TheoremBase

Symmetry by the swap, separation by the diagonal coupling and by the Lipschitz bound together with the determination of a finite Borel measure by bounded Lipschitz test functions, and the triangle inequality by quantising the middle measure, modifying the two near-optimal couplings, and gluing over the finitely supported quantised measure.

Proof

Each result cited is universally quantified over the data in its own statement. Throughout, Π(⋅,⋅)\Pi(\cdot,\cdot) and II are the couplings and their quadratic cost; by The Quadratic Wasserstein Distance on Euclidean Space (i), for α,β∈P2(Rd)\alpha,\beta\in\mathcal{P}_{2}(\mathbb{R}^{d}) the number W2(α,β)W_{2}(\alpha,\beta) is nonnegative, W2(α,β)2W_{2}(\alpha,\beta)^{2} is the greatest lower bound of J(α,β)={I(π):π∈Π(α,β)}J(\alpha,\beta)=\{I(\pi):\pi\in\Pi(\alpha,\beta)\}, a set of nonnegative real numbers by Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (iii), and W2(α,β)2≤I(π)W_{2}(\alpha,\beta)^{2}\le I(\pi) for every π∈Π(α,β)\pi\in\Pi(\alpha,\beta), so that W2(α,β)≤I(π)W_{2}(\alpha,\beta)\le\sqrt{I(\pi)} by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field. We use the following approximation: for α,β∈P2(Rd)\alpha,\beta\in\mathcal{P}_{2}(\mathbb{R}^{d}) and real ε>0\varepsilon>0 there is π∈Π(α,β)\pi\in\Pi(\alpha,\beta) with I(π)<W2(α,β)+ε\sqrt{I(\pi)}<W_{2}(\alpha,\beta)+\varepsilon. Indeed, with W=W2(α,β)W=W_{2}(\alpha,\beta) and η=2Wε+ε2\eta=2W\varepsilon+\varepsilon^{2}, which is positive because 0≤2Wε0\le2W\varepsilon by claim 5 of Elementary Arithmetic in an Ordered Field (WW being nonnegative and 0<2ε0<2\varepsilon by claims 8 and 5 of Elementary Order Arithmetic in an Ordered Field), 0<ε20<\varepsilon^{2} by claim 5 of Elementary Order Arithmetic in an Ordered Field, and claim 3 there, claim 4 of Approximation Property of the Supremum and the Infimum in R\mathbb{R} gives π∈Π(α,β)\pi\in\Pi(\alpha,\beta) with I(π)<W2+η=(W+ε)2I(\pi)<W^{2}+\eta=(W+\varepsilon)^{2} (claim 5 of Zero Products and Elementary Identities in a Field), whence I(π)<W+ε\sqrt{I(\pi)}<W+\varepsilon by claim 1 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field.

Claim 1. By Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (ii), π↦σ#π\pi\mapsto\sigma_{\#}\pi is a bijection of Π(μ,ν)\Pi(\mu,\nu) onto Π(ν,μ)\Pi(\nu,\mu) with I(σ#π)=I(π)I(\sigma_{\#}\pi)=I(\pi); hence J(μ,ν)=J(ν,μ)J(\mu,\nu)=J(\nu,\mu), so the two sets have the same greatest lower bound, and W2(μ,ν)=W2(ν,μ)W_{2}(\mu,\nu)=W_{2}(\nu,\mu) by The Quadratic Wasserstein Distance on Euclidean Space (i), the nonnegative square root being unique by Existence and Uniqueness of the Nonnegative Square Root.

Claim 2. If μ=ν\mu=\nu, then (id,id)#μ∈Π(μ,μ)(\mathrm{id},\mathrm{id})_{\#}\mu\in\Pi(\mu,\mu) has quadratic cost 00 by Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (iv), so W2(μ,μ)2≤0W_{2}(\mu,\mu)^{2}\le0; being nonnegative, W2(μ,μ)2=0W_{2}(\mu,\mu)^{2}=0, and W2(μ,μ)=0W_{2}(\mu,\mu)=0 by claim 3 of Zero Products and Elementary Identities in a Field. Conversely suppose W2(μ,ν)=0W_{2}(\mu,\nu)=0, and let f:Rd→Rf:\mathbb{R}^{d}\to\mathbb{R} be bounded and Lipschitz with some constant L≥0L\ge0 from (Rd,dE)(\mathbb{R}^{d},d_{E}) to R\mathbb{R} with the absolute-value metric, the notion of Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound. Put Δ=∣∫f dμ−∫f dν∣\Delta=|\int f\,d\mu-\int f\,d\nu|, the integrals existing by Probability Measures on Euclidean Space and Random Vectors: Standing Notation (iii) since ff is bounded and Borel (continuous by A Lipschitz Map is Uniformly Continuous and Continuous, hence Borel by Probability Measures on Euclidean Space and Random Vectors: Standing Notation (ii)). For every real ε>0\varepsilon>0 the approximation gives π∈Π(μ,ν)\pi\in\Pi(\mu,\nu) with I(π)<ε\sqrt{I(\pi)}<\varepsilon, and then Δ≤LI(π)≤Lε\Delta\le L\sqrt{I(\pi)}\le L\varepsilon by Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (viii) and claim 5 of Elementary Arithmetic in an Ordered Field. If L=0L=0 this gives Δ≤0\Delta\le0; if 0<L0<L and 0<Δ0<\Delta held, the choice ε=ΔL−1⋅2−1\varepsilon=\Delta L^{-1}\cdot2^{-1}, positive by claims 7, 5 and 8 of Elementary Order Arithmetic in an Ordered Field, would give Δ≤Δ⋅2−1<Δ\Delta\le\Delta\cdot2^{-1}<\Delta by claim 8 there, which is impossible. Hence Δ=0\Delta=0, that is, ∫f dμ=∫f dν\int f\,d\mu=\int f\,d\nu for every bounded Lipschitz ff. Now (Rd,dE)(\mathbb{R}^{d},d_{E}) is a nonempty metric space whose Borel σ\sigma-algebra is B(Rd)\mathcal{B}(\mathbb{R}^{d}) by Probability Measures on Euclidean Space and Random Vectors: Standing Notation (i), and μ,ν\mu,\nu are finite measures on it; so μ=ν\mu=\nu by claim 1 of Lipschitz Test Functions Determine a Finite Borel Measure, and Uniqueness of Weak Limits.

