Proof of Riemann Integrability Criterion via Upper and Lower Sums
theoremthm:calc-riemann-integrability-criterion-2026aSuppose is bounded. Then is Riemann integrable iff for every there exists a partition with . If this holds, refining partitions produces upper sums decreasing and lower sums increasing with arbitrarily small gap, so the upper and lower integrals coincide. Conversely, if is integrable, upper and lower integrals are equal to the common integral value, hence there exists a partition with gap by the definitions of infimum/supremum of upper/lower sums.
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Prerequisites
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