Proof of Constant Plan-Jet Viscosity Subsolutions and Supersolutions of the Discounted Hamilton-Jacobi Equation on Square-Integrable Noncommutative Laws
lemmalem:nc-constant-sub-supersolutions-2026aPlan jets of a constant have momentum of norm at most the slack, so the slack can cancel the momentum and the hypothesis at zero momentum applies.
Each result cited is universally quantified over the data in its own statement.
Claim 1. We verify the jet form of Test Functions and Plan Jets: Touching Transfers Plan Jets, and the Jet Form of Plan-Jet Viscosity Solutions §sub. Let , , and . By Plan Jets at a Common Realisation: Superdifferential and Subdifferential Momenta are Close, and the Plan Jets of a Constant §constants, . By Every Square-Integrable Noncommutative Law is the Law of a Square-Integrable Tuple; Realisation of Couplings and of Almost Optimal Pairs §coupling there are a tracial W*-probability space and -tuples of it with ; then by Calculus of Laws of Square-Integrable Tuples: Bounded Tuples, the Lipschitz Bound, Moments, Affine Push-Forwards, Couplings and Embeddings §push-forward and Calculus of Laws of Square-Integrable Tuples: Bounded Tuples, the Lipschitz Bound, Moments, Affine Push-Forwards, Couplings and Embeddings §moments, so (Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field). Put , an -tuple by Sums, Real Multiples and the Pairing of Square-Integrable Tuples in a Tracial W*-Probability Space §operations, with and . Then, by hypothesis,
Hence is a plan-jet viscosity subsolution.
Claim 2. Identical, with Test Functions and Plan Jets: Touching Transfers Plan Jets, and the Jet Form of Plan-Jet Viscosity Solutions §super, plans (to which Plan Jets at a Common Realisation: Superdifferential and Subdifferential Momenta are Close, and the Plan Jets of a Constant §constants applies equally), and the conclusion .
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Prerequisites
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