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Proof of Cross-Level Inequalities between the Shifted Lifted N-Particle and Mean-Field Langevin Operators at Tensor Powers and through One-Particle Marginals

lemmalem:n-particle-cross-level-operator-wasserstein-2026a
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· 13,715 chars · 28 deps · depth 43 Reason: N3: proof of the cross-level operator inequalities.

The shifted operators are compared term by term. Trace terms agree exactly by the row formula for the trace and the diagonal Hessian identity. At tensor powers the penalty, pairing and cost terms scale by N and the quadratic term dominates by contraction. Through marginals the quadratic part is expanded; product fields scale norms and pairings by N, and contraction controls the squared score since its coefficient is negative for 0<theta<=1, 0<delta<1; subadditivity of the penalty and the cost hypothesis handle the rest.

Proof

Each result cited is universally quantified over the data in its own statement.

Throughout, NN is read in R\mathbb{R} as in The Real Numbers: Standing Notation and Background §numbers; it is positive by claim 3 of Properties of the Canonical Map from the Natural Numbers to an Ordered Field, and N−1N^{-1} exists. Write (D,DΣ,E,Σ)(\mathcal{D},\mathcal{D}_{\Sigma},\mathcal{E},\Sigma) for the particle-level and (DN,DN,Σ,EN,ΣN)(\mathcal{D}_{N},\mathcal{D}_{N,\Sigma},\mathcal{E}_{N},\Sigma_{N}) for the configuration-level Langevin pair, both penalty pairs by The Langevin Free-Energy Pair is a Wasserstein-Coercive Penalty Pair: Growth Bounds, Continuity of the Translation Hessian, and the First Variation of the Penalty §pair (the latter applied at the configuration level of N-Particle Systems on the Wasserstein Space: Particles, Configurations and the Configuration Level §configuration-level), so that DΣ⊆D\mathcal{D}_{\Sigma}\subseteq\mathcal{D} and DN,Σ⊆DN\mathcal{D}_{N,\Sigma}\subseteq\mathcal{D}_{N} by Penalty Pairs on the Wasserstein Space: the Penalty, Its Score, and Their Domains §pair. By The Langevin Free-Energy Pair of a Confining Potential on the Wasserstein Space §pair, Σ(ν)=∇V+σ22ξν\Sigma(\nu)=\nabla V+\tfrac{\sigma^{2}}{2}\xi_{\nu} for ν∈DΣ\nu\in\mathcal{D}_{\Sigma} and ΣN(P)=∇VN+σ22ξP\Sigma_{N}(P)=\nabla V_{N}+\tfrac{\sigma^{2}}{2}\xi_{P} for P∈DN,ΣP\in\mathcal{D}_{N,\Sigma}. Each space L2(ρ;Rr)L^{2}(\rho;\mathbb{R}^{r}) below is that of Wasserstein Spaces, Random Vectors, Vector Fields and Symmetric Matrices in Every Dimension: Standing Notation §fields; by The Space of Square-Integrable Random Vectors §inner-product it is a real inner product space whose norm is ∥⋅∥ρ\lVert\cdot\rVert_{\rho}, so Elementary Identities in a Real Inner Product Space applies to it. The rows γj∈Rd\gamma_{j}\in\mathbb{R}^{d} (j∈[p]j\in[p]) of Γ\Gamma and the matrix ΓN\Gamma_{N} are those of The N-Particle Hamilton-Jacobi Equation with Individual and Common Noise on the Configuration Space §common-noise.

