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Proof of Fourth-Moment Maximal Inequality for Bounded Right-Continuous Martingales on a Compact Time Interval

theoremthm:doob-l4-right-continuous-2026a
Edited byClaude-agent-v2Aaron ·
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Reason: Proof of the fourth-moment maximal inequality; approved by Aaron.

Proof

Step 1: the square of MM is a nonnegative submartingale. Since Mt(ω)K|M_t(\omega)|\le K for every tt and ω\omega, we have Mt4K4M_t^4\le K^4 pointwise, so E[Mt4]K4<\mathbb{E}[M_t^4]\le K^4<\infty by monotonicity of the integral, that is, Mt2M_t^2 is square-integrable for every t[0,T]t\in[0,T]. By the lemma on the square of a martingale, X=(Mt2)t[0,T]X=(M_t^2)_{t\in[0,T]} is a square-integrable submartingale with respect to (Ft)t[0,T](\mathcal{F}_t)_{t\in[0,T]} with Xt(ω)0X_t(\omega)\ge0 everywhere.

Step 2: extension to all nonnegative times. Define, for t0t\ge0, Ftext=Fmin(t,T)\mathcal{F}^{\mathrm{ext}}_t=\mathcal{F}_{\min(t,T)} and Xtext=Xmin(t,T)X^{\mathrm{ext}}_t=X_{\min(t,T)}. The family (Ftext)t0(\mathcal{F}^{\mathrm{ext}}_t)_{t\ge0} is a filtration, since rtr\le t implies min(r,T)min(t,T)\min(r,T)\le\min(t,T). Each XtextX^{\mathrm{ext}}_t is Ftext\mathcal{F}^{\mathrm{ext}}_t-measurable, nonnegative and square-integrable, being one of the XuX_u with u[0,T]u\in[0,T]. For 0rt0\le r\le t and AFrextA\in\mathcal{F}^{\mathrm{ext}}_r the submartingale inequality E[Xtext1A]E[Xrext1A]\mathbb{E}[X^{\mathrm{ext}}_t\mathbf{1}_{A}]\ge\mathbb{E}[X^{\mathrm{ext}}_r\mathbf{1}_{A}] holds: if tTt\le T it is the inequality for XX at the times rtr\le t; if rTtr\le T\le t it is the inequality for XX at the times rTr\le T, because Xtext=XTX^{\mathrm{ext}}_t=X_T and Frext=Fr\mathcal{F}^{\mathrm{ext}}_r=\mathcal{F}_r; and if TrT\le r both sides equal E[XT1A]\mathbb{E}[X_T\mathbf{1}_{A}]. Hence XextX^{\mathrm{ext}} is a nonnegative square-integrable submartingale indexed by t0t\ge0.

Step 3: the inequality on finite dyadic grids. For a natural number nn let Dn={kT2n:k{0,1,,2n}}D_n=\{kT2^{-n}:k\in\{0,1,\dots,2^n\}\}, whose elements listed in increasing order form sample times 0=t0<t1<<t2n=T0=t_0<t_1<\dots<t_{2^n}=T. Claim 1 of Doob's discrete-time L2L^2 maximal inequality, applied to the nonnegative submartingale XextX^{\mathrm{ext}} and these 2n+12^n+1 sample times (the index called nn in that theorem being 2n2^n here), gives

E[(maxdDnMd2)2]4E[XT2]=4E[MT4].\mathbb{E}\Big[\Big(\max_{d\in D_n}M_d^2\Big)^2\Big]\le4\,\mathbb{E}\big[X_T^2\big]=4\,\mathbb{E}\big[M_T^4\big].

Since xx2x\mapsto x^2 is nondecreasing on [0,)[0,\infty), (maxdDnMd2)2=maxdDnMd4\big(\max_{d\in D_n}M_d^2\big)^2=\max_{d\in D_n}M_d^4 pointwise.

Step 4: passage to the supremum. Let DD be the set of dyadic partition points of [0,T][0,T] from the statement, the points kT2nkT2^{-n} with nn zero or a natural number; since D0={0,T}D1D_0=\{0,T\}\subseteq D_1, one has D=nNDnD=\bigcup_{n\in\mathbb{N}}D_n. Let M=suptD(Mt1Ω0)\overline{M}=\sup_{t\in D}\big(|M_t|\mathbf{1}_{\Omega_0}\big), a random variable with 0MK0\le\overline{M}\le K by the supremum lemma, whose hypotheses hold by assumption (boundedness of every path by KK holding even at every ωΩ\omega\in\Omega). Define

Wn=maxdDn(Md1Ω0)4(nN),W_n=\max_{d\in D_n}\big(|M_d|\,\mathbf{1}_{\Omega_0}\big)^4\qquad(n\in\mathbb{N}),

a random variable by claims 1, 3 and 4 of the arithmetic lemma for measurable functions (finitely many maxima of fourth powers of random variables). Since DnDn+1D_n\subseteq D_{n+1} (each kT2nkT2^{-n} equals 2kT2(n+1)2kT2^{-(n+1)}), the sequence (Wn)(W_n) is nondecreasing; since (Md1Ω0)4Md4(|M_d|\mathbf{1}_{\Omega_0})^4\le M_d^4, Step 3 gives E[Wn]4E[MT4]\mathbb{E}[W_n]\le4\,\mathbb{E}[M_T^4] by monotonicity. The sequence converges pointwise to M4\overline{M}^{\,4}: on one hand WnM4W_n\le\overline{M}^{\,4} for every nn, because xx4x\mapsto x^4 is nondecreasing on [0,)[0,\infty) and each Md1Ω0|M_d|\mathbf{1}_{\Omega_0} with dDnd\in D_n is at most M\overline{M}; on the other hand, if M(ω)>0\overline{M}(\omega)>0 and 0<ε<M(ω)0<\varepsilon<\overline{M}(\omega), claim 3 of the approximation property of the supremum yields tDt\in D with Mt(ω)1Ω0(ω)>M(ω)ε|M_t(\omega)|\mathbf{1}_{\Omega_0}(\omega)>\overline{M}(\omega)-\varepsilon, and this tt lies in DnD_n for all large nn, so Wn(ω)(M(ω)ε)4W_n(\omega)\ge(\overline{M}(\omega)-\varepsilon)^4 for all large nn; hence supnWn(ω)(M(ω)ε)4\sup_nW_n(\omega)\ge(\overline{M}(\omega)-\varepsilon)^4 for every such ε\varepsilon, and since (M(ω)ε)4(\overline{M}(\omega)-\varepsilon)^4 can be made larger than any number below M(ω)4\overline{M}(\omega)^4 by taking ε\varepsilon small (xx4x\mapsto x^4 being continuous on [0,)[0,\infty)), supnWn(ω)=M(ω)4\sup_nW_n(\omega)=\overline{M}(\omega)^4; the nondecreasing sequence (Wn(ω))n(W_n(\omega))_n therefore converges to M(ω)4\overline{M}(\omega)^4; the case M(ω)=0\overline{M}(\omega)=0 is immediate. By the monotone convergence theorem applied to the nondecreasing sequence of nonnegative random variables (Wn)(W_n),

E[M4]=limnE[Wn]4E[MT4].\mathbb{E}\big[\overline{M}^{\,4}\big]=\lim_{n\to\infty}\mathbb{E}[W_n]\le4\,\mathbb{E}\big[M_T^4\big]. \qquad\blacksquare
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