Each result cited is universally quantified over the data in its own statement. Write ι for the canonical map of The Canonical Map from the Natural Numbers to a Field, πl:Rq→R, πl(x)=xl, for the coordinate functions, and W2={y∈Rq:∥y∥>2}. Continuity of a function on Rq is that of Differential Calculus and Convexity on Euclidean Open Sets: Standing Notation §extrema; by claim 1 of Euclidean Continuity Agrees with Metric Continuity for Real-Valued Functions it agrees with continuity at every point in the sense of Continuity at a Point for Maps Between Euclidean Spaces, which is the notion used in C^k Maps on a Euclidean Open Set. A function of class Ck+1 is of class C1 and its partial derivatives are of class Ck, by clause 2 of C^k Maps on a Euclidean Open Set; a smooth function is of class Ck for every k (Smooth Map on a Euclidean Open Set), so its partial derivatives are smooth as well. A function of class C1 is continuous with continuous partial derivatives, by clause 1 of C^k Maps on a Euclidean Open Set.
For points y,y′∈Rq we use y=y′+(y−y′) and ∥y−y′∥=∥y′−y∥ (claims 2 and 3 of Euclidean Space Rn is a Real Vector Space, and claim 5 of Elementary Properties of the Euclidean Norm on Rn with λ=−1), together with dE(y,y′)=∥y−y′∥ (claim 2 of Elementary Properties of the Euclidean Norm on Rn).
Step 0: the derivatives of χ are bounded and vanish on W2. The set W2 is open: if y∈W2 and ∥y′−y∥<∥y∥−2, then ∥y∥≤∥y′∥+∥y−y′∥ by claim 6 of Elementary Properties of the Euclidean Norm on Rn applied to y=y′+(y−y′), so ∥y′∥>2; this says that the open ball of centre y and radius ∥y∥−2 lies in W2, so W2 is open in the metric sense, hence open by Euclidean Openness Agrees with Metric Openness on Rn. Let u:Rq→R be of class C1 with u=0 on W2 and let l∈[q]. Then u∣W2=0⋅u∣W2 is of class C1 on W2 by claim 3 of Restriction of a Ck Map to an Open Subset, so by the scalar-multiple rule of claim 1 of Constants, Coordinate Functions, Sums and Products of Ck Functions on a Euclidean Open Set, ∂l(u∣W2)=0⋅∂l(u∣W2)=0 on W2, and by claim 1 of Restriction of a Ck Map to an Open Subset, ∂lu=0 on W2. Applying this to u=χ and then to u=∂iχ (which is smooth, hence of class C1, and vanishes on W2 by the first application), we get ∂iχ=0 and ∂j∂iχ=0 on W2 for all i,j∈[q]. These functions are continuous on Rq (as χ is of class C2) and vanish whenever ∥y∥>2, so they are compactly supported by claim 2 of Compact Support on Rn Means Vanishing Outside a Bounded Set and bounded by claim 1 of A Continuous Compactly Supported Function on Rn is Bounded and Integrable. For i,j∈[q] choose bounds Bi and Bji, nonnegative real numbers by that definition, with ∣∂iχ(y)∣≤Bi and ∣∂j∂iχ(y)∣≤Bji for every y, and put
M1=i=1∑qBi,M2=i=1∑q(j=1∑qBji),
finite sums of nonnegative real numbers. By claim 6 of Properties of Finite Sums (each summand of a sum of nonnegative terms is at most the sum, applied once for M1 and twice for M2), Bi≤M1 and Bji≤M2 for all i,j, and M1,M2≥0 by claim 5 there.
