Existence comes from recursion on N with a step that multiplies by the next term below n and does nothing from n on, restricted to [n]; uniqueness is proved by induction on the set of k that exceed n or where the two maps agree.
Indices. By Intervals of Natural Numbers: Initial Segments, Adding One Element, Splitting and Shifting §segment, . Since by Arithmetic and Order of the Natural Numbers §least, . Let with . Then : otherwise by Arithmetic and Order of the Natural Numbers §trichotomy and Arithmetic and Order of the Natural Numbers §partial-order, and contradicts Arithmetic and Order of the Natural Numbers §successor. So , and is defined.
Existence. Let be given by if and otherwise, a map by Maps and Relations Given by Formulas §binary. By Recursion on the Natural Numbers Starting at One §recursion, applied with the set , the element and the map , there is a map with and for every . Let . Then , and for with we have , so
Uniqueness. Let both have the stated properties, and let be the set of such that either , or and . Then , since and . Let . If , then . Otherwise by Arithmetic and Order of the Natural Numbers §trichotomy, and since by Arithmetic and Order of the Natural Numbers §successor, Arithmetic and Order of the Natural Numbers §partial-order gives ; in particular fails by trichotomy, so because , and
so again . By Arithmetic and Order of the Natural Numbers §induction, . For we have , so fails by trichotomy, and gives . Hence by Basic Properties of Functions: Equality, Composition, Identity, Inverse and Restriction §equality.
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