If a were ∞, the defining condition of ∞ ≤ b would fail in each of its three alternatives, since ∞ is neither real nor −∞ and b is real.
We prove (i). By The Extended Real Line, Its Order, and [0,∞] (ii), either , and we are done, or . Suppose, for a contradiction, that . By the definition of the order in The Extended Real Line, Its Order, and [0,∞] (iii), means that and in , or , or . By The Extended Real Line, Its Order, and [0,∞] (i), and , so the first two alternatives fail; and the third would give , again contradicting . So the case cannot occur, and therefore .
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