Step 1: claim 1. Fix R>0; R−1>0 by claim 7 of Elementary Order Arithmetic in an Ordered Field, so ∣R−1∣=R−1 by Absolute Value in an Ordered Field, and claim 5 of Elementary Properties of the Euclidean Norm on Rn gives ∥R−1x∥=R−1∥x∥ for every x. Multiplying by R−1, respectively by R, using claim 5 of Elementary Arithmetic in an Ordered Field for the weak inequalities and claim 10 of Elementary Order Arithmetic in an Ordered Field for the strict one, together with RR−1=1, we get for every x:
∥x∥≤R⟺∥R−1x∥≤1,∥x∥≥2R⟺∥R−1x∥≥2,∥x∥>2R⟺∥R−1x∥>2.
Consequently 0≤χR≤1, χR(x)=1 whenever ∥x∥≤R, χR(x)=0 whenever ∥x∥≥2R, and χR is compactly supported by claim 2 of Compact Support on Rn Means Vanishing Outside a Bounded Set.
Apply Partial Derivatives, Continuity and Ck Regularity under a Scaling Substitution with n=q, m=1, c=0Rq, λ=R−1, μ=1, U=Rq (open by claim 1 of Euclidean Space is Open in Itself, and Ck Maps are Continuous) and f=χ: since 0Rq+R−1x=R−1x (claim 1 of Euclidean Space Rn is a Real Vector Space), the function g there is χR and V=Rq. By claim 5 there χR is smooth, and by claim 2 there, for every x and i∈[q],
∂iχR(x)=R−1∂iχ(R−1x).
Apply the same lemma with the same c,λ,μ,U to f=∂iχ (smooth): the function gi(x)=∂iχ(R−1x) has, by claim 2 there, ∂jgi(x)=R−1∂j∂iχ(R−1x) for every x and j∈[q]. Since ∂iχR=R−1gi on Rq, the scalar-multiple rule of claim 1 of Constants, Coordinate Functions, Sums and Products of Ck Functions on a Euclidean Open Set gives
∂j∂iχR(x)=R−1∂jgi(x)=R−2∂j∂iχ(R−1x),
where R−2=R−1R−1. By Step 0 and claim 4 of Properties of the Absolute Value in an Ordered Field, ∣∂iχR(x)∣≤R−1Bi≤M1R−1 and ∣∂j∂iχR(x)∣≤R−2Bji≤M2R−2 (claim 5 of Elementary Arithmetic in an Ordered Field). This proves claim 1. We record for Step 3 that if ∥x∥>2R then R−1x∈W2, so by Step 0
χR(x)=0,∂iχR(x)=0,∂j∂iχR(x)=0(∥x∥>2R).
Step 2: the function s(x)=21∥x∥2. By claim 2 of Elementary Properties of the Euclidean Norm on Rn, s(x)=21dE(x,0Rq)2, so A Scaled Squared Distance to a Point is of Class C2, with Gradient and Hessian applies with n=q, U=Rq, a=0Rq, c=21 and its function q taken to be s: by its claim 1, ∂js(x)=2⋅21(xj−0)=xj, that is ∂js=πj; by its claim 2, s is of class C2; and by its claim 3, D2s(x)=(2⋅21)Iq=Iq (the matrix scalar multiple being that of Differential Calculus and Convexity on Euclidean Open Sets: Standing Notation §background), so by Hessian Matrix of a C^2 Function, ∂j∂is(x)=(Iq)ji=δji for all i,j∈[q] and all x. Moreover s is smooth: x↦∥x∥2 is smooth by The Squared Euclidean Norm is Smooth, and s is its scalar multiple by 21, smooth by claim 3 of Constants, Coordinate Functions, Sums and Products of Ck Functions on a Euclidean Open Set.
