Proof of A Viscosity Subsolution or Supersolution of Class is Classical
propositionprop:viscosity-c2-implies-classical-2026aThroughout, carries the operations and the order of its ordered field structure, where abbreviates and means that and ; the order is a total order and is in particular reflexive. Regard as a metric space through the Euclidean distance , which is a metric by Euclidean Distance is a Metric on ; this is the metric used in the local extremum notions below. For write for the gradient of at and for the Hessian matrix of at .
Step 1 (The test function itself). Take ; this function is of class on by hypothesis, so it is admissible as a test function in either viscosity notion, and and for every . For this choice the function of that definition has value at , and by claim 3 of Additive Cancellation and Elementary Additive Identities in a Field. Write for this function, so that for every .
Step 2 (Every point of is both a local maximum and a local minimum of ). Let . By claim 6 of Elementary Order Arithmetic in an Ordered Field we have in , so is an admissible radius. Every with satisfies and , whence and by reflexivity of . Therefore has a local maximum at relative to and also a local minimum at relative to .
Step 3 (Proof of claim 1). Assume that is a viscosity subsolution of on and let . By Steps 1 and 2 the function associated with the test function has a local maximum at relative to , so the defining condition of a viscosity subsolution, applied to this and this , gives
that is, . Since was arbitrary and is of class on , this is exactly the statement that is a classical subsolution of on .
Step 4 (Proof of claim 2). Assume that is a viscosity supersolution of on and let . By Steps 1 and 2 the same function , with , has a local minimum at relative to , so the defining condition of a viscosity supersolution gives
that is, . Since was arbitrary and is of class on , is a classical supersolution of on .
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Prerequisites
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