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Proof of On the Real Line the Tangent Space is the Whole Space of Square-Integrable Vector Fields

theoremthm:tangent-space-line-2026a
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· 6,150 chars · 17 deps · depth 28 Reason: Phase B2b: proof that the representation clause supplies a tangent field with the same pairings, whose difference from the given field pairs to zero with every test function once a scaling argument kills the remaining constant.

The representation clause produces a tangent field pairing with all gradients of test functions as the given field does; the difference pairs to zero with every derivative of a test function, hence with every mean-zero test function, hence with every test function once a scaling argument against test functions of arbitrarily large mass kills the remaining constant, and a field pairing to zero with all test functions vanishes.

Proof

Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. By Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §l2mu the triple (R,B(R),μ)(\mathbb{R},\mathcal{B}(\mathbb{R}),\mu) is a probability space and L2(μ;R)L^{2}(\mu;\mathbb{R}) is the space of classes of square-integrable random variables on it, with ξ,ημ=Rξηdμ\langle\xi,\eta\rangle_{\mu}=\int_{\mathbb{R}}\xi\eta\,d\mu and ξμ2=Rξ2dμ\lVert\xi\rVert_{\mu}^{2}=\int_{\mathbb{R}}\xi^{2}\,d\mu, by claim 1 of One-Dimensional Test Functions: Scalars, Derivatives, and the Difference Quotient of the Derivative. For ψCc(R)\psi\in C_{c}^{\infty}(\mathbb{R}) claim 2 of that lemma gives ψ=ψ\nabla\psi=\psi' and ξ,ψμ=Rξψdμ\langle\xi,\nabla\psi\rangle_{\mu}=\int_{\mathbb{R}}\xi\,\psi'\,d\mu. Write λ1\lambda_{1} for the Lebesgue measure on B(R)\mathcal{B}(\mathbb{R}).

Since TμT_{\mu} is a subset of L2(μ;R)L^{2}(\mu;\mathbb{R}) by Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §closed, it suffices to prove the reverse inclusion. Let ηL2(μ;R)\eta\in L^{2}(\mu;\mathbb{R}), and fix a Borel representative of it, again written η\eta.

Step 1 (A tangent field with the same pairings). Define :Cc(R)R\ell:C_{c}^{\infty}(\mathbb{R})\to\mathbb{R} by (ψ)=η,ψμ\ell(\psi)=\langle\eta,\nabla\psi\rangle_{\mu}. It is linear: for ψ,ϕCc(R)\psi,\phi\in C_{c}^{\infty}(\mathbb{R}) and a,bRa,b\in\mathbb{R}, The Gradient of a Test Function is Bounded and Square-Integrable, and Its Laplacian Bounded and Integrable, Against Every Probability Measure §linear gives (aψ+bϕ)=aψ+bϕ\nabla(a\psi+b\phi)=a\nabla\psi+b\nabla\phi, and claim 2 of Linearity and Monotonicity of the Lebesgue Integral gives the linearity of the integral. By claim 1 of Cauchy-Schwarz and Triangle Inequalities for the Mean-Square Norm, applied on the probability space (R,B(R),μ)(\mathbb{R},\mathcal{B}(\mathbb{R}),\mu) to the square-integrable random variables η\eta and ψ\nabla\psi,

(ψ)ημψμfor every ψCc(R).|\ell(\psi)|\le\lVert\eta\rVert_{\mu}\,\lVert\nabla\psi\rVert_{\mu}\qquad\text{for every }\psi\in C_{c}^{\infty}(\mathbb{R}).

Hence Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients §representation, applied with C=ημC=\lVert\eta\rVert_{\mu}, provides ξTμ\xi\in T_{\mu} with ξ,ψμ=(ψ)\langle\xi,\nabla\psi\rangle_{\mu}=\ell(\psi) for every ψCc(R)\psi\in C_{c}^{\infty}(\mathbb{R}).

Put w=ηξL2(μ;R)w=\eta-\xi\in L^{2}(\mu;\mathbb{R}), with a Borel representative again written ww. By linearity of the inner product,

Rwψdμ=0for every ψCc(R).()\int_{\mathbb{R}}w\,\psi'\,d\mu=0\qquad\text{for every }\psi\in C_{c}^{\infty}(\mathbb{R}). \tag{$*$}

If wμ=0\lVert w\rVert_{\mu}=0 then ww is the zero class and η=ξTμ\eta=\xi\in T_{\mu}, as required; so assume 0<wμ0<\lVert w\rVert_{\mu}.

Note that ww is integrable with respect to μ\mu, with Rwdμwμ\int_{\mathbb{R}}|w|\,d\mu\le\lVert w\rVert_{\mu}: this is claim 1 of Cauchy-Schwarz and Triangle Inequalities for the Mean-Square Norm applied to w|w| and the constant random variable 11, whose mean-square norm is 11 since μ\mu is a probability measure.

