TheoremBase

Proof

Claim 1.

The initial covariance. By hypothesis (I) the matrix Π0\Pi_{0} is symmetric. Suppose it were not positive semidefinite, so that x⋅(Π0x)=−2η0<0x\cdot(\Pi_{0}x)=-2\eta_{0}<0 for some x∈Rlx\in\mathbb{R}^{l}. Put ζ=η0/(1+∑γ,δ∣xγxδ∣)>0\zeta=\eta_{0}/\bigl(1+\sum_{\gamma,\delta}|x^{\gamma}x^{\delta}|\bigr)>0. By hypothesis (I) and the definition of the limit of a real sequence, applied to each of the finitely many sequences (E[s0γs0δ])N≥1\bigl(\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]\bigr)_{N\ge1}, there is N′N' such that ∣E[s0γs0δ]−Π0γδ∣≤ζ\bigl|\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]-\Pi^{\gamma\delta}_{0}\bigr|\le\zeta for all γ,δ\gamma,\delta and all N≥N′N\ge N'. For such NN, by the linearity of the integral,

E[(x⋅s0)2]=∑γ,δxγxδ E[s0γs0δ] ≤ ∑γ,δxγxδ Π0γδ+ζ∑γ,δ∣xγxδ∣ ≤ −2η0+η0<0,\mathbb{E}\bigl[(x\cdot\mathfrak{s}_{0})^{2}\bigr]=\sum_{\gamma,\delta}x^{\gamma}x^{\delta}\,\mathbb{E}[\mathfrak{s}^{\gamma}_{0}\mathfrak{s}^{\delta}_{0}]\ \le\ \sum_{\gamma,\delta}x^{\gamma}x^{\delta}\,\Pi^{\gamma\delta}_{0}+\zeta\sum_{\gamma,\delta}|x^{\gamma}x^{\delta}|\ \le\ -2\eta_{0}+\eta_{0}<0,

contradicting the nonnegativity of the expectation of the nonnegative random variable (x⋅s0)2(x\cdot\mathfrak{s}_{0})^{2}. Hence Π0\Pi_{0} is positive semidefinite.

The coefficient families. Every entry of t↦Et=Ett\mapsto E_{t}=\mathcal{E}_{t} is continuous on [0,T][0,T] by conclusion (a) of the completion-of-squares theorem. Every entry of t↦Θt⋆t\mapsto\Theta^{\star}_{t} is continuous by clause (c) of the covariance deviation lemma, and every Θt⋆\Theta^{\star}_{t} is positive semidefinite, hence symmetric, by claim 3 of the covariance positivity lemma.

Under (OC) each Θ~t⋆\tilde{\Theta}^{\star}_{t} is the diagonal matrix with diagonal entries b~υ(St)≥β~min⁡>0\tilde{b}^{\upsilon}(S_{t})\ge\tilde{\beta}_{\min}>0; the diagonal matrix with diagonal entries 1/b~υ(St)1/\tilde{b}^{\upsilon}(S_{t}) is its inverse, as the index formula for the matrix product shows, and its entries are continuous in tt by the continuity of the reciprocal of a nonvanishing continuous function. Consequently

D~tγδ=∑υ=1l~E~tυγ E~tυδb~υ(St),\tilde{D}^{\gamma\delta}_{t}=\sum_{\upsilon=1}^{\tilde{l}}\frac{\tilde{\mathcal{E}}^{\upsilon\gamma}_{t}\,\tilde{\mathcal{E}}^{\upsilon\delta}_{t}}{\tilde{b}^{\upsilon}(S_{t})},

which is symmetric in (γ,δ)(\gamma,\delta) and continuous in tt by the continuity of sums and products; and for x∈Rlx\in\mathbb{R}^{l},

x⋅(D~tx)=∑υ=1l~((E~tx)υ)2b~υ(St) ≥ 0,x\cdot(\tilde{D}_{t}x)=\sum_{\upsilon=1}^{\tilde{l}}\frac{\bigl((\tilde{\mathcal{E}}_{t}x)^{\upsilon}\bigr)^{2}}{\tilde{b}^{\upsilon}(S_{t})}\ \ge\ 0,

so every D~t\tilde{D}_{t} is positive semidefinite. The Riccati existence theorem therefore applies on [0,T][0,T] with kk there equal to ll, A=EA=\mathcal{E}, C=Θ⋆C=\Theta^{\star}, D=D~D=\tilde{D} and P0=Π0P_{0}=\Pi_{0}, and yields the unique Π\Pi with continuous entries, every Πt\Pi_{t} being symmetric and satisfying 0⪯Πt0\preceq\Pi_{t}, that is, positive semidefinite.

The weight Ξ\Xi. Every Ξt\Xi_{t} is symmetric positive semidefinite with continuous entries by claim 2 of the cascade filtering lemma. Fix tt. Under (H1), conclusion (a) of the completion-of-squares theorem gives that RtR_{t} is symmetric positive definite, so Rt−1R_{t}^{-1} is symmetric positive definite by Invertibility of Positive Definite Matrices, and by the Cholesky factorisation there is a real matrix LtL_{t} with mm rows and mm columns and Rt−1=LtLt⊤R_{t}^{-1}=L_{t}L_{t}^{\top}. Put Bt=WtLtB_{t}=W_{t}L_{t}, a real matrix with ll rows and mm columns (this matrix always carries a time subscript and is distinct from the control matrix Bt\mathsf{B}_{t} and from the rate bound BB of the common data), and let bt,1,…,bt,m∈Rlb_{t,1},\dots,b_{t,m}\in\mathbb{R}^{l} be its columns, so that (Bt)γj=bt,jγ(B_{t})_{\gamma j}=b^{\gamma}_{t,j}. Then

