Proof of A Product of Compact Subsets is Compact in the Product Metric
corollarycor:product-compact-subsets-metric-2026aLet be the restriction of to and the restriction of to ; these are metrics by claim 1 of The Restriction of a Metric to a Subset Induces the Subspace Topology.
Step 1: the factors are compact topological spaces in their metric topologies. By the definition of a compact subset, the hypothesis on says that with the subspace topology inherited from is a compact topological space. By claim 2 of The Restriction of a Metric to a Subset Induces the Subspace Topology that subspace topology is exactly the collection of subsets of open in the metric space . Hence , with the topology of its open subsets, is a compact topological space, and likewise for .
Step 2: the product metric of the restrictions is the restriction of the product metric. Let . By the definition of the product metric, the product metric of and takes at this pair of points the value , which is the value of , hence of , at the same pair. So the product metric of and equals .
Step 3: compactness of the product. By Product of Two Compact Spaces is Compact applied to the two compact topological spaces of Step 1, the set equipped with the product topology of those two topologies is compact. By The Product Metric Induces the Product Topology applied to the metric spaces and , that product topology is exactly the collection of subsets of open in the metric space , using Step 2. This proves the second assertion of the corollary.
Step 4: compactness as a subset of . By claim 2 of The Restriction of a Metric to a Subset Induces the Subspace Topology, applied to the metric space and its subset , the collection of subsets of open in is the subspace topology inherited from . By Step 3 that topology is compact, so is compact in in the sense of the definition of a compact subset.
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Prerequisites
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