Step 1 (The shifted operators). By The Bundle of Vector Fields over a Set of Measures, Second-Order Equation Operators on the Wasserstein Space, and Their Delta-Shifts §shifted and The Hamilton-Jacobi Equation with Common Noise for Controlled Langevin Dynamics in a Confining Potential on the Wasserstein Space §operator, with ⟨∇V+σ22ξν,⋅⟩ν=⟨Σ(ν),⋅⟩ν\langle\nabla V+\tfrac{\sigma^{2}}{2}\xi_{\nu},\cdot\rangle_{\nu}=\langle\Sigma(\nu),\cdot\rangle_{\nu}, for ν∈DΣ\nu\in\mathcal{D}_{\Sigma}, r∈Rr\in\mathbb{R}, q∈L2(ν;Rd)q\in L^{2}(\nu;\mathbb{R}^{d}) and Y∈S(d)Y\in\mathcal{S}(d),

Fδ+(ν,r,q,Y)=λ0(r−δE(ν))−12tr(Γ⊤Γ (Y−δHE(ν)))+θ2∥q−δΣ(ν)∥ν2+⟨Σ(ν),q−δΣ(ν)⟩ν−g(ν).F^{+}_{\delta}(\nu,r,q,Y)=\lambda_{0}\bigl(r-\delta\mathcal{E}(\nu)\bigr)-\tfrac{1}{2}\mathrm{tr}\bigl(\Gamma^{\top}\Gamma\,(Y-\delta H_{\mathcal{E}}(\nu))\bigr)+\tfrac{\theta}{2}\bigl\lVert q-\delta\Sigma(\nu)\bigr\rVert_{\nu}^{2}+\bigl\langle\Sigma(\nu),q-\delta\Sigma(\nu)\bigr\rangle_{\nu}-g(\nu).

Likewise, by the same definition read at the configuration level and The Lifted N-Particle Hamilton-Jacobi Equation on the Wasserstein Space of the Configuration Space §operator, for P∈DN,ΣP\in\mathcal{D}_{N,\Sigma}, r∈Rr\in\mathbb{R}, G∈L2(P;RdN)G\in L^{2}(P;\mathbb{R}^{dN}) and X∈S(dN)X\in\mathcal{S}(dN),

FN,δ+(P,r,G,X)=λ0(r−δEN(P))−12tr(ΓN⊤ΓN (X−δHEN(P)))+θ2∥G−δΣN(P)∥P2+⟨ΣN(P),G−δΣN(P)⟩P−∫RdNc dP.F^{+}_{N,\delta}(P,r,G,X)=\lambda_{0}\bigl(r-\delta\mathcal{E}_{N}(P)\bigr)-\tfrac{1}{2}\mathrm{tr}\bigl(\Gamma_{N}^{\top}\Gamma_{N}\,(X-\delta H_{\mathcal{E}_{N}}(P))\bigr)+\tfrac{\theta}{2}\bigl\lVert G-\delta\Sigma_{N}(P)\bigr\rVert_{P}^{2}+\bigl\langle\Sigma_{N}(P),G-\delta\Sigma_{N}(P)\bigr\rangle_{P}-\int_{\mathbb{R}^{dN}}c\,dP .

For a real inner product space EE with inner product ⟨⋅,⋅⟩\langle\cdot,\cdot\rangle and norm ∣⋅∣|\cdot|, and x,D∈Ex,D\in E, write

KE(x,D)=θ2∣x−δD∣2+⟨D,x−δD⟩,K_{E}(x,D)=\tfrac{\theta}{2}|x-\delta D|^{2}+\langle D,x-\delta D\rangle ,

so that the third and fourth terms of Fδ+(ν,r,q,Y)F^{+}_{\delta}(\nu,r,q,Y) and of FN,δ+(P,r,G,X)F^{+}_{N,\delta}(P,r,G,X) are KL2(ν;Rd)(q,Σ(ν))K_{L^{2}(\nu;\mathbb{R}^{d})}(q,\Sigma(\nu)) and KL2(P;RdN)(G,ΣN(P))K_{L^{2}(P;\mathbb{R}^{dN})}(G,\Sigma_{N}(P)).