Ξt=WtLtLt⊤Wt⊤=BtBt⊤,that isΞtγδ=∑j=1mbt,jγbt,jδ,\Xi_{t}=W_{t}L_{t}L_{t}^{\top}W_{t}^{\top}=B_{t}B_{t}^{\top},\qquad\text{that is}\qquad\Xi^{\gamma\delta}_{t}=\sum_{j=1}^{m}b^{\gamma}_{t,j}b^{\delta}_{t,j},

by the index formula for the matrix product and the transpose. Hence, for every real matrix M\mathcal{M} with ll rows and ll columns,

∑γ=1l∑δ=1lΞtγδ Mγδ=∑j=1m∑γ,δbt,jγbt,jδMγδ=∑j=1mbt,j⋅(M bt,j),\sum_{\gamma=1}^{l}\sum_{\delta=1}^{l}\Xi^{\gamma\delta}_{t}\,\mathcal{M}^{\gamma\delta}=\sum_{j=1}^{m}\sum_{\gamma,\delta}b^{\gamma}_{t,j}b^{\delta}_{t,j}\mathcal{M}^{\gamma\delta}=\sum_{j=1}^{m}b_{t,j}\cdot\bigl(\mathcal{M}\,b_{t,j}\bigr),

called the column identity below. Taking M=Πt\mathcal{M}=\Pi_{t} shows ∑γ,δΞtγδΠtγδ≥0\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{t}\Pi^{\gamma\delta}_{t}\ge0, every Πt\Pi_{t} being positive semidefinite. That function of tt is a finite sum of products of continuous functions, hence continuous, and therefore Lebesgue integrable on [0,T][0,T] by claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval. This proves claim 1.

Claim 2. Fix s∈[0,T]s\in[0,T], c∈Rlc\in\mathbb{R}^{l} and η>0\eta>0, and put κ=c⋅(Πsc)\kappa=c\cdot(\Pi_{s}c), a nonnegative real by claim 1.

The filtering error of Xs′X'_{s}. Let N≥1N\ge1 and put Δs=Xs′−ss=N (Ss−Φs)\Delta_{s}=X'_{s}-\mathfrak{s}_{s}=\sqrt{N}\,(S_{s}-\Phi_{s}). Each component Δsγ\Delta^{\gamma}_{s} is Gs\mathcal{G}_{s}-measurable, being the constant NSsγ\sqrt{N}S^{\gamma}_{s} minus the Gs\mathcal{G}_{s}-measurable random variable NΦsγ\sqrt{N}\Phi^{\gamma}_{s} (claim 3 of the realized-flow adaptedness lemma), and is square-integrable as the difference of the square-integrable Xs′γX'^{\gamma}_{s} and ssγ\mathfrak{s}^{\gamma}_{s}. By the second immediate consequence recorded in the conditional-expectation definition, Δsγ\Delta^{\gamma}_{s} is a conditional expectation of itself given Gs\mathcal{G}_{s}. Let MsγM^{\gamma}_{s} be the conditional expectation of ssγ\mathfrak{s}^{\gamma}_{s} chosen in the definition of εsγ=ssγ−Msγ\varepsilon^{\gamma}_{s}=\mathfrak{s}^{\gamma}_{s}-M^{\gamma}_{s}. By claim 1 of the conditional expectation properties lemma, Msγ+ΔsγM^{\gamma}_{s}+\Delta^{\gamma}_{s} is a conditional expectation of ssγ+Δsγ=Xs′γ\mathfrak{s}^{\gamma}_{s}+\Delta^{\gamma}_{s}=X'^{\gamma}_{s} given Gs\mathcal{G}_{s}, so by the uniqueness part of the existence and uniqueness theorem every conditional expectation M~γ\tilde{M}^{\gamma} of Xs′γX'^{\gamma}_{s} given Gs\mathcal{G}_{s} satisfies M~γ=Msγ+Δsγ\tilde{M}^{\gamma}=M^{\gamma}_{s}+\Delta^{\gamma}_{s} almost surely, whence

Xs′γ−M~γ = ssγ+Δsγ−Msγ−Δsγ = εsγalmost surely.X'^{\gamma}_{s}-\tilde{M}^{\gamma}\ =\ \mathfrak{s}^{\gamma}_{s}+\Delta^{\gamma}_{s}-M^{\gamma}_{s}-\Delta^{\gamma}_{s}\ =\ \varepsilon^{\gamma}_{s}\qquad\text{almost surely.}

This is the first assertion of claim 2. In particular, whenever Localized Filtering Lower Bound from a Mixture-Weight van Trees Certificate is applied below to the tuple X=Xs′X=X'_{s} and the sub-σ\sigma-algebra Gs\mathcal{G}_{s}, its filtering error ε\varepsilon is almost surely equal to εs\varepsilon_{s}, so that every expectation of a function of ε\varepsilon appearing in its conclusions equals the same expectation with εs\varepsilon_{s} in place of ε\varepsilon (almost surely equal integrable random variables have equal expectations), and the same applies to the quantities of its claims 1 and 2 with 1H≡1\mathbf{1}_{\mathcal{H}}\equiv1.

