Proof of Mean-Square Stability of the Optimal Map of a Uniquely Mapped Pair Along Couplings of Nearly Optimal Cost
theoremthm:optimal-map-stability-euclidean-2026aIf the conclusion failed, a subsequence bounded away from zero would, by tightness and Prokhorov, converge weakly to a coupling of optimal cost, hence to the coupling induced by the map; replacing the map by a nearby bounded Lipschitz field and truncating the resulting continuous integrand at a height controlled by the tail of the second moment of the second marginal then forces the subsequence to zero.
Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. Let be the canonical map from to , positive by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field. For a Borel map write
Borel and nonnegative by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, in agreement with the notation of the statement. For every the change-of-variables formula, with and , gives
Step 1 (Comparison of two maps). Let be Borel with and let . Writing , and , the inequality of Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, applied to and , gives pointwise. Integrating against and using claim 1 of Linearity and Monotonicity of the Lebesgue Integral and ,
Step 2 (A uniform tail bound). For put and if and otherwise; each is Borel by Pairs of Euclidean Points: Coordinate Projections, Pairings, the Product Measure on a Euclidean Space, Borel Norm Functions and Finite Sets §functions, satisfies , and converges pointwise to , since for fixed claim 1 of The Archimedean Property of the Real Numbers gives with and claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field makes for every . As is integrable with respect to , claim 7 of The Lebesgue Integral and Null Sets: Almost-Everywhere Comparison, Markov's Inequality, and Dominated Convergence Almost Everywhere gives that converges to .
Step 3 (The limit of a weakly convergent subsequence is the coupling induced by ). Let be a sequence in with converging to . By Tightness from Bounded Second Moments, and Tightness of the Couplings of Two Measures with Finite Second Moment §couplings the set is a tight family, so Prokhorov's Theorem on Euclidean Space: a Tight Sequence of Probability Measures Has a Weakly Convergent Subsequence provides a subsequence converging weakly to some , and by The Couplings of Two Probability Measures on Euclidean Space are Closed under Weak Convergence.
Let be a positive real number. Since converges to by A Subsequence of a Convergent Sequence Has the Same Limit, there is with for every . The sequence still converges weakly to , so Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit §limit gives . As was arbitrary, Comparison of Real Numbers with Arbitrary Positive Slack §slack-above gives ; the reverse inequality holds because is the greatest lower bound of the costs of couplings of and , by The Quadratic Wasserstein Distance on Euclidean Space §distance. Hence and is optimal, so by unique mapping.
Step 4 (The subsequence has vanishing discrepancy). Keep the notation of Step 3 and let be a positive real number. By The Bounded Lipschitz Vector Fields are Dense in the Square-Integrable Vector Fields Against a Probability Measure §dense there is a bounded Lipschitz , say with , such that .
The function is continuous: is continuous by A Lipschitz Map is Uniformly Continuous, the projections are continuous by claim 1 of Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit, and is obtained from them by composition and by the continuous map , continuous by claim 3 of Euclidean Space is Open in Itself, and Maps are Continuous; claim 3 of Semicontinuity and Continuity Under Composition with a Continuous Map gives the composition. Moreover
By Step 2 choose with and with ; the order of choice is , then and , then . Put and , and let , which is continuous by claim 4 of Continuity of the Absolute Value, Maximum and Minimum of Real-Valued Functions on a Metric Space and satisfies , hence is bounded.
Let and let , a Borel set. For one has , so and therefore , whence . Since off and on , claim 1 of Linearity and Monotonicity of the Lebesgue Integral, together with the change-of-variables formula and , gives
Using together with , claim 1 of Linearity and Monotonicity of the Lebesgue Integral and the change-of-variables formula,
Since is bounded and continuous and converges weakly to , the sequence converges to , so there is with for every . Combining this with applied to and then with ,
Step 5 (Claim 1). Suppose the sequence does not converge to . Its terms are nonnegative, so there are a positive real and a subsequence with for every . By A Subsequence of a Convergent Sequence Has the Same Limit the costs converge to , so Steps 3 and 4 apply to and yield, for every positive real , a further subsequence along which eventually. Taking produces an index with , contradicting the choice of the subsequence. Hence converges to , which is claim 1.
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Prerequisites
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