TheoremBase

Weak compactness in the separable Hilbert space V gives the subsequence; if the sequence also converges in H, the weak limit must be that limit by uniqueness of weak limits in H, and the subsequence criterion upgrades this to weak convergence in V of the whole sequence.

Proof

We use Bounded Sequences in a Separable Real Hilbert Space Have Weakly Convergent Subsequences, Elementary Properties of a Hilbert Triple: the Embedding, the Riesz Map and the Form Operator, Elementary Properties of Weak Convergence in a Real Inner Product Space and The Subsequence Criterion for Convergence in a Metric Space.

Claim 1. VV is a real Hilbert space with (V,dV)(V,d_{V}) separable, so Bounded Sequences in a Separable Real Hilbert Space Have Weakly Convergent Subsequences applied in VV gives a subsequence (xnj)j(x_{n_{j}})_{j} of (xm)(x_{m}) and w∈Vw\in V with ∣w∣V≤C|w|_{V}\le C such that xnj⇀wx_{n_{j}}\rightharpoonup w in VV. By Elementary Properties of a Hilbert Triple: the Embedding, the Riesz Map and the Form Operator (ii) the subsequence also converges weakly to ww in HH.

Claim 2. Suppose (xm)(x_{m}) converges to xx in (H,dH)(H,d_{H}). Let (xnj)j(x_{n_{j}})_{j} be any subsequence. By claim 1 applied to this subsequence (which is still bounded by CC in VV), there are a further subsequence (ui)i=(xnji)i(u_{i})_{i}=(x_{n_{j_{i}}})_{i} and w∈Vw\in V with ∣w∣V≤C|w|_{V}\le C such that ui⇀wu_{i}\rightharpoonup w in VV and in HH. Since (ui)(u_{i}) is a subsequence of (xm)(x_{m}) (The Subsequence Criterion for Convergence in a Metric Space (i)), it converges to xx in HH by A Subsequence of a Convergent Sequence Has the Same Limit, hence weakly to xx in HH by Elementary Properties of Weak Convergence in a Real Inner Product Space (ii); by Elementary Properties of Weak Convergence in a Real Inner Product Space (i) in HH, w=xw=x. Applying this to (xm)(x_{m}) itself, the subsequence determined by the identity index sequence nj=jn_{j}=j (strictly increasing by claim 5 of Properties of the Order on the Natural Numbers), shows x=w∈Vx=w\in V and ∣x∣V≤C|x|_{V}\le C.

Finally, (xm)(x_{m}) converges weakly to xx in VV: fix y∈Vy\in V and consider the real sequence (⟨xm,y⟩V)m(\langle x_{m},y\rangle_{V})_{m} in the metric space (R,dR)(\mathbb{R},d_{\mathbb{R}}) of The Absolute Value Metric on the Real Numbers. By what was shown, every subsequence (xnj)(x_{n_{j}}) has a further subsequence (ui)(u_{i}) with ui⇀xu_{i}\rightharpoonup x in VV, so that (⟨ui,y⟩V)i(\langle u_{i},y\rangle_{V})_{i} converges to ⟨x,y⟩V\langle x,y\rangle_{V} (Weak Convergence of a Sequence in a Real Inner Product Space, read in (R,dR)(\mathbb{R},d_{\mathbb{R}}) via claim 1 of Convergence, Limits and the Cauchy Condition for Real Sequences Agree with Those in the Real Line as a Metric Space, which is Complete). Hence every subsequence of (⟨xm,y⟩V)m(\langle x_{m},y\rangle_{V})_{m} has a further subsequence converging to ⟨x,y⟩V\langle x,y\rangle_{V}, and The Subsequence Criterion for Convergence in a Metric Space (ii) gives that (⟨xm,y⟩V)m(\langle x_{m},y\rangle_{V})_{m} converges to ⟨x,y⟩V\langle x,y\rangle_{V}. As yy was arbitrary, xm⇀xx_{m}\rightharpoonup x in VV.

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