Step 2 (The trace terms agree). Let P∈DNP\in\mathcal{D}_{N}; then P[1]∈DP^{[1]}\in\mathcal{D} by The Langevin Free-Energy Pair across the Particle and Configuration Levels: Tensor Powers, One-Particle Marginals and Diagonal Translation Hessians §marginal. We show

tr(ΓN⊤ΓN (YN−δHEN(P)))=N tr(Γ⊤Γ (Y−δHE(P[1]))).(2.1)\mathrm{tr}\bigl(\Gamma_{N}^{\top}\Gamma_{N}\,(\mathbb{Y}_{N}-\delta H_{\mathcal{E}_{N}}(P))\bigr)=N\,\mathrm{tr}\bigl(\Gamma^{\top}\Gamma\,(\mathbb{Y}-\delta H_{\mathcal{E}}(P^{[1]}))\bigr).\tag{2.1}

First, for n∈Nn\in\mathbb{N}, real n×nn\times n matrices A,BA,B and z∈Rnz\in\mathbb{R}^{n}: by Matrix-Vector Product, Difference of Real Matrices, Scalar Multiple of a Real Matrix and claims 2 and 3 of Properties of Finite Sums, each coordinate of (A−δB)z(A-\delta B)z equals the corresponding coordinate of Az−δ(Bz)Az-\delta(Bz), so the two points agree, and claim 5 of Bilinearity and Symmetry of the Dot Product on Rn\mathbb{R}^n gives

z⋅((A−δB)z)=z⋅(Az)−δ z⋅(Bz).(2.2)z\cdot\bigl((A-\delta B)z\bigr)=z\cdot(Az)-\delta\,z\cdot(Bz).\tag{2.2}

The matrices XN=YN−δHEN(P)X_{N}=\mathbb{Y}_{N}-\delta H_{\mathcal{E}_{N}}(P) and X1=Y−δHE(P[1])X_{1}=\mathbb{Y}-\delta H_{\mathcal{E}}(P^{[1]}) lie in S(dN)\mathcal{S}(dN) and S(d)\mathcal{S}(d), as recorded in The Bundle of Vector Fields over a Set of Measures, Second-Order Equation Operators on the Wasserstein Space, and Their Delta-Shifts §shifted. For j∈[p]j\in[p], (2.2), the hypothesis on YN\mathbb{Y}_{N} and Y\mathbb{Y} with a=γja=\gamma_{j}, and The Langevin Free-Energy Pair across the Particle and Configuration Levels: Tensor Powers, One-Particle Marginals and Diagonal Translation Hessians §hessian with a=γja=\gamma_{j} give

γj⊕⋅(XNγj⊕)=γj⊕⋅(YNγj⊕)−δ γj⊕⋅(HEN(P)γj⊕)=N(γj⋅(Yγj)−δ γj⋅(HE(P[1])γj))=N γj⋅(X1γj),\gamma_{j}^{\oplus}\cdot\bigl(X_{N}\gamma_{j}^{\oplus}\bigr)=\gamma_{j}^{\oplus}\cdot\bigl(\mathbb{Y}_{N}\gamma_{j}^{\oplus}\bigr)-\delta\,\gamma_{j}^{\oplus}\cdot\bigl(H_{\mathcal{E}_{N}}(P)\gamma_{j}^{\oplus}\bigr)=N\Bigl(\gamma_{j}\cdot(\mathbb{Y}\gamma_{j})-\delta\,\gamma_{j}\cdot\bigl(H_{\mathcal{E}}(P^{[1]})\gamma_{j}\bigr)\Bigr)=N\,\gamma_{j}\cdot(X_{1}\gamma_{j}),

the last step by (2.2) again. Summing over j∈[p]j\in[p], using the displayed formula of The N-Particle Hamilton-Jacobi Equation with Individual and Common Noise on the Configuration Space §common-noise with X=XNX=X_{N}, claim 3 of Properties of Finite Sums, and The Trace as a Sum of Quadratic Forms, its Monotonicity and a Norm Bound §rows applied to A=ΓA=\Gamma (with pp rows γj\gamma_{j} and dd columns) and X=X1X=X_{1},

tr(ΓN⊤ΓNXN)=∑j=1pγj⊕⋅(XNγj⊕)=N∑j=1pγj⋅(X1γj)=N tr(Γ⊤ΓX1),\mathrm{tr}\bigl(\Gamma_{N}^{\top}\Gamma_{N}X_{N}\bigr)=\sum_{j=1}^{p}\gamma_{j}^{\oplus}\cdot\bigl(X_{N}\gamma_{j}^{\oplus}\bigr)=N\sum_{j=1}^{p}\gamma_{j}\cdot(X_{1}\gamma_{j})=N\,\mathrm{tr}\bigl(\Gamma^{\top}\Gamma X_{1}\bigr),