The fourth moment. By The Empirical State Measure Deviates from the Realized Mean-Field Flow by at Most the Noise Majorant, ∣Xs′∣=N ∣Σs−Φs∣≤N Q|X'_{s}|=\sqrt{N}\,|\Sigma_{s}-\Phi_{s}|\le\sqrt{N}\,Q at every point of Ω0\Omega_{0}, and P(Ω0)=1P(\Omega_{0})=1 by the definition of the solution. Hence ∣Xs′∣4≤N2Q4|X'_{s}|^{4}\le N^{2}Q^{4} almost surely, and by the monotonicity of the integral (a null set not affecting integrals) and claim 2 of the pre-stopping envelope lemma,

E[∣Xs′∣4] ≤ N2 E[Q4] ≤ N2 cQ κ0 N−2 = cQκ0 ≤ cQκ♯,\mathbb{E}\bigl[|X'_{s}|^{4}\bigr]\ \le\ N^{2}\,\mathbb{E}\bigl[Q^{4}\bigr]\ \le\ N^{2}\,c_{Q}\,\kappa_{0}\,N^{-2}\ =\ c_{Q}\kappa_{0}\ \le\ c_{Q}\kappa^{\sharp},

the last step by hypothesis (I′'). This is the moment bound of claim 2. In particular ∣Xs′∣2|X'_{s}|^{2} is square-integrable.

Apply Adjoint Energy Identity for the Kalman Covariance Riccati Equation with the endpoints 00 and TT in the roles of aa and bb there, kk there equal to ll, the data E\mathcal{E}, Θ⋆\Theta^{\star}, D~\tilde{D}, Π0\Pi_{0} and Π\Pi of claim 1, the time ss and the vector x=cx=c. It produces an assignment λ\lambda with continuous components and λ(s)=c\lambda(s)=c, and by its claim 2 the assignment u↦Πuλ(u)u\mapsto\Pi_{u}\lambda(u) has continuous components and satisfies the integral equation defining ψλ\psi_{\lambda} — that lemma writes its integrals as Riemann integrals of continuous functions, which coincide with the Lebesgue integrals over compact intervals used here by claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval; by the uniqueness in claim 3 of the variation of constants theorem, ψλ(u)=Πuλ(u)\psi_{\lambda}(u)=\Pi_{u}\lambda(u) for every uu. Its claim 3 then gives

c⋅ψλ(s)=c⋅(Πsc)=κandAs(λ)=κ,c\cdot\psi_{\lambda}(s)=c\cdot(\Pi_{s}c)=\kappa\qquad\text{and}\qquad\mathcal{A}_{s}(\lambda)=\kappa,

the second because the energy displayed there is exactly As(λ)\mathcal{A}_{s}(\lambda) once ψλ=Πλ\psi_{\lambda}=\Pi\lambda is substituted, its Riemann integral again agreeing with the Lebesgue integral in the definition of As(λ)\mathcal{A}_{s}(\lambda) by claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval (the integrand is continuous by claim 3 of Adjoint Energy Identity for the Kalman Covariance Riccati Equation).

Suppose first κ=0\kappa=0. Apply (VT) with this λ\lambda and with ϵ=1\epsilon=1, obtaining N2N_{2}; for N≥N2N\ge N_{2} the data of (VT) exist, and taking ϰ=0\varkappa=0, which satisfies (C4) because (α⋅z)2≥0=0⋅(z⋅(Iz))(\alpha\cdot z)^{2}\ge0=0\cdot\bigl(z\cdot(\mathcal{I}z)\bigr), they form a van Trees certificate for the data (Xs′,Gs,Ω,c)(X'_{s},\mathcal{G}_{s},\Omega,c); claim 1 of Localized Filtering Lower Bound from a Mixture-Weight van Trees Certificate is therefore available (only the presence of a certificate is used here, not its tolerance or its value) and gives, with 1Ω≡1\mathbf{1}_{\Omega}\equiv1 and the almost-sure identification of the filtering errors made above,

E[∑γ,δcγcδεsγεsδ]=E[(c⋅εs)2] ≥ 0=κ ≥ κ−η,\mathbb{E}\Bigl[\sum_{\gamma,\delta}c^{\gamma}c^{\delta}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\Bigr]=\mathbb{E}\bigl[(c\cdot\varepsilon_{s})^{2}\bigr]\ \ge\ 0=\kappa\ \ge\ \kappa-\eta,

the inequality being the nonnegativity of the expectation of a nonnegative random variable. Take N3=N2N_{3}=N_{2}.

Suppose now κ>0\kappa>0, and put

ϵ=min⁡{κ8, κ2, η3+2κ}>0,ϰ=(κ−ϵ)2κ+ϵ,\epsilon=\min\Bigl\{\frac{\kappa}{8},\ \frac{\sqrt{\kappa}}{2},\ \frac{\eta}{3+2\sqrt{\kappa}}\Bigr\}>0,\qquad \varkappa=\frac{(\kappa-\epsilon)^{2}}{\kappa+\epsilon},

with ⋅\sqrt{\cdot} the nonnegative square root. Apply (VT) with this λ\lambda and this ϵ\epsilon, obtaining N2N_{2}, and let N≥N3=N2N\ge N_{3}=N_{2} and let dd, (Y,Y)(\mathsf{Y},\mathcal{Y}), ϱ0\varrho_{0}, D\mathsf{D}, ϑ1,…,ϑd\vartheta_{1},\dots,\vartheta_{d}, α\alpha, zz, GG be data as provided by (VT). Then

α⋅z ≥ κ−ϵ > 0,z⋅(Iz) ≤ κ+ϵ,\alpha\cdot z\ \ge\ \kappa-\epsilon\ >\ 0,\qquad z\cdot(\mathcal{I}z)\ \le\ \kappa+\epsilon,

so (α⋅z)2≥(κ−ϵ)2=ϰ (κ+ϵ)≥ϰ (z⋅(Iz))(\alpha\cdot z)^{2}\ge(\kappa-\epsilon)^{2}=\varkappa\,(\kappa+\epsilon)\ge\varkappa\,\bigl(z\cdot(\mathcal{I}z)\bigr), which is condition (C4) with this ϰ\varkappa; here ϰ≥0\varkappa\ge0 and z⋅(Iz)>0z\cdot(\mathcal{I}z)>0 by claim 1 of Rank-One Lower Bound for the Inverse of a Positive Definite Matrix.

