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Proof of Lyapunov Representation and Positive Semidefiniteness for Linear Matrix Equations

lemmalem:lyapunov-equation-psd-2026b
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Reason: Re-grounded on the new metric FTC layer: FTC Part I and Part II citations replaced by thm:ftc-part1-closed-interval-2026a and thm:ftc-part2-closed-interval-2026a, with the endpoint continuity now required by Part II supplied explicitly via lem:restriction-continuity-derivative-2026a.

Proof

Preliminaries. We use: entrywise sums and products of continuous real-valued functions are continuous (Continuity of Sums and Products of Real-Valued Functions on a Metric Space); matrix products are rearranged with Associativity of the Matrix Product; the transpose reversal (UV)=VU(UV)^{\top}=V^{\top}U^{\top} and the transpose-dot identity y(Mz)=(My)zy\cdot(Mz)=(M^{\top}y)\cdot z of claim 3 of Componentwise Estimates, Transpose Identities, and Indefinite Riemann Integrals; and the identity x((atU(r)dr)x)=atx(U(r)x)drx\cdot\bigl(\bigl(\int_a^tU(r)\,dr\bigr)x\bigr)=\int_a^t x\cdot(U(r)x)\,dr of claim 6 there.

Claim 1. Uniqueness and existence. Identify k×kk\times k matrices with Rk2\mathbb{R}^{k^{2}} as in the proof conventions of Fundamental Solution and Variation of Constants for Linear Ordinary Differential Equations. The map F(t,X)=A(t)X+XA(t)+C(t)F(t,X)=A(t)X+XA(t)^{\top}+C(t) is composition continuous, and Lipschitz in XX with constant 2k3α2k^{3}\alpha where α\alpha bounds the entries of AA (entry estimates from claims 1 and 2 of Componentwise Estimates, Transpose Identities, and Indefinite Riemann Integrals; the bound on those entries existing because [a,b][a,b] is nonempty, as a<ba<b, and compact by Closed Interval [a,b][a,b] is Compact in R\mathbb{R}, so that Extreme Value Theorem on a Compact Subset of a Metric Space applies to each continuous entry). By Global Existence and Uniqueness for Lipschitz Ordinary Differential Equations in Integral Form there is exactly one continuous solution PP.

Representation. Let Φ,Ψ\Phi,\Psi be as in Fundamental Solution and Variation of Constants for Linear Ordinary Differential Equations and put Y(t)=atΨ(r)C(r)Ψ(r)drY(t)=\int_a^t\Psi(r)C(r)\Psi(r)^{\top}\,dr (entrywise; the integrand has continuous entries). By claim 4 of Componentwise Estimates, Transpose Identities, and Indefinite Riemann Integrals the entries of YY are continuous on all of [a,b][a,b], and by claim 3 of Fundamental Theorem of Calculus, Part I, on a Closed Real Interval, applied entrywise (the integrand has continuous entries), they are differentiable at every point of (a,b)(a,b) with Y=ΨCΨY'=\Psi C\Psi^{\top}. Define P^(t)=Φ(t)(P0+Y(t))Φ(t)\widehat P(t)=\Phi(t)\bigl(P_0+Y(t)\bigr)\Phi(t)^{\top}; its entries are continuous on [a,b][a,b]. On (a,b)(a,b): Φ=AΦ\Phi'=A\Phi, and (Φ)=(Φ)=(AΦ)=ΦA(\Phi^{\top})'=(\Phi')^{\top}=(A\Phi)^{\top}=\Phi^{\top}A^{\top} (transposition commutes with entrywise differentiation, being a relabelling of entries); the product and sum rules (Sum and Product Rules for One-Dimensional Derivatives and Continuity, applied entrywise to the finite sums defining the products) give

P^=AΦ(P0+Y)Φ+ΦΨCΨΦ+Φ(P0+Y)ΦA=AP^+C+P^A,\widehat P'=A\Phi(P_0+Y)\Phi^{\top}+\Phi\,\Psi C\Psi^{\top}\,\Phi^{\top}+\Phi(P_0+Y)\Phi^{\top}A^{\top}=A\widehat P+C+\widehat PA^{\top},

using ΦΨ=Ik\Phi\Psi=I_k (identity matrix) and ΨΦ=(ΦΨ)=Ik\Psi^{\top}\Phi^{\top}=(\Phi\Psi)^{\top}=I_k. The entries of the right side are continuous on [a,b][a,b], hence continuous on [a,t][a,t] for every t(a,b]t\in(a,b] by claim 1 of Restriction Stability of Continuity and of the Derivative and Riemann integrable there by claim 3 of the integral toolkit on a compact interval; each entry of P^\widehat P is continuous on [a,b][a,b] and differentiable at every point of (a,b)(a,b) with derivative the corresponding entry of the right side, and by Restriction Stability of Continuity and of the Derivative these properties pass to the restrictions to [a,t][a,t]. Since P^(a)=P0\widehat P(a)=P_0, Fundamental Theorem of Calculus, Part II, on a Closed Real Interval, applied on [a,t][a,t] for each t(a,b]t\in(a,b] (degenerate t=at=a by the convention of Mean-Square Riemann Integral of a Family of Random Variables), yields the integral equation for P^\widehat P; by the uniqueness just proved, P=P^P=\widehat P.

Claim 2. Suppose P0=P0P_0^{\top}=P_0 and C(t)=C(t)C(t)^{\top}=C(t) for all tt. Transposing the integral equation entrywise (the transpose of an entrywise integral is the entrywise integral of the transpose, a relabelling) and using (AP)=PA(AP)^{\top}=P^{\top}A^{\top} and (PA)=AP(PA^{\top})^{\top}=AP^{\top} (claim 3 of Componentwise Estimates, Transpose Identities, and Indefinite Riemann Integrals) shows that tP(t)t\mapsto P(t)^{\top} satisfies the same integral equation; by uniqueness, P(t)=P(t)P(t)^{\top}=P(t).

Claim 3. Suppose additionally that P0P_0 and every C(t)C(t) are positive semidefinite. Fix tt and xRkx\in\mathbb{R}^{k}, and put w=Φ(t)xw=\Phi(t)^{\top}x. By the transpose-dot identity (twice) and the representation,

x(P(t)x)=w((P0+Y(t))w)=w(P0w)+w(Y(t)w),x\cdot\bigl(P(t)x\bigr)=w\cdot\bigl((P_0+Y(t))w\bigr)=w\cdot(P_0w)+w\cdot\bigl(Y(t)w\bigr),

and by claim 6 of Componentwise Estimates, Transpose Identities, and Indefinite Riemann Integrals and the transpose-dot identity again,

w(Y(t)w)=atw(Ψ(r)C(r)Ψ(r)w)dr=at(Ψ(r)w)(C(r)(Ψ(r)w))dr0,w\cdot\bigl(Y(t)w\bigr)=\int_a^t w\cdot\bigl(\Psi(r)C(r)\Psi(r)^{\top}w\bigr)\,dr=\int_a^t\bigl(\Psi(r)^{\top}w\bigr)\cdot\Bigl(C(r)\bigl(\Psi(r)^{\top}w\bigr)\Bigr)\,dr\ge0,

the integrand being continuous and nonnegative (monotonicity of the integral via claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval and Linearity and Monotonicity of the Lebesgue Integral; degenerate t=at=a by the convention of Mean-Square Riemann Integral of a Family of Random Variables). Also w(P0w)0w\cdot(P_0w)\ge0. Hence x(P(t)x)0x\cdot(P(t)x)\ge0; with the symmetry from claim 2, P(t)P(t) is positive semidefinite. \blacksquare

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