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Proof of Two Sufficient Conditions for the Map Property: Absolute Continuity, and Atomlessness on the Line

lemmalem:map-property-sufficient-wasserstein-2026a
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· 2,781 chars · 7 deps · depth 30 Reason: Proof of both sufficient conditions for the map property, combining unique mapping with tangency of the optimal displacement in each of the two cases.

Both clauses combine an existing unique-mapping result with an existing tangency result: the tangency corollary for an absolutely continuous source, and on the line the fact that the tangent space is the whole space of square-integrable fields.

Proof

Each result cited is universally quantified over the data in its own statement, and is applied here to the data named in the statement above. By The Map Property of a Set of Probability Measures §map-property it suffices, in each claim, to fix μQ\mu\in Q and νP2(Rd)\nu\in\mathcal{P}_{2}(\mathbb{R}^{d}) and to show that the ordered pair (μ,ν)(\mu,\nu) is uniquely mapped and that idTTμ\mathrm{id}-T\in T_{\mu} for an optimal map TT from μ\mu to ν\nu; the choice of TT is immaterial, by the independence recorded in that clause.

Claim 1. Let μQ\mu\in Q and νP2(Rd)\nu\in\mathcal{P}_{2}(\mathbb{R}^{d}). By hypothesis μ\mu is absolutely continuous, so Out of an Absolutely Continuous Measure the Optimal Map and the Optimal Displacement are Tangent §uniquely-mapped applies to the pair (μ,ν)(\mu,\nu): it is uniquely mapped, and there is an optimal map from μ\mu to ν\nu. Let TT be such a map. By Out of an Absolutely Continuous Measure the Optimal Map and the Optimal Displacement are Tangent §tangent one has RdT2dμ=M2(ν)<\int_{\mathbb{R}^{d}}\lVert T\rVert^{2}\,d\mu=M_{2}(\nu)<\infty, so that the class of TT belongs to L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}), and

idTTμ.\mathrm{id}-T\in T_{\mu}.

The class of idT\mathrm{id}-T named in that clause and the one named in The Map Property of a Set of Probability Measures §map-property, which is supplied by The Optimal Map as a Square-Integrable Vector Field: Integrability, Transport Cost and Uniqueness of the Class §square-integrable, are the same element of L2(μ;Rd)L^{2}(\mu;\mathbb{R}^{d}): both are the class of the Borel map xxT(x)x\mapsto x-T(x), the class of a Borel map being determined by the map, by Square-Integrable Vector Fields Against a Probability Measure on Euclidean Space, and Test Functions: Standing Notation §l2mu. Hence the condition of The Map Property of a Set of Probability Measures §map-property holds for μ\mu and ν\nu. As μQ\mu\in Q and νP2(Rd)\nu\in\mathcal{P}_{2}(\mathbb{R}^{d}) were arbitrary, QQ has the map property.

Claim 2. Let d=1d=1, let μQ\mu\in Q and let νP2(R)\nu\in\mathcal{P}_{2}(\mathbb{R}). By hypothesis μ\mu is atomless, so On the Real Line an Atomless Source is Uniquely Mapped, by a Nondecreasing Optimal Map §uniquely-mapped gives that the ordered pair (μ,ν)(\mu,\nu) is uniquely mapped. By Optimal Transport Maps and Uniquely Mapped Pairs of Probability Measures §uniquely-mapped there is then an optimal map TT from μ\mu to ν\nu; fix one. By The Optimal Map as a Square-Integrable Vector Field: Integrability, Transport Cost and Uniqueness of the Class §square-integrable, applied with TT in the role of the Borel map there and using T#μ=νT_{\#}\mu=\nu from Optimal Transport Maps and Uniquely Mapped Pairs of Probability Measures §map, the classes of TT and of idT\mathrm{id}-T belong to L2(μ;R)L^{2}(\mu;\mathbb{R}).

By On the Real Line the Tangent Space is the Whole Space of Square-Integrable Vector Fields §everything, applied to μP2(R)\mu\in\mathcal{P}_{2}(\mathbb{R}), the tangent space at μ\mu is the whole space:

Tμ=L2(μ;R).T_{\mu}=L^{2}(\mu;\mathbb{R}).

Therefore idTTμ\mathrm{id}-T\in T_{\mu}, and the condition of The Map Property of a Set of Probability Measures §map-property holds for μ\mu and ν\nu. As μQ\mu\in Q and νP2(R)\nu\in\mathcal{P}_{2}(\mathbb{R}) were arbitrary, QQ has the map property.

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