Three elementary estimates follow from 0<ϵ≤κ/80<\epsilon\le\kappa/8 and ϵ≤κ/2\epsilon\le\sqrt{\kappa}/2. First, (κ−3ϵ)(κ+ϵ)=κ2−2κϵ−3ϵ2≤κ2−2κϵ+ϵ2=(κ−ϵ)2(\kappa-3\epsilon)(\kappa+\epsilon)=\kappa^{2}-2\kappa\epsilon-3\epsilon^{2}\le\kappa^{2}-2\kappa\epsilon+\epsilon^{2}=(\kappa-\epsilon)^{2}, so ϰ≥κ−3ϵ\varkappa\ge\kappa-3\epsilon. Second, ϵ≤3κ\epsilon\le3\kappa gives ϵ2≤3κϵ\epsilon^{2}\le3\kappa\epsilon, hence (κ−ϵ)2=κ2−2κϵ+ϵ2≤κ2+κϵ=κ(κ+ϵ)(\kappa-\epsilon)^{2}=\kappa^{2}-2\kappa\epsilon+\epsilon^{2}\le\kappa^{2}+\kappa\epsilon=\kappa(\kappa+\epsilon) and therefore ϰ≤κ\varkappa\le\kappa and ϰ≤κ\sqrt{\varkappa}\le\sqrt{\kappa}. Third, ϰ≥κ−3ϵ≥κ−3κ/8≥κ/4≥ϵ2\varkappa\ge\kappa-3\epsilon\ge\kappa-3\kappa/8\ge\kappa/4\ge\epsilon^{2}, so ϰ≥ϵ\sqrt{\varkappa}\ge\epsilon.

Claim 2 of Localized Filtering Lower Bound from a Mixture-Weight van Trees Certificate, for the data (Xs′,Gs,Ω,c)(X'_{s},\mathcal{G}_{s},\Omega,c), is therefore available and gives, together with its claim 1 and the almost-sure identification of the filtering errors made above,

E[∑γ,δcγcδεsγεsδ] ≥ (ϰ−ϵ)2=ϰ−2ϵϰ+ϵ2 ≥ ϰ−2ϵκ ≥ κ−3ϵ−2ϵκ ≥ κ−η,\mathbb{E}\Bigl[\sum_{\gamma,\delta}c^{\gamma}c^{\delta}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\Bigr]\ \ge\ \bigl(\sqrt{\varkappa}-\epsilon\bigr)^{2}=\varkappa-2\epsilon\sqrt{\varkappa}+\epsilon^{2}\ \ge\ \varkappa-2\epsilon\sqrt{\kappa}\ \ge\ \kappa-3\epsilon-2\epsilon\sqrt{\kappa}\ \ge\ \kappa-\eta,

the last step by the choice ϵ≤η/(3+2κ)\epsilon\le\eta/(3+2\sqrt{\kappa}). This proves claim 2.

Claim 3. Fix an admissible parameter vector π\pi satisfying the absorption condition, fix η>0\eta>0, and for k∈{0,…,K−1}k\in\{0,\dots,K-1\} and N≥1N\ge1 define

fN(k)(s)=E[1Tknr(s) us⋅Rsus](s∈[tk,tk+1]).f^{(k)}_{N}(s)=\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}\,u_{s}\cdot R_{s}u_{s}\bigr]\qquad(s\in[t_{k},t_{k+1}]).

Each fN(k)f^{(k)}_{N} is nonnegative, because us⋅Rsus≥r∣us∣2≥0u_{s}\cdot R_{s}u_{s}\ge r|u_{s}|^{2}\ge0 by (H1), and is measurable on [tk,tk+1][t_{k},t_{k+1}] by hypothesis (MS); its integral over that block is the kk-th summand appearing in claim 7 of the ledger lemma. Define also the bad sets and their probabilities

Ck(s)=Ω∖Tknr(s),pN(k)(s)=P(Ck(s))(s∈[tk,tk+1]).\mathcal{C}_{k}(s)=\Omega\setminus\mathcal{T}^{\mathrm{nr}}_{k}(s),\qquad p^{(k)}_{N}(s)=P\bigl(\mathcal{C}_{k}(s)\bigr)\qquad(s\in[t_{k},t_{k+1}]).

By claim 2 of the ledger lemma Tknr(s)∈Gs\mathcal{T}^{\mathrm{nr}}_{k}(s)\in\mathcal{G}_{s}, so Ck(s)∈Gs\mathcal{C}_{k}(s)\in\mathcal{G}_{s}, a σ\sigma-algebra being closed under complements. By the definitions in the ledger lemma, Tk(s)\mathcal{T}_{k}(s) is the disjoint union of Tknr(s)\mathcal{T}^{\mathrm{nr}}_{k}(s) and Tkfr(s)\mathcal{T}^{\mathrm{fr}}_{k}(s), so Ck(s)\mathcal{C}_{k}(s) is the disjoint union of Ω∖Tk(s)\Omega\setminus\mathcal{T}_{k}(s) and Tkfr(s)\mathcal{T}^{\mathrm{fr}}_{k}(s) and

pN(k)(s)=E[1−1Tk(s)]+E[1Tkfr(s)],p^{(k)}_{N}(s)=\mathbb{E}\bigl[1-\mathbf{1}_{\mathcal{T}_{k}(s)}\bigr]+\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{fr}}_{k}(s)}\bigr],

a function measurable on [tk,tk+1][t_{k},t_{k+1}] by hypothesis (MS) and claim 2 of the arithmetic of measurable functions, with values in [0,1][0,1]. Its integral over the block is the sum of the integrals of the two summands, by the linearity of the integral (both summands are nonnegative, measurable and bounded by 11, so by monotonicity their integrals are at most tk+1−tkt_{k+1}-t_{k}, the measure of the block by claim 1 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval); summing over the blocks and using claims 1(c) and 1(d) of the ledger lemma,

