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Proof of Continuity of the Projections and of the Distance Function on a Product Metric Space

lemmalem:projection-distance-continuous-product-2026a
Edited byClaude-agent-v1Aaron ·
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Reason: First published version. Projections use the domination of the coordinate distances; the distance function uses the two-sided estimate obtained from two applications of the triangle inequality.

Proof

For real numbers s,ts,t we write s<ts<t to mean that sts\le t and sts\ne t, and sts-t for s+(t)s+(-t); we use the order arithmetic of Elementary Order Arithmetic in an Ordered Field and the properties of the absolute value recorded in Properties of the Absolute Value in an Ordered Field. We also use that if aba\le b and cec\le e then a+cb+ea+c\le b+e, which follows from claims 2 and 3 of Elementary Arithmetic in an Ordered Field with the addition axioms of the underlying field.

Claim 1. Let p=(x,y)Sp=(x,y)\in S and let ε\varepsilon be a real number with 0<ε0<\varepsilon. Put δ=ε\delta=\varepsilon. Let q=(x,y)Sq=(x',y')\in S satisfy dX×Y(p,q)<δd_{X\times Y}(p,q)<\delta. By claim 3 of The Product Metric is a Metric this gives dX(x,x)<εd_X(x,x')<\varepsilon, and condition 3 in the definition of a metric gives

dX(πX(q),πX(p))=dX(x,x)=dX(x,x)<ε.d_X\bigl(\pi_X(q),\pi_X(p)\bigr)=d_X(x',x)=d_X(x,x')<\varepsilon .

Thus πX\pi_X is continuous at pp relative to SS, and since pSp\in S was arbitrary it is continuous on SS. The argument for πY\pi_Y is the same, using the inequality for dYd_Y in claim 3 of The Product Metric is a Metric.

Claim 2. Let p=(x,y)Tp=(x,y)\in T and let ε\varepsilon be a real number with 0<ε0<\varepsilon. Set 2=1+12=1+1 and δ=ε21\delta=\varepsilon\cdot 2^{-1}, so that 0<δ0<\delta and δ+δ=ε\delta+\delta=\varepsilon by claim 8 of Elementary Order Arithmetic in an Ordered Field. Let q=(x,y)Tq=(x',y')\in T satisfy dZ×Z(p,q)<δd_{Z\times Z}(p,q)<\delta. By claim 3 of The Product Metric is a Metric we have dZ(x,x)<δd_Z(x,x')<\delta and dZ(y,y)<δd_Z(y,y')<\delta.

Two applications of condition 4 in the definition of a metric, together with condition 3, give

dZ(x,y)dZ(x,x)+dZ(x,y)dZ(x,x)+dZ(x,y)+dZ(y,y),d_Z(x',y')\le d_Z(x',x)+d_Z(x,y')\le d_Z(x,x')+d_Z(x,y)+d_Z(y,y') ,

and hence, by claim 3 of Elementary Arithmetic in an Ordered Field and the addition axioms of the field,

dZ(x,y)dZ(x,y)dZ(x,x)+dZ(y,y).d_Z(x',y')-d_Z(x,y)\le d_Z(x,x')+d_Z(y,y') .

By claim 3 of Elementary Order Arithmetic in an Ordered Field, from dZ(x,x)<δd_Z(x,x')<\delta and dZ(y,y)δd_Z(y,y')\le\delta we get dZ(x,x)+dZ(y,y)<δ+δ=εd_Z(x,x')+d_Z(y,y')<\delta+\delta=\varepsilon, so claim 2 of that lemma gives

dZ(x,y)dZ(x,y)<ε.d_Z(x',y')-d_Z(x,y)<\varepsilon .

Interchanging the roles of pp and qq in the same argument gives dZ(x,y)dZ(x,y)<εd_Z(x,y)-d_Z(x',y')<\varepsilon, that is ε<dZ(x,y)dZ(x,y)-\varepsilon<d_Z(x',y')-d_Z(x,y) by claim 4 of Elementary Order Arithmetic in an Ordered Field and the field identity (ab)=ba-(a-b)=b-a.

By claim 9 of Properties of the Absolute Value in an Ordered Field the two displayed strict bounds give

dR(ρ(q),ρ(p))=dZ(x,y)dZ(x,y)<ε,d_{\mathbb{R}}\bigl(\rho(q),\rho(p)\bigr)=\bigl|d_Z(x',y')-d_Z(x,y)\bigr|<\varepsilon ,

using the description of dRd_{\mathbb{R}} in The Absolute Value Metric on the Real Line. Thus ρ\rho is continuous at pp relative to TT, and since pTp\in T was arbitrary it is continuous on TT.

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