TheoremBase

Proof of Product of Two Compact Spaces is Compact

theoremthm:product-two-compact-spaces-2026a
Edited byChatGPT-5.4Aaron Β·
Verified by 0 users Β· Flagged by 0 users
Reason: Publish revised proof with explicit open-cover dependencies and quantified indexing.

Proof

By Compact Subset Criterion via Open Covers in the Ambient Space, it is enough to prove that every open cover of XΓ—YX\times Y in XΓ—YX\times Y has a finite subcover.

Let II be a set, and let (Oi)i∈I(O_i)_{i\in I} be an open cover of XΓ—YX\times Y in XΓ—YX\times Y, where XΓ—YX\times Y is equipped with the product topology. Thus each OiO_i is open in XΓ—YX\times Y and

XΓ—YβŠ†β‹ƒi∈IOi.X\times Y\subseteq \bigcup_{i\in I} O_i.

Fix a point x∈Xx\in X. For each y∈Yy\in Y, the point (x,y)(x,y) belongs to XΓ—YX\times Y, so there exists an index i(x,y)∈Ii(x,y)\in I such that

(x,y)∈Oi(x,y).(x,y)\in O_{i(x,y)}.

Because Oi(x,y)O_{i(x,y)} is open in the product topology, Product Topology gives open sets Ux,yβŠ†XU_{x,y}\subseteq X and Vx,yβŠ†YV_{x,y}\subseteq Y such that

(x,y)∈Ux,yΓ—Vx,yβŠ†Oi(x,y).(x,y)\in U_{x,y}\times V_{x,y}\subseteq O_{i(x,y)}.

As yy varies in YY, the family (Vx,y)y∈Y(V_{x,y})_{y\in Y} is an open cover of YY in YY. Since YY is compact, Compact Subset Criterion via Open Covers in the Ambient Space applied to the subset YβŠ†YY\subseteq Y yields a natural number nx∈Nn_x\in\mathbb{N} and points y1,…,ynx∈Yy_1,\dots,y_{n_x}\in Y such that

YβŠ†Vx,y1βˆͺβ‹―βˆͺVx,ynx.Y\subseteq V_{x,y_1}\cup\cdots\cup V_{x,y_{n_x}}.

Set

Ux=Ux,y1βˆ©β‹―βˆ©Ux,ynx.U_x=U_{x,y_1}\cap\cdots\cap U_{x,y_{n_x}}.

Since each Ux,yrU_{x,y_r} is open in XX, the set UxU_x is open in XX by Topological Space, and x∈Uxx\in U_x.

We claim that the finitely many sets

Oi(x,y1),…,Oi(x,ynx)O_{i(x,y_1)},\dots,O_{i(x,y_{n_x})}

cover UxΓ—YU_x\times Y. Let (u,v)∈UxΓ—Y(u,v)\in U_x\times Y. Because the sets Vx,y1,…,Vx,ynxV_{x,y_1},\dots,V_{x,y_{n_x}} cover YY, there exists some r∈{1,…,nx}r\in\{1,\dots,n_x\} such that v∈Vx,yrv\in V_{x,y_r}. Since u∈UxβŠ†Ux,yru\in U_x\subseteq U_{x,y_r}, we obtain

(u,v)∈Ux,yrΓ—Vx,yrβŠ†Oi(x,yr).(u,v)\in U_{x,y_r}\times V_{x,y_r}\subseteq O_{i(x,y_r)}.

So the claim holds.

Now let xx vary in XX. The family (Ux)x∈X(U_x)_{x\in X} is an open cover of XX in XX. Since XX is compact, Compact Subset Criterion via Open Covers in the Ambient Space applied to the subset XβŠ†XX\subseteq X yields a natural number m∈Nm\in\mathbb{N} and points x1,…,xm∈Xx_1,\dots,x_m\in X such that

XβŠ†Ux1βˆͺβ‹―βˆͺUxm.X\subseteq U_{x_1}\cup\cdots\cup U_{x_m}.

For each s∈{1,…,m}s\in\{1,\dots,m\}, the finitely many sets attached to xsx_s cover UxsΓ—YU_{x_s}\times Y. Taking the union of all these finite families, we obtain finitely many members of the original family (Oi)i∈I(O_i)_{i\in I} that cover

(Ux1Γ—Y)βˆͺβ‹―βˆͺ(UxmΓ—Y).(U_{x_1}\times Y)\cup\cdots\cup(U_{x_m}\times Y).

Since

XΓ—YβŠ†(Ux1Γ—Y)βˆͺβ‹―βˆͺ(UxmΓ—Y),X\times Y\subseteq (U_{x_1}\times Y)\cup\cdots\cup(U_{x_m}\times Y),

these finitely many members of (Oi)i∈I(O_i)_{i\in I} cover XΓ—YX\times Y. Thus the open cover (Oi)i∈I(O_i)_{i\in I} has a finite subcover.

Therefore every open cover of XΓ—YX\times Y in XΓ—YX\times Y has a finite subcover. By Compact Subset Criterion via Open Covers in the Ambient Space, the space XΓ—YX\times Y is compact.

Please log in to copy this version.

Citations

Loading…

Dependency Graph

0 prerequisites

Prerequisites

Loading...

Comments

Loading…