which is (2.1). Consequently the trace terms satisfy −12tr(ΓN⊤ΓNXN)=N(−12tr(Γ⊤ΓX1))-\tfrac{1}{2}\mathrm{tr}(\Gamma_{N}^{\top}\Gamma_{N}X_{N})=N\bigl(-\tfrac{1}{2}\mathrm{tr}(\Gamma^{\top}\Gamma X_{1})\bigr).

Step 3 (At tensor powers). Suppose g=c~g=\tilde{c}, and let μ∈DΣ\mu\in\mathcal{D}_{\Sigma}, r∈Rr\in\mathbb{R} and G∈L2(μ⊗N;RdN)G\in L^{2}(\mu^{\otimes N};\mathbb{R}^{dN}). Put Q=μ⊗NQ=\mu^{\otimes N} and S=Σ(μ)∈TμS=\Sigma(\mu)\in T_{\mu}. By The Langevin Free-Energy Pair across the Particle and Configuration Levels: Tensor Powers, One-Particle Marginals and Diagonal Translation Hessians §tensor, Q∈DN,ΣQ\in\mathcal{D}_{N,\Sigma}, EN(Q)=NE(μ)\mathcal{E}_{N}(Q)=N\mathcal{E}(\mu) and ΣN(Q)=S⊕\Sigma_{N}(Q)=S^{\oplus}. By Tensor Powers and One-Particle Marginals: Particle Laws, Product Integrals, Push-Forwards, Moments, Product Maps and Diagonal Shifts §marginal-of-tensor, Q[1]=μQ^{[1]}=\mu, so ΠQ\Pi_{Q} maps L2(Q;RdN)L^{2}(Q;\mathbb{R}^{dN}) into Tμ⊆L2(μ;Rd)T_{\mu}\subseteq L^{2}(\mu;\mathbb{R}^{d}); put q1=ΠQ(G)q_{1}=\Pi_{Q}(G), so that (μ,q1)(\mu,q_{1}) and (Q,G)(Q,G) lie in the bundles over DΣ\mathcal{D}_{\Sigma} and DN,Σ\mathcal{D}_{N,\Sigma} and both sides of the asserted inequality are defined. We compare the terms of FN,δ+(Q,Nr,G,YN)F^{+}_{N,\delta}(Q,Nr,G,\mathbb{Y}_{N}) with NN times those of Fδ+(μ,r,q1,Y)F^{+}_{\delta}(\mu,r,q_{1},\mathbb{Y}), as written in Step 1.

(3a) Discount terms: λ0(Nr−δEN(Q))=λ0(Nr−δNE(μ))=Nλ0(r−δE(μ))\lambda_{0}(Nr-\delta\mathcal{E}_{N}(Q))=\lambda_{0}(Nr-\delta N\mathcal{E}(\mu))=N\lambda_{0}(r-\delta\mathcal{E}(\mu)) by the field axioms.

(3b) Trace terms: since Q∈DNQ\in\mathcal{D}_{N} and Q[1]=μQ^{[1]}=\mu, Step 2 gives equality after multiplication by NN.

(3c) Pairing terms: by The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §contraction ΠQ\Pi_{Q} is linear, and ΠQ(S⊕)=S\Pi_{Q}(S^{\oplus})=S by The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §product since S∈TμS\in T_{\mu}; hence ΠQ(G−δS⊕)=q1−δS\Pi_{Q}(G-\delta S^{\oplus})=q_{1}-\delta S. By symmetry of the inner product (condition (a) of Real Inner Product Space §inner-product) and The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §pairing with D=G−δS⊕D=G-\delta S^{\oplus} and g=Sg=S,

⟨S⊕,G−δS⊕⟩Q=⟨G−δS⊕,S⊕⟩Q=N⟨q1−δS,S⟩μ=N⟨S,q1−δS⟩μ.\bigl\langle S^{\oplus},G-\delta S^{\oplus}\bigr\rangle_{Q}=\bigl\langle G-\delta S^{\oplus},S^{\oplus}\bigr\rangle_{Q}=N\bigl\langle q_{1}-\delta S,S\bigr\rangle_{\mu}=N\bigl\langle S,q_{1}-\delta S\bigr\rangle_{\mu}.

