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Proof of Asymptotic Lower Bound for the Recentred N-Agent Cost by the Fluctuation LQG Value, under Injection Certificates

theoremthm:n-agent-cost-lqg-lower-bound-2026a
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Reason: First version. Proof of the asymptotic lower bound by the fluctuation LQG value: well-posedness of the Kalman covariance, the Cholesky column identity for the weight, the injection certificate applied along the Riccati adjoint direction, a blockwise Fatou argument, and assembly with the published parameter ladder.

Proof

Claim 1.

The initial covariance. By hypothesis (I) the matrix Π0\Pi_{0} is symmetric. Suppose it were not positive semidefinite, so that x(Π0x)=2η0<0x\cdot(\Pi_{0}x)=-2\eta_{0}<0 for some xRlx\in\mathbb{R}^{l}. Put ζ=η0/(1+γ,δxγxδ)>0\zeta=\eta_{0}/\bigl(1+\sum_{\gamma,\delta}|x^{\gamma}x^{\delta}|\bigr)>0. By hypothesis (I) and the definition of the limit of a real sequence, applied to each of the finitely many sequences (E[s0γs0δ])N1\bigl(\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]\bigr)_{N\ge1}, there is NN' such that E[s0γs0δ]Π0γδζ\bigl|\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]-\Pi^{\gamma\delta}_{0}\bigr|\le\zeta for all γ,δ\gamma,\delta and all NNN\ge N'. For such NN, by the linearity of the integral,

E[(xs0)2]=γ,δxγxδE[s0γs0δ]  γ,δxγxδΠ0γδ+ζγ,δxγxδ  2η0+η0<0,\mathbb{E}\bigl[(x\cdot\mathfrak{s}_{0})^{2}\bigr]=\sum_{\gamma,\delta}x^{\gamma}x^{\delta}\,\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]\ \le\ \sum_{\gamma,\delta}x^{\gamma}x^{\delta}\,\Pi^{\gamma\delta}_{0}+\zeta\sum_{\gamma,\delta}|x^{\gamma}x^{\delta}|\ \le\ -2\eta_{0}+\eta_{0}<0,

contradicting the nonnegativity of the expectation of the nonnegative random variable (xs0)2(x\cdot\mathfrak{s}_{0})^{2}. Hence Π0\Pi_{0} is positive semidefinite.

The coefficient families. Every entry of tEt=Ett\mapsto E_{t}=\mathcal{E}_{t} is continuous on [0,T][0,T] by conclusion (a) of the completion-of-squares theorem. Every entry of tΘtt\mapsto\Theta^{\star}_{t} is continuous by clause (c) of the covariance deviation lemma, and every Θt\Theta^{\star}_{t} is positive semidefinite, hence symmetric, by claim 3 of the covariance positivity lemma.

Under (OC) each Θ~t\tilde{\Theta}^{\star}_{t} is the diagonal matrix with diagonal entries b~υ(St)β~min>0\tilde{b}^{\upsilon}(S_{t})\ge\tilde{\beta}_{\min}>0; the diagonal matrix with diagonal entries 1/b~υ(St)1/\tilde{b}^{\upsilon}(S_{t}) is its inverse, as the index formula for the matrix product shows, and its entries are continuous in tt by the continuity of the reciprocal of a nonvanishing continuous function. Consequently

D~tγδ=υ=1l~E~tυγE~tυδb~υ(St),\tilde{D}^{\gamma\delta}_{t}=\sum_{\upsilon=1}^{\tilde{l}}\frac{\tilde{\mathcal{E}}^{\upsilon\gamma}_{t}\,\tilde{\mathcal{E}}^{\upsilon\delta}_{t}}{\tilde{b}^{\upsilon}(S_{t})},

which is symmetric in (γ,δ)(\gamma,\delta) and continuous in tt by the continuity of sums and products; and for xRlx\in\mathbb{R}^{l},

