A minimising sequence of couplings is tight, so Prokhorov's theorem extracts a weakly convergent subsequence. Its limit is again a coupling, and by lower semicontinuity its cost does not exceed the infimum.
Each result cited below is universally quantified over the data in its own statement and is applied with the data named at the point of citation.
Step 1 (The infimum). Put . By The Quadratic Wasserstein Distance on a Hilbert Space §distance, whose preamble uses Couplings on a Hilbert Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, the Lipschitz Bound and the Moment Bound §product and Couplings on a Hilbert Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, the Lipschitz Bound and the Moment Bound §cost-finite, is a nonempty set of nonnegative real numbers, its greatest lower bound is a nonnegative real number, and is the nonnegative square root of ; hence by Existence and Uniqueness of the Nonnegative Square Root. Since is a lower bound of , every satisfies . It therefore suffices to produce with .
Step 2 (A minimising sequence). For let , where is the canonical map. By claims 2 and 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field, and exists with . For each , claim 4 of Approximation Property of the Supremum and the Infimum in , applied to the set , which is nonempty and bounded below by , and to the positive number , provides a coupling; choose one, , with
Thus every is a real number with .
Step 3 (Extraction). The space is a real Hilbert space with distance by Borel Probability Measures on a Real Hilbert Space with an Orthonormal Basis: Standing Notation §pairs, so is a metric space by The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §metric. By Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §tight the set is tight in . The set of terms of the sequence is a subset of , so for each tolerance a compact set witnessing the tightness of witnesses it for that subset as well; hence the sequence is tight in the sense of Tight Family of Borel Measures on a Metric Space §sequence. Its terms are Borel measures on of total mass by Borel Probability Measures on a Real Hilbert Space with an Orthonormal Basis: Standing Notation §measures. Hence Prokhorov's Theorem on a Metric Space: a Tight Sequence of Borel Probability Measures Has a Weakly Convergent Subsequence §subsequence, applied to the metric space and the sequence , gives a strictly increasing sequence in and a Borel measure on with , that is , such that .
Step 4 (The limit is a coupling). Put and for every . For every bounded continuous the sequence is constant with value , and therefore converges to , the distance from each term to that value being ; so in the sense of Weak Convergence of Finite Borel Measures on a Metric Space, and likewise . Since for every and , Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §closed, applied to the sequences , , and the measures , gives .
Step 5 (The cost of the limit). Put for . By Step 2 each is real with , and , so is bounded. By Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §lsc, applied in the situation of Step 4, and , where is the limit inferior.
We show . Let with be given; the following choices are made in this order. First, by claim 3 of The Archimedean Property of the Real Numbers choose with . Second, by claim 3 of Basic Properties of the Limit Inferior and Limit Superior of a Bounded Real Sequence choose with for every . Third, let be the larger of and . By Strictly Increasing Sequences of Natural Numbers Dominate Their Index, , so ; hence , with equality if and by claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field if , and so , both numbers being positive. By Step 2,
so . As was arbitrary, : otherwise , and the choice would give .
Step 6 (Conclusion). Steps 4 and 5 give with , and Step 1 gives . Hence , which is the assertion.
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