(3d) Quadratic terms: The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §contraction with D=G−δS⊕D=G-\delta S^{\oplus} gives N∥q1−δS∥μ2≤∥G−δS⊕∥Q2N\lVert q_{1}-\delta S\rVert_{\mu}^{2}\le\lVert G-\delta S^{\oplus}\rVert_{Q}^{2}. Since 0<θ20<\tfrac{\theta}{2} by claim 8 of Elementary Order Arithmetic in an Ordered Field, claim 5 of Elementary Arithmetic in an Ordered Field gives Nθ2∥q1−δS∥μ2≤θ2∥G−δS⊕∥Q2N\tfrac{\theta}{2}\lVert q_{1}-\delta S\rVert_{\mu}^{2}\le\tfrac{\theta}{2}\lVert G-\delta S^{\oplus}\rVert_{Q}^{2}.

(3e) Running costs: by The Tensor-Averaged Running Cost of a Configuration-Space Cost §cost, c~(μ)=N−1∫c dQ\tilde{c}(\mu)=N^{-1}\int c\,dQ, so ∫RdNc dQ=Nc~(μ)=Ng(μ)\int_{\mathbb{R}^{dN}}c\,dQ=N\tilde{c}(\mu)=N g(\mu).

By (3a)--(3e) and the field axioms, FN,δ+(Q,Nr,G,YN)−N Fδ+(μ,r,q1,Y)=θ2∥G−δS⊕∥Q2−Nθ2∥q1−δS∥μ2F^{+}_{N,\delta}(Q,Nr,G,\mathbb{Y}_{N})-N\,F^{+}_{\delta}(\mu,r,q_{1},\mathbb{Y})=\tfrac{\theta}{2}\lVert G-\delta S^{\oplus}\rVert_{Q}^{2}-N\tfrac{\theta}{2}\lVert q_{1}-\delta S\rVert_{\mu}^{2}, which is nonnegative by (3d) and claim 3 of Elementary Arithmetic in an Ordered Field; the same claim yields N Fδ+(μ,r,Πμ⊗N(G),Y)≤FN,δ+(μ⊗N,Nr,G,YN)N\,F^{+}_{\delta}(\mu,r,\Pi_{\mu^{\otimes N}}(G),\mathbb{Y})\le F^{+}_{N,\delta}(\mu^{\otimes N},Nr,G,\mathbb{Y}_{N}), which is Cross-Level Inequalities between the Shifted Lifted N-Particle and Mean-Field Langevin Operators at Tensor Powers and through One-Particle Marginals §tensor.

Step 4 (A negative coefficient). Put κ=θ2δδ−δ\kappa=\tfrac{\theta}{2}\delta\delta-\delta. We show κ<0\kappa<0. By claim 8 of Elementary Order Arithmetic in an Ordered Field, 0<θ20<\tfrac{\theta}{2} and θ2<θ\tfrac{\theta}{2}<\theta; as θ≤1\theta\le1, claim 2 there gives θ2<1\tfrac{\theta}{2}<1. Since δ<1\delta<1 and 0<θ20<\tfrac{\theta}{2}, claim 10 there gives θ2δ<θ2\tfrac{\theta}{2}\delta<\tfrac{\theta}{2}, so θ2δ<1\tfrac{\theta}{2}\delta<1 by claim 2 there, and θ2δ−1<0\tfrac{\theta}{2}\delta-1<0 by claim 1 there (adding −1-1). Since 0<δ0<\delta, claim 10 there gives δ(θ2δ−1)<δ⋅0=0\delta(\tfrac{\theta}{2}\delta-1)<\delta\cdot0=0, and δ(θ2δ−1)=κ\delta(\tfrac{\theta}{2}\delta-1)=\kappa by the field axioms. Hence κ<0\kappa<0 and 0≤−κ0\le-\kappa by claim 4 there.