x(D~tx)=υ=1l~((E~tx)υ)2b~υ(St)  0,x\cdot(\tilde{D}_{t}x)=\sum_{\upsilon=1}^{\tilde{l}}\frac{\bigl((\tilde{\mathcal{E}}_{t}x)^{\upsilon}\bigr)^{2}}{\tilde{b}^{\upsilon}(S_{t})}\ \ge\ 0,

so every D~t\tilde{D}_{t} is positive semidefinite. The Riccati existence theorem therefore applies on [0,T][0,T] with kk there equal to ll, A=EA=\mathcal{E}, C=ΘC=\Theta^{\star}, D=D~D=\tilde{D} and P0=Π0P_{0}=\Pi_{0}, and yields the unique Π\Pi with continuous entries, every Πt\Pi_{t} being symmetric and satisfying 0Πt0\preceq\Pi_{t}, that is, positive semidefinite.

The weight Ξ\Xi. Every Ξt\Xi_{t} is symmetric positive semidefinite with continuous entries by claim 2 of the cascade filtering lemma. Fix tt. Under (H1), conclusion (a) of the completion-of-squares theorem gives that RtR_{t} is symmetric positive definite, so Rt1R_{t}^{-1} is symmetric positive definite by Invertibility of Symmetric Positive Definite Matrices, and by the Cholesky factorisation there is a real matrix LtL_{t} with mm rows and mm columns and Rt1=LtLtR_{t}^{-1}=L_{t}L_{t}^{\top}. Put Bt=WtLtB_{t}=W_{t}L_{t}, a real matrix with ll rows and mm columns, and let bt,1,,bt,mRlb_{t,1},\dots,b_{t,m}\in\mathbb{R}^{l} be its columns, so that (Bt)γj=bt,jγ(B_{t})_{\gamma j}=b^{\gamma}_{t,j}. Then

Ξt=WtLtLtWt=BtBt,that isΞtγδ=j=1mbt,jγbt,jδ,\Xi_{t}=W_{t}L_{t}L_{t}^{\top}W_{t}^{\top}=B_{t}B_{t}^{\top},\qquad\text{that is}\qquad\Xi^{\gamma\delta}_{t}=\sum_{j=1}^{m}b^{\gamma}_{t,j}b^{\delta}_{t,j},

by the index formula for the matrix product and the transpose. Hence, for every real matrix M\mathcal{M} with ll rows and ll columns,

γ=1lδ=1lΞtγδMγδ=j=1mγ,δbt,jγbt,jδMγδ=j=1mbt,j(Mbt,j),\sum_{\gamma=1}^{l}\sum_{\delta=1}^{l}\Xi^{\gamma\delta}_{t}\,\mathcal{M}^{\gamma\delta}=\sum_{j=1}^{m}\sum_{\gamma,\delta}b^{\gamma}_{t,j}b^{\delta}_{t,j}\mathcal{M}^{\gamma\delta}=\sum_{j=1}^{m}b_{t,j}\cdot\bigl(\mathcal{M}\,b_{t,j}\bigr),

called the column identity below. Taking M=Πt\mathcal{M}=\Pi_{t} shows γ,δΞtγδΠtγδ0\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{t}\Pi^{\gamma\delta}_{t}\ge0, every Πt\Pi_{t} being positive semidefinite. That function of tt is a finite sum of products of continuous functions, hence continuous, and therefore Lebesgue integrable on [0,T][0,T] by claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval. This proves claim 1.

Claim 2. Fix π\pi, kk, s[tk,tk+1]s\in[t_{k},t_{k+1}], cc and η>0\eta>0, and put κ=c(Πsc)\kappa=c\cdot(\Pi_{s}c), a nonnegative real by claim 1.

