Throughout, (X,F,ΞΌ) and the notation are as in the statement. By Ο-Algebra and Measurable Space (i), FβP(X), with P(X) the power set; a sequence in F is thus a sequence in P(X), and a sequence in P(X) whose terms lie in F is a sequence in F (Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (v)). For a sequence (Enβ) in F, nβ¦ΞΌ(Enβ) is a sequence in [0,β], the composite of (Enβ) with ΞΌ (Basic Properties of Functions: Equality, Composition, Identity, Inverse and Restriction (ii)); this applies to (ΞΌ(Enβ)), (ΞΌ(Amβ)), (ΞΌ(Bmβ)) and (ΞΌ(Dmβ)) below. Countable additivity and ΞΌ(β
)=0 are those of Measure, Measure Space, and Probability Measure (i).
Finite additivity. Let r and (Aiβ)iβ[r]β be as in (i). By Maps Defined by Cases (i), applied on N to the condition nβ[r] with the values AnββF and β
βF (Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (vi)), there is a sequence (Enβ) in F with Enβ=Anβ for nβ[r] and Enβ=β
for nβNβ[r]. It is pairwise disjoint: for mξ =k in N, either m,kβ[r] and Emββ©Ekβ=Amββ©Akβ=β
, or one of Emβ,Ekβ is β
. Its union is βi=1rβAiβ: an element of some Enβ shows Enβξ =β
, so nβ[r] and the element lies in Anβ; and Aiβ=Eiβ for iβ[r]. Hence βi=1rβAiβ=βnβNβEnββF by Ο-Algebra and Measurable Space (i), and countable additivity gives ΞΌ(βi=1rβAiβ)=βnβNβΞΌ(Enβ). If kβN and r<k, then kβ€r fails by Arithmetic and Order of the Natural Numbers (vi) and Arithmetic and Order of the Natural Numbers (vii), so kβ/[r] by Intervals of Natural Numbers: Initial Segments, Adding One Element, Splitting and Shifting (i), and ΞΌ(Ekβ)=ΞΌ(β
)=0. By Sums of Sequences in [0,β]: Real Series, Linearity, Comparison, Rearrangement, Double Series and Monotone Convergence (vii), βnβNβΞΌ(Enβ) is therefore the r-th partial sum of (ΞΌ(Enβ)), the iterated sum of its restriction to [r] (Iterated Operations: Finite Sums and Finite Products (ii)). That restriction is the map iβ¦ΞΌ(Aiβ) on [r], as Eiβ=Aiβ for iβ[r], so the partial sum is βi=1rβΞΌ(Aiβ).
Two sets. Let A,B be as in (ii). By Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (iii), with U=A and V=B, there is a sequence (Enβ) in P(X) with E1β=A, E2β=B and Enβ=β
for nξ =1,2; its terms lie in F (Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (vi)), so it is a sequence in F. Since 2=1+1 by Arithmetic and Order of the Natural Numbers (xiv), 1<2 by Arithmetic and Order of the Natural Numbers (xi). The sequence is pairwise disjoint: for mξ =k, either {m,k}={1,2} and Emββ©Ekβ=Aβ©B=β
, or one of Emβ,Ekβ is β
. Its union is AβͺB, since an element of some Enβ shows Enβξ =β
, so n=1 or n=2. Countable additivity gives ΞΌ(AβͺB)=βnβNβΞΌ(Enβ). If kβN and 2<k, then kξ =2 by Arithmetic and Order of the Natural Numbers (vii), and 1<k by Arithmetic and Order of the Natural Numbers (vi), so kξ =1; thus ΞΌ(Ekβ)=ΞΌ(β
)=0. By Sums of Sequences in [0,β]: Real Series, Linearity, Comparison, Rearrangement, Double Series and Monotone Convergence (vii) with n=2 and Iterated Operations: Recursion, Splitting, Reordering, Termwise Combination and Homomorphisms (i) with n=1, βnβNβΞΌ(Enβ)=βk=12βΞΌ(Ekβ)=ΞΌ(E1β)+ΞΌ(E2β)=ΞΌ(A)+ΞΌ(B).
