The representation clause produces a tangent field pairing with all gradients of test functions as the given field does; the difference pairs to zero with every derivative of a test function, hence with every mean-zero test function, hence with every test function once a scaling argument against test functions of arbitrarily large mass kills the remaining constant, and a field pairing to zero with all test functions vanishes.
Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here. By Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation (ii) the triple is a probability space and is the space of classes of square-integrable random variables on it, with and , by claim 1 of One-Dimensional Test Functions: Scalars, Derivatives, and the Difference Quotient of the Derivative. For claim 2 of that lemma gives and . Write for the Lebesgue measure on .
Since is a subset of by Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients (i), it suffices to prove the reverse inclusion. Let , and fix a Borel representative of it, again written .
Step 1 (A tangent field with the same pairings). Define by . It is linear: for and , The Gradient of a Test Function is Bounded and Square-Integrable, and Its Laplacian Bounded and Integrable, Against Every Probability Measure (iii) gives , and claim 2 of Linearity and Monotonicity of the Lebesgue Integral, and the Integrability Criterion gives the linearity of the integral. By claim 1 of Cauchy-Schwarz and Triangle Inequalities for the Mean-Square Norm, applied on the probability space to the square-integrable random variables and ,
Hence Basic Properties of the Tangent Space: Closed Subspace, the Identity Map Belongs to It, Second-Moment Limits, and Representation of Bounded Functionals on Gradients (iv), applied with , provides with for every .
Put , with a Borel representative again written . By linearity of the inner product,
If then is the zero class and , as required; so assume .
Note that is integrable with respect to , with : this is claim 1 of Cauchy-Schwarz and Triangle Inequalities for the Mean-Square Norm applied to and the constant random variable , whose mean-square norm is since is a probability measure.
Step 2 (Pairing with mean-zero test functions). Let with . By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function (v) there is with , so gives
Step 3 (Pairing with an arbitrary test function). Let be as in Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function (ii), so is nonnegative with , and put , a real number because is bounded by A Continuous Compactly Supported Function on is Bounded and Integrable and is integrable.
Let and put , a real number by Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function (i). By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function (iv) the function is a test function with , so Step 2 and claim 2 of Linearity and Monotonicity of the Lebesgue Integral, and the Integrability Criterion give
Step 4 (The constant vanishes). Let be a positive real number and put , a positive real number by claim 7 of Elementary Order Arithmetic in an Ordered Field and claim 5 of that lemma. By Test Functions on the Real Line: Unit Mass, Large Mass, Mean-Zero Correction, and the Primitive of a Mean-Zero Test Function (iii) there is with and . Applying to , and using pointwise together with claims 1 and 2 of Linearity and Monotonicity of the Lebesgue Integral, and the Integrability Criterion,
the first inequality by claim 5 of Elementary Arithmetic in an Ordered Field with the nonnegative factor and claim 4 of Properties of the Absolute Value in an Ordered Field. Multiplying by the positive gives . As was an arbitrary positive real number, Comparison of Real Numbers with Arbitrary Positive Slack (iii) gives , hence by claim 1 of Properties of the Absolute Value in an Ordered Field.
Step 5 (Conclusion). By with ,
Since is Borel and integrable with respect to , Test Functions Approximate Bounded Continuous Functions Pointwise, Determine a Finite Borel Measure, and Detect a Vanishing Density (iii), applied in dimension with , gives . Hence is the zero class of by Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation (ii), contradicting ; so that case does not occur, and .
Therefore , and with the reverse inclusion noted at the outset, .
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