Β· 2,947 chars Β· 7 deps Β· depth 25 Reason: First publication: proof of the comparison of the Lebesgue seminorms on the torus, by rescaling the seminorm by a power and using that the cell has measure one.
Rescaling by the power r turns the claim into the statement that a function integrable for the exponent s/r is integrable, which holds because the torus has total measure one.
Proof
Each result cited is universally quantified over the data in its own statement, and is applied here to the data named in the statement above.
Write β£vβ£r for the map on Q sending x to the power(β£v(x)β£)r.
Step 1. Apply Elementary Properties of the p-Seminorm Β§rescaling to the measurable map v, with its r taken to be r and its s taken to be q; the hypotheses hold because 0<r, 1β€q and 1β€rq=s. It gives that β£vβ£r is measurable and that vβLs(Tn) if and only if β£vβ£rβLq(Tn), and that in that case
ββ£vβ£rβqβ=(β₯vβ₯sβ)r.
Since vβLs(Tn) by hypothesis, β£vβ£rβLq(Tn) and this identity holds.
Step 3. Apply Elementary Properties of the p-Seminorm Β§rescaling again to v, this time with its r taken to be r and its s taken to be 1; the hypotheses hold because 0<r, 1β€1 and 1β€rβ 1=r. It gives that vβLr(Tn) if and only if β£vβ£rβL1(Tn), and that in that case
ββ£vβ£rβ1β=(β₯vβ₯rβ)r.
By Step 2 the right-hand condition holds, so vβLr(Tn), which is the first assertion of the claim, and this identity holds.