TheoremBase

Insert the identity on both sides and reassociate: B = I B = (CA)B = C(AB) = C I = C.

Proof

Each result cited is universally quantified over the data in its own statement. The rules of Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes are used with m=n=p=qm=n=p=q.

Assume AB=InAB=I_{n} and CA=InCA=I_{n}. By Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes §identity (with BB, respectively CC, in place of AA), InB=BI_{n}B=B and CIn=CCI_{n}=C; by Algebraic Rules for Matrix Products, Matrix-Vector Products and Transposes §associative (with CC, AA, BB in place of AA, BB, CC), (CA)B=C(AB)(CA)B=C(AB). Hence

B=InB=(CA)B=C(AB)=CIn=C.B=I_{n}B=(CA)B=C(AB)=CI_{n}=C.

Citations

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Dependencies

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