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Proof of Mean-Square Stability of the Optimal Map of a Uniquely Mapped Pair Along Couplings of Nearly Optimal Cost

theoremthm:optimal-map-stability-euclidean-2026a
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· 8,363 chars · 29 deps · depth 27 Reason: Phase B2b: proof by contradiction through tightness and Prokhorov, identifying the weak limit as the coupling induced by the map, then replacing the map by a nearby bounded Lipschitz field and truncating at a height set by the tail of the second moment of the second marginal.

If the conclusion failed, a subsequence bounded away from zero would, by tightness and Prokhorov, converge weakly to a coupling of optimal cost, hence to the coupling induced by the map; replacing the map by a nearby bounded Lipschitz field and truncating the resulting continuous integrand at a height controlled by the tail of the second moment of the second marginal then forces the subsequence to zero.

Proof

Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. Let ι\iota be the canonical map from N\mathbb{N} to R\mathbb{R}, positive by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. For a Borel map S:RdRdS:\mathbb{R}^{d}\to\mathbb{R}^{d} write

DS(z)=S(pr1(z))pr2(z)2(zRd+d),D_{S}(z)=\bigl\lVert S(\mathrm{pr}_{1}(z))-\mathrm{pr}_{2}(z)\bigr\rVert^{2}\qquad(z\in\mathbb{R}^{d+d}),

Borel and nonnegative by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, in agreement with the notation DTD_{T} of the statement. For every πΠ(μ,ν)\pi'\in\Pi(\mu,\nu) the change-of-variables formula, with (pr1)#π=μ(\mathrm{pr}_{1})_{\#}\pi'=\mu and (pr2)#π=ν(\mathrm{pr}_{2})_{\#}\pi'=\nu, gives

Rd+dS(pr1(z))T(pr1(z))2π(dz)=RdST2dμ,Rd+dpr2(z)2π(dz)=M2(ν).()\int_{\mathbb{R}^{d+d}}\lVert S(\mathrm{pr}_{1}(z))-T(\mathrm{pr}_{1}(z))\rVert^{2}\,\pi'(dz)=\int_{\mathbb{R}^{d}}\lVert S-T\rVert^{2}\,d\mu,\qquad \int_{\mathbb{R}^{d+d}}\lVert\mathrm{pr}_{2}(z)\rVert^{2}\,\pi'(dz)=M_{2}(\nu). \tag{$*$}

Step 1 (Comparison of two maps). Let S:RdRdS:\mathbb{R}^{d}\to\mathbb{R}^{d} be Borel with S2dμ<\int\lVert S\rVert^{2}\,d\mu<\infty and let πΠ(μ,ν)\pi'\in\Pi(\mu,\nu). Writing a=T(pr1(z))a=T(\mathrm{pr}_{1}(z)), b=S(pr1(z))b=S(\mathrm{pr}_{1}(z)) and c=pr2(z)c=\mathrm{pr}_{2}(z), the inequality xy22x2+2y2\lVert x-y\rVert^{2}\le2\lVert x\rVert^{2}+2\lVert y\rVert^{2} of Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, applied to x=abx=a-b and y=cby=c-b, gives DT(z)2ab2+2DS(z)D_{T}(z)\le2\lVert a-b\rVert^{2}+2D_{S}(z) pointwise. Integrating against π\pi' and using claim 1 of Linearity and Monotonicity of the Lebesgue Integral and ()(*),

Rd+dDTdπ2RdTS2dμ+2Rd+dDSdπ.()\int_{\mathbb{R}^{d+d}}D_{T}\,d\pi'\le2\int_{\mathbb{R}^{d}}\lVert T-S\rVert^{2}\,d\mu+2\int_{\mathbb{R}^{d+d}}D_{S}\,d\pi' . \tag{$**$}

Step 2 (A uniform tail bound). For jNj\in\mathbb{N} put Rj=ι(j)R_{j}=\iota(j) and hj(y)=y2h_{j}(y)=\lVert y\rVert^{2} if Rj<y2R_{j}<\lVert y\rVert^{2} and hj(y)=0h_{j}(y)=0 otherwise; each hjh_{j} is Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, satisfies 0hj20\le h_{j}\le\lVert\cdot\rVert^{2}, and converges pointwise to 00, since for fixed yy claim 1 of The Archimedean Property of the Real Numbers gives jj with y2<ι(j)\lVert y\rVert^{2}<\iota(j) and claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field makes hj(y)=0h_{j'}(y)=0 for every jjj'\ge j. As 2\lVert\cdot\rVert^{2} is integrable with respect to ν\nu, claim 7 of The Lebesgue Integral and Null Sets: Almost-Everywhere Comparison, Markov's Inequality, and Dominated Convergence Almost Everywhere gives that (Rdhjdν)jN\bigl(\int_{\mathbb{R}^{d}}h_{j}\,d\nu\bigr)_{j\in\mathbb{N}} converges to 00.