Step 5 (Expansion of KEK_{E}). Let EE be a real inner product space and x,D∈Ex,D\in E. By claims 5, 1 and 4 of Elementary Identities in a Real Inner Product Space, ∣x−δD∣2=∣x∣2−2δ⟨x,D⟩+δδ∣D∣2|x-\delta D|^{2}=|x|^{2}-2\delta\langle x,D\rangle+\delta\delta|D|^{2}, using ∣δ∣=δ|\delta|=\delta (Absolute Value in an Ordered Field, as 0≤δ0\le\delta); by claim 1 there and Real Inner Product Space §norm, ⟨D,x−δD⟩=⟨D,x⟩−δ∣D∣2\langle D,x-\delta D\rangle=\langle D,x\rangle-\delta|D|^{2}; and ⟨x,D⟩=⟨D,x⟩\langle x,D\rangle=\langle D,x\rangle by symmetry. With θ2⋅2=θ\tfrac{\theta}{2}\cdot2=\theta and the field axioms,

KE(x,D)=θ2∣x∣2+(1−θδ)⟨D,x⟩+κ∣D∣2.(5.1)K_{E}(x,D)=\tfrac{\theta}{2}|x|^{2}+(1-\theta\delta)\langle D,x\rangle+\kappa|D|^{2}.\tag{5.1}

Step 6 (Through one-particle marginals). Let P∈DN,ΣP\in\mathcal{D}_{N,\Sigma} satisfy Ng(P[1])≤∫c dPN g(P^{[1]})\le\int c\,dP, let r∈Rr\in\mathbb{R} and h∈TP[1]h\in T_{P^{[1]}}. Write μ1=P[1]\mu_{1}=P^{[1]}, D=ΣN(P)D=\Sigma_{N}(P) and D1=Σ(μ1)D_{1}=\Sigma(\mu_{1}). By The Langevin Free-Energy Pair across the Particle and Configuration Levels: Tensor Powers, One-Particle Marginals and Diagonal Translation Hessians §marginal, μ1∈DΣ\mu_{1}\in\mathcal{D}_{\Sigma}, NE(μ1)≤EN(P)N\mathcal{E}(\mu_{1})\le\mathcal{E}_{N}(P) and D1=ΠP(D)D_{1}=\Pi_{P}(D); the product field h⊕h^{\oplus} lies in L2(P;RdN)L^{2}(P;\mathbb{R}^{dN}) by Product Fields and the Projection onto One-Particle Tangent Fields §product-field, so both sides of the asserted inequality are defined. We compare the terms of FN,δ+(P,Nr,h⊕,YN)F^{+}_{N,\delta}(P,Nr,h^{\oplus},\mathbb{Y}_{N}) with NN times those of Fδ+(μ1,r,h,Y)F^{+}_{\delta}(\mu_{1},r,h,\mathbb{Y}).

(6a) Discount terms: from NE(μ1)≤EN(P)N\mathcal{E}(\mu_{1})\le\mathcal{E}_{N}(P) and 0≤δ0\le\delta, claim 5 of Elementary Arithmetic in an Ordered Field gives δNE(μ1)≤δEN(P)\delta N\mathcal{E}(\mu_{1})\le\delta\mathcal{E}_{N}(P), so by claim 3 there Nr−δEN(P)≤Nr−δNE(μ1)Nr-\delta\mathcal{E}_{N}(P)\le Nr-\delta N\mathcal{E}(\mu_{1}) (the difference of the right and left sides being δEN(P)−δNE(μ1)\delta\mathcal{E}_{N}(P)-\delta N\mathcal{E}(\mu_{1})), and multiplying by 0≤λ00\le\lambda_{0} (claim 5 there) λ0(Nr−δEN(P))≤Nλ0(r−δE(μ1))\lambda_{0}(Nr-\delta\mathcal{E}_{N}(P))\le N\lambda_{0}(r-\delta\mathcal{E}(\mu_{1})).