Step 2 (Pairing with mean-zero test functions). Let φCc(R)\varphi\in C_{c}^{\infty}(\mathbb{R}) with Rφdλ1=0\int_{\mathbb{R}}\varphi\,d\lambda_{1}=0. By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function §primitive there is ψCc(R)\psi\in C_{c}^{\infty}(\mathbb{R}) with ψ=φ\psi'=\varphi, so ()(*) gives

Rwφdμ=0.\int_{\mathbb{R}}w\,\varphi\,d\mu=0 .

Step 3 (Pairing with an arbitrary test function). Let θ\theta be as in Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function §unit, so θCc(R)\theta\in C_{c}^{\infty}(\mathbb{R}) is nonnegative with Rθdλ1=1\int_{\mathbb{R}}\theta\,d\lambda_{1}=1, and put a=Rwθdμa=\int_{\mathbb{R}}w\,\theta\,d\mu, a real number because θ\theta is bounded by A Continuous Compactly Supported Function on Rn\mathbb{R}^n is Bounded and Integrable and ww is integrable.

Let ψCc(R)\psi\in C_{c}^{\infty}(\mathbb{R}) and put c=Rψdλ1c=\int_{\mathbb{R}}\psi\,d\lambda_{1}, a real number by Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function §integrable. By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function §correction the function φ=ψcθ\varphi=\psi-c\,\theta is a test function with φdλ1=0\int\varphi\,d\lambda_{1}=0, so Step 2 and claim 2 of Linearity and Monotonicity of the Lebesgue Integral give

0=Rwφdμ=Rwψdμca,that isRwψdμ=aRψdλ1.()0=\int_{\mathbb{R}}w\,\varphi\,d\mu=\int_{\mathbb{R}}w\,\psi\,d\mu-c\,a,\qquad\text{that is}\qquad \int_{\mathbb{R}}w\,\psi\,d\mu=a\int_{\mathbb{R}}\psi\,d\lambda_{1}. \tag{$**$}

Step 4 (The constant vanishes). Let ε\varepsilon be a positive real number and put C=wμε1C=\lVert w\rVert_{\mu}\,\varepsilon^{-1}, a positive real number by claim 7 of Elementary Order Arithmetic in an Ordered Field and claim 5 of that lemma. By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function §large there is χCc(R)\chi\in C_{c}^{\infty}(\mathbb{R}) with 0χ10\le\chi\le1 and CRχdλ1C\le\int_{\mathbb{R}}\chi\,d\lambda_{1}. Applying ()(**) to χ\chi, and using wχw|w\chi|\le|w| pointwise together with claims 1 and 2 of Linearity and Monotonicity of the Lebesgue Integral,

aCaRχdλ1=RwχdμRwdμwμ,|a|\,C\le|a|\int_{\mathbb{R}}\chi\,d\lambda_{1}=\Bigl|\int_{\mathbb{R}}w\,\chi\,d\mu\Bigr|\le\int_{\mathbb{R}}|w|\,d\mu\le\lVert w\rVert_{\mu},

the first inequality by claim 5 of Elementary Arithmetic in an Ordered Field with the nonnegative factor a|a| and claim 4 of Properties of the Absolute Value in an Ordered Field. Multiplying by the positive C1C^{-1} gives awμC1=ε|a|\le\lVert w\rVert_{\mu}C^{-1}=\varepsilon. As ε\varepsilon was an arbitrary positive real number, Comparison of Real Numbers with Arbitrary Positive Slack §vanishing gives a=0|a|=0, hence a=0a=0 by claim 1 of Properties of the Absolute Value in an Ordered Field.

Step 5 (Conclusion). By ()(**) with a=0a=0,

Rwψdμ=0for every ψCc(R).\int_{\mathbb{R}}w\,\psi\,d\mu=0\qquad\text{for every }\psi\in C_{c}^{\infty}(\mathbb{R}).

Since ww is Borel and integrable with respect to μP(R)\mu\in\mathcal{P}(\mathbb{R}), Test Functions Approximate Bounded Continuous Functions Pointwise, Determine a Finite Borel Measure, and Detect a Vanishing Density §vanishing, applied in dimension d=1d=1 with g=wg=w, gives μ({xR:w(x)0})=0\mu(\{x\in\mathbb{R}:w(x)\ne0\})=0. Hence ww is the zero class of L2(μ;R)L^{2}(\mu;\mathbb{R}) by Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §l2mu, contradicting 0<wμ0<\lVert w\rVert_{\mu}; so that case does not occur, and η=ξTμ\eta=\xi\in T_{\mu}.

Therefore L2(μ;R)TμL^{2}(\mu;\mathbb{R})\subseteq T_{\mu}, and with the reverse inclusion noted at the outset, Tμ=L2(μ;R)T_{\mu}=L^{2}(\mu;\mathbb{R}).

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