Monotonicity. Let AβB in F. Then BβAβF by Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (x), Aβ©(BβA)=β
, and Aβͺ(BβA)=B because AβB. By (ii), ΞΌ(B)=ΞΌ(A)+ΞΌ(BβA), and ΞΌ(A)β€ΞΌ(A)+ΞΌ(BβA) by Arithmetic in [0,β]: Monoid Laws, Distributivity, Monotonicity and Cancellation (v).
Differences. Let AβB in F with ΞΌ(B)<β. As in the previous paragraph, ΞΌ(B)=ΞΌ(A)+ΞΌ(BβA). By (iii), ΞΌ(A)β€ΞΌ(B) and, as BβAβB, ΞΌ(BβA)β€ΞΌ(B); so ΞΌ(A) and ΞΌ(BβA) are real (Small Facts about [0,β]: Zero, Finiteness and Sums of Zeros (iii)). By Addition and Multiplication on [0,β] (i), ΞΌ(A)+ΞΌ(BβA) is then the sum in R, so ΞΌ(B) is real and ΞΌ(BβA)=ΞΌ(B)βΞΌ(A) (Differences, Quotients and Absolute Values of Real Numbers, Read in the Type Real (i)). If ΞΌ is finite, then ΞΌ(X)<β by Measure, Measure Space, and Probability Measure (iii), XβF by Ο-Algebra and Measurable Space (i) and AβX for AβF, so the case B=X gives ΞΌ(XβA)=ΞΌ(X)βΞΌ(A), which is (v).
The disjointing sequence. This paragraph prepares the next ones. Let (Anβ) be a sequence in F. By Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (iv), there are sequences (Cnβ) and (Bnβ) in P(X) with C1β=X, Cn+1β=Cnββ©(XβAnβ) and Bnβ=Anββ©Cnβ for every nβN. By The Disjointing Sequence of a Sequence of Sets, these sequences have the following properties. (D1) (Bnβ) is a sequence in F, by The Disjointing Sequence of a Sequence of Sets (v), as every Anβ lies in F. (D2) BnββAnβ for every n, by The Disjointing Sequence of a Sequence of Sets (ii), and (Bnβ) is pairwise disjoint, Bmββ©Bkβ=β
for mξ =k, by The Disjointing Sequence of a Sequence of Sets (iii). (D3) If nβN and xβAnβ, then xβBmβ for some mβN with mβ€n, that is, for some mβ[n] by Intervals of Natural Numbers: Initial Segments, Adding One Element, Splitting and Shifting (i); and βnβNβBnβ=βnβNβAnβ; both by The Disjointing Sequence of a Sequence of Sets (iv).
Countable subadditivity. Let (Amβ) be a sequence in F and (Bmβ) its disjointing sequence as above. By (D3), (D1), (D2) and countable additivity, ΞΌ(βmβAmβ)=ΞΌ(βmβBmβ)=βmβNβΞΌ(Bmβ). By (D2) and (iii), ΞΌ(Bmβ)β€ΞΌ(Amβ) for every m, so βmβNβΞΌ(Bmβ)β€βmβNβΞΌ(Amβ) by Sums of Sequences in [0,β]: Real Series, Linearity, Comparison, Rearrangement, Double Series and Monotone Convergence (x).
Subadditivity for two sets. Let A,BβF. Then BβAβF by Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (x), Aβ©(BβA)=β
and Aβͺ(BβA)=AβͺB, so ΞΌ(AβͺB)=ΞΌ(A)+ΞΌ(BβA) by (ii). As BβAβB, ΞΌ(BβA)β€ΞΌ(B) by (iii), and then ΞΌ(A)+ΞΌ(BβA)β€ΞΌ(A)+ΞΌ(B) by Arithmetic in [0,β]: Monoid Laws, Distributivity, Monotonicity and Cancellation (iv) and the commutativity in Arithmetic in [0,β]: Monoid Laws, Distributivity, Monotonicity and Cancellation (i).
