Proof of First-Order Operators Satisfy the Second-Order Structure and Tail-Insensitivity Conditions
lemmalem:first-order-implies-second-order-hilbert-triple-2026aThe second-order structure inequality is required for fewer pairs of forms than the first-order one, and a first-order operator has shifts that ignore the form argument, so both tail differences vanish identically.
Each result cited is universally quantified over the data in its own statement.
Proof of claim 1. Let be positive and let be a structure pair for at . The requirements that The First-Order Structure Condition for a Second-Order Equation Operator on a Hilbert Triple §pair and The Second-Order Structure Condition for an Equation Operator on a Hilbert Triple §pair place on and on are the same, namely that be a modulus of continuity and that be a real-valued function on the pairs with and for which is a modulus of continuity for each real ; and the displayed inequality is the same in the two clauses. The two clauses differ only in the range of the form arguments: the first demands the inequality for all , the second only for the pairs of members of that are admitted at . Since every pair admitted at is in particular a pair of members of , each instance of the inequality demanded by the second clause is an instance of one supplied by the first, for the same , the same with and the same with and . Hence is a second-order structure pair for at .
Suppose now that satisfies the first-order structure condition and let be positive. By The First-Order Structure Condition for a Second-Order Equation Operator on a Hilbert Triple §structure there is a structure pair for at , and by the previous paragraph it is a second-order structure pair for at . As was an arbitrary positive real, satisfies the second-order structure condition by The Second-Order Structure Condition for an Equation Operator on a Hilbert Triple §structure.
Proof of claim 2. Let be the tail forms of , which are defined because is an orthonormal basis of all of whose members lie in . Let be positive and let satisfy ; in particular is positive, so A First-Order Equation Operator is Degenerate Elliptic and Its -Shifts Ignore the Form Argument §shifts applies to with this .
For the condition of The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §lower, let , , and be sequences as there. For each the forms and both belong to , by Hilbert Triples: Standing Notation and Background §restriction, and , and ; so A First-Order Equation Operator is Degenerate Elliptic and Its -Shifts Ignore the Form Argument §shifts, applied with these data and the two form arguments and , gives
Since , the right-hand side of the inequality required in The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §lower exceeds its left-hand side for every , so that requirement holds with .
For the condition of The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §upper, let the four sequences be as there. The same claim of A First-Order Equation Operator is Degenerate Elliptic and Its -Shifts Ignore the Form Argument, applied with the form arguments and , gives
and again makes the required inequality hold for every , so that requirement holds with .
As , , and were arbitrary subject to the stated restrictions, is tail-insensitive along by The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §along-basis.
Proof of claim 3. Since is not finite-dimensional, An Orthonormal Basis of the Ambient Space Contained in the Form Space of a Hilbert Triple §basis provides an orthonormal basis of with for every . By claim 2, is tail-insensitive along . Hence satisfies the tail-insensitivity condition by The Tail-Insensitivity Condition for an Equation Operator on a Hilbert Triple §condition.
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Prerequisites
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