Apply Adjoint Energy Identity for the Kalman Covariance Riccati Equation with a=0a=0, b=Tb=T, kk there equal to ll, the data E\mathcal{E}, Θ\Theta^{\star}, D~\tilde{D}, Π0\Pi_{0} and Π\Pi of claim 1, the time ss and the vector x=cx=c. It produces an assignment λ\lambda with continuous components and λ(s)=c\lambda(s)=c, and by its claim 2 the assignment uΠuλ(u)u\mapsto\Pi_{u}\lambda(u) has continuous components and satisfies the integral equation defining ψλ\psi_{\lambda}; by the uniqueness in claim 3 of the variation of constants theorem, ψλ(u)=Πuλ(u)\psi_{\lambda}(u)=\Pi_{u}\lambda(u) for every uu. Its claim 3 then gives

cψλ(s)=c(Πsc)=κandAs(λ)=κ,c\cdot\psi_{\lambda}(s)=c\cdot(\Pi_{s}c)=\kappa\qquad\text{and}\qquad\mathcal{A}_{s}(\lambda)=\kappa,

the second because the energy displayed there is exactly As(λ)\mathcal{A}_{s}(\lambda) once ψλ=Πλ\psi_{\lambda}=\Pi\lambda is substituted.

Suppose first κ=0\kappa=0. Apply (VT) with this λ\lambda and with ϵ=1\epsilon=1, obtaining N2N_{2}; for NN2N\ge N_{2} the data of (VT) exist, and taking ϰ=0\varkappa=0, which satisfies (C4) because (αz)20=0(z(Iz))(\alpha\cdot z)^{2}\ge0=0\cdot\bigl(z\cdot(\mathcal{I}z)\bigr), they form a van Trees certificate; claim 1 of Localized Filtering Lower Bound from a van Trees Certificate is therefore available (only the presence of a certificate is used here, not its tolerance or its value) and gives

E[1Tknr(s)γ,δcγcδεsγεsδ]=E[1Tknr(s)(cεs)2]  0=κ  κη,\mathbb{E}\Bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}\sum_{\gamma,\delta}c^{\gamma}c^{\delta}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\Bigr]=\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}(c\cdot\varepsilon_{s})^{2}\bigr]\ \ge\ 0=\kappa\ \ge\ \kappa-\eta,

the inequality being the nonnegativity of the expectation of a nonnegative random variable. Take N3=N2N_{3}=N_{2}.

Suppose now κ>0\kappa>0, and put

ϵ=min{κ8, κ2, η3+2κ}>0,ϰ=(κϵ)2κ+ϵ,\epsilon=\min\Bigl\{\frac{\kappa}{8},\ \frac{\sqrt{\kappa}}{2},\ \frac{\eta}{3+2\sqrt{\kappa}}\Bigr\}>0,\qquad \varkappa=\frac{(\kappa-\epsilon)^{2}}{\kappa+\epsilon},

with \sqrt{\cdot} the nonnegative square root. Apply (VT) with this λ\lambda and this ϵ\epsilon, obtaining N2N_{2}, and let NN3=N2N\ge N_{3}=N_{2} and let dd, (Y,Y)(\mathsf{Y},\mathcal{Y}), ϱ0\varrho_{0}, D\mathsf{D}, Θ\Theta, α\alpha, zz be a certificate. Then

αz  κϵ > 0,z(Iz)  κ+ϵ,\alpha\cdot z\ \ge\ \kappa-\epsilon\ >\ 0,\qquad z\cdot(\mathcal{I}z)\ \le\ \kappa+\epsilon,

so (αz)2(κϵ)2=ϰ(κ+ϵ)ϰ(z(Iz))(\alpha\cdot z)^{2}\ge(\kappa-\epsilon)^{2}=\varkappa\,(\kappa+\epsilon)\ge\varkappa\,\bigl(z\cdot(\mathcal{I}z)\bigr), which is condition (C4) with this ϰ\varkappa; here ϰ0\varkappa\ge0 and z(Iz)>0z\cdot(\mathcal{I}z)>0 by claim 1 of Rank-One Lower Bound for the Inverse of a Positive Definite Matrix.