Claim 3. Let ε∈R\varepsilon\in\mathbb{R} satisfy 0<ε0<\varepsilon. By the approximation there are π12∈Π(μ,ν)\pi_{12}\in\Pi(\mu,\nu) and π23∈Π(ν,λ)\pi_{23}\in\Pi(\nu,\lambda) with

I(π12)<W2(μ,ν)+ε,I(π23)<W2(ν,λ)+ε,\sqrt{I(\pi_{12})}<W_{2}(\mu,\nu)+\varepsilon,\qquad\sqrt{I(\pi_{23})}<W_{2}(\nu,\lambda)+\varepsilon ,

both costs being finite. By Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (vi) there is a Borel T:Rd→RdT:\mathbb{R}^{d}\to\mathbb{R}^{d} with finite image F=T(Rd)F=T(\mathbb{R}^{d}) and ∫∥T(y)−y∥2 ν(dy)≤ε2\int\lVert T(y)-y\rVert^{2}\,\nu(dy)\le\varepsilon^{2}, so that ∫∥T(y)−y∥2 ν(dy)≤ε\sqrt{\int\lVert T(y)-y\rVert^{2}\,\nu(dy)}\le\varepsilon by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field; put ρ=T#ν∈P(Rd)\rho=T_{\#}\nu\in\mathcal{P}(\mathbb{R}^{d}), which satisfies ρ(Rd∖F)=0\rho(\mathbb{R}^{d}\setminus F)=0 by the same clause. By Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (v), π12′=(pr1,T∘pr2)#π12∈Π(μ,ρ)\pi'_{12}=(\mathrm{pr}_{1},T\circ\mathrm{pr}_{2})_{\#}\pi_{12}\in\Pi(\mu,\rho) and π23′=(T∘pr1,pr2)#π23∈Π(ρ,λ)\pi'_{23}=(T\circ\mathrm{pr}_{1},\mathrm{pr}_{2})_{\#}\pi_{23}\in\Pi(\rho,\lambda) have finite costs with

I(π12′)≤I(π12)+ε,I(π23′)≤I(π23)+ε,\sqrt{I(\pi'_{12})}\le\sqrt{I(\pi_{12})}+\varepsilon,\qquad\sqrt{I(\pi'_{23})}\le\sqrt{I(\pi_{23})}+\varepsilon ,

the second by claim 2 of Monotonicity of Squaring on the Nonnegative Elements of an Ordered Field applied to the bound on I(π23′)I(\pi'_{23}) recorded there. By Couplings on Euclidean Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, and the Lipschitz Bound (vii) applied to ρ\rho, FF, π12′\pi'_{12} and π23′\pi'_{23}, there is π13∈Π(μ,λ)\pi_{13}\in\Pi(\mu,\lambda) with I(π13)≤I(π12′)+I(π23′)\sqrt{I(\pi_{13})}\le\sqrt{I(\pi'_{12})}+\sqrt{I(\pi'_{23})}. Combining these inequalities by claims 2 and 3 of Elementary Order Arithmetic in an Ordered Field,

W2(μ,λ)≤I(π13)<W2(μ,ν)+W2(ν,λ)+ε+ε+ε+ε.W_{2}(\mu,\lambda)\le\sqrt{I(\pi_{13})}<W_{2}(\mu,\nu)+W_{2}(\nu,\lambda)+\varepsilon+\varepsilon+\varepsilon+\varepsilon .

Write S=W2(μ,ν)+W2(ν,λ)S=W_{2}(\mu,\nu)+W_{2}(\nu,\lambda). If S<W2(μ,λ)S<W_{2}(\mu,\lambda) held, let γ=W2(μ,λ)−S\gamma=W_{2}(\mu,\lambda)-S, positive by claim 3 of Elementary Arithmetic in an Ordered Field and claim 1 of Elementary Order Arithmetic in an Ordered Field, and choose ε=γ⋅2−1⋅2−1⋅2−1\varepsilon=\gamma\cdot2^{-1}\cdot2^{-1}\cdot2^{-1}, positive by claim 8 of Elementary Order Arithmetic in an Ordered Field; three applications of that claim give ε+ε+ε+ε=γ⋅2−1<γ\varepsilon+\varepsilon+\varepsilon+\varepsilon=\gamma\cdot2^{-1}<\gamma, so the display yields W2(μ,λ)<S+γ=W2(μ,λ)W_{2}(\mu,\lambda)<S+\gamma=W_{2}(\mu,\lambda), which is impossible. Hence W2(μ,λ)≤SW_{2}(\mu,\lambda)\le S.

Claim 4. By Metric Space, a metric on P2(Rd)\mathcal{P}_{2}(\mathbb{R}^{d}) is a real-valued function of two arguments that is nonnegative, vanishes exactly on pairs of equal points, is symmetric, and satisfies the triangle inequality; W2W_{2} has these properties by The Quadratic Wasserstein Distance on Euclidean Space (i) and claims 2, 1 and 3. So (P2(Rd),W2)(\mathcal{P}_{2}(\mathbb{R}^{d}),W_{2}) is a metric space.

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