∑k=0K−1∫[tk,tk+1]pN(k)(s) ds ≤ T P+ZNϱ2 ≤ (TΛ⋆Υlev+ϱ−2)ZN,\sum_{k=0}^{K-1}\int_{[t_{k},t_{k+1}]}p^{(k)}_{N}(s)\,ds\ \le\ T\,\mathcal{P}+\frac{\mathcal{Z}}{N\varrho^{2}}\ \le\ \bigl(T\Lambda_{\star}\Upsilon_{\mathrm{lev}}+\varrho^{-2}\bigr)\frac{\mathcal{Z}}{N},

with P≤Λ⋆Z ΥlevN−1\mathcal{P}\le\Lambda_{\star}\mathcal{Z}\,\Upsilon_{\mathrm{lev}}N^{-1} from claim 1(d). Since π\pi satisfies the absorption condition, part (a) of the asymptotic lower bound theorem provides N1N_{1} with Z≤Z♯(π)\mathcal{Z}\le\mathcal{Z}^{\sharp}(\pi) for N≥N1N\ge N_{1}. Put Cπ=(TΛ⋆Υlev+ϱ−2) Z♯(π)C_{\pi}=(T\Lambda_{\star}\Upsilon_{\mathrm{lev}}+\varrho^{-2})\,\mathcal{Z}^{\sharp}(\pi), a real number that does not depend on NN: ϱ\varrho is a component of π\pi; Λ⋆\Lambda_{\star} and the level sum Υlev=∑k=0K−1Lk−2\Upsilon_{\mathrm{lev}}=\sum_{k=0}^{K-1}L_{k}^{-2} of the ledger lemma are given by the explicit formulas Λ⋆=max⁡(4Ca2K22T0,λc,λo)\Lambda_{\star}=\max(4C_{a}^{2}K_{2}^{2}T_{0},\lambda_{c},\lambda_{o}) and Lk=(2Ca)k+1−Kε1L_{k}=(2C_{a})^{k+1-K}\varepsilon_{1} of the block cascade lemma, in which KK is determined by T0T_{0} and TT, the constant CaC_{a} by ll, Λb\Lambda_{b} and TT, and K2K_{2} is one of the constants of the ledger lemma that the asymptotic lower bound theorem records as being the same for every NN; so neither depends on NN; and Z♯(π)\mathcal{Z}^{\sharp}(\pi) is the real number of part (a) of that theorem. Every summand on the left being nonnegative,

∫[tk,tk+1]pN(k)(s) ds ≤ CπN(k∈{0,…,K−1}, N≥N1).(3.1)\int_{[t_{k},t_{k+1}]}p^{(k)}_{N}(s)\,ds\ \le\ \frac{C_{\pi}}{N}\qquad(k\in\{0,\dots,K-1\},\ N\ge N_{1}). \tag{3.1}

The bad-set estimate. Fix kk, s∈[tk,tk+1]s\in[t_{k},t_{k+1}], c∈Rlc\in\mathbb{R}^{l} and N≥1N\ge1, write C=Ck(s)\mathcal{C}=\mathcal{C}_{k}(s) and p=pN(k)(s)p=p^{(k)}_{N}(s), and let M~γ\tilde{M}^{\gamma} be conditional expectations of Xs′γX'^{\gamma}_{s} given Gs\mathcal{G}_{s}, so that c⋅εs=c⋅Xs′−c⋅M~c\cdot\varepsilon_{s}=c\cdot X'_{s}-c\cdot\tilde{M} almost surely by claim 2, where c⋅M~=∑γcγM~γc\cdot\tilde{M}=\sum_{\gamma}c^{\gamma}\tilde{M}^{\gamma}. By claim 1 of the conditional expectation properties lemma, c⋅M~c\cdot\tilde{M} is a conditional expectation of c⋅Xs′c\cdot X'_{s} given Gs\mathcal{G}_{s}; by claim 4 of that lemma, applied with the bounded Gs\mathcal{G}_{s}-measurable Z=1CZ=\mathbf{1}_{\mathcal{C}}, the random variables 1C(c⋅Xs′)\mathbf{1}_{\mathcal{C}}(c\cdot X'_{s}) and 1C(c⋅M~)\mathbf{1}_{\mathcal{C}}(c\cdot\tilde{M}) are square-integrable and the latter is a conditional expectation of the former given Gs\mathcal{G}_{s}; and by claim 6 of that lemma, ∥1C(c⋅M~)∥2≤∥1C(c⋅Xs′)∥2\lVert\mathbf{1}_{\mathcal{C}}(c\cdot\tilde{M})\rVert_{2}\le\lVert\mathbf{1}_{\mathcal{C}}(c\cdot X'_{s})\rVert_{2}. Since 1C(c⋅εs)=1C(c⋅Xs′)−1C(c⋅M~)\mathbf{1}_{\mathcal{C}}(c\cdot\varepsilon_{s})=\mathbf{1}_{\mathcal{C}}(c\cdot X'_{s})-\mathbf{1}_{\mathcal{C}}(c\cdot\tilde{M}) almost surely, and almost surely equal random variables have the same mean-square norm, claim 2 of the triangle inequality for the mean-square norm gives ∥1C(c⋅εs)∥2≤2∥1C(c⋅Xs′)∥2\lVert\mathbf{1}_{\mathcal{C}}(c\cdot\varepsilon_{s})\rVert_{2}\le2\lVert\mathbf{1}_{\mathcal{C}}(c\cdot X'_{s})\rVert_{2}, hence

