TheoremBase

A minimising sequence of couplings is tight, so Prokhorov's theorem extracts a weakly convergent subsequence. Its limit is again a coupling, and by lower semicontinuity its cost does not exceed the infimum.

Proof

Each result cited below is universally quantified over the data in its own statement and is applied with the data named at the point of citation.

Step 1 (The infimum). Put J={I(σ):σ∈Π(μ,ν)}J=\{I(\sigma):\sigma\in\Pi(\mu,\nu)\}. By The Quadratic Wasserstein Distance on a Hilbert Space §distance, whose preamble uses Couplings on a Hilbert Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, the Lipschitz Bound and the Moment Bound §product and Couplings on a Hilbert Space: Product Coupling, Swap, Finiteness of the Cost, Push-Forward Couplings, Modifying One Marginal, Quantisation, Gluing over a Finitely Supported Measure, the Lipschitz Bound and the Moment Bound §cost-finite, JJ is a nonempty set of nonnegative real numbers, its greatest lower bound c=inf⁡Jc=\inf J is a nonnegative real number, and W2(μ,ν)W_{2}(\mu,\nu) is the nonnegative square root of cc; hence W2(μ,ν)2=cW_{2}(\mu,\nu)^{2}=c by Existence and Uniqueness of the Nonnegative Square Root. Since cc is a lower bound of JJ, every σ∈Π(μ,ν)\sigma\in\Pi(\mu,\nu) satisfies c≤I(σ)c\le I(\sigma). It therefore suffices to produce π∈Π(μ,ν)\pi\in\Pi(\mu,\nu) with I(π)≤cI(\pi)\le c.

Step 2 (A minimising sequence). For j∈Nj\in\mathbb{N} let tj=ι(j)t_{j}=\iota(j), where ι:N→R\iota:\mathbb{N}\to\mathbb{R} is the canonical map. By claims 2 and 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field, 1≤tj1\le t_{j} and tj−1t_{j}^{-1} exists with 0<tj−1≤10<t_{j}^{-1}\le1. For each j∈Nj\in\mathbb{N}, claim 4 of Approximation Property of the Supremum and the Infimum in R\mathbb{R}, applied to the set JJ, which is nonempty and bounded below by 00, and to the positive number tj−1t_{j}^{-1}, provides a coupling; choose one, πj∈Π(μ,ν)\pi_{j}\in\Pi(\mu,\nu), with

I(πj)<c+tj−1.I(\pi_{j})<c+t_{j}^{-1}.

Thus every I(πj)I(\pi_{j}) is a real number with 0≤I(πj)<c+10\le I(\pi_{j})<c+1.

Step 3 (Extraction). The space X×XX\times X is a real Hilbert space with distance dd by Borel Probability Measures on a Real Hilbert Space with an Orthonormal Basis: Standing Notation §pairs, so (X×X,d)(X\times X,d) is a metric space by The Norm Metric of a Real Inner Product Space: Triangle Inequalities, Limits and Continuity §metric. By Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §tight the set Π(μ,ν)\Pi(\mu,\nu) is tight in (X×X,d)(X\times X,d). The set {πj:j∈N}\{\pi_{j}:j\in\mathbb{N}\} of terms of the sequence (πj)j∈N(\pi_{j})_{j\in\mathbb{N}} is a subset of Π(μ,ν)\Pi(\mu,\nu), so for each tolerance a compact set witnessing the tightness of Π(μ,ν)\Pi(\mu,\nu) witnesses it for that subset as well; hence the sequence (πj)j∈N(\pi_{j})_{j\in\mathbb{N}} is tight in the sense of Tight Family of Borel Measures on a Metric Space §sequence. Its terms are Borel measures on (X×X,d)(X\times X,d) of total mass 11 by Borel Probability Measures on a Real Hilbert Space with an Orthonormal Basis: Standing Notation §measures. Hence Prokhorov's Theorem on a Metric Space: a Tight Sequence of Borel Probability Measures Has a Weakly Convergent Subsequence §subsequence, applied to the metric space (X×X,d)(X\times X,d) and the sequence (πj)j∈N(\pi_{j})_{j\in\mathbb{N}}, gives a strictly increasing sequence (kj)j∈N(k_{j})_{j\in\mathbb{N}} in N\mathbb{N} and a Borel measure π\pi on (X×X,d)(X\times X,d) with π(X×X)=1\pi(X\times X)=1, that is π∈P(X×X)\pi\in\mathcal{P}(X\times X), such that πkj⇒π\pi_{k_{j}}\Rightarrow\pi.

