a nonempty compact set containing P0P_{0} (Claim 2). The function u=ψFu=\psi\circ F is continuous (Claim 1(b)), hence uniformly continuous on K0K_{0} by Heine-Cantor Theorem: Continuity on a Compact Subset Implies Uniform Continuity, and JM0J\le M_{0} on K0K_{0} for some real M0M_{0} by Extreme Value Theorem on a Compact Subset of a Metric Space. Let θ\theta be a positive real number. Choose a positive ω\omega such that u(x)u(x)<θ|u(x)-u(x')|<\theta for all x,xK0x,x'\in K_{0} with dE(x,x)<ωd_{E}(x,x')<\omega, and then, by claim 2 of The Archimedean Property of the Real Numbers, NNN\in\mathbb{N} with σds<Nω\sigma_{d}\,s<N\omega, where σd=e\sigma_{d}=\lVert e\rVert. Let QκQ_{\kappa}, κ[N]d\kappa\in[N]^{d}, be the cells of claim 1 of Uniform Grids on a Half-Open Box and Grid Hulls of a Compact Set in Rn\mathbb{R}^n (with n=dn=d, corner aa, side ss, m=Nm=N): pairwise disjoint Borel sets with union P0P_{0}, any two points of one cell being at distance at most σds/N<ω\sigma_{d}s/N<\omega. Each QκQ_{\kappa} is the half-open cube P(a+sN(κe),sN)P(a+\tfrac{s}{N}(\kappa-e),\tfrac{s}{N}) and contains its corner pκ=a+sN(κe)p_{\kappa}=a+\tfrac{s}{N}(\kappa-e). Put mκ=u(pκ)+θm_{\kappa}=u(p_{\kappa})+\theta, a nonnegative real number; then u(x)<mκ<u(x)+2θu(x)<m_{\kappa}<u(x)+2\theta for xQκx\in Q_{\kappa}. The sets F(Qκ)F(Q_{\kappa}) are Borel (Claim 1(d)), pairwise disjoint with union F(P0)SF(P_{0})\supseteq S, and ψ(F(x))=u(x)<mκ\psi(F(x))=u(x)<m_{\kappa} for xQκx\in Q_{\kappa}; as ψ\psi vanishes off SS, ψκmκ1F(Qκ)\psi\le\sum_{\kappa}m_{\kappa}\mathbf{1}_{F(Q_{\kappa})} pointwise. By claim 1 of Linearity and Monotonicity of the Lebesgue Integral (with induction over the finite set [N]d[N]^{d}), The Integral of an Indicator Function is the Measure of the Set, and Claim 3 applied to each half-open cube QκQ_{\kappa},

ψdλκmκλ(F(Qκ))κmκ1QκJdλκ1Qκ(u+2θ)Jdλ=1P0(u+2θ)JdλuJdλ+2θM0sd,\int\psi\,d\lambda\le\sum_{\kappa}m_{\kappa}\,\lambda(F(Q_{\kappa}))\le\sum_{\kappa}\int m_{\kappa}\mathbf{1}_{Q_{\kappa}}J\,d\lambda\le\sum_{\kappa}\int\mathbf{1}_{Q_{\kappa}}(u+2\theta)J\,d\lambda=\int\mathbf{1}_{P_{0}}(u+2\theta)J\,d\lambda\le\int uJ\,d\lambda+2\theta M_{0}s^{d},

where the third inequality uses mκ<u(x)+2θm_{\kappa}<u(x)+2\theta on QκQ_{\kappa} and 0<J0<J, and the last uses 1P0uJuJ\mathbf{1}_{P_{0}}uJ\le uJ, 1P0JM01P0\mathbf{1}_{P_{0}}J\le M_{0}\mathbf{1}_{P_{0}} and λ(P0)=sd\lambda(P_{0})=s^{d}. If uJdλ=\int uJ\,d\lambda=\infty there is nothing to prove; otherwise the display holds for every positive θ\theta, and were ψdλ>uJdλ\int\psi\,d\lambda>\int uJ\,d\lambda, a θ\theta with 2θM0sd<ψdλuJdλ2\theta M_{0}s^{d}<\int\psi\,d\lambda-\int uJ\,d\lambda (note 0<M00<M_{0}) would contradict it.