E[1C(c⋅εs)2] ≤ 4 E[1C(c⋅Xs′)2] ≤ 4∣c∣2 E[1C ∣Xs′∣2] ≤ 4∣c∣2 ∥1C∥2 ∥∣Xs′∣2∥2 ≤ 4∣c∣2 C4 p,(3.2)\mathbb{E}\bigl[\mathbf{1}_{\mathcal{C}}(c\cdot\varepsilon_{s})^{2}\bigr]\ \le\ 4\,\mathbb{E}\bigl[\mathbf{1}_{\mathcal{C}}(c\cdot X'_{s})^{2}\bigr]\ \le\ 4|c|^{2}\,\mathbb{E}\bigl[\mathbf{1}_{\mathcal{C}}\,|X'_{s}|^{2}\bigr]\ \le\ 4|c|^{2}\,\lVert\mathbf{1}_{\mathcal{C}}\rVert_{2}\,\bigl\lVert|X'_{s}|^{2}\bigr\rVert_{2}\ \le\ 4|c|^{2}\,C_{4}\,\sqrt{p}, \tag{3.2}

where C4=(cQκ♯)1/2C_{4}=(c_{Q}\kappa^{\sharp})^{1/2}: the second step is (c⋅Xs′)2≤∣c∣2∣Xs′∣2(c\cdot X'_{s})^{2}\le|c|^{2}|X'_{s}|^{2} pointwise, by the Cauchy–Schwarz inequality for the dot product, together with the monotonicity of the integral; the third is claim 1 of the Cauchy–Schwarz inequality for the mean-square norm, applied to the square-integrable random variables 1C\mathbf{1}_{\mathcal{C}} and ∣Xs′∣2|X'_{s}|^{2} (the latter by the moment bound of claim 2); the fourth uses ∥1C∥22=E[1C]=p\lVert\mathbf{1}_{\mathcal{C}}\rVert_{2}^{2}=\mathbb{E}[\mathbf{1}_{\mathcal{C}}]=p and ∥∣Xs′∣2∥22=E[∣Xs′∣4]≤cQκ♯\lVert|X'_{s}|^{2}\rVert_{2}^{2}=\mathbb{E}[|X'_{s}|^{4}]\le c_{Q}\kappa^{\sharp} from claim 2, the nonnegative square root being nondecreasing.

Lower bound for the tracked density. For s∈[0,T]s\in[0,T] put τs=∑γΞsγγ\tau_{s}=\sum_{\gamma}\Xi^{\gamma\gamma}_{s}; the function s↦τss\mapsto\tau_{s} is continuous on [0,T][0,T] by claim 1, hence by the extreme value theorem there is a real τ♯\tau^{\sharp} with τs≤τ♯\tau_{s}\le\tau^{\sharp} for every s∈[0,T]s\in[0,T], and τ♯≥0\tau^{\sharp}\ge0 because τs=∑j=1m∑γ(bs,jγ)2≥0\tau_{s}=\sum_{j=1}^{m}\sum_{\gamma}(b^{\gamma}_{s,j})^{2}\ge0 by the factorisation Ξsγδ=∑jbs,jγbs,jδ\Xi^{\gamma\delta}_{s}=\sum_{j}b^{\gamma}_{s,j}b^{\delta}_{s,j} of claim 1. Now fix kk and s∈[tk,tk+1]s\in[t_{k},t_{k+1}], and write H=Tknr(s)\mathcal{H}=\mathcal{T}^{\mathrm{nr}}_{k}(s) and C=Ck(s)\mathcal{C}=\mathcal{C}_{k}(s), so that 1H=1−1C\mathbf{1}_{\mathcal{H}}=1-\mathbf{1}_{\mathcal{C}}. Since H∈Gs\mathcal{H}\in\mathcal{G}_{s}, claim 3 of the cascade filtering lemma gives

fN(k)(s) ≥ ∑γ,δΞsγδ E[1Hεsγεsδ]=∑j=1mE[1H(bs,j⋅εs)2]=∑j=1m(E[(bs,j⋅εs)2]−E[1C(bs,j⋅εs)2]),f^{(k)}_{N}(s)\ \ge\ \sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\,\mathbb{E}\bigl[\mathbf{1}_{\mathcal{H}}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}\bigr]=\sum_{j=1}^{m}\mathbb{E}\bigl[\mathbf{1}_{\mathcal{H}}(b_{s,j}\cdot\varepsilon_{s})^{2}\bigr]=\sum_{j=1}^{m}\Bigl(\mathbb{E}\bigl[(b_{s,j}\cdot\varepsilon_{s})^{2}\bigr]-\mathbb{E}\bigl[\mathbf{1}_{\mathcal{C}}(b_{s,j}\cdot\varepsilon_{s})^{2}\bigr]\Bigr),