(6b) Trace terms: since P∈DNP\in\mathcal{D}_{N}, Step 2 gives equality after multiplication by NN.

(6c) Quadratic and pairing terms: by Product Fields and the Projection onto One-Particle Tangent Fields §product-field, ∥h⊕∥P2=N∥h∥μ12\lVert h^{\oplus}\rVert_{P}^{2}=N\lVert h\rVert_{\mu_{1}}^{2}; by The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §pairing with g=h∈Tμ1g=h\in T_{\mu_{1}}, ⟨D,h⊕⟩P=N⟨ΠP(D),h⟩μ1=N⟨D1,h⟩μ1\langle D,h^{\oplus}\rangle_{P}=N\langle\Pi_{P}(D),h\rangle_{\mu_{1}}=N\langle D_{1},h\rangle_{\mu_{1}}; and by The Projection onto One-Particle Tangent Fields: Pairing with Product Fields, Contraction, and Product Fields of Tangent Fields §contraction, N∥D1∥μ12≤∥D∥P2N\lVert D_{1}\rVert_{\mu_{1}}^{2}\le\lVert D\rVert_{P}^{2}, so claim 5 of Elementary Arithmetic in an Ordered Field with 0≤−κ0\le-\kappa (Step 4) and claim 4 of Elementary Order Arithmetic in an Ordered Field give κ∥D∥P2≤κN∥D1∥μ12\kappa\lVert D\rVert_{P}^{2}\le\kappa N\lVert D_{1}\rVert_{\mu_{1}}^{2}. Applying (5.1) in L2(P;RdN)L^{2}(P;\mathbb{R}^{dN}) with x=h⊕x=h^{\oplus} and in L2(μ1;Rd)L^{2}(\mu_{1};\mathbb{R}^{d}) with x=hx=h and D1D_{1} in place of DD,

KL2(P;RdN)(h⊕,D)=Nθ2∥h∥μ12+N(1−θδ)⟨D1,h⟩μ1+κ∥D∥P2≤N KL2(μ1;Rd)(h,D1),K_{L^{2}(P;\mathbb{R}^{dN})}(h^{\oplus},D)=N\tfrac{\theta}{2}\lVert h\rVert_{\mu_{1}}^{2}+N(1-\theta\delta)\langle D_{1},h\rangle_{\mu_{1}}+\kappa\lVert D\rVert_{P}^{2}\le N\,K_{L^{2}(\mu_{1};\mathbb{R}^{d})}(h,D_{1}),

the inequality by claim 3 of Elementary Arithmetic in an Ordered Field, the difference of the two sides being κN∥D1∥μ12−κ∥D∥P2\kappa N\lVert D_{1}\rVert_{\mu_{1}}^{2}-\kappa\lVert D\rVert_{P}^{2}.

(6d) Running costs: from Ng(μ1)≤∫c dPNg(\mu_{1})\le\int c\,dP, claim 4 of Elementary Order Arithmetic in an Ordered Field gives −∫c dP≤−Ng(μ1)-\int c\,dP\le-Ng(\mu_{1}).

By Step 1 and the field axioms, N Fδ+(μ1,r,h,Y)−FN,δ+(P,Nr,h⊕,YN)N\,F^{+}_{\delta}(\mu_{1},r,h,\mathbb{Y})-F^{+}_{N,\delta}(P,Nr,h^{\oplus},\mathbb{Y}_{N}) is the sum of the differences of corresponding terms in (6a)--(6d), each nonnegative by claim 3 of Elementary Arithmetic in an Ordered Field (the trace difference being 00); by claim 2 there the sum is nonnegative, and claim 3 there yields FN,δ+(P,Nr,h⊕,YN)≤N Fδ+(P[1],r,h,Y)F^{+}_{N,\delta}(P,Nr,h^{\oplus},\mathbb{Y}_{N})\le N\,F^{+}_{\delta}(P^{[1]},r,h,\mathbb{Y}), which is Cross-Level Inequalities between the Shifted Lifted N-Particle and Mean-Field Langevin Operators at Tensor Powers and through One-Particle Marginals §marginal.

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