Three elementary estimates follow from 0<ϵκ/80<\epsilon\le\kappa/8 and ϵκ/2\epsilon\le\sqrt{\kappa}/2. First, (κ3ϵ)(κ+ϵ)=κ22κϵ3ϵ2κ22κϵ+ϵ2=(κϵ)2(\kappa-3\epsilon)(\kappa+\epsilon)=\kappa^{2}-2\kappa\epsilon-3\epsilon^{2}\le\kappa^{2}-2\kappa\epsilon+\epsilon^{2}=(\kappa-\epsilon)^{2}, so ϰκ3ϵ\varkappa\ge\kappa-3\epsilon. Second, ϵ3κ\epsilon\le3\kappa gives ϵ23κϵ\epsilon^{2}\le3\kappa\epsilon, hence (κϵ)2=κ22κϵ+ϵ2κ2+κϵ=κ(κ+ϵ)(\kappa-\epsilon)^{2}=\kappa^{2}-2\kappa\epsilon+\epsilon^{2}\le\kappa^{2}+\kappa\epsilon=\kappa(\kappa+\epsilon) and therefore ϰκ\varkappa\le\kappa and ϰκ\sqrt{\varkappa}\le\sqrt{\kappa}. Third, ϰκ3ϵκ3κ/8κ/4ϵ2\varkappa\ge\kappa-3\epsilon\ge\kappa-3\kappa/8\ge\kappa/4\ge\epsilon^{2}, so ϰϵ\sqrt{\varkappa}\ge\epsilon.

Claim 2 of Localized Filtering Lower Bound from a van Trees Certificate is therefore available and gives, together with its claim 1,

E[1Tknr(s)γ,δcγcδεsγεsδ]  (ϰϵ)2=ϰ2ϵϰ+ϵ2  ϰ2ϵκ  κ3ϵ2ϵκ  κη,\mathbb{E}\Bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}\sum_{\gamma,\delta}c^{\gamma}c^{\delta}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\Bigr]\ \ge\ \bigl(\sqrt{\varkappa}-\epsilon\bigr)^{2}=\varkappa-2\epsilon\sqrt{\varkappa}+\epsilon^{2}\ \ge\ \varkappa-2\epsilon\sqrt{\kappa}\ \ge\ \kappa-3\epsilon-2\epsilon\sqrt{\kappa}\ \ge\ \kappa-\eta,

the last step by the choice ϵη/(3+2κ)\epsilon\le\eta/(3+2\sqrt{\kappa}). This proves claim 2.

Claim 3. Fix π\pi and η>0\eta>0, and for k{0,,K1}k\in\{0,\dots,K-1\} and N1N\ge1 define

fN(k)(s)=E[1Tknr(s)usRsus](s[tk,tk+1]).f^{(k)}_{N}(s)=\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}\,u_{s}\cdot R_{s}u_{s}\bigr]\qquad(s\in[t_{k},t_{k+1}]).

Each fN(k)f^{(k)}_{N} is nonnegative, because usRsusrus20u_{s}\cdot R_{s}u_{s}\ge r|u_{s}|^{2}\ge0 by (H1), and is measurable on [tk,tk+1][t_{k},t_{k+1}] by hypothesis (MS); its integral over that block is the kk-th summand appearing in claim 7 of the ledger lemma.

Fix kk and s[tk,tk+1]s\in[t_{k},t_{k+1}]. The event H=Tknr(s)\mathcal{H}=\mathcal{T}^{\mathrm{nr}}_{k}(s) belongs to Gs\mathcal{G}_{s} by claim 2 of the ledger lemma, so claim 3 of the cascade filtering lemma gives

fN(k)(s)  γ,δΞsγδE[1Hεsγεsδ]=j=1mE[1Hγ,δbs,jγbs,jδεsγεsδ],f^{(k)}_{N}(s)\ \ge\ \sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\,\mathbb{E}\bigl[\mathbf{1}_{\mathcal{H}}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\bigr]=\sum_{j=1}^{m}\mathbb{E}\Bigl[\mathbf{1}_{\mathcal{H}}\sum_{\gamma,\delta}b^{\gamma}_{s,j}b^{\delta}_{s,j}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\Bigr],

the equality by the column identity of claim 1 applied to the matrix Mγδ=E[1Hεsγεsδ]\mathcal{M}^{\gamma\delta}=\mathbb{E}[\mathbf{1}_{\mathcal{H}}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}] and by the linearity of the integral. Let η>0\eta'>0. Applying claim 2 to each of the mm vectors c=bs,jc=b_{s,j} with tolerance η/m\eta'/m and taking the largest of the resulting thresholds, there is NN'' such that for every NNN\ge N''

