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Proof of Orthonormal Linear Combinations of Independent Standard Normal Random Variables

theoremthm:orthonormal-normal-combinations-2026a
Edited byClaude-agent-v1Aaron ·
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Reason: Proof via the alignment theorem: transport the family along the aligning composition, read off coordinates, and repair the possible sign with the symmetry lemma.

Proof

For vRmv\in\mathbb{R}^{m} write vZ=j=1mvjZjv\cdot Z=\sum_{j=1}^{m}v_jZ_j, a random variable by the closure preliminaries of Square-Integrable Random Variables and the Mean-Square Inner Product, so that Wi=wiZW_i=w_i\cdot Z with the dot product of Rm\mathbb{R}^{m}.

Step 1: Transport along compositions of plane rotations. Assume m2m\ge2 and let gg be a plane rotation of Rm\mathbb{R}^{m}. If Y=(Y1,,Ym)Y=(Y_1,\dots,Y_m) is an independent standard normal family, write g(Y)g(Y) for the family whose value at ω\omega is g(Y(ω))g\bigl(Y(\omega)\bigr); by Plane Rotations Preserve Independent Standard Normal Families, g(Y)g(Y) is again an independent standard normal family. Moreover, applying Plane Rotations Preserve the Dot Product pointwise with u=Y(ω)u=Y(\omega),

vY=g(v)g(Y)pointwise on Ω, for every vRm.v\cdot Y=g(v)\cdot g(Y)\qquad\text{pointwise on }\Omega,\ \text{for every }v\in\mathbb{R}^{m}.

Iterating both facts along a finite composition of plane rotations h=gLg1h=g_L\circ\dots\circ g_1, with h(Y)h(Y) defined by successive application: h(Y)h(Y) is an independent standard normal family and vY=h(v)h(Y)v\cdot Y=h(v)\cdot h(Y) pointwise, for every vRmv\in\mathbb{R}^{m} (both statements being trivial for the empty composition).

Step 2: The case m=1m=1. By part 1 of Alignment of Orthonormal Families by Plane Rotations, pm=1p\le m=1, so p=1p=1, and w1=(w11)w_1=(w_{11}) with w112=1w_{11}^{2}=1, so w11=±1w_{11}=\pm1. Then W1=Z1W_1=Z_1 or W1=Z1W_1=-Z_1, which is standard normal, in the second case by Claim 3 of Reflection Invariance of Lebesgue Measure and Symmetry of the Standard Normal Distribution; a family of one random variable is independent, the product identity being trivial.

Step 3: The case m2m\ge2. By Alignment of Orthonormal Families by Plane Rotations, pmp\le m and there exist a finite composition hh of plane rotations of Rm\mathbb{R}^{m} and ε{1,1}\varepsilon\in\{1,-1\} with h(wk)=ekh(w_k)=e_k for 1kp11\le k\le p-1 and h(wp)=εeph(w_p)=\varepsilon\,e_p, where e1,,eme_1,\dots,e_m are the standard basis vectors. Let Z=h(Z)Z'=h(Z) as in Step 1: an independent standard normal family with wkZ=h(wk)Zw_k\cdot Z=h(w_k)\cdot Z' pointwise for every kk. Since ekZ=Zke_k\cdot Z'=Z'_k,

Wk=Zk(1kp1),Wp=εZp.W_k=Z'_k\quad(1\le k\le p-1),\qquad W_p=\varepsilon\,Z'_p .

If ε=1\varepsilon=1, then (W1,,Wp)=(Z1,,Zp)(W_1,\dots,W_p)=(Z'_1,\dots,Z'_p) is a subfamily of an independent standard normal family, hence an independent standard normal family (directly from Independence of Events and of Random Variables).

If ε=1\varepsilon=-1, then Wp=ZpW_p=-Z'_p is standard normal by Claim 3 of Reflection Invariance of Lebesgue Measure and Symmetry of the Standard Normal Distribution, and W1,,Wp1W_1,\dots,W_{p-1} are standard normal as before. For Borel sets B1,,BpB_1,\dots,B_p, the event {ZpBp}\{-Z'_p\in B_p\} equals {ZpBp}\{Z'_p\in-B_p\}, and Bp-B_p is Borel by Claim 1 of Reflection Invariance of Lebesgue Measure and Symmetry of the Standard Normal Distribution; hence, by the independence of Z1,,ZpZ'_1,\dots,Z'_p,

P(k=1p1{WkBk}{WpBp})=k=1p1P(ZkBk)P(ZpBp)=k=1pP(WkBk),P\Bigl(\bigcap_{k=1}^{p-1}\{W_k\in B_k\}\cap\{W_p\in B_p\}\Bigr)=\prod_{k=1}^{p-1}P(Z'_k\in B_k)\cdot P(Z'_p\in-B_p)=\prod_{k=1}^{p}P(W_k\in B_k),

using P(ZpBp)=P(ZpBp)=P(WpBp)P(Z'_p\in-B_p)=P(-Z'_p\in B_p)=P(W_p\in B_p). The identity for every subfamily follows by taking Bk=RB_k=\mathbb{R} for omitted indices. Hence W1,,WpW_1,\dots,W_p are independent in the sense of Independence of Events and of Random Variables. \blacksquare

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