The atoms of the two formulas are pair memberships in the order and memberships, so the formulas are predicative; unwinding upper and lower bounds and least and greatest elements shows they define the supremum and the infimum, which then substitute into formulas and define maps.
Each result cited is universally quantified over the data in its own statement.
Clause supremum. Predicativity. By Partial and Total Orders on a Set and the Associated Strict Relation §partial, , , and the parts of replacing them stand for and the like, written with the ordered pair as a defined set symbol. The other atomic parts are memberships, the quantifiers are over the set variables and , and no class abstraction is written in or . So no quantifier of or is applied to a class variable, and both are predicative by Predicativity of Expressions with Abbreviations, and Symbol-Free Forms of the Basic Defined Set Symbols §closure.
Meaning. Let and be sets. The first conjunct of , which is also that of , holds if and only if , by Subclasses and Subsets §subclass; if it fails, both sides of both claims fail. Let now be a subset of . By Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order §bounds, Class Abstraction: the Class of All Sets Satisfying a Predicative Formula §restricted and Class Abstraction: the Class of All Sets Satisfying a Predicative Formula §abstraction, for every set , if and only if and for every , and if and only if and for every . Hence the second and third conjuncts of state that , and the fourth that for every ; by Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order §least, together they state that is a least element of , that is, by Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order §supremum, a supremum of . Likewise the second and third conjuncts of state that , and the fourth that for every ; together they state that is a greatest element of , that is, an infimum of . Since has at most one supremum and at most one infimum, by Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order §supremum, is a supremum of if and only if has a supremum and , and is an infimum of if and only if has an infimum and .
Clause bound-symbol. We give the argument for ; the one for is the same with , infimum, and in place of , supremum, and .
Predicativity. is predicative by the clause supremum. The formula is with the set variable , which does not occur in , put for , so it has the same quantifiers as ; and is built from , and the formula by connectives and quantifiers over the set variables and . As no quantifier of is applied to a class variable, neither is any quantifier of , and is predicative by Predicativity of Expressions with Abbreviations, and Symbol-Free Forms of the Basic Defined Set Symbols §closure.
Uniqueness. Fix any values of the parameters, and let be a set with . By its first conjunct some set satisfies , and by its second any sets and with and are equal. So exactly one set satisfies .
The partial order . Let be a set. By the clause supremum, holds for a set if and only if is a subset of that has a supremum and . Hence the first conjunct of holds if and only if is a subset of that has a supremum, and then any sets and with and both equal , so the second conjunct holds as well. So holds if and only if is a subset of that has a supremum, and then is the set with . For a subset of , agrees with the formula of Bounds, Least and Greatest Elements, Suprema and Infima for a Partial Order §supremum, by the paragraph Meaning of the clause supremum; so the symbol given by is the supremum of that definition.
The defined set symbol. By the above, and are predicative and, for all values of the parameters and all sets satisfying , exactly one set satisfies ; these are the hypotheses of Predicativity of Expressions with Abbreviations, and Symbol-Free Forms of the Basic Defined Set Symbols §elimination with , for , for and for . By Formulas of the Language of Class Theory, Free Variables, Predicative Formulas and Abbreviations §defined-set-symbols, is then the defined set symbol with argument given by the predicative , and it is used properly where has a supremum, since there exactly one set satisfies .
Clause maps. Suppose first that is a subset of that has a supremum for every . By the clause bound-symbol, is a defined set symbol with argument given by the predicative , used properly where has a supremum; so in the expression every defined set symbol is used properly for every , and by the clause supremum and the conjunct of . Hence Maps and Relations Given by Formulas §map, applied to the sets and and the expression , gives exactly one map with for every . The same argument with and gives the map for the infimum.
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