Claim 6 (The inverse map). H=F1H=F^{-1} satisfies the hypotheses of the theorem, with inverse FF, and J(H(y))detDH(y)=1J(H(y))\det DH(y)=1 for every yRdy\in\mathbb{R}^{d}.

HH is a bijection with inverse FF, and the components of HH and of FF are of class C1C^{1}. Let yRdy\in\mathbb{R}^{d} and x=H(y)x=H(y), so F(x)=yF(x)=y. By hypothesis DH(y)=DF1(F(x))DH(y)=DF^{-1}(F(x)) is the inverse matrix of DF(x)DF(x). Since DF(x)DF(x) is symmetric and positive definite, Invertibility of Symmetric Positive Definite Matrices shows that it is invertible with symmetric positive definite inverse, which is DH(y)DH(y) by the uniqueness of the inverse in Inverse Matrix and Invertible Real Square Matrix. The identities DF(x)DH(y)=Id=DH(y)DF(x)DF(x)\,DH(y)=I_{d}=DH(y)\,DF(x) also say that DH1(H(y))=DF(x)DH^{-1}(H(y))=DF(x) is the inverse matrix of DH(y)DH(y). Finally J(H(y))detDH(y)=det(DF(x)DH(y))=detId=1J(H(y))\det DH(y)=\det\bigl(DF(x)\,DH(y)\bigr)=\det I_{d}=1 by The Determinant is Multiplicative and claim 1 of Row Properties of the Determinant.

Claim 7 (Continuous integrands). Under the hypotheses of Claim 5,

Rdψdλ=Rd(ψF)Jdλin [0,].\int_{\mathbb{R}^{d}}\psi\,d\lambda=\int_{\mathbb{R}^{d}}(\psi\circ F)\,J\,d\lambda\qquad\text{in }[0,\infty].

The inequality \le is Claim 5. If S=S=\varnothing both sides are 00. Otherwise let P0F1(S)P_{0}\supseteq F^{-1}(S) and K0P0K_{0}\supseteq P_{0} be as in the proof of Claim 5. The function ψ=(ψF)J\psi'=(\psi\circ F)J is continuous (Claim 1(b), (c) and claim 5 of Continuity of Sums and Products of Real-Valued Functions on a Metric Space) and nonnegative, and vanishes outside the compact set K0K_{0}: if xK0x\notin K_{0} then xF1(S)x\notin F^{-1}(S), so F(x)SF(x)\notin S and ψ(F(x))=0\psi(F(x))=0. By Claim 6, Claim 5 applies to the map H=F1H=F^{-1} and the function ψ\psi' with the compact set K0K_{0}, giving ψdλ(ψH)detDHdλ\int\psi'\,d\lambda\le\int(\psi'\circ H)\det DH\,d\lambda. Since F(H(y))=yF(H(y))=y and J(H(y))detDH(y)=1J(H(y))\det DH(y)=1 (Claim 6), (ψH)(y)detDH(y)=ψ(y)(\psi'\circ H)(y)\det DH(y)=\psi(y) for every yy, which gives \ge.

Claim 8 (Lebesgue measure through FF). For every AB(Rd)A\in\mathcal{B}(\mathbb{R}^{d}), λ(A)=Rd(1AF)Jdλ\lambda(A)=\int_{\mathbb{R}^{d}}(\mathbf{1}_{A}\circ F)\,J\,d\lambda.

A weight. Let h=g1h=g_{1} be the Gaussian of The Gaussian Kernels on Euclidean Space: Scaling, Derivatives up to Order Three, the Convolution Identity, Moments and Tails in dimension q=dq=d, which is the Gaussian smoothing weight φ1\varphi_{1} of claim 1 of The Gaussian Smoothing Weight: Normalization, Derivatives, Exponential Tilting, Moments, and First-Order Remainder with m=dm=d and η=1\eta=1; by that claim (with a=0Rda=0_{\mathbb{R}^{d}}), 0<h(z)0<h(z) for every zz and hdλ=1\int h\,d\lambda=1. By The Gaussian Kernels on Euclidean Space: Scaling, Derivatives up to Order Three, the Convolution Identity, Moments and Tails §derivatives, hh is smooth, hence continuous by claim 3 of Euclidean Space is Open in Itself, and CkC^k Maps are Continuous; 1/h1/h is continuous by claim 2 of Continuity of the Reciprocal of a Nonvanishing Real-Valued Function on a Metric Space; both are Borel. The function k=(hF)Jk=(h\circ F)J is continuous (Claim 1(b), (c) and claim 5 of Continuity of Sums and Products of Real-Valued Functions on a Metric Space), positive and Borel. Let ν2\nu_{2} and μk\mu_{k} be the measures with densities hh and kk with respect to λ\lambda (claim 3 of Image Measures, Measures with Densities, and Change of Variables), and ν1\nu_{1} the image measure of μk\mu_{k} under the Borel map FF (claim 1 there). By claims 2 and 3 there, for every Borel g:Rd[0,]g:\mathbb{R}^{d}\to[0,\infty],