Continuity from below. Let (Amβ) and A be as in (viii), and (Bmβ) the disjointing sequence of (Amβ). First, AkββAnβ whenever nβN and kβ[n], as then kβ€n by Intervals of Natural Numbers: Initial Segments, Adding One Element, Splitting and Shifting (i) (Monotone Sequences of Sets, Unions of Traces, and Disjointness of Smaller Sets (i)). Now fix nβN. The family (Bkβ)kβ[n]β, the restriction of (Bkβ) to [n], is pairwise disjoint with terms in F by (D1) and (D2), and its union is Anβ: for kβ[n], BkββAkββAnβ by (D2) and the inclusions just shown, and every xβAnβ lies in Bmβ for some mβ[n] by (D3). By (i) with r=n, ΞΌ(Anβ)=βk=1nβΞΌ(Bkβ), which is the n-th partial sum snβ of (ΞΌ(Bkβ)) (Iterated Operations: Finite Sums and Finite Products (ii)). Hence {snβ:nβN}={ΞΌ(Anβ):nβN}, and by (D3), countable additivity and Sum of a Sequence in [0,β] (ii),
ΞΌ(A)=ΞΌ(kβNββBkβ)=kβNββΞΌ(Bkβ)=sup{snβ:nβN}=nsupβΞΌ(Anβ).
Continuity from above. Let (Amβ) and A be as in (ix); AβF by Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (viii). As A1ββFβP(X), every subset of A1β is a subset of X, so P(A1β)βP(X). By Monotone Sequences of Sets, Unions of Traces, and Disjointness of Smaller Sets (ii), AmββA1β for every m; so (Amβ), a sequence in P(X) whose terms lie in the subset P(A1β) of P(X), is a sequence in P(A1β) (Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (v)), and Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (i), applied to A1β, gives the sequence (Dmβ) in P(A1β) with Dmβ=A1ββAmβ. As the range of (Dmβ) lies in P(A1β)βP(X), (Dmβ) is a sequence in P(X) by Functions, Values of a Function, and Functions from One Class to Another (iii). Its terms lie in F by Closure Properties of Ο-Algebras, Intersections and Traces of Ο-Algebras, and the Generated Ο-Algebra (x), so it is a sequence in F by Sequences and Maps of Sets: Complements, Traces, Two-Term Sequences, the Disjointing Sequence, and Sequences in a Subset (v). Also AβAmβ for every m, by Indexed Families of Sets and Their Union, Intersection and Product (iii). As ΞΌ(A1β)<β, (iv) with B=A1β shows that ΞΌ(A1β), ΞΌ(A) and every ΞΌ(Amβ) are real, ΞΌ(Dmβ)=ΞΌ(A1β)βΞΌ(Amβ) for every m, and ΞΌ(A1ββA)=ΞΌ(A1β)βΞΌ(A). Moreover DmββDm+1β, as Am+1ββAmβ; and βmβDmβ=A1ββA, since x lies in some Dmβ exactly when xβA1β and xβ/Amβ for some m, that is, xβA1β and xβ/βmβAmβ. By (viii) applied to (Dmβ),
ΞΌ(A1β)βΞΌ(A)=ΞΌ(A1ββA)=msupβΞΌ(Dmβ).
Let S={ΞΌ(Amβ):mβN}. We show that ΞΌ(A) is the greatest lower bound of S, which makes it the infimum infmβΞΌ(Amβ) by Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order (iv). It is a lower bound of S: ΞΌ(A)β€ΞΌ(Amβ) by (iii), as AβAmβ. Let bβ[ββ,β] be a lower bound of S. If b=ββ, then bβ€ΞΌ(A) by Order and Suprema in the Extended Real Line (ii). Otherwise bβ€ΞΌ(A1β) with ΞΌ(A1β) real, so bξ =β by Order and Suprema in the Extended Real Line (ii), and bβR by The Extended Real Line, Its Order, and [0,β] (ii). For every m, bβ€ΞΌ(Amβ) holds in R by Order and Suprema in the Extended Real Line (i), so ΞΌ(Dmβ)=ΞΌ(A1β)βΞΌ(Amβ)β€ΞΌ(A1β)βb (Differences, Quotients and Absolute Values of Real Numbers, Read in the Type Real (i)). Thus the real number ΞΌ(A1β)βb is an upper bound of {ΞΌ(Dmβ):mβN}, and the supremum, being the least upper bound (Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order (iv)), satisfies ΞΌ(A1β)βΞΌ(A)=supmβΞΌ(Dmβ)β€ΞΌ(A1β)βb. Both sides are real, so this holds in R by Order and Suprema in the Extended Real Line (i), and bβ€ΞΌ(A) (Differences, Quotients and Absolute Values of Real Numbers, Read in the Type Real (i)). Hence ΞΌ(A)=infmβΞΌ(Amβ).