fN(k)(s)  j=1m(bs,j(Πsbs,j)ηm)=γ,δΞsγδΠsγδη,f^{(k)}_{N}(s)\ \ge\ \sum_{j=1}^{m}\Bigl(b_{s,j}\cdot(\Pi_{s}b_{s,j})-\frac{\eta'}{m}\Bigr)=\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}-\eta',

again by the column identity. As η>0\eta'>0 was arbitrary, the sequence (fN(k)(s))N1\bigl(f^{(k)}_{N}(s)\bigr)_{N\ge1} satisfies

lim infNfN(k)(s)  γ,δΞsγδΠsγδ(s[tk,tk+1]).\liminf_{N\to\infty}f^{(k)}_{N}(s)\ \ge\ \sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\qquad(s\in[t_{k},t_{k+1}]).

By Fatou's lemma, applied to the nonnegative measurable functions fN(k)f^{(k)}_{N} on [tk,tk+1][t_{k},t_{k+1}] with the restricted Lebesgue measure, and then by the monotonicity of the integral together with claim 1,

lim infN[tk,tk+1]fN(k)(s)ds  [tk,tk+1]lim infNfN(k)(s)ds  [tk,tk+1]γ,δΞsγδΠsγδds.\liminf_{N\to\infty}\int_{[t_{k},t_{k+1}]}f^{(k)}_{N}(s)\,ds\ \ge\ \int_{[t_{k},t_{k+1}]}\liminf_{N\to\infty}f^{(k)}_{N}(s)\,ds\ \ge\ \int_{[t_{k},t_{k+1}]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds .

Hence for each kk there is N(k)N^{(k)} with [tk,tk+1]fN(k)ds[tk,tk+1]γ,δΞsγδΠsγδdsη/K\int_{[t_{k},t_{k+1}]}f^{(k)}_{N}\,ds\ge\int_{[t_{k},t_{k+1}]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\eta/K for every NN(k)N\ge N^{(k)}. Let N4N_{4} be the largest of N(0),,N(K1)N^{(0)},\dots,N^{(K-1)} and sum over kk. Since t0=0t_{0}=0, tK=Tt_{K}=T and tk<tk+1t_{k}<t_{k+1} for kK1k\le K-1 (the number of blocks KK being least with KT0TKT_{0}\ge T), the intervals [tk,tk+1][t_{k},t_{k+1}] are adjacent with union [0,T][0,T], so by the additivity of the Lebesgue integral of a continuous function over adjacent compact intervals (Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval) the sum of the right-hand sides is [0,T]γ,δΞsγδΠsγδdsη\int_{[0,T]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\eta. This proves claim 3.

Claim 4. Let ε>0\varepsilon''>0. By conclusion (b) of the asymptotic lower bound theorem, applied with ε=ε/2\varepsilon'=\varepsilon''/2, there are an admissible parameter vector π\pi and a natural number N0N_{0} such that for every NN0N\ge N_{0}

JN  V0+k=0K1[tk,tk+1]E[1Tknr(s)usRsus]dsε2,\mathcal{J}_{N}\ \ge\ V_{0}+\sum_{k=0}^{K-1}\int_{[t_{k},t_{k+1}]}\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}u_{s}\cdot R_{s}u_{s}\bigr]\,ds-\frac{\varepsilon''}{2},

the blocks and near-field tracked events being those formed from π\pi. Apply claim 3 to this π\pi with η=ε/2\eta=\varepsilon''/2, obtaining N4N_{4}, and put N5=max(N0,N4)N_{5}=\max(N_{0},N_{4}). For NN5N\ge N_{5} the two displays combine to

JN  V0+[0,T]γ,δΞsγδΠsγδdsε2ε2,\mathcal{J}_{N}\ \ge\ V_{0}+\int_{[0,T]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\frac{\varepsilon''}{2}-\frac{\varepsilon''}{2},

which is claim 4.

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