TheoremBase

Proof

Apply Existence of Independent Sequences with Prescribed Distributions to the constant sequence νm=ν\nu_m=\nu for every m∈Nm\in\mathbb{N} (with N\mathbb{N} the natural numbers). This produces exactly the probability space named in the statement — Ω=(0,1)\Omega=(0,1), F\mathcal{F} the Borel subsets of (0,1)(0,1), and PP the restriction of Lebesgue measure, a probability measure since (0,1)(0,1) has measure 11 — together with an independent sequence (Xm)m∈N(X_m)_{m\in\mathbb{N}} of random variables on it such that every XmX_m has distribution ν\nu. Since all the XmX_m share the distribution ν\nu, the sequence is independent and identically distributed with common distribution ν\nu, as required. ■\blacksquare

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