TheoremBase

Enumerate T by a bijection from [m], rewrite the sum as a finite sum over [m], and induct on the number of summands using the recursion of finite sums and the continuity of sums and scalar multiples.

Proof

Each result cited is universally quantified over the data in its own statement.

If Z=∅Z=\emptyset, every map from ZZ to R\mathbb{R} is continuous on ZZ vacuously by Continuous Map Between Metric Spaces, and there is nothing to prove. Assume therefore that Z≠∅Z\ne\emptyset and fix x0∈Zx_{0}\in Z. Then Continuity of Sums and Products of Real-Valued Functions on a Metric Space applies with its metric space (Z,d)(Z,d), with A=ZA=Z and with x=x0x=x_{0}, and claim Continuity of Sums and Products of Real-Valued Functions on a Metric Space §on-set of it says: if f,g:Z→Rf,g:Z\to\mathbb{R} are continuous on ZZ and c∈Rc\in\mathbb{R}, then the maps z↦f(z)+g(z)z\mapsto f(z)+g(z) and z↦c f(z)z\mapsto c\,f(z) are continuous on ZZ.

Enumerating TT. Since TT is finite and nonempty, by Finite Set there is a natural number mm such that TT has mm elements, that is, there is a bijection θ:[m]→T\theta:[m]\to T. For z∈Zz\in Z let az:[m]→Ra^{z}:[m]\to\mathbb{R} be the map with values akz=bθ(k) fθ(k)(z)a^{z}_{k}=b_{\theta(k)}\,f_{\theta(k)}(z). By Sum over a Finite Index Set, applied to the map T→RT\to\mathbb{R}, t↦bt ft(z)t\mapsto b_{t}\,f_{t}(z), and to the bijection θ\theta,

∑t∈Tbt ft(z)=∑k=1makzfor every z∈Z.(1)\sum_{t\in T}b_{t}\,f_{t}(z)=\sum_{k=1}^{m}a^{z}_{k}\qquad\text{for every }z\in Z. \tag{1}

For j∈[m]j\in[m] let gj:Z→Rg_{j}:Z\to\mathbb{R} be the map gj(z)=∑k=1jakzg_{j}(z)=\sum_{k=1}^{j}a^{z}_{k}, the finite sum of a1z,…,ajza^{z}_{1},\dots,a^{z}_{j}.

Induction. Let II be the set of natural numbers nn such that, if n≤mn\le m, then gng_{n} is continuous on ZZ. We show that II satisfies the two hypotheses of Principle of Induction for the Natural Numbers.

1∈I1\in I: we have 1∈[m]1\in[m] by Properties of the Order on the Natural Numbers §least, and by claim 1 of Properties of Finite Sums, applied to aza^{z}, we have g1(z)=a1z=bθ(1) fθ(1)(z)g_{1}(z)=a^{z}_{1}=b_{\theta(1)}\,f_{\theta(1)}(z) for every z∈Zz\in Z. Since fθ(1)f_{\theta(1)} is continuous on ZZ, g1g_{1} is continuous on ZZ by Continuity of Sums and Products of Real-Valued Functions on a Metric Space §on-set, with f=g=fθ(1)f=g=f_{\theta(1)} and c=bθ(1)c=b_{\theta(1)}.

S(n)∈IS(n)\in I for every n∈In\in I: let n∈In\in I and suppose S(n)≤mS(n)\le m. By Properties of the Order on the Natural Numbers §successor, n<S(n)n<S(n), so n≤S(n)n\le S(n) and then n≤mn\le m by Properties of the Order on the Natural Numbers §basic; since n∈In\in I, gng_{n} is continuous on ZZ. As S(n)∈[m]S(n)\in[m], claim 1 of Properties of Finite Sums, applied to aza^{z}, gives

gS(n)(z)=gn(z)+aS(n)z=gn(z)+bθ(S(n)) fθ(S(n))(z)for every z∈Z.g_{S(n)}(z)=g_{n}(z)+a^{z}_{S(n)}=g_{n}(z)+b_{\theta(S(n))}\,f_{\theta(S(n))}(z)\qquad\text{for every }z\in Z.

The map z↦bθ(S(n)) fθ(S(n))(z)z\mapsto b_{\theta(S(n))}\,f_{\theta(S(n))}(z) is continuous on ZZ by Continuity of Sums and Products of Real-Valued Functions on a Metric Space §on-set, because fθ(S(n))f_{\theta(S(n))} is; hence gS(n)g_{S(n)}, the sum of two maps continuous on ZZ, is continuous on ZZ by the same claim. Thus S(n)∈IS(n)\in I.

By Principle of Induction for the Natural Numbers, I=NI=\mathbb{N}. In particular m∈Im\in I, and m≤mm\le m by Properties of the Order on the Natural Numbers §basic, so gmg_{m} is continuous on ZZ. By (1), gmg_{m} is the map z↦∑t∈Tbt ft(z)z\mapsto\sum_{t\in T}b_{t}\,f_{t}(z), which proves Finite Linear Combinations of Continuous Real-Valued Maps on a Metric Space are Continuous §continuous.

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