Each result cited is universally quantified over the data appearing in its own statement, and is applied here to the data named in the statement above. We use countable choice, to select one approximating simple function for each index.
Claim 1. If X is empty then Z=β
has measure 0 and the unique map XβR lies in Lp, its integral being 0; both sides of the asserted equivalence hold and there is nothing to prove. Assume therefore that X is nonempty, so that a simple function on (X,F) has at least one value.
Let s=βi=1rβciβ1Aiββ be the standard representation of Simple Functions, Nonnegative Simple Functions, and the Simple Integral, with the ciβ the distinct values of s and Aiβ=sβ1({ciβ})βF. The set Z={xβX:s(x)ξ =0} is the union of those Aiβ with ciβξ =0, a union of finitely many members of F, so ZβF in every case; only its measure is at issue.
Suppose ΞΌ(Z)<β. Let K be the largest of the finitely many numbers β£c1ββ£,β¦,β£crββ£. For xβ/Z we have s(x)=0 and hence (β£s(x)β£)p=0, while for xβZ we have β£s(x)β£β€K and hence (β£s(x)β£)pβ€Kp by Properties of Real Powers (v). So β£sβ£pβ€Kp1Zβ pointwise, and by the monotonicity and homogeneity in claim 1 of Linearity and Monotonicity of the Lebesgue Integral, and the Integrability Criterion together with The Integral of an Indicator Function is the Measure of the Set,
β«Xββ£sβ£pdΞΌβ€KpΞΌ(Z)<β,
so sβLp, the map s being measurable.
Conversely suppose sβLp. If Z is empty then ΞΌ(Z)=0<β. Otherwise let c be the smallest of the numbers β£ciββ£ with ciβξ =0, a positive real number, so that cβ€β£s(x)β£ for every xβZ and hence cp1Zββ€β£sβ£p pointwise by Properties of Real Powers (v). As above this gives cpΞΌ(Z)β€β«Xββ£sβ£pdΞΌ<β. Since cp is positive by Properties of Real Powers (i), the value ΞΌ(Z)=β would force cpΞΌ(Z)=β; hence ΞΌ(Z)<β.
Claim 2. By Approximation of Measurable Functions by Dyadic Simple Functions (iii) there is a sequence (smβ)mβNβ of simple functions with β£smββ£β€β£fβ£ pointwise and with (smβ(x))mβ converging to f(x) for every xβX. By Elementary Properties of the p-Seminorm (iii) each smβ lies in Lp.
For every x and m, claims 2 and 5 of Properties of the Absolute Value in an Ordered Field give β£f(x)βsmβ(x)β£β€β£f(x)β£+β£smβ(x)β£β€2β£f(x)β£, so by Properties of Real Powers (v) and Properties of Real Powers (iii),
(β£f(x)βsmβ(x)β£)pβ€2p(β£f(x)β£)p,
and the map 2pβ£fβ£p is integrable because fβLp. Moreover (β£f(x)βsmβ(x)β£)mβ converges to 0 for every x, hence so does ((β£f(x)βsmβ(x)β£)p)mβ by Properties of Real Powers (vii) together with 0p=0. The maps β£fβsmββ£p are measurable by Power-Integrable Functions and the p-Seminorm (i), so The Lebesgue Integral and Null Sets (vii), applied with the limit function 0Xβ, gives
mββlimββ«Xββ£fβsmββ£pdΞΌ=0.
By Elementary Properties of the p-Seminorm (i) this integral is (β₯fβsmββ₯pβ)p, and applying Properties of Real Powers (vii) with the exponent 1/p, together with ((β₯fβsmββ₯pβ)p)1/p=β₯fβsmββ₯pβ and 01/p=0, we get that β₯fβsmββ₯pβ converges to 0. In particular there is m with β₯fβsmββ₯pββ€Ξ΅, and s=smβ is as required.
Claim 3. Let FβLp and let fβLp be a representative of F. For each mβN apply claim 2 with the positive number 1/m and choose a simple smββLp with β₯fβsmββ₯pββ€1/m. Then [smβ]βS and
dpβ(F,[smβ])=β₯fβsmββ₯pββ€m1β,
by the formula for dpβ in The RieszβFischer Theorem (i). Since (1/m)mβ converges to 0, claim 3 of Order Properties of Limits of Real Sequences shows that (dpβ(F,[smβ]))mβ converges to 0, that is, ([smβ])mβ converges to F in (Lp,dpβ). By Sequential Characterization of the Closure in a Metric Space the point F lies in the closure of S. As F was arbitrary, that closure is all of Lp, so S is dense in Lp.