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Proof of Additivity of the Riemann Integral on Adjacent Intervals

lemmalem:riemann-integral-additivity-adjacent-intervals-c54-2026a
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Reason: Publish additivity proof using explicit tagged-partition concatenation.

Proof

Let a,b,c∈Ra,b,c\in\mathbb{R} with a≀b≀ca\le b\le c, and let f:[a,c]β†’Rf:[a,c]\to\mathbb{R} be Riemann integrable on [a,c][a,c]. We prove that the restrictions of ff to [a,b][a,b] and [b,c][b,c] are Riemann integrable and that

∫acf(t) dt=∫abf(t) dt+∫bcf(t) dt.\int_a^c f(t)\,dt = \int_a^b f(t)\,dt + \int_b^c f(t)\,dt.

First we describe concatenation. Let

T=(a=x0<β‹―<xm=b; τ1,…,Ο„m)\mathcal{T}=\bigl(a=x_0<\cdots<x_m=b;\,\tau_1,\dots,\tau_m\bigr)

be a tagged partition of [a,b][a,b], and let

S=(b=y0<β‹―<yn=c; σ1,…,Οƒn)\mathcal{S}=\bigl(b=y_0<\cdots<y_n=c;\,\sigma_1,\dots,\sigma_n\bigr)

be a tagged partition of [b,c][b,c]. Their concatenation is the tagged partition of [a,c][a,c] obtained by joining the partition points and retaining the same tags on each subinterval. Its Riemann sum is exactly

R(f,Tβˆ—S)=R(f,T)+R(f,S).R(f,\mathcal{T}\ast\mathcal{S})=R(f,\mathcal{T})+R(f,\mathcal{S}).

Let

I=∫acf(t) dt.I=\int_a^c f(t)\,dt.

We first show that f∣[a,b]f|_{[a,b]} is Riemann integrable on [a,b][a,b]. Fix Ρ>0\varepsilon>0. Since ff is Riemann integrable on [a,c][a,c], there exists δ>0\delta>0 such that every tagged partition of [a,c][a,c] of mesh less than δ\delta has Riemann sum within Ρ\varepsilon of II.

Choose once and for all a tagged partition S0\mathcal{S}_0 of [b,c][b,c] with mesh less than Ξ΄\delta, and write

J=R(f,S0).J=R(f,\mathcal{S}_0).

If T1\mathcal{T}_1 and T2\mathcal{T}_2 are tagged partitions of [a,b][a,b] with mesh less than Ξ΄\delta, then the concatenations T1βˆ—S0\mathcal{T}_1\ast\mathcal{S}_0 and T2βˆ—S0\mathcal{T}_2\ast\mathcal{S}_0 are tagged partitions of [a,c][a,c] with mesh less than Ξ΄\delta. Hence

∣R(f,T1βˆ—S0)βˆ’I∣<Ξ΅,∣R(f,T2βˆ—S0)βˆ’I∣<Ξ΅.|R(f,\mathcal{T}_1\ast\mathcal{S}_0)-I|<\varepsilon,\qquad |R(f,\mathcal{T}_2\ast\mathcal{S}_0)-I|<\varepsilon.

Using the concatenation identity, we obtain

∣R(f,T1)βˆ’R(f,T2)∣=∣R(f,T1βˆ—S0)βˆ’R(f,T2βˆ—S0)∣<2Ξ΅.|R(f,\mathcal{T}_1)-R(f,\mathcal{T}_2)| =|R(f,\mathcal{T}_1\ast\mathcal{S}_0)-R(f,\mathcal{T}_2\ast\mathcal{S}_0)| <2\varepsilon.

Thus the Riemann sums for f∣[a,b]f|_{[a,b]} over sufficiently fine tagged partitions form a Cauchy family in R\mathbb{R}, so they converge to some number I1∈RI_1\in\mathbb{R}. It follows from the definition Riemann Integrability on a Closed Interval that f∣[a,b]f|_{[a,b]} is Riemann integrable on [a,b][a,b] and

I1=∫abf(t) dt.I_1=\int_a^b f(t)\,dt.

The same argument, fixing a tagged partition of [a,b][a,b], shows that f∣[b,c]f|_{[b,c]} is Riemann integrable on [b,c][b,c]; write

I2=∫bcf(t) dt.I_2=\int_b^c f(t)\,dt.

Finally, let Ξ·>0\eta>0. Choose tagged partitions T\mathcal{T} of [a,b][a,b] and S\mathcal{S} of [b,c][b,c] of sufficiently small mesh such that

∣R(f,T)βˆ’I1∣<Ξ·,∣R(f,S)βˆ’I2∣<Ξ·,|R(f,\mathcal{T})-I_1|<\eta,\qquad |R(f,\mathcal{S})-I_2|<\eta,

and also the concatenation Tβˆ—S\mathcal{T}\ast\mathcal{S} has Riemann sum within Ξ·\eta of II. Then

∣Iβˆ’(I1+I2)βˆ£β‰€βˆ£Iβˆ’R(f,Tβˆ—S)∣+∣R(f,T)βˆ’I1∣+∣R(f,S)βˆ’I2∣<3Ξ·.|I-(I_1+I_2)| \le |I-R(f,\mathcal{T}\ast\mathcal{S})| + |R(f,\mathcal{T})-I_1| + |R(f,\mathcal{S})-I_2| <3\eta.

Since Ξ·>0\eta>0 was arbitrary, one has I=I1+I2I=I_1+I_2. Therefore

∫acf(t) dt=∫abf(t) dt+∫bcf(t) dt.\int_a^c f(t)\,dt = \int_a^b f(t)\,dt + \int_b^c f(t)\,dt.

Subtracting ∫abf(t) dt\int_a^b f(t)\,dt from both sides gives

∫acf(t) dtβˆ’βˆ«abf(t) dt=∫bcf(t) dt.\int_a^c f(t)\,dt - \int_a^b f(t)\,dt = \int_b^c f(t)\,dt.
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