Reason: First published proof of lem:l2-interval-separable-2026a: dyadic averaging for the approximation, then rational rounding of the finitely many values, with countability of the dense set from the published countability chain.
Proof
Write λ=λ[0,T], B=B[0,T], PT=T−1λ, and let Gm, Im,p, Am be as in the dyadic averaging lemma.
Claim 1.Square-integrability. Let w=∑p=12mcp1Im,p∈Dm. Its i-th component is wi=∑pcpi1Im,p, a simple function built from the sets Im,p∈B, hence B-measurable. Since the atoms are pairwise disjoint with union [0,T], w takes only the values c1,…,c2m, so with C the greatest element of the finite family (∣cp∣)p∈{1,…,2m}, which exists by Greatest Element of a Finite Family in a Totally Ordered Set, we get ∣w∣2≤C2 pointwise and, by monotonicity, ∫[0,T]∣w∣2dλ≤C2λ([0,T])=C2T<∞. So w∈L2([0,T];Rd).
Step A: dyadic averages approximate u. By claim 7 of the inner-product lemma, each component ui is a square-integrable random variable on ([0,T],B,PT). By claim 3 of the dyadic averaging lemma, Amui is a conditional expectation of ui given Gm; by claim 1 of that lemma the Gm (m≥1) form a nondecreasing sequence of sub-σ-algebras of B; and by claim 2 of that lemma their generated σ-algebra is B itself. Since ui is B-measurable and square-integrable, the choice Y=ui satisfies conditions (i), (ii), (iii) of the definition of conditional expectation with G=B, so ui is a conditional expectation of ui given B. Levy's upward theorem in mean square, applied to ui and this filtration, therefore gives ∥Amui−ui∥2→0 as m→∞.
Let Amu:[0,T]→Rd be the map with components (Amu)i=Amui, that is
Each Amui is bounded and B-measurable by claim 3 of the dyadic averaging lemma, so Amu∈L2([0,T];Rd) by the argument already given in claim 1. By claim 7 of the inner-product lemma,
∥[Amu]−[u]∥L22=Ti=1∑d∥Amui−ui∥22,
a finite sum of real sequences each with limit 0, hence with limit 0. Fix m≥1 with ∥[Amu]−[u]∥L2<ε/2 and abbreviate bp=bm,p.
which lies in Dm and hence in D. Let κ be the greatest element of the finite family (∣bp−cp∣2)p∈{1,…,2m}, which exists by Greatest Element of a Finite Family in a Totally Ordered Set; then κ<ε2(4T)−1. By claim 1 of the dyadic averaging lemma the level-m atoms are pairwise disjoint with union [0,T], so each t∈[0,T] lies in exactly one atom Im,p, and there Amu takes the value bp and w the value cp, whence ∣w(t)−Amu(t)∣2=∣cp−bp∣2≤κ. Therefore, by monotonicity,
∥[w]−[Amu]∥L22=∫[0,T]∣w−Amu∣2dλ≤κT<4ε2,
and since both sides are nonnegative, ∥[w]−[Amu]∥L2<ε/2.
Conclusion. Note first that ∥v−v′∥L2=∥v′−v∥L2 for all v,v′, by the absolute homogeneity in claim 5 of the inner-product lemma applied to the scalar −1. By the triangle inequality of that same claim,
∥[u]−[w]∥L2≤∥[u]−[Amu]∥L2+∥[Amu]−[w]∥L2<ε.
Density. Let U be a nonempty open subset of L2([0,T];Rd) and let ξ∈U. There is a real ε>0 with {ζ:dL2(ζ,ξ)<ε}⊆U. Choosing a representative u∈L2([0,T];Rd) of ξ and applying claim 2 produces w∈D with dL2([w],ξ)=∥[w]−[u]∥L2=∥[u]−[w]∥L2<ε, so [w]∈U. Thus {[w]:w∈D} meets every nonempty open subset, so its closure is the whole space and it is dense. Finally, {[w]:w∈D} is the set of values of the map w↦[w] on D, so it is countable by claim 1 above and claim 4 of Basic Properties of Countable Sets.