gdν1=gFdμk=(gF)kdλ,gdν2=ghdλ.()\int g\,d\nu_{1}=\int g\circ F\,d\mu_{k}=\int(g\circ F)\,k\,d\lambda,\qquad\int g\,d\nu_{2}=\int g\,h\,d\lambda .\tag{$*$}

Both are measures on B(Rd)\mathcal{B}(\mathbb{R}^{d}), the Borel σ\sigma-algebra of (Rd,dE)(\mathbb{R}^{d},d_{E}) (Probability Measures on Euclidean Space and Random Vectors: Standing Notation §spaces), and ν2(Rd)=hdλ=1\nu_{2}(\mathbb{R}^{d})=\int h\,d\lambda=1 by (*) and The Integral of an Indicator Function is the Measure of the Set.

(i) Nonnegative continuous integrands. If ψ:RdR\psi:\mathbb{R}^{d}\to\mathbb{R} is continuous, 0ψ0\le\psi, and ψ\psi vanishes outside a compact set SS, then ψh\psi h has the same properties (claim 5 of Continuity of Sums and Products of Real-Valued Functions on a Metric Space), and by (*) and Claim 7 applied to ψh\psi h,

ψdν1=((ψh)F)Jdλ=ψhdλ=ψdν2.\int\psi\,d\nu_{1}=\int\bigl((\psi h)\circ F\bigr)J\,d\lambda=\int\psi h\,d\lambda=\int\psi\,d\nu_{2}.

(ii) ν1\nu_{1} is finite. For mNm\in\mathbb{N} let Am={z:m<z}A_{m}=\{z:m<\lVert z\rVert\}, which is Borel by The Gaussian Kernels on Euclidean Space: Scaling, Derivatives up to Order Three, the Convolution Identity, Moments and Tails §moments (with s=1s=1, R=mR=m), and Em=RdAm={z:zm}E_{m}=\mathbb{R}^{d}\setminus A_{m}=\{z:\lVert z\rVert\le m\}, Borel by Sigma-Algebra and Measurable Space. Let χm\chi_{m} be the cutoff of Scaled Cutoffs and the Second-Moment Test Functions: Uniform Derivative Bounds and Agreement on a Ball §cutoff with q=dq=d and R=mR=m: it is smooth, hence continuous (claim 3 of Euclidean Space is Open in Itself, and CkC^k Maps are Continuous), compactly supported, so it vanishes outside its compact support by claim 1 of Compact Support on Rn\mathbb{R}^n Means Vanishing Outside a Bounded Set; moreover 0χm10\le\chi_{m}\le1 and χm=1\chi_{m}=1 on EmE_{m}, so 1Emχm1\mathbf{1}_{E_{m}}\le\chi_{m}\le1. By The Integral of an Indicator Function is the Measure of the Set, claim 1 of Linearity and Monotonicity of the Lebesgue Integral and (i),

ν1(Em)χmdν1=χmdν2ν2(Rd)=1.\nu_{1}(E_{m})\le\int\chi_{m}\,d\nu_{1}=\int\chi_{m}\,d\nu_{2}\le\nu_{2}(\mathbb{R}^{d})=1 .

The sets EmE_{m} increase with mm, and their union is Rd\mathbb{R}^{d} because every zz has z<m\lVert z\rVert<m for some mm by claim 1 of The Archimedean Property of the Real Numbers. By claim 5 of Basic Properties of a Measure, ν1(Rd)\nu_{1}(\mathbb{R}^{d}) is the least upper bound of the numbers ν1(Em)\nu_{1}(E_{m}), so ν1(Rd)1\nu_{1}(\mathbb{R}^{d})\le1.

