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Proof of The Viscous Hamilton-Jacobi Operator with a Drift that is One-Sided Lipschitz on Sublevel Sets Satisfies the Operator Hypotheses of the Weighted-Penalty Comparison Principle

lemmalem:quadratic-operator-weighted-penalty-euclidean-2026a
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· 9,029 chars · 27 deps · depth 24 Reason: Phase F: proof that the quadratic operator meets the comparison hypotheses.

Continuity is checked term by term; strict properness and convexity follow from monotonicity and linearity of the trace and the convex-combination identity for the squared norm; on each sublevel set the structure condition is the sum of those for the drift and for the remaining terms, given by two published examples.

Proof

Each result cited is universally quantified over the data in its own statement. The order and arithmetic of R\mathbb{R} are those of the ordered field of real numbers; multiplying an inequality by a nonnegative real preserves it (claim 5 of Elementary Arithmetic in an Ordered Field), and 0<2−10<2^{-1} by claims 8 and 7 of Elementary Order Arithmetic in an Ordered Field, so θ2\tfrac{\theta}{2} and κ2\tfrac{\kappa}{2} are nonnegative. Write

G0(r,p,X)=λr+θ2∥p∥2−κ2tr⁡(X),so thatF(x,r,p,X)=G0(r,p,X)+b(x)⋅p−G(x).G_{0}(r,p,X)=\lambda r+\tfrac{\theta}{2}\lVert p\rVert^{2}-\tfrac{\kappa}{2}\operatorname{tr}(X),\qquad\text{so that}\qquad F(x,r,p,X)=G_{0}(r,p,X)+b(x)\cdot p-G(x).

Hypothesis Comparison Principle with a Weighted Penalty for Operators Convex in the Value, Gradient and Matrix Variables §strictly-proper with γ=λ\gamma=\lambda. If X⪯YX\preceq Y in S(n)\mathcal{S}(n), then tr⁡(X)≤tr⁡(Y)\operatorname{tr}(X)\le\operatorname{tr}(Y) by The Trace as a Sum of Quadratic Forms, its Monotonicity and a Norm Bound §monotone; multiplying by κ2≥0\tfrac{\kappa}{2}\ge0 and applying claim 4 of Elementary Order Arithmetic in an Ordered Field gives −κ2tr⁡(Y)≤−κ2tr⁡(X)-\tfrac{\kappa}{2}\operatorname{tr}(Y)\le-\tfrac{\kappa}{2}\operatorname{tr}(X), and adding the remaining terms gives

G0(r,p,Y)≤G0(r,p,X)andF(x,r,p,Y)≤F(x,r,p,X).(1)G_{0}(r,p,Y)\le G_{0}(r,p,X)\quad\text{and}\quad F(x,r,p,Y)\le F(x,r,p,X). \tag{1}

So FF is degenerate elliptic. For s≤rs\le r, all terms other than λr\lambda r and λs\lambda s cancel, and F(x,r,p,X)−F(x,s,p,X)=λ(r−s)F(x,r,p,X)-F(x,s,p,X)=\lambda(r-s) by distributivity. Thus FF is strictly proper with constant λ\lambda.

Hypothesis Comparison Principle with a Weighted Penalty for Operators Convex in the Value, Gradient and Matrix Variables §convex. Fix x∈Dx\in D, triples (r,p,X)(r,p,X) and (s,q,Y)(s,q,Y), and tt with 0≤t≤10\le t\le1. The maps r↦λrr\mapsto\lambda r, p↦b(x)⋅pp\mapsto b(x)\cdot p (claim 5 of Bilinearity and Symmetry of the Dot Product on Rn\mathbb{R}^n) and X↦tr⁡(X)X\mapsto\operatorname{tr}(X) (claim 1 of Basic Properties of the Trace) are linear, and G(x)=(1−t)G(x)+tG(x)G(x)=(1-t)G(x)+tG(x), so these terms of FF at the combined triple equal the same combination of their values at the two triples. For the quadratic term, The Squared Norm of a Convex Combination of Two Points, applied with weight 1−t1-t on pp and tt on qq, gives

