Sketch: the intersection of the nonempty family of convex supersets of S is convex, contains S and lies in each of them; two such sets contain each other.
No choice is used; every object below is defined by a formula. Let be the set of all that are convex and contain .
Let
which is exactly the set displayed in (ii). Then is convex by Operations Preserving Convexity in : Intersections, Translates, Scalar Multiples, Sums, Affine Images and Preimages, Closure and Interior (ii); it contains , because every member of does; and it is contained in every convex , because such a is a member of . So has the property required in (i).
For uniqueness, suppose that and both have this property. Each is a convex superset of , so the property of gives and the property of gives ; hence . This proves (i), and since the unique such set is the intersection constructed above, it also proves (ii).
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