Step 3 (The limit of a weakly convergent subsequence is the coupling induced by TT). Let (σk)kN(\sigma_{k})_{k\in\mathbb{N}} be a sequence in Π(μ,ν)\Pi(\mu,\nu) with (I(σk))k(I(\sigma_{k}))_{k} converging to W2(μ,ν)2W_{2}(\mu,\nu)^{2}. By Tightness from Bounded Second Moments, and Tightness of the Couplings of Two Measures with Finite Second Moment §couplings the set Π(μ,ν)\Pi(\mu,\nu) is a tight family, so Prokhorov's Theorem on Euclidean Space: a Tight Sequence of Probability Measures Has a Weakly Convergent Subsequence provides a subsequence (σkj)j(\sigma_{k_{j}})_{j} converging weakly to some πP(Rd+d)\pi\in\mathcal{P}(\mathbb{R}^{d+d}), and πΠ(μ,ν)\pi\in\Pi(\mu,\nu) by The Couplings of Two Probability Measures on Euclidean Space are Closed under Weak Convergence.

Let η\eta be a positive real number. Since (I(σkj))j(I(\sigma_{k_{j}}))_{j} converges to W2(μ,ν)2W_{2}(\mu,\nu)^{2} by A Subsequence of a Convergent Sequence Has the Same Limit, there is j0j_{0} with I(σkj)W2(μ,ν)2+ηI(\sigma_{k_{j}})\le W_{2}(\mu,\nu)^{2}+\eta for every jj0j\ge j_{0}. The sequence (σkj)jj0(\sigma_{k_{j}})_{j\ge j_{0}} still converges weakly to π\pi, so Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit §limit gives I(π)W2(μ,ν)2+ηI(\pi)\le W_{2}(\mu,\nu)^{2}+\eta. As η\eta was arbitrary, Comparison of Real Numbers with Arbitrary Positive Slack §slack-above gives I(π)W2(μ,ν)2I(\pi)\le W_{2}(\mu,\nu)^{2}; the reverse inequality holds because W2(μ,ν)2W_{2}(\mu,\nu)^{2} is the greatest lower bound of the costs of couplings of μ\mu and ν\nu, by The Quadratic Wasserstein Distance on Euclidean Space §distance. Hence I(π)=W2(μ,ν)2I(\pi)=W_{2}(\mu,\nu)^{2} and π\pi is optimal, so π=(id,T)#μ\pi=(\mathrm{id},T)_{\#}\mu by unique mapping.

Step 4 (The subsequence has vanishing discrepancy). Keep the notation of Step 3 and let η\eta be a positive real number. By The Bounded Lipschitz Vector Fields are Dense in the Square-Integrable Vector Fields Against a Probability Measure §dense there is a bounded Lipschitz S:RdRdS:\mathbb{R}^{d}\to\mathbb{R}^{d}, say with SMS\lVert S\rVert\le M_{S}, such that RdTS2dμη\int_{\mathbb{R}^{d}}\lVert T-S\rVert^{2}\,d\mu\le\eta.

The function DSD_{S} is continuous: SS is continuous by A Lipschitz Map is Uniformly Continuous, the projections are continuous by claim 1 of Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit, and DSD_{S} is obtained from them by composition and by the continuous map vv2v\mapsto\lVert v\rVert^{2}, continuous by claim 3 of Euclidean Space is Open in Itself, and CkC^k Maps are Continuous; claim 3 of Semicontinuity and Continuity Under Composition with a Continuous Map gives the composition. Moreover

DS(z)2MS2+2pr2(z)2D_{S}(z)\le2M_{S}^{2}+2\lVert\mathrm{pr}_{2}(z)\rVert^{2}

pointwise, by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions.

By Step 2 choose j1Nj_{1}\in\mathbb{N} with Rdhj1dνη\int_{\mathbb{R}^{d}}h_{j_{1}}\,d\nu\le\eta and with 2MS2Rj12M_{S}^{2}\le R_{j_{1}}; the order of choice is η\eta, then SS and MSM_{S}, then j1j_{1}. Put R=Rj1R=R_{j_{1}} and K=4RK=4R, and let g=min(DS,K)g=\min(D_{S},K), which is continuous by claim 4 of Continuity of the Absolute Value, Maximum and Minimum of Real-Valued Functions on a Metric Space and satisfies 0gK0\le g\le K, hence is bounded.