∥(1−t)p+tq∥2=(1−t)∥p∥2+t∥q∥2−t(1−t)∥p−q∥2≤(1−t)∥p∥2+t∥q∥2,\lVert(1-t)p+tq\rVert^{2}=(1-t)\lVert p\rVert^{2}+t\lVert q\rVert^{2}-t(1-t)\lVert p-q\rVert^{2}\le(1-t)\lVert p\rVert^{2}+t\lVert q\rVert^{2},

since t(1−t)∥p−q∥2t(1-t)\lVert p-q\rVert^{2} is a product of nonnegative reals (claim 1 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n, claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field). Multiplying by θ2≥0\tfrac{\theta}{2}\ge0 and adding the linear terms gives the inequality of Second-Order Equation Operator Convex in the Value, Gradient and Matrix Variables.

Hypothesis Comparison Principle with a Weighted Penalty for Operators Convex in the Value, Gradient and Matrix Variables §continuity. Fix (x0,r0,p0,X0)(x_{0},r_{0},p_{0},X_{0}) and a positive ε\varepsilon, and put ε′=ε⋅5−1\varepsilon'=\varepsilon\cdot5^{-1} with 5=1+1+1+1+15=1+1+1+1+1, positive by claims 3, 6, 7 and 5 of Elementary Order Arithmetic in an Ordered Field. For (y,s,q,Y)(y,s,q,Y) put h=q−p0h=q-p_{0}. By the field axioms

F(y,s,q,Y)−F(x0,r0,p0,X0)=λ(s−r0)+θ2(∥q∥2−∥p0∥2)+(b(y)−b(x0))⋅q+b(x0)⋅h−κ2(tr⁡(Y)−tr⁡(X0))−(G(y)−G(x0)),F(y,s,q,Y)-F(x_{0},r_{0},p_{0},X_{0})=\lambda(s-r_{0})+\tfrac{\theta}{2}\bigl(\lVert q\rVert^{2}-\lVert p_{0}\rVert^{2}\bigr)+\bigl(b(y)-b(x_{0})\bigr)\cdot q+b(x_{0})\cdot h-\tfrac{\kappa}{2}\bigl(\operatorname{tr}(Y)-\operatorname{tr}(X_{0})\bigr)-\bigl(G(y)-G(x_{0})\bigr),