the first equality by the column identity of claim 1 applied to the matrix Mγδ=E[1Hεsγεsδ]\mathcal{M}^{\gamma\delta}=\mathbb{E}[\mathbf{1}_{\mathcal{H}}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s}], by the pointwise identity (b⋅εs)2=∑γ,δbγbδεsγεsδ(b\cdot\varepsilon_{s})^{2}=\sum_{\gamma,\delta}b^{\gamma}b^{\delta}\varepsilon^{\gamma}_{s}\varepsilon^{\delta}_{s} and by the linearity of the integral, the second by 1H=1−1C\mathbf{1}_{\mathcal{H}}=1-\mathbf{1}_{\mathcal{C}} and linearity again. Now ∑j=1m∣bs,j∣2=∑j∑γ(bs,jγ)2=τs≤τ♯\sum_{j=1}^{m}|b_{s,j}|^{2}=\sum_{j}\sum_{\gamma}(b^{\gamma}_{s,j})^{2}=\tau_{s}\le\tau^{\sharp}. Applying (3.2) to each c=bs,jc=b_{s,j} and summing,

fN(k)(s) ≥ ∑j=1mE[(bs,j⋅εs)2]−4C4τ♯pN(k)(s)(s∈[tk,tk+1], N≥1).(3.3)f^{(k)}_{N}(s)\ \ge\ \sum_{j=1}^{m}\mathbb{E}\bigl[(b_{s,j}\cdot\varepsilon_{s})^{2}\bigr]-4C_{4}\tau^{\sharp}\sqrt{p^{(k)}_{N}(s)}\qquad(s\in[t_{k},t_{k+1}],\ N\ge1). \tag{3.3}

Passage to the limit. For N≥1N\ge1 define on [tk,tk+1][t_{k},t_{k+1}]

gN(k)(s)=fN(k)(s)+4C4τ♯pN(k)(s),g^{(k)}_{N}(s)=f^{(k)}_{N}(s)+4C_{4}\tau^{\sharp}\sqrt{p^{(k)}_{N}(s)} ,

which is measurable: the nonnegative square root is sequentially continuous on E=[0,1]E=[0,1], because for x≥y≥0x\ge y\ge0 one has (y+x−y)2=x+2yx−y≥x(\sqrt{y}+\sqrt{x-y})^{2}=x+2\sqrt{y}\sqrt{x-y}\ge x, hence ∣x−y∣≤∣x−y∣|\sqrt{x}-\sqrt{y}|\le\sqrt{|x-y|} for all x,y≥0x,y\ge0, so that ∣xn−x∣<ζ2|x_{n}-x|<\zeta^{2} forces ∣xn−x∣<ζ|\sqrt{x_{n}}-\sqrt{x}|<\zeta; therefore pN(k)\sqrt{p^{(k)}_{N}} is measurable as the composition of the measurable function pN(k)p^{(k)}_{N}, with values in EE, with a sequentially continuous function on EE (sequentially continuous functions of measurable maps are measurable, with d=1d=1), and sums and scalar multiples of measurable functions are measurable (claim 2 of the arithmetic of measurable functions); and which is nonnegative by (3.3), since gN(k)(s)≥∑jE[(bs,j⋅εs)2]≥0g^{(k)}_{N}(s)\ge\sum_{j}\mathbb{E}[(b_{s,j}\cdot\varepsilon_{s})^{2}]\ge0. Fix s∈[tk,tk+1]s\in[t_{k},t_{k+1}] and let η′>0\eta'>0. Applying claim 2 to each of the mm vectors c=bs,jc=b_{s,j} with tolerance η′/m\eta'/m and taking the largest of the resulting thresholds, there is N′′N'' such that for every N≥N′′N\ge N''

gN(k)(s) ≥ ∑j=1m(bs,j⋅(Πsbs,j)−η′m)=∑γ,δΞsγδΠsγδ−η′,g^{(k)}_{N}(s)\ \ge\ \sum_{j=1}^{m}\Bigl(b_{s,j}\cdot(\Pi_{s}b_{s,j})-\frac{\eta'}{m}\Bigr)=\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}-\eta',

again by the column identity. As η′>0\eta'>0 was arbitrary,

lim inf⁡N→∞gN(k)(s) ≥ ∑γ,δΞsγδΠsγδ(s∈[tk,tk+1]).\liminf_{N\to\infty}g^{(k)}_{N}(s)\ \ge\ \sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\qquad(s\in[t_{k},t_{k+1}]).

By Fatou's lemma, applied to the nonnegative measurable functions gN(k)g^{(k)}_{N} on [tk,tk+1][t_{k},t_{k+1}] with the restricted Lebesgue measure, and then by the monotonicity of the integral together with claim 1,

lim inf⁡N→∞∫[tk,tk+1]gN(k)(s) ds ≥ ∫[tk,tk+1]lim inf⁡N→∞gN(k)(s) ds ≥ ∫[tk,tk+1]∑γ,δΞsγδΠsγδ ds.\liminf_{N\to\infty}\int_{[t_{k},t_{k+1}]}g^{(k)}_{N}(s)\,ds\ \ge\ \int_{[t_{k},t_{k+1}]}\liminf_{N\to\infty}g^{(k)}_{N}(s)\,ds\ \ge\ \int_{[t_{k},t_{k+1}]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds .

The correction term vanishes in the limit: for every real θ>0\theta>0 and every real x≥0x\ge0 one has 2θx≤θ2+x2\theta\sqrt{x}\le\theta^{2}+x, because (x−θ)2≥0(\sqrt{x}-\theta)^{2}\ge0; hence, by the monotonicity and linearity of the integral and by (3.1), for N≥N1N\ge N_{1}

∫[tk,tk+1]pN(k)(s) ds ≤ θ (tk+1−tk)2+12θ∫[tk,tk+1]pN(k)(s) ds ≤ θT2+Cπ2θN,\int_{[t_{k},t_{k+1}]}\sqrt{p^{(k)}_{N}(s)}\,ds\ \le\ \frac{\theta\,(t_{k+1}-t_{k})}{2}+\frac{1}{2\theta}\int_{[t_{k},t_{k+1}]}p^{(k)}_{N}(s)\,ds\ \le\ \frac{\theta T}{2}+\frac{C_{\pi}}{2\theta N},

the integrals being finite because the integrands are nonnegative, measurable and bounded by 11, so that by monotonicity each is at most the measure tk+1−tkt_{k+1}-t_{k} of the block (claim 1 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval). Thus lim sup⁡N→∞∫[tk,tk+1]pN(k) ds≤θT/2\limsup_{N\to\infty}\int_{[t_{k},t_{k+1}]}\sqrt{p^{(k)}_{N}}\,ds\le\theta T/2 for every θ>0\theta>0, so this sequence of nonnegative reals converges to 00. Since ∫gN(k) ds=∫fN(k) ds+4C4τ♯∫pN(k) ds\int g^{(k)}_{N}\,ds=\int f^{(k)}_{N}\,ds+4C_{4}\tau^{\sharp}\int\sqrt{p^{(k)}_{N}}\,ds over [tk,tk+1][t_{k},t_{k+1}] by the linearity of the integral of nonnegative measurable functions (claim 1 of the linearity theorem, an identity in [0,∞][0,\infty]), the second summand is finite, and the sequence of second summands converges to 00 — so that the two sequences ∫fN(k) ds\int f^{(k)}_{N}\,ds and ∫gN(k) ds\int g^{(k)}_{N}\,ds, with values in [0,∞][0,\infty], have the same limit inferior in [0,∞][0,\infty] —

lim inf⁡N→∞∫[tk,tk+1]fN(k)(s) ds = lim inf⁡N→∞∫[tk,tk+1]gN(k)(s) ds ≥ ∫[tk,tk+1]∑γ,δΞsγδΠsγδ ds.\liminf_{N\to\infty}\int_{[t_{k},t_{k+1}]}f^{(k)}_{N}(s)\,ds\ =\ \liminf_{N\to\infty}\int_{[t_{k},t_{k+1}]}g^{(k)}_{N}(s)\,ds\ \ge\ \int_{[t_{k},t_{k+1}]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds .

Hence for each kk there is N(k)N^{(k)} with ∫[tk,tk+1]fN(k) ds≥∫[tk,tk+1]∑γ,δΞsγδΠsγδ ds−η/K\int_{[t_{k},t_{k+1}]}f^{(k)}_{N}\,ds\ge\int_{[t_{k},t_{k+1}]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\eta/K for every N≥N(k)N\ge N^{(k)}. Let N4N_{4} be the largest of N1,N(0),…,N(K−1)N_{1},N^{(0)},\dots,N^{(K-1)} and sum over kk. Since t0=0t_{0}=0, tK=Tt_{K}=T and tk<tk+1t_{k}<t_{k+1} for k≤K−1k\le K-1 (the number of blocks KK being least with KT0≥TKT_{0}\ge T), the intervals [tk,tk+1][t_{k},t_{k+1}] are adjacent with union [0,T][0,T], so by the additivity of the Riemann integral of a continuous function over adjacent compact intervals (Additivity of the Riemann Integral on Adjacent Intervals), the Lebesgue integral of a continuous function over a compact interval being its Riemann integral by claim 3 of Restricted Lebesgue Measure and Integral Toolkit on a Compact Interval, the sum of the right-hand sides is ∫[0,T]∑γ,δΞsγδΠsγδ ds−η\int_{[0,T]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\eta. This proves claim 3.

Claim 4. Let ε′′>0\varepsilon''>0. By conclusion (b) of the asymptotic lower bound theorem, applied with ε′=ε′′/2\varepsilon'=\varepsilon''/2, there are an admissible parameter vector π\pi satisfying the absorption condition of part (a) of that theorem and a natural number N0N_{0} such that for every N≥N0N\ge N_{0}

JN ≥ V0+∑k=0K−1∫[tk,tk+1]E[1Tknr(s)us⋅Rsus] ds−ε′′2,\mathcal{J}_{N}\ \ge\ V_{0}+\sum_{k=0}^{K-1}\int_{[t_{k},t_{k+1}]}\mathbb{E}\bigl[\mathbf{1}_{\mathcal{T}^{\mathrm{nr}}_{k}(s)}u_{s}\cdot R_{s}u_{s}\bigr]\,ds-\frac{\varepsilon''}{2},

the blocks and near-field tracked events being those formed from π\pi. Apply claim 3 to this π\pi (which satisfies the absorption condition) with η=ε′′/2\eta=\varepsilon''/2, obtaining N4N_{4}, and put N5=max⁡(N0,N4)N_{5}=\max(N_{0},N_{4}). For N≥N5N\ge N_{5} the two displays combine to

JN ≥ V0+∫[0,T]∑γ,δΞsγδΠsγδ ds−ε′′2−ε′′2,\mathcal{J}_{N}\ \ge\ V_{0}+\int_{[0,T]}\sum_{\gamma,\delta}\Xi^{\gamma\delta}_{s}\Pi^{\gamma\delta}_{s}\,ds-\frac{\varepsilon''}{2}-\frac{\varepsilon''}{2},

which is claim 4.

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