Step 3: claim 2. Fix R>0. As ψR=χRs is a product of smooth functions, it is smooth by claim 3 of Constants, Coordinate Functions, Sums and Products of Ck Functions on a Euclidean Open Set; it vanishes wherever χR does, hence whenever ∥x∥≥2R, so it is compactly supported by claim 2 of Compact Support on Rn Means Vanishing Outside a Bounded Set. By the product rule of claim 1 of Constants, Coordinate Functions, Sums and Products of Ck Functions on a Euclidean Open Set and Step 2, for all x and i,j∈[q],
∂iψR(x)=∂iχR(x)s(x)+χR(x)xi,
and, applying the sum and product rules of the same claim to this expression (whose two summands are products of functions of class C1), with ∂jπi=∂j∂is=δji by Step 2,
∂j∂iψR(x)=∂j∂iχR(x)s(x)+∂iχR(x)xj+∂jχR(x)xi+χR(x)δji.
Put M=2M2+4M1+1, which does not depend on R; since M1,M2≥0 (Step 0) and 0≤1 (claim 1 of Elementary Arithmetic in an Ordered Field), claim 2 there gives 0≤M and M1+1≤M, and 0≤∥x∥ for every x by claim 1 of Elementary Properties of the Euclidean Norm on Rn. Fix x and i,j. If ∥x∥>2R, all terms on the right of both displays vanish by Step 1, so ∂iψR(x)=0 and ∂j∂iψR(x)=0, and the two bounds hold because their right sides are nonnegative (0≤M∥x∥ by claim 5 of Elementary Arithmetic in an Ordered Field). If ∥x∥≤2R, then s(x)=21∥x∥∥x∥≤212R∥x∥=R∥x∥ and s(x)≤21(2R)2=2R2 (claim 5 of Elementary Arithmetic in an Ordered Field and claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field), ∣xi∣,∣xj∣≤∥x∥≤2R by claim 4 of Elementary Properties of the Euclidean Norm on Rn, and ∣χR(x)∣≤1. Using claim 1, the multiplicativity and the triangle inequality of the absolute value (claims 4 and 5 of Properties of the Absolute Value in an Ordered Field) and claim 5 of Elementary Arithmetic in an Ordered Field,
∣∂iψR(x)∣≤M1R−1⋅R∥x∥+∥x∥=(M1+1)∥x∥≤M∥x∥,
∣∂j∂iψR(x)∣≤M2R−2⋅2R2+M1R−1⋅2R+M1R−1⋅2R+1=2M2+4M1+1=M.
Finally, ΔψR(x)=∑i=1q∂i∂iψR(x) satisfies ∣ΔψR(x)∣≤∑i=1q∣∂i∂iψR(x)∣ by claim 2 of Comparison and Absolute Value Bounds for Finite Sums of Real Numbers, and ∑i=1q∣∂i∂iψR(x)∣≤∑i=1qM by claim 1 of the same lemma; and ∑i=1qM=Mι(q)=qM by claim 3 of Properties of Finite Sums and The Canonical Map from the Natural Numbers to a Field. This proves claim 2.
Step 4: claim 3. Fix R>0 and let B={y∈Rq:∥y∥<R}. The set B is open: if y∈B and ∥y′−y∥<R−∥y∥, then ∥y′∥≤∥y∥+∥y′−y∥<R by claim 6 of Elementary Properties of the Euclidean Norm on Rn applied to y′=y+(y′−y), so the argument of Step 0 applies. By Step 1, χR(y)=1 for every y∈B, so ψR(y)=s(y) for every y∈B; that is, ψR∣B=s∣B. Let x∈B and i,j∈[q]. By claim 1 of Restriction of a Ck Map to an Open Subset applied to ψR and to s (both of class C1 on Rq),
∂iψR(x)=∂i(ψR∣B)(x)=∂i(s∣B)(x)=∂is(x)=xi,
the last equality by Step 2. Since this holds at every point of B, the functions ∂iψR and ∂is (both of class C1 on Rq, as ψR and s are of class C2) have the same restriction to B, and the same claim 1 gives ∂j∂iψR(x)=∂j∂is(x)=δji=δij. Hence ΔψR(x)=∑i=1qδii=∑i=1q1=ι(q)=q by The Canonical Map from the Natural Numbers to a Field, and ψR(x)=s(x)=21∥x∥2. This proves claim 3.