using claims 2 and 5 of Bilinearity and Symmetry of the Dot Product on Rn\mathbb{R}^n for b(y)⋅q−b(x0)⋅p0b(y)\cdot q-b(x_{0})\cdot p_{0}. We bound the six terms, assuming ∥h∥≤1\lVert h\rVert\le1. (i) ∣λ(s−r0)∣=λ∣s−r0∣|\lambda(s-r_{0})|=\lambda|s-r_{0}| by claim 4 of Properties of the Absolute Value in an Ordered Field. (ii) ∣∥q∥2−∥p0∥2∣≤(2∥p0∥+1)∥h∥|\lVert q\rVert^{2}-\lVert p_{0}\rVert^{2}|\le(2\lVert p_{0}\rVert+1)\lVert h\rVert, exactly as in bound (iii) of the proof of claim 1 of The Viscous Hamilton-Jacobi Operator is Continuous, Strictly Proper and Satisfies the Structure Condition: expand ∥p0+h∥2\lVert p_{0}+h\rVert^{2} by Bilinearity and Symmetry of the Dot Product on Rn\mathbb{R}^n, bound ∣p0⋅h∣|p_{0}\cdot h| by Cauchy-Schwarz Inequality for the Euclidean Dot Product, and use ∥h∥2≤∥h∥\lVert h\rVert^{2}\le\lVert h\rVert. (iii) ∥q∥≤∥p0∥+1\lVert q\rVert\le\lVert p_{0}\rVert+1 by claim 6 of Elementary Properties of the Euclidean Norm on Rn\mathbb{R}^n, so ∣(b(y)−b(x0))⋅q∣≤(∥p0∥+1)∥b(y)−b(x0)∥|(b(y)-b(x_{0}))\cdot q|\le(\lVert p_{0}\rVert+1)\lVert b(y)-b(x_{0})\rVert by Cauchy-Schwarz Inequality for the Euclidean Dot Product. (iv) ∣b(x0)⋅h∣≤∥b(x0)∥ ∥h∥|b(x_{0})\cdot h|\le\lVert b(x_{0})\rVert\,\lVert h\rVert by Cauchy-Schwarz Inequality for the Euclidean Dot Product. (v) ∣tr⁡(Y)−tr⁡(X0)∣≤βn dS(n)(Y,X0)|\operatorname{tr}(Y)-\operatorname{tr}(X_{0})|\le\beta_{n}\,d_{\mathcal{S}(n)}(Y,X_{0}) by claim 1 of Basic Properties of the Trace and The Trace as a Sum of Quadratic Forms, its Monotonicity and a Norm Bound §norm-bound, with dS(n)(Y,X0)=∥Y−X0∥d_{\mathcal{S}(n)}(Y,X_{0})=\lVert Y-X_{0}\rVert (Second-Order Equations on Euclidean Open Sets §matrices). (vi) By continuity of GG and of bb at x0x_{0} there is a positive δ0\delta_{0} such that every y∈Dy\in D with dE(y,x0)<δ0d_{E}(y,x_{0})<\delta_{0} satisfies ∣G(y)−G(x0)∣<ε′|G(y)-G(x_{0})|<\varepsilon' and ∥b(y)−b(x0)∥<ε′(∥p0∥+1)−1\lVert b(y)-b(x_{0})\rVert<\varepsilon'(\lVert p_{0}\rVert+1)^{-1}. Group the six terms into five: A=λ(s−r0)A=\lambda(s-r_{0}), B=θ2(∥q∥2−∥p0∥2)+b(x0)⋅hB=\tfrac{\theta}{2}(\lVert q\rVert^{2}-\lVert p_{0}\rVert^{2})+b(x_{0})\cdot h, C=(b(y)−b(x0))⋅qC=(b(y)-b(x_{0}))\cdot q, E=κ2(tr⁡(Y)−tr⁡(X0))E=\tfrac{\kappa}{2}(\operatorname{tr}(Y)-\operatorname{tr}(X_{0})) and G(y)−G(x0)G(y)-G(x_{0}). By (ii), (iv) and the triangle inequality, ∣B∣≤cB∥h∥|B|\le c_{B}\lVert h\rVert with cB=θ2(2∥p0∥+1)+∥b(x0)∥+1c_{B}=\tfrac{\theta}{2}(2\lVert p_{0}\rVert+1)+\lVert b(x_{0})\rVert+1. Let δ\delta be the least (claim 9 of Elementary Order Arithmetic in an Ordered Field) of the positive numbers 11, δ0\delta_{0}, ε′(λ+1)−1\varepsilon'(\lambda+1)^{-1}, ε′cB−1\varepsilon'c_{B}^{-1} and ε′(κ2βn+1)−1\varepsilon'(\tfrac{\kappa}{2}\beta_{n}+1)^{-1}. If dE(y,x0)d_{E}(y,x_{0}), ∣s−r0∣|s-r_{0}|, ∥h∥\lVert h\rVert and dS(n)(Y,X0)d_{\mathcal{S}(n)}(Y,X_{0}) are less than δ\delta, then ∥h∥≤1\lVert h\rVert\le1, and by (i), (iii), (v), (vi) and the bound on BB each of ∣A∣|A|, ∣B∣|B|, ∣C∣|C|, ∣E∣|E| and ∣G(y)−G(x0)∣|G(y)-G(x_{0})| is less than ε′\varepsilon' (claim 10 of Elementary Order Arithmetic in an Ordered Field, multiplying the bound on δ\delta by the relevant positive factor). By the triangle inequality (claim 5 of Properties of the Absolute Value in an Ordered Field) and claim 3 of Elementary Order Arithmetic in an Ordered Field, ∣F(y,s,q,Y)−F(x0,r0,p0,X0)∣<5ε′=ε|F(y,s,q,Y)-F(x_{0},r_{0},p_{0},X_{0})|<5\varepsilon'=\varepsilon. So FF is continuous at (x0,r0,p0,X0)(x_{0},r_{0},p_{0},X_{0}), and as the quadruple was arbitrary FF is continuous.