Step 4 (The limit is a coupling). Put μj=μ\mu_{j}=\mu and νj=ν\nu_{j}=\nu for every j∈Nj\in\mathbb{N}. For every bounded continuous f:X→Rf:X\to\mathbb{R} the sequence (∫Xf dμj)j∈N\bigl(\int_{X}f\,d\mu_{j}\bigr)_{j\in\mathbb{N}} is constant with value ∫Xf dμ\int_{X}f\,d\mu, and therefore converges to ∫Xf dμ\int_{X}f\,d\mu, the distance from each term to that value being 00; so μj⇒μ\mu_{j}\Rightarrow\mu in the sense of Weak Convergence of Finite Borel Measures on a Metric Space, and likewise νj⇒ν\nu_{j}\Rightarrow\nu. Since πkj∈Π(μj,νj)\pi_{k_{j}}\in\Pi(\mu_{j},\nu_{j}) for every jj and πkj⇒π\pi_{k_{j}}\Rightarrow\pi, Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §closed, applied to the sequences (μj)(\mu_{j}), (νj)(\nu_{j}), (πkj)(\pi_{k_{j}}) and the measures μ,ν,π\mu,\nu,\pi, gives π∈Π(μ,ν)\pi\in\Pi(\mu,\nu).

Step 5 (The cost of the limit). Put aj=I(πkj)a_{j}=I(\pi_{k_{j}}) for j∈Nj\in\mathbb{N}. By Step 2 each aja_{j} is real with ∣aj∣≤c+1|a_{j}|\le c+1, and 0<c+10<c+1, so (aj)j∈N(a_{j})_{j\in\mathbb{N}} is bounded. By Couplings on a Hilbert Space: Tightness, Closedness under Weak Convergence, and Lower Semicontinuity of the Quadratic Cost §lsc, applied in the situation of Step 4, I(π)<∞I(\pi)<\infty and I(π)≤ℓI(\pi)\le\ell, where ℓ=lim inf⁡jaj\ell=\liminf_{j}a_{j} is the limit inferior.

We show ℓ≤c\ell\le c. Let ε∈R\varepsilon\in\mathbb{R} with 0<ε0<\varepsilon be given; the following choices are made in this order. First, by claim 3 of The Archimedean Property of the Real Numbers choose N∈NN\in\mathbb{N} with 0<tN−1<ε0<t_{N}^{-1}<\varepsilon. Second, by claim 3 of Basic Properties of the Limit Inferior and Limit Superior of a Bounded Real Sequence choose M∈NM\in\mathbb{N} with ℓ−ε<am\ell-\varepsilon<a_{m} for every m≥Mm\ge M. Third, let mm be the larger of NN and MM. By Strictly Increasing Sequences of Natural Numbers Dominate Their Index, m≤kmm\le k_{m}, so N≤kmN\le k_{m}; hence tN≤tkmt_{N}\le t_{k_{m}}, with equality if N=kmN=k_{m} and by claim 6 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field if N<kmN<k_{m}, and so tkm−1≤tN−1t_{k_{m}}^{-1}\le t_{N}^{-1}, both numbers being positive. By Step 2,

ℓ−ε<am=I(πkm)<c+tkm−1≤c+tN−1<c+ε,\ell-\varepsilon<a_{m}=I(\pi_{k_{m}})<c+t_{k_{m}}^{-1}\le c+t_{N}^{-1}<c+\varepsilon ,

so ℓ<c+2ε\ell<c+2\varepsilon. As ε>0\varepsilon>0 was arbitrary, ℓ≤c\ell\le c: otherwise c<ℓc<\ell, and the choice ε=(ℓ−c)/2\varepsilon=(\ell-c)/2 would give ℓ<ℓ\ell<\ell.

Step 6 (Conclusion). Steps 4 and 5 give π∈Π(μ,ν)\pi\in\Pi(\mu,\nu) with I(π)≤ℓ≤cI(\pi)\le\ell\le c, and Step 1 gives c≤I(π)c\le I(\pi). Hence I(π)=c=W2(μ,ν)2I(\pi)=c=W_{2}(\mu,\nu)^{2}, which is the assertion.

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