Let πΠ(μ,ν)\pi'\in\Pi(\mu,\nu) and let E={z:K<DS(z)}E=\{z:K<D_{S}(z)\}, a Borel set. For zEz\in E one has 4R<DS(z)2MS2+2pr2(z)2R+2pr2(z)24R<D_{S}(z)\le2M_{S}^{2}+2\lVert\mathrm{pr}_{2}(z)\rVert^{2}\le R+2\lVert\mathrm{pr}_{2}(z)\rVert^{2}, so R<pr2(z)2R<\lVert\mathrm{pr}_{2}(z)\rVert^{2} and therefore 2MS2Rpr2(z)22M_{S}^{2}\le R\le\lVert\mathrm{pr}_{2}(z)\rVert^{2}, whence DS(z)3pr2(z)2=3hj1(pr2(z))D_{S}(z)\le3\lVert\mathrm{pr}_{2}(z)\rVert^{2}=3h_{j_{1}}(\mathrm{pr}_{2}(z)). Since DS=gD_{S}=g off EE and DS3hj1pr2D_{S}\le3\,h_{j_{1}}\circ\mathrm{pr}_{2} on EE, claim 1 of Linearity and Monotonicity of the Lebesgue Integral, together with the change-of-variables formula and (pr2)#π=ν(\mathrm{pr}_{2})_{\#}\pi'=\nu, gives

Rd+dDSdπRd+dgdπ+3Rdhj1dνRd+dgdπ+3η.()\int_{\mathbb{R}^{d+d}}D_{S}\,d\pi'\le\int_{\mathbb{R}^{d+d}}g\,d\pi'+3\int_{\mathbb{R}^{d}}h_{j_{1}}\,d\nu\le\int_{\mathbb{R}^{d+d}}g\,d\pi'+3\eta . \tag{$\dagger$}

Using π=(id,T)#μ\pi=(\mathrm{id},T)_{\#}\mu together with gDSg\le D_{S}, claim 1 of Linearity and Monotonicity of the Lebesgue Integral and the change-of-variables formula,

Rd+dgdπRd+dDSdπ=RdST2dμη.\int_{\mathbb{R}^{d+d}}g\,d\pi\le\int_{\mathbb{R}^{d+d}}D_{S}\,d\pi=\int_{\mathbb{R}^{d}}\lVert S-T\rVert^{2}\,d\mu\le\eta .

Since gg is bounded and continuous and (σkj)j(\sigma_{k_{j}})_{j} converges weakly to π\pi, the sequence (gdσkj)j\bigl(\int g\,d\sigma_{k_{j}}\bigr)_{j} converges to gdπη\int g\,d\pi\le\eta, so there is j2j_{2} with gdσkj2η\int g\,d\sigma_{k_{j}}\le2\eta for every jj2j\ge j_{2}. Combining this with ()(\dagger) applied to σkj\sigma_{k_{j}} and then with ()(**),

Rd+dDTdσkj2η+2(2η+3η)=12ηfor every jj2.\int_{\mathbb{R}^{d+d}}D_{T}\,d\sigma_{k_{j}}\le2\eta+2\bigl(2\eta+3\eta\bigr)=12\eta\qquad\text{for every }j\ge j_{2}.

Step 5 (Claim 1). Suppose the sequence (DTdπn)nN\bigl(\int D_{T}\,d\pi_{n}\bigr)_{n\in\mathbb{N}} does not converge to 00. Its terms are nonnegative, so there are a positive real ε\varepsilon and a subsequence (πnk)kN(\pi_{n_{k}})_{k\in\mathbb{N}} with εDTdπnk\varepsilon\le\int D_{T}\,d\pi_{n_{k}} for every kk. By A Subsequence of a Convergent Sequence Has the Same Limit the costs I(πnk)I(\pi_{n_{k}}) converge to W2(μ,ν)2W_{2}(\mu,\nu)^{2}, so Steps 3 and 4 apply to σk=πnk\sigma_{k}=\pi_{n_{k}} and yield, for every positive real η\eta, a further subsequence along which DTdσkj12η\int D_{T}\,d\sigma_{k_{j}}\le12\eta eventually. Taking η=ε24\eta=\tfrac{\varepsilon}{24} produces an index jj with DTdπnkjε2<ε\int D_{T}\,d\pi_{n_{k_{j}}}\le\tfrac{\varepsilon}{2}<\varepsilon, contradicting the choice of the subsequence. Hence (DTdπn)n\bigl(\int D_{T}\,d\pi_{n}\bigr)_{n} converges to 00, which is claim 1.

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