Hypothesis Comparison Principle with a Weighted Penalty for Operators Convex in the Value, Gradient and Matrix Variables §structure. Fix RR with DRD_{R} nonempty and put Ω=DR\Omega=D_{R}. By Basic Properties of the Sublevel Sets of a Penalty §sublevel-sets, Ω\Omega is nonempty, open and bounded, so it satisfies Bounded Open Domain in Euclidean Space §domain, and Ω‾\overline{\Omega} is compact, nonempty and contained in DD. The part without drift. By (1), G0G_{0} is degenerate elliptic in the matrix variable in the sense of Structure Condition: a Degenerate Elliptic Operator with a Continuous Inhomogeneity. The restriction ff of GG to Ω‾\overline{\Omega} is continuous on Ω‾\overline{\Omega} by claim 4 of Semicontinuity and Continuity Under Composition with a Continuous Map, so A Continuous Function on a Compact Set Admits a Nondecreasing Modulus of Continuity gives a modulus of continuity ω1\omega_{1} that is nondecreasing (A Continuous Function on a Compact Set Admits a Nondecreasing Modulus of Continuity §monotone) and dominates the oscillation of ff (A Continuous Function on a Compact Set Admits a Nondecreasing Modulus of Continuity §domination). By Structure Condition: a Degenerate Elliptic Operator with a Continuous Inhomogeneity §structure, the operator F1(x,r,p,X)=G0(r,p,X)−f(x)=G0(r,p,X)−G(x)F_{1}(x,r,p,X)=G_{0}(r,p,X)-f(x)=G_{0}(r,p,X)-G(x) on Ω\Omega and ω1\omega_{1} satisfy the structure condition of Comparison Principle for the Dirichlet Problem for Second-Order Equations §structure. The drift. By the one-sided bound on DRD_{R}, the restriction of bb to Ω\Omega and c=cRc=c_{R} satisfy the hypothesis of Structure Condition: a Linear First-Order Operator with an Almost Monotone Drift, so by Structure Condition: a Linear First-Order Operator with an Almost Monotone Drift §structure the operator F2(x,r,p,X)=b(x)⋅pF_{2}(x,r,p,X)=b(x)\cdot p on Ω\Omega and the modulus ωcR(τ)=cRτ\omega_{c_{R}}(\tau)=c_{R}\tau satisfy the same structure condition. The sum. F∣Ω=F1+F2F|_{\Omega}=F_{1}+F_{2} pointwise. For data x,y,r,α,X,Yx,y,r,\alpha,X,Y as in Comparison Principle for the Dirichlet Problem for Second-Order Equations §structure, with τ=α∥x−y∥2+∥x−y∥\tau=\alpha\lVert x-y\rVert^{2}+\lVert x-y\rVert, adding the two structure inequalities gives

F∣Ω(y,r,α(x−y),Y)−F∣Ω(x,r,α(x−y),X)≤ω1(τ)+cRτ=ωR(τ),ωR=ω1+ωcR.F|_{\Omega}\bigl(y,r,\alpha(x-y),Y\bigr)-F|_{\Omega}\bigl(x,r,\alpha(x-y),X\bigr)\le\omega_{1}(\tau)+c_{R}\tau=\omega_{R}(\tau),\qquad\omega_{R}=\omega_{1}+\omega_{c_{R}} .

ωR\omega_{R} is a modulus of continuity: it is nonnegative as a sum of nonnegative functions (claim 2 of Elementary Arithmetic in an Ordered Field), and given a positive ε\varepsilon, if δ1\delta_{1} and δ2\delta_{2} serve ε⋅2−1\varepsilon\cdot2^{-1} for ω1\omega_{1} and for ωcR\omega_{c_{R}} (a modulus by Linear Moduli of Continuity §modulus), the least of them serves ε\varepsilon for ωR\omega_{R}. This is hypothesis Comparison Principle with a Weighted Penalty for Operators Convex in the Value, Gradient and Matrix Variables §structure.

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