Proof of A Closed Subset of a Euclidean Space is a Countable Union of Compact Sets, and Its Coordinate Projections are Borel
lemmalem:projection-closed-set-borel-euclidean-2026aEvery point of a closed set lies in some closed ball about the origin by the Archimedean property, which gives the exhaustion; the image of each member under a coordinate projection is compact, hence Borel, and the projection of the whole set is their countable union.
Throughout, each result cited is universally quantified over the data appearing in its own statement and is applied to the data named here.
Step 1 (Claim 1). Let be closed and let for ; compactness of each is recorded in the statement. Every is a subset of , so . Conversely let . The Euclidean norm is a real number, so by claim 1 of The Archimedean Property of the Real Numbers there is with . By claim 2 of Elementary Properties of the Euclidean Norm on the Euclidean distance equals , so and hence . Therefore .
Step 2 (Claim 2). Let be closed and let be as in claim 1, applied with . The projection is continuous for the Euclidean distances: by claim 1 of Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit it is nonexpansive, hence Lipschitz with constant , hence continuous by A Lipschitz Map is Uniformly Continuous.
For each the image is compact by Continuous Image of a Compact Space is Compact, being compact, and therefore belongs to by Compact Subsets of a Metric Space are Closed and Borel §borel. Since the image of a union is the union of the images,
which belongs to , a -algebra being closed under countable unions.
The same argument applies to , which is nonexpansive by claim 1 of Continuity of the Coordinate Projections and of the Quadratic Cost Function, and Passage of a Cost Bound to a Weak Limit as well, and gives .
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Prerequisites
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