TheoremBase

Evaluates e * e' in two ways, once using that e' is neutral and once using that e is neutral.

Proof

By Associative and Commutative Binary Operations, and Neutral Elements §neutral, the neutrality of e′e' gives x∗e′=xx\ast e'=x for every x∈Xx\in X, in particular e∗e′=ee\ast e'=e; and the neutrality of ee gives e∗x=xe\ast x=x for every x∈Xx\in X, in particular e∗e′=e′e\ast e'=e'. Hence

e=e∗e′=e′.e=e\ast e'=e'.

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