(iii) ν1=ν2\nu_{1}=\nu_{2}. Let ψCc(Rd)\psi\in C_{c}^{\infty}(\mathbb{R}^{d}) (Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §test, Test Functions on Euclidean Space, Their Gradient Maps and Laplacians §space). It is smooth, hence continuous, and compactly supported; by claim 2 of Compact Support on Rn\mathbb{R}^n Means Vanishing Outside a Bounded Set there is a positive RR with ψ(x)=0\psi(x)=0 whenever R<xR<\lVert x\rVert, and by claim 1 of A Continuous Compactly Supported Function on Rn\mathbb{R}^n is Bounded and Integrable and Bounded Real-Valued Function on a Set there is a real M0M\ge0 with ψ(x)M|\psi(x)|\le M for all xx. Let χ=χR\chi=\chi_{R} be the cutoff of Scaled Cutoffs and the Second-Moment Test Functions: Uniform Derivative Bounds and Agreement on a Ball §cutoff with q=dq=d, and put ψ1=ψ+Mχ\psi_{1}=\psi+M\chi and ψ2=Mχ\psi_{2}=M\chi, continuous by claim 5 of Continuity of Sums and Products of Real-Valued Functions on a Metric Space. Both are nonnegative: if xR\lVert x\rVert\le R then χ(x)=1\chi(x)=1 and 0ψ(x)+M0\le\psi(x)+M by claim 6 of Properties of the Absolute Value in an Ordered Field, and otherwise ψ(x)=0\psi(x)=0. Both vanish outside the compact support of χ\chi: there χ(x)=0\chi(x)=0 by claim 1 of Compact Support on Rn\mathbb{R}^n Means Vanishing Outside a Bounded Set, so R<xR<\lVert x\rVert (as χ=1\chi=1 on xR\lVert x\rVert\le R) and ψ(x)=0\psi(x)=0. By (i), ψidν1=ψidν2\int\psi_{i}\,d\nu_{1}=\int\psi_{i}\,d\nu_{2} for i=1,2i=1,2, and these integrals are at most 2M2M by (ii), ψi2M\psi_{i}\le2M, claim 1 of Linearity and Monotonicity of the Lebesgue Integral and The Integral of an Indicator Function is the Measure of the Set. So ψ1\psi_{1}, ψ2\psi_{2} are integrable with respect to ν1\nu_{1} and ν2\nu_{2}, their integrals in the sense of Integrable Function and the Lebesgue Integral being the ones above since their negative parts are 00; by claim 2 of Linearity and Monotonicity of the Lebesgue Integral applied to ψ=ψ1ψ2\psi=\psi_{1}-\psi_{2},

ψdν1=ψ1dν1ψ2dν1=ψ1dν2ψ2dν2=ψdν2.\int\psi\,d\nu_{1}=\int\psi_{1}\,d\nu_{1}-\int\psi_{2}\,d\nu_{1}=\int\psi_{1}\,d\nu_{2}-\int\psi_{2}\,d\nu_{2}=\int\psi\,d\nu_{2}.

Since ν1\nu_{1} and ν2\nu_{2} are finite Borel measures on (Rd,dE)(\mathbb{R}^{d},d_{E}), Test Functions Approximate Bounded Continuous Functions Pointwise, Determine a Finite Borel Measure, and Detect a Vanishing Density §determination gives ν1(B)=ν2(B)\nu_{1}(B)=\nu_{2}(B) for every BB(Rd)B\in\mathcal{B}(\mathbb{R}^{d}).

(iv) Conclusion. Let AB(Rd)A\in\mathcal{B}(\mathbb{R}^{d}) and uA=1A(1/h)u_{A}=\mathbf{1}_{A}\cdot(1/h), Borel and nonnegative. Pointwise uAh=1Au_{A}h=\mathbf{1}_{A} and (uAF)k=(1AF)J(u_{A}\circ F)\,k=(\mathbf{1}_{A}\circ F)\,J. By The Integral of an Indicator Function is the Measure of the Set, (*) and (iii),

λ(A)=1Adλ=uAhdλ=uAdν2=uAdν1=(1AF)Jdλ.\lambda(A)=\int\mathbf{1}_{A}\,d\lambda=\int u_{A}h\,d\lambda=\int u_{A}\,d\nu_{2}=\int u_{A}\,d\nu_{1}=\int(\mathbf{1}_{A}\circ F)\,J\,d\lambda .

Step 1 (Proof of claim 2). Let ρ0\rho_{0} be the measure with density JJ (Borel and positive) with respect to λ\lambda, and ρF\rho_{F} its image measure under FF (claims 3 and 1 of Image Measures, Measures with Densities, and Change of Variables). Since 1F1(A)=1AF\mathbf{1}_{F^{-1}(A)}=\mathbf{1}_{A}\circ F, Claim 8 gives ρF(A)=ρ0(F1(A))=(1AF)Jdλ=λ(A)\rho_{F}(A)=\rho_{0}(F^{-1}(A))=\int(\mathbf{1}_{A}\circ F)J\,d\lambda=\lambda(A) for every Borel AA, so ρF=λ\rho_{F}=\lambda. For Borel f:Rd[0,]f:\mathbb{R}^{d}\to[0,\infty], claims 2 and 3 of Image Measures, Measures with Densities, and Change of Variables give

fdλ=fdρF=fFdρ0=(fF)Jdλin [0,].\int f\,d\lambda=\int f\,d\rho_{F}=\int f\circ F\,d\rho_{0}=\int(f\circ F)\,J\,d\lambda\qquad\text{in }[0,\infty].

For Borel f:RdRf:\mathbb{R}^{d}\to\mathbb{R}, the same claims say that ff is integrable with respect to ρF=λ\rho_{F}=\lambda if and only if fFf\circ F is integrable with respect to ρ0\rho_{0}, if and only if (fF)J(f\circ F)J is integrable with respect to λ\lambda, and that then the same chain of equalities holds in R\mathbb{R}.

Step 2 (Proof of claim 3). Let ρ\rho be a density of μ\mu with respect to λ\lambda in the sense of The Radon-Nikodym Theorem for a Finite Measure and a Sigma-Finite Measure, and Uniqueness of Densities: ρ\rho is Borel, 0ρ0\le\rho, and μ(A)=1Aρdλ\mu(A)=\int\mathbf{1}_{A}\rho\,d\lambda for every Borel AA. Since FF is Borel, F#μP(Rd)F_{\#}\mu\in\mathcal{P}(\mathbb{R}^{d}) is defined, with F#μ(B)=μ(F1(B))F_{\#}\mu(B)=\mu(F^{-1}(B)) (Probability Measures on Euclidean Space and Random Vectors: Standing Notation §pushforward); it is a finite measure. The function JF1J\circ F^{-1} is continuous (Claim 1(b), (c)) and positive, so 1/(JF1)1/(J\circ F^{-1}) is continuous by claim 2 of Continuity of the Reciprocal of a Nonvanishing Real-Valued Function on a Metric Space, hence Borel; ρF1\rho\circ F^{-1} is Borel; so ρ~=(ρF1)(1/(JF1))\tilde\rho=(\rho\circ F^{-1})\cdot\bigl(1/(J\circ F^{-1})\bigr) is Borel, and it is nonnegative. Let BB(Rd)B\in\mathcal{B}(\mathbb{R}^{d}). For each xx, F1(F(x))=xF^{-1}(F(x))=x gives ρ~(F(x))J(x)=ρ(x)\tilde\rho(F(x))\,J(x)=\rho(x), so pointwise ((1Bρ~)F)J=1F1(B)ρ\bigl((\mathbf{1}_{B}\tilde\rho)\circ F\bigr)J=\mathbf{1}_{F^{-1}(B)}\,\rho. By Step 1 applied to the Borel function 1Bρ~0\mathbf{1}_{B}\tilde\rho\ge0,

F#μ(B)=μ(F1(B))=1F1(B)ρdλ=((1Bρ~)F)Jdλ=1Bρ~dλ.F_{\#}\mu(B)=\mu(F^{-1}(B))=\int\mathbf{1}_{F^{-1}(B)}\,\rho\,d\lambda=\int\bigl((\mathbf{1}_{B}\tilde\rho)\circ F\bigr)J\,d\lambda=\int\mathbf{1}_{B}\,\tilde\rho\,d\lambda .

Hence ρ~\tilde\rho is a density of F#μF_{